Optimal. Leaf size=31 \[ x+\frac {x}{x+\frac {1}{8} \left (2 x-\log (4)+\frac {5 x}{5+x \log (x)}\right )} \]
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Rubi [F]
time = 2.84, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {3065 x^2+(-200-550 x) \log (4)+25 \log ^2(4)+\left (40 x^2+1100 x^3+\left (-80 x-210 x^2\right ) \log (4)+10 x \log ^2(4)\right ) \log (x)+\left (100 x^4+\left (-8 x^2-20 x^3\right ) \log (4)+x^2 \log ^2(4)\right ) \log ^2(x)}{3025 x^2-550 x \log (4)+25 \log ^2(4)+\left (1100 x^3-210 x^2 \log (4)+10 x \log ^2(4)\right ) \log (x)+\left (100 x^4-20 x^3 \log (4)+x^2 \log ^2(4)\right ) \log ^2(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {5 \left (613 x^2-110 x \log (4)+5 (-8+\log (4)) \log (4)\right )+10 x \left (110 x^2+x (4-21 \log (4))+(-8+\log (4)) \log (4)\right ) \log (x)+x^2 \left (100 x^2-20 x \log (4)+(-8+\log (4)) \log (4)\right ) \log ^2(x)}{(55 x-5 \log (4)+x (10 x-\log (4)) \log (x))^2} \, dx\\ &=\int \left (\frac {100 x^2-20 x \log (4)-(8-\log (4)) \log (4)}{(10 x-\log (4))^2}+\frac {40 x \left (100 x^3-5 \log ^2(4)+x \log (4) (100+\log (4))-10 x^2 (55+\log (16))\right )}{(10 x-\log (4))^2 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2}+\frac {40 x (10 x+\log (4))}{(10 x-\log (4))^2 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )}\right ) \, dx\\ &=40 \int \frac {x \left (100 x^3-5 \log ^2(4)+x \log (4) (100+\log (4))-10 x^2 (55+\log (16))\right )}{(10 x-\log (4))^2 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2} \, dx+40 \int \frac {x (10 x+\log (4))}{(10 x-\log (4))^2 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )} \, dx+\int \frac {100 x^2-20 x \log (4)-(8-\log (4)) \log (4)}{(10 x-\log (4))^2} \, dx\\ &=40 \int \left (-\frac {11 x}{2 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2}+\frac {x^2}{\left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2}-\frac {3 \log ^2(4)}{20 (10 x-\log (4)) \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2}-\frac {\log (4)}{10 \left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )^2}-\frac {\log ^3(4)}{20 (-10 x+\log (4))^2 \left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )^2}\right ) \, dx+40 \int \left (\frac {1}{10 \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )}+\frac {\log (64)}{10 (10 x-\log (4)) \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )}-\frac {\log ^2(4)}{5 (-10 x+\log (4))^2 \left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )}\right ) \, dx+\int \left (1-\frac {8 \log (4)}{(-10 x+\log (4))^2}\right ) \, dx\\ &=x+\frac {4 \log (4)}{5 (10 x-\log (4))}+4 \int \frac {1}{55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)} \, dx+40 \int \frac {x^2}{\left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2} \, dx-220 \int \frac {x}{\left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2} \, dx-(4 \log (4)) \int \frac {1}{\left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )^2} \, dx-\left (6 \log ^2(4)\right ) \int \frac {1}{(10 x-\log (4)) \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )^2} \, dx-\left (8 \log ^2(4)\right ) \int \frac {1}{(-10 x+\log (4))^2 \left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )} \, dx-\left (2 \log ^3(4)\right ) \int \frac {1}{(-10 x+\log (4))^2 \left (-55 x+5 \log (4)-10 x^2 \log (x)+x \log (4) \log (x)\right )^2} \, dx+(4 \log (64)) \int \frac {1}{(10 x-\log (4)) \left (55 x-5 \log (4)+10 x^2 \log (x)-x \log (4) \log (x)\right )} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.15, size = 52, normalized size = 1.68 \begin {gather*} x+\frac {\log (256)}{50 x-5 \log (4)}-\frac {40 x^2}{(10 x-\log (4)) (55 x-5 \log (4)+x (10 x-\log (4)) \log (x))} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(71\) vs.
