Optimal. Leaf size=23 \[ \log (x+(5-x \log (x)) (5+2 x-\log (\log (2 x)))) \]
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Rubi [F]
time = 12.44, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {-5+x \log (x)+\left (6 x-2 x^2+\left (-5 x-4 x^2\right ) \log (x)\right ) \log (2 x)+(x+x \log (x)) \log (2 x) \log (\log (2 x))}{\left (25 x+11 x^2+\left (-5 x^2-2 x^3\right ) \log (x)\right ) \log (2 x)+\left (-5 x+x^2 \log (x)\right ) \log (2 x) \log (\log (2 x))} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {-5+x \log (x)+\left (6 x-2 x^2+\left (-5 x-4 x^2\right ) \log (x)\right ) \log (2 x)+(x+x \log (x)) \log (2 x) \log (\log (2 x))}{x \log (2 x) \left (25+11 x-5 x \log (x)-2 x^2 \log (x)-5 \log (\log (2 x))+x \log (x) \log (\log (2 x))\right )} \, dx\\ &=\int \left (\frac {1+\log (x)}{-5+x \log (x)}+\frac {-25+10 x \log (x)-x^2 \log ^2(x)+55 x \log (2 x)+x^2 \log (2 x)-20 x^2 \log (x) \log (2 x)+2 x^3 \log ^2(x) \log (2 x)}{x (-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}\right ) \, dx\\ &=\int \frac {1+\log (x)}{-5+x \log (x)} \, dx+\int \frac {-25+10 x \log (x)-x^2 \log ^2(x)+55 x \log (2 x)+x^2 \log (2 x)-20 x^2 \log (x) \log (2 x)+2 x^3 \log ^2(x) \log (2 x)}{x (-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx\\ &=\log (5-x \log (x))+\int \left (\frac {55}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}+\frac {x}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}-\frac {20 x \log (x)}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}+\frac {2 x^2 \log ^2(x)}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}-\frac {25}{x (-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}+\frac {10 \log (x)}{(-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}-\frac {x \log ^2(x)}{(-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )}\right ) \, dx\\ &=\log (5-x \log (x))+2 \int \frac {x^2 \log ^2(x)}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx+10 \int \frac {\log (x)}{(-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx-20 \int \frac {x \log (x)}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx-25 \int \frac {1}{x (-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx+55 \int \frac {1}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx+\int \frac {x}{(-5+x \log (x)) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx-\int \frac {x \log ^2(x)}{(-5+x \log (x)) \log (2 x) \left (-25-11 x+5 x \log (x)+2 x^2 \log (x)+5 \log (\log (2 x))-x \log (x) \log (\log (2 x))\right )} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(82\) vs. \(2(23)=46\).
time = 0.06, size = 82, normalized size = 3.57 \begin {gather*} \log \left (25+11 x-5 x (\log (x)-\log (2 x))-2 x^2 (\log (x)-\log (2 x))-5 x \log (2 x)-2 x^2 \log (2 x)-5 \log (\log (2 x))+x (\log (x)-\log (2 x)) \log (\log (2 x))+x \log (2 x) \log (\log (2 x))\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 1.41, size = 38, normalized size = 1.65
method | result | size |
default | \(\ln \left (2 x^{2} \ln \left (x \right )-\ln \left (x \right ) \ln \left (\ln \left (2\right )+\ln \left (x \right )\right ) x +5 x \ln \left (x \right )-11 x +5 \ln \left (\ln \left (2\right )+\ln \left (x \right )\right )-25\right )\) | \(38\) |
risch | \(\ln \left (x \right )+\ln \left (\ln \left (x \right )-\frac {5}{x}\right )+\ln \left (\ln \left (\ln \left (2\right )+\ln \left (x \right )\right )-\frac {2 x^{2} \ln \left (x \right )+5 x \ln \left (x \right )-11 x -25}{x \ln \left (x \right )-5}\right )\) | \(48\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 56 vs.
\(2 (23) = 46\).
time = 0.51, size = 56, normalized size = 2.43 \begin {gather*} \log \left (x\right ) + \log \left (-\frac {{\left (2 \, x^{2} + 5 \, x\right )} \log \left (x\right ) - {\left (x \log \left (x\right ) - 5\right )} \log \left (\log \left (2\right ) + \log \left (x\right )\right ) - 11 \, x - 25}{x \log \left (x\right ) - 5}\right ) + \log \left (\frac {x \log \left (x\right ) - 5}{x}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 56 vs.
\(2 (23) = 46\).
time = 0.35, size = 56, normalized size = 2.43 \begin {gather*} \log \left (x\right ) + \log \left (-\frac {{\left (2 \, x^{2} + 5 \, x\right )} \log \left (x\right ) - {\left (x \log \left (x\right ) - 5\right )} \log \left (\log \left (2\right ) + \log \left (x\right )\right ) - 11 \, x - 25}{x \log \left (x\right ) - 5}\right ) + \log \left (\frac {x \log \left (x\right ) - 5}{x}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 48 vs.
\(2 (20) = 40\).
time = 0.89, size = 48, normalized size = 2.09 \begin {gather*} \log {\left (x \right )} + \log {\left (\log {\left (x \right )} - \frac {5}{x} \right )} + \log {\left (\log {\left (\log {\left (x \right )} + \log {\left (2 \right )} \right )} + \frac {- 2 x^{2} \log {\left (x \right )} - 5 x \log {\left (x \right )} + 11 x + 25}{x \log {\left (x \right )} - 5} \right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.42, size = 37, normalized size = 1.61 \begin {gather*} \log \left (2 \, x^{2} \log \left (x\right ) - x \log \left (x\right ) \log \left (\log \left (2\right ) + \log \left (x\right )\right ) + 5 \, x \log \left (x\right ) - 11 \, x + 5 \, \log \left (\log \left (2\right ) + \log \left (x\right )\right ) - 25\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.87, size = 57, normalized size = 2.48 \begin {gather*} \ln \left (\frac {x\,\ln \left (x\right )-5}{x}\right )+\ln \left (\frac {11\,x-5\,\ln \left (\ln \left (2\,x\right )\right )-2\,x^2\,\ln \left (x\right )-5\,x\,\ln \left (x\right )+x\,\ln \left (\ln \left (2\,x\right )\right )\,\ln \left (x\right )+25}{x\,\ln \left (x\right )-5}\right )+\ln \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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