Optimal. Leaf size=30 \[ \frac {e^x \log (3)}{x \left (x+x \log \left (9 e^{-x}\right )-x \log (2 x)\right )} \]
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Rubi [F]
time = 1.16, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {e^x (-1+2 x) \log (3)+e^x (-2+x) \log (3) \log \left (9 e^{-x}\right )+e^x (2-x) \log (3) \log (2 x)}{x^3+x^3 \log ^2\left (9 e^{-x}\right )-2 x^3 \log (2 x)+x^3 \log ^2(2 x)+\log \left (9 e^{-x}\right ) \left (2 x^3-2 x^3 \log (2 x)\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {e^x \log (3) \left (-1+2 x+(-2+x) \log \left (9 e^{-x}\right )-(-2+x) \log (2 x)\right )}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2} \, dx\\ &=\log (3) \int \frac {e^x \left (-1+2 x+(-2+x) \log \left (9 e^{-x}\right )-(-2+x) \log (2 x)\right )}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2} \, dx\\ &=\log (3) \int \left (\frac {e^x (1+x)}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2}+\frac {e^x (-2+x)}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )}\right ) \, dx\\ &=\log (3) \int \frac {e^x (1+x)}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2} \, dx+\log (3) \int \frac {e^x (-2+x)}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )} \, dx\\ &=\log (3) \int \left (\frac {e^x}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2}+\frac {e^x}{x^2 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2}\right ) \, dx+\log (3) \int \left (-\frac {2 e^x}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )}+\frac {e^x}{x^2 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )}\right ) \, dx\\ &=\log (3) \int \frac {e^x}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2} \, dx+\log (3) \int \frac {e^x}{x^2 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )^2} \, dx+\log (3) \int \frac {e^x}{x^2 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )} \, dx-(2 \log (3)) \int \frac {e^x}{x^3 \left (1+\log \left (9 e^{-x}\right )-\log (2 x)\right )} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.15, size = 28, normalized size = 0.93 \begin {gather*} -\frac {e^x \log (3)}{x^2 \left (-1-\log \left (9 e^{-x}\right )+\log (2 x)\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.40, size = 29, normalized size = 0.97
method | result | size |
risch | \(\frac {2 \ln \left (3\right ) {\mathrm e}^{x}}{x^{2} \left (2+4 \ln \left (3\right )-2 \ln \left (2 x \right )-2 \ln \left ({\mathrm e}^{x}\right )\right )}\) | \(29\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.52, size = 33, normalized size = 1.10 \begin {gather*} -\frac {e^{x} \log \left (3\right )}{x^{3} - x^{2} {\left (2 \, \log \left (3\right ) - \log \left (2\right ) + 1\right )} + x^{2} \log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.34, size = 32, normalized size = 1.07 \begin {gather*} -\frac {e^{x} \log \left (3\right )}{x^{3} - 2 \, x^{2} \log \left (3\right ) + x^{2} \log \left (2 \, x\right ) - x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.14, size = 31, normalized size = 1.03 \begin {gather*} - \frac {e^{x} \log {\left (3 \right )}}{x^{3} + x^{2} \log {\left (2 x \right )} - 2 x^{2} \log {\left (3 \right )} - x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.42, size = 36, normalized size = 1.20 \begin {gather*} -\frac {e^{x} \log \left (3\right )}{x^{3} - 2 \, x^{2} \log \left (3\right ) + x^{2} \log \left (2\right ) + x^{2} \log \left (x\right ) - x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.92, size = 50, normalized size = 1.67 \begin {gather*} \frac {{\mathrm {e}}^x\,\left (\ln \left (3\right )-2\,\ln \left (2\,x\right )\,\ln \left (3\right )+\ln \left (2\,x\right )\,\ln \left (9\right )+x\,\ln \left (3\right )\right )}{x^2\,\left (x+1\right )\,\left (\ln \left (9\,{\mathrm {e}}^{-x}\right )-\ln \left (2\,x\right )+1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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