Optimal. Leaf size=29 \[ \frac {e^{-x+\frac {5}{\log (3)}} (3+2 x-\log (2)) (5+\log (2))}{x} \]
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Rubi [A]
time = 0.20, antiderivative size = 57, normalized size of antiderivative = 1.97, number of steps
used = 6, number of rules used = 4, integrand size = 49, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.082, Rules used = {2230, 2225,
2208, 2209} \begin {gather*} \frac {e^{\frac {5}{\log (3)}} \left (15-\log ^2(2)-\log (4)\right ) 3^{-\frac {x}{\log (3)}}}{x}+2 e^{\frac {5}{\log (3)}} (5+\log (2)) 3^{-\frac {x}{\log (3)}} \end {gather*}
Antiderivative was successfully verified.
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Rule 2208
Rule 2209
Rule 2225
Rule 2230
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \left (-2 e^{\frac {5-x \log (3)}{\log (3)}} (5+\log (2))+\frac {e^{\frac {5-x \log (3)}{\log (3)}} \left (-15+\log ^2(2)+\log (4)\right )}{x^2}+\frac {e^{\frac {5-x \log (3)}{\log (3)}} \left (-15+\log ^2(2)+\log (4)\right )}{x}\right ) \, dx\\ &=-\left ((2 (5+\log (2))) \int e^{\frac {5-x \log (3)}{\log (3)}} \, dx\right )+\left (-15+\log ^2(2)+\log (4)\right ) \int \frac {e^{\frac {5-x \log (3)}{\log (3)}}}{x^2} \, dx+\left (-15+\log ^2(2)+\log (4)\right ) \int \frac {e^{\frac {5-x \log (3)}{\log (3)}}}{x} \, dx\\ &=2\ 3^{-\frac {x}{\log (3)}} e^{\frac {5}{\log (3)}} (5+\log (2))+\frac {3^{-\frac {x}{\log (3)}} e^{\frac {5}{\log (3)}} \left (15-\log ^2(2)-\log (4)\right )}{x}-e^{\frac {5}{\log (3)}} \text {Ei}(-x) \left (15-\log ^2(2)-\log (4)\right )+\left (15-\log ^2(2)-\log (4)\right ) \int \frac {e^{\frac {5-x \log (3)}{\log (3)}}}{x} \, dx\\ &=2\ 3^{-\frac {x}{\log (3)}} e^{\frac {5}{\log (3)}} (5+\log (2))+\frac {3^{-\frac {x}{\log (3)}} e^{\frac {5}{\log (3)}} \left (15-\log ^2(2)-\log (4)\right )}{x}\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.02, size = 29, normalized size = 1.00 \begin {gather*} \frac {e^{-x+\frac {5}{\log (3)}} (3+2 x-\log (2)) (5+\log (2))}{x} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(83\) vs.
\(2(28)=56\).
