Optimal. Leaf size=25 \[ \log \left (\frac {x+e^4 x \log (x)}{\log \left (\frac {5+\log (2)}{6+\log (x)}\right )}\right ) \]
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Rubi [A]
time = 0.34, antiderivative size = 27, normalized size of antiderivative = 1.08, number of steps
used = 12, number of rules used = 7, integrand size = 87, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.080, Rules used = {6, 6820, 6860,
45, 2437, 2339, 29} \begin {gather*} \log (x)+\log \left (e^4 \log (x)+1\right )-\log \left (\log \left (\frac {5+\log (2)}{\log (x)+6}\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Rule 6
Rule 29
Rule 45
Rule 2339
Rule 2437
Rule 6820
Rule 6860
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\text {Subst}\left (\int \frac {1+e^4 x+6 \log \left (\frac {5+\log (2)}{6+x}\right )+6 e^4 \log \left (\frac {5+\log (2)}{6+x}\right )+x \log \left (\frac {5+\log (2)}{6+x}\right )+7 e^4 x \log \left (\frac {5+\log (2)}{6+x}\right )+e^4 x^2 \log \left (\frac {5+\log (2)}{6+x}\right )}{\left (6+x+6 e^4 x+e^4 x^2\right ) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \frac {1+e^4 x+6 \log \left (\frac {5+\log (2)}{6+x}\right )+6 e^4 \log \left (\frac {5+\log (2)}{6+x}\right )+x \log \left (\frac {5+\log (2)}{6+x}\right )+7 e^4 x \log \left (\frac {5+\log (2)}{6+x}\right )+e^4 x^2 \log \left (\frac {5+\log (2)}{6+x}\right )}{\left (6+\left (1+6 e^4\right ) x+e^4 x^2\right ) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \frac {1+e^4 x+\left (6+6 e^4\right ) \log \left (\frac {5+\log (2)}{6+x}\right )+x \log \left (\frac {5+\log (2)}{6+x}\right )+7 e^4 x \log \left (\frac {5+\log (2)}{6+x}\right )+e^4 x^2 \log \left (\frac {5+\log (2)}{6+x}\right )}{\left (6+\left (1+6 e^4\right ) x+e^4 x^2\right ) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \frac {1+e^4 x+\left (6+6 e^4\right ) \log \left (\frac {5+\log (2)}{6+x}\right )+\left (1+7 e^4\right ) x \log \left (\frac {5+\log (2)}{6+x}\right )+e^4 x^2 \log \left (\frac {5+\log (2)}{6+x}\right )}{\left (6+\left (1+6 e^4\right ) x+e^4 x^2\right ) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \frac {1+e^4 x+\left (6+x+e^4 \left (6+7 x+x^2\right )\right ) \log \left (\frac {5+\log (2)}{6+x}\right )}{\left (6+\left (1+6 e^4\right ) x+e^4 x^2\right ) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \left (\frac {1+e^4+e^4 x}{1+e^4 x}+\frac {1}{(6+x) \log \left (\frac {5+\log (2)}{6+x}\right )}\right ) \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \frac {1+e^4+e^4 x}{1+e^4 x} \, dx,x,\log (x)\right )+\text {Subst}\left (\int \frac {1}{(6+x) \log \left (\frac {5+\log (2)}{6+x}\right )} \, dx,x,\log (x)\right )\\ &=\text {Subst}\left (\int \left (1+\frac {e^4}{1+e^4 x}\right ) \, dx,x,\log (x)\right )+\text {Subst}\left (\int \frac {1}{x \log \left (\frac {5+\log (2)}{x}\right )} \, dx,x,6+\log (x)\right )\\ &=\log (x)+\log \left (1+e^4 \log (x)\right )-\text {Subst}\left (\int \frac {1}{x} \, dx,x,\log \left (\frac {5+\log (2)}{6+\log (x)}\right )\right )\\ &=\log (x)+\log \left (1+e^4 \log (x)\right )-\log \left (\log \left (\frac {5+\log (2)}{6+\log (x)}\right )\right )\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.04, size = 28, normalized size = 1.12 \begin {gather*} 6+\log (x)+\log \left (1+e^4 \log (x)\right )-\log \left (\log \left (\frac {5+\log (2)}{6+\log (x)}\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(63\) vs.
\(2(24)=48\).
time = 5.20, size = 64, normalized size = 2.56
method | result | size |
risch | \(\ln \left (x \right )+\ln \left (\ln \left (x \right )+{\mathrm e}^{-4}\right )-\ln \left (\ln \left (\ln \left (x \right )+6\right )-\ln \left (\ln \left (2\right )+5\right )\right )\) | \(26\) |
norman | \(\ln \left (x \right )-\ln \left (\ln \left (\frac {\ln \left (2\right )+5}{\ln \left (x \right )+6}\right )\right )+\ln \left ({\mathrm e}^{4} \ln \left (x \right )+1\right )\) | \(27\) |
default | \(-\left (-1+\frac {\ln \left (\frac {1}{\ln \left (x \right )+6}\right )}{\ln \left (x \right )+6}\right ) \left (\ln \left (x \right )+6\right )+\ln \left (\frac {6 \,{\mathrm e}^{4}}{\ln \left (x \right )+6}-{\mathrm e}^{4}-\frac {1}{\ln \left (x \right )+6}\right )-\ln \left (\ln \left (\ln \left (2\right )+5\right )+\ln \left (\frac {1}{\ln \left (x \right )+6}\right )\right )\) | \(64\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.64, size = 30, normalized size = 1.20 \begin {gather*} \log \left ({\left (e^{4} \log \left (x\right ) + 1\right )} e^{\left (-4\right )}\right ) + \log \left (x\right ) - \log \left (-\log \left (\log \left (2\right ) + 5\right ) + \log \left (\log \left (x\right ) + 6\right )\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 26, normalized size = 1.04 \begin {gather*} \log \left (e^{4} \log \left (x\right ) + 1\right ) + \log \left (x\right ) - \log \left (\log \left (\frac {\log \left (2\right ) + 5}{\log \left (x\right ) + 6}\right )\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.13, size = 26, normalized size = 1.04 \begin {gather*} \log {\left (x \right )} + \log {\left (\log {\left (x \right )} + e^{-4} \right )} - \log {\left (\log {\left (\frac {\log {\left (2 \right )} + 5}{\log {\left (x \right )} + 6} \right )} \right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.47, size = 27, normalized size = 1.08 \begin {gather*} \log \left (e^{4} \log \left (x\right ) + 1\right ) + \log \left (x\right ) - \log \left (-\log \left (\log \left (2\right ) + 5\right ) + \log \left (\log \left (x\right ) + 6\right )\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.91, size = 24, normalized size = 0.96 \begin {gather*} \ln \left ({\mathrm {e}}^{-4}+\ln \left (x\right )\right )-\ln \left (\ln \left (\frac {\ln \left (2\right )+5}{\ln \left (x\right )+6}\right )\right )+\ln \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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