Optimal. Leaf size=20 \[ x \left (\frac {3}{2 \log (5)}-3 e^{-11 x} \log (x)\right ) \]
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Rubi [A]
time = 0.03, antiderivative size = 37, normalized size of antiderivative = 1.85, number of steps
used = 6, number of rules used = 4, integrand size = 34, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {12, 2225, 2207,
2634} \begin {gather*} \frac {3 x}{2 \log (5)}-\frac {3}{11} e^{-11 x} \log (x)+\frac {3}{11} e^{-11 x} (1-11 x) \log (x) \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2207
Rule 2225
Rule 2634
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\frac {\int \left (3-6 e^{-11 x} \log (5)+e^{-11 x} (-6+66 x) \log (5) \log (x)\right ) \, dx}{2 \log (5)}\\ &=\frac {3 x}{2 \log (5)}+\frac {1}{2} \int e^{-11 x} (-6+66 x) \log (x) \, dx-3 \int e^{-11 x} \, dx\\ &=\frac {3 e^{-11 x}}{11}+\frac {3 x}{2 \log (5)}-\frac {3}{11} e^{-11 x} \log (x)+\frac {3}{11} e^{-11 x} (1-11 x) \log (x)-\frac {1}{2} \int -6 e^{-11 x} \, dx\\ &=\frac {3 e^{-11 x}}{11}+\frac {3 x}{2 \log (5)}-\frac {3}{11} e^{-11 x} \log (x)+\frac {3}{11} e^{-11 x} (1-11 x) \log (x)+3 \int e^{-11 x} \, dx\\ &=\frac {3 x}{2 \log (5)}-\frac {3}{11} e^{-11 x} \log (x)+\frac {3}{11} e^{-11 x} (1-11 x) \log (x)\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.06, size = 20, normalized size = 1.00 \begin {gather*} \frac {3 \left (x-2 e^{-11 x} x \log (5) \log (x)\right )}{\log (25)} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.50, size = 22, normalized size = 1.10
method | result | size |
norman | \(\frac {3 x}{2 \ln \left (5\right )}-3 x \,{\mathrm e}^{-11 x} \ln \left (x \right )\) | \(18\) |
risch | \(\frac {3 x}{2 \ln \left (5\right )}-3 x \,{\mathrm e}^{-11 x} \ln \left (x \right )\) | \(18\) |
default | \(\frac {3 x -6 \ln \left (5\right ) {\mathrm e}^{-11 x} \ln \left (x \right ) x}{2 \ln \left (5\right )}\) | \(22\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.26, size = 21, normalized size = 1.05 \begin {gather*} -\frac {3 \, {\left (2 \, x e^{\left (-11 \, x\right )} \log \left (5\right ) \log \left (x\right ) - x\right )}}{2 \, \log \left (5\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 21, normalized size = 1.05 \begin {gather*} -\frac {3 \, {\left (2 \, x e^{\left (-11 \, x\right )} \log \left (5\right ) \log \left (x\right ) - x\right )}}{2 \, \log \left (5\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.09, size = 19, normalized size = 0.95 \begin {gather*} \frac {3 x}{2 \log {\left (5 \right )}} - 3 x e^{- 11 x} \log {\left (x \right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.40, size = 36, normalized size = 1.80 \begin {gather*} -\frac {3 \, {\left (2 \, {\left (11 \, x e^{\left (-11 \, x\right )} \log \left (x\right ) + e^{\left (-11 \, x\right )}\right )} \log \left (5\right ) - 2 \, e^{\left (-11 \, x\right )} \log \left (5\right ) - 11 \, x\right )}}{22 \, \log \left (5\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.10, size = 17, normalized size = 0.85 \begin {gather*} \frac {3\,x}{2\,\ln \left (5\right )}-3\,x\,{\mathrm {e}}^{-11\,x}\,\ln \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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