time = 1.52, size = 84, normalized size = 2.90
method | result | size |
gosper | \(-\frac {{\mathrm e}^{-\frac {x \ln \left (3\right )-5}{\ln \left (3\right )}} \left (\ln \left (2\right )+5\right ) \left (-3-2 x +\ln \left (2\right )\right )}{x}\) | \(30\) |
risch | \(-\frac {\left (\ln \left (2\right )^{2}-2 x \ln \left (2\right )+2 \ln \left (2\right )-10 x -15\right ) {\mathrm e}^{-\frac {x \ln \left (3\right )-5}{\ln \left (3\right )}}}{x}\) | \(37\) |
norman | \(\frac {\left (-\ln \left (2\right )^{2}-2 \ln \left (2\right )+15\right ) {\mathrm e}^{\frac {-x \ln \left (3\right )+5}{\ln \left (3\right )}}+\left (10+2 \ln \left (2\right )\right ) x \,{\mathrm e}^{\frac {-x \ln \left (3\right )+5}{\ln \left (3\right )}}}{x}\) | \(53\) |
derivativedivides | \(-\frac {\ln \left (2\right )^{2} {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+\frac {15 \,{\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+10 \,{\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}-\frac {2 \ln \left (2\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+2 \ln \left (2\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}\) | \(84\) |
default | \(-\frac {\ln \left (2\right )^{2} {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+\frac {15 \,{\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+10 \,{\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}-\frac {2 \ln \left (2\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}}{x}+2 \ln \left (2\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}-x}\) | \(84\) |
meijerg | \(\left (-2 \ln \left (2\right )-10\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}} \left (1-{\mathrm e}^{-x}\right )-\left (\ln \left (2\right )^{2}+2 \ln \left (2\right )-15\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}} \expIntegral \left (1, x\right )+\ln \left (2\right )^{2} {\mathrm e}^{\frac {5}{\ln \left (3\right )}} \left (\frac {-2 x +2}{2 x}-\frac {{\mathrm e}^{-x}}{x}+\expIntegral \left (1, x\right )+1-\frac {1}{x}\right )+2 \ln \left (2\right ) {\mathrm e}^{\frac {5}{\ln \left (3\right )}} \left (\frac {-2 x +2}{2 x}-\frac {{\mathrm e}^{-x}}{x}+\expIntegral \left (1, x\right )+1-\frac {1}{x}\right )-15 \,{\mathrm e}^{\frac {5}{\ln \left (3\right )}} \left (\frac {-2 x +2}{2 x}-\frac {{\mathrm e}^{-x}}{x}+\expIntegral \left (1, x\right )+1-\frac {1}{x}\right )\) | \(165\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.52, size = 115, normalized size = 3.97 \begin {gather*} {\rm Ei}\left (-x\right ) e^{\frac {5}{\log \left (3\right )}} \log \left (2\right )^{2} - e^{\frac {5}{\log \left (3\right )}} \Gamma \left (-1, x\right ) \log \left (2\right )^{2} + 2 \, {\rm Ei}\left (-x\right ) e^{\frac {5}{\log \left (3\right )}} \log \left (2\right ) - 2 \, e^{\frac {5}{\log \left (3\right )}} \Gamma \left (-1, x\right ) \log \left (2\right ) - 15 \, {\rm Ei}\left (-x\right ) e^{\frac {5}{\log \left (3\right )}} + 15 \, e^{\frac {5}{\log \left (3\right )}} \Gamma \left (-1, x\right ) + 2 \, e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} \log \left (2\right ) + 10 \, e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 35, normalized size = 1.21 \begin {gather*} \frac {{\left (2 \, {\left (x - 1\right )} \log \left (2\right ) - \log \left (2\right )^{2} + 10 \, x + 15\right )} e^{\left (-\frac {x \log \left (3\right ) - 5}{\log \left (3\right )}\right )}}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.06, size = 34, normalized size = 1.17 \begin {gather*} \frac {\left (2 x \log {\left (2 \right )} + 10 x - 2 \log {\left (2 \right )} - \log {\left (2 \right )}^{2} + 15\right ) e^{\frac {- x \log {\left (3 \right )} + 5}{\log {\left (3 \right )}}}}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 80 vs.
\(2 (28) = 56\).
time = 0.41, size = 80, normalized size = 2.76 \begin {gather*} \frac {2 \, x e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} \log \left (2\right ) - e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} \log \left (2\right )^{2} + 10 \, x e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} - 2 \, e^{\left (-x + \frac {5}{\log \left (3\right )}\right )} \log \left (2\right ) + 15 \, e^{\left (-x + \frac {5}{\log \left (3\right )}\right )}}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.23, size = 34, normalized size = 1.17 \begin {gather*} \frac {{\mathrm {e}}^{\frac {5}{\ln \left (3\right )}-x}\,\left (10\,x-\ln \left (4\right )+x\,\ln \left (4\right )-{\ln \left (2\right )}^2+15\right )}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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