\(2(25)=50\).
time = 14.13, size = 72, normalized size = 2.32
method | result | size |
risch | \(\frac {5 x \ln \left (2\right )-25 x^{2}-4 \ln \left (2\right )}{5 \ln \left (2\right )-25 x}-\frac {20 x^{2}}{\left (\ln \left (2\right )-5 x \right ) \left (2 x \ln \left (2\right ) \ln \left (x \right )-10 x^{2} \ln \left (x \right )+10 \ln \left (2\right )-55 x \right )}\) | \(64\) |
default | \(\frac {\left (4-\ln \left (2\right )\right ) x +\left (\frac {2 \ln \left (2\right )^{2}}{5}-\frac {8 \ln \left (2\right )}{5}\right ) \ln \left (x \right ) x -55 x^{2}-10 x^{3} \ln \left (x \right )+2 \ln \left (2\right )^{2}-8 \ln \left (2\right )}{2 x \ln \left (2\right ) \ln \left (x \right )-10 x^{2} \ln \left (x \right )+10 \ln \left (2\right )-55 x}\) | \(72\) |
norman | \(\frac {\left (4-\ln \left (2\right )\right ) x +\left (\frac {2 \ln \left (2\right )^{2}}{5}-\frac {8 \ln \left (2\right )}{5}\right ) \ln \left (x \right ) x -55 x^{2}-10 x^{3} \ln \left (x \right )+2 \ln \left (2\right )^{2}-8 \ln \left (2\right )}{2 x \ln \left (2\right ) \ln \left (x \right )-10 x^{2} \ln \left (x \right )+10 \ln \left (2\right )-55 x}\) | \(72\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 68 vs.
\(2 (26) = 52\).
time = 0.51, size = 68, normalized size = 2.19 \begin {gather*} \frac {275 \, x^{2} - 10 \, x {\left (5 \, \log \left (2\right ) + 2\right )} + 2 \, {\left (25 \, x^{3} - 5 \, x^{2} \log \left (2\right ) + 4 \, x \log \left (2\right )\right )} \log \left (x\right ) + 40 \, \log \left (2\right )}{5 \, {\left (2 \, {\left (5 \, x^{2} - x \log \left (2\right )\right )} \log \left (x\right ) + 55 \, x - 10 \, \log \left (2\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 68 vs.
\(2 (26) = 52\).
time = 0.37, size = 68, normalized size = 2.19 \begin {gather*} \frac {275 \, x^{2} - 10 \, {\left (5 \, x - 4\right )} \log \left (2\right ) + 2 \, {\left (25 \, x^{3} - {\left (5 \, x^{2} - 4 \, x\right )} \log \left (2\right )\right )} \log \left (x\right ) - 20 \, x}{5 \, {\left (2 \, {\left (5 \, x^{2} - x \log \left (2\right )\right )} \log \left (x\right ) + 55 \, x - 10 \, \log \left (2\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 63 vs.
\(2 (24) = 48\).
time = 0.19, size = 63, normalized size = 2.03 \begin {gather*} - \frac {20 x^{2}}{275 x^{2} - 105 x \log {\left (2 \right )} + \left (50 x^{3} - 20 x^{2} \log {\left (2 \right )} + 2 x \log {\left (2 \right )}^{2}\right ) \log {\left (x \right )} + 10 \log {\left (2 \right )}^{2}} + x + \frac {4 \log {\left (2 \right )}}{25 x - 5 \log {\left (2 \right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 65 vs.
\(2 (26) = 52\).
time = 0.44, size = 65, normalized size = 2.10 \begin {gather*} x - \frac {20 \, x^{2}}{50 \, x^{3} \log \left (x\right ) - 20 \, x^{2} \log \left (2\right ) \log \left (x\right ) + 2 \, x \log \left (2\right )^{2} \log \left (x\right ) + 275 \, x^{2} - 105 \, x \log \left (2\right ) + 10 \, \log \left (2\right )^{2}} + \frac {4 \, \log \left (2\right )}{5 \, {\left (5 \, x - \log \left (2\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {100\,{\ln \left (2\right )}^2-2\,\ln \left (2\right )\,\left (550\,x+200\right )+{\ln \left (x\right )}^2\,\left (4\,x^2\,{\ln \left (2\right )}^2-2\,\ln \left (2\right )\,\left (20\,x^3+8\,x^2\right )+100\,x^4\right )+3065\,x^2+\ln \left (x\right )\,\left (40\,x\,{\ln \left (2\right )}^2-2\,\ln \left (2\right )\,\left (210\,x^2+80\,x\right )+40\,x^2+1100\,x^3\right )}{\ln \left (x\right )\,\left (1100\,x^3-420\,\ln \left (2\right )\,x^2+40\,{\ln \left (2\right )}^2\,x\right )-1100\,x\,\ln \left (2\right )+100\,{\ln \left (2\right )}^2+3025\,x^2+{\ln \left (x\right )}^2\,\left (100\,x^4-40\,\ln \left (2\right )\,x^3+4\,{\ln \left (2\right )}^2\,x^2\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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