Optimal. Leaf size=24 \[ 4+\frac {\log \left (5 \left (2+x+\frac {1}{10} (2-x+\log (x))\right )\right )}{\log (x)} \]
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Rubi [F]
time = 0.69, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {(1+9 x) \log (x)+(-22-9 x-\log (x)) \log \left (\frac {1}{2} (22+9 x+\log (x))\right )}{\left (22 x+9 x^2\right ) \log ^2(x)+x \log ^3(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {\log (2)+\frac {(1+9 x) \log (x)}{22+9 x+\log (x)}-\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ &=\int \left (\frac {22 \log (2)+9 x \log (2)+9 x \log (x)+(1+\log (2)) \log (x)}{x \log ^2(x) (22+9 x+\log (x))}-\frac {\log (22+9 x+\log (x))}{x \log ^2(x)}\right ) \, dx\\ &=\int \frac {22 \log (2)+9 x \log (2)+9 x \log (x)+(1+\log (2)) \log (x)}{x \log ^2(x) (22+9 x+\log (x))} \, dx-\int \frac {\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ &=\int \left (\frac {\log (2)}{x \log ^2(x)}+\frac {1+9 x}{x (22+9 x) \log (x)}+\frac {-1-9 x}{x (22+9 x) (22+9 x+\log (x))}\right ) \, dx-\int \frac {\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ &=\log (2) \int \frac {1}{x \log ^2(x)} \, dx+\int \frac {1+9 x}{x (22+9 x) \log (x)} \, dx+\int \frac {-1-9 x}{x (22+9 x) (22+9 x+\log (x))} \, dx-\int \frac {\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ &=\log (2) \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,\log (x)\right )+\int \frac {1+9 x}{x (22+9 x) \log (x)} \, dx+\int \left (-\frac {1}{22 x (22+9 x+\log (x))}-\frac {189}{22 (22+9 x) (22+9 x+\log (x))}\right ) \, dx-\int \frac {\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ &=-\frac {\log (2)}{\log (x)}-\frac {1}{22} \int \frac {1}{x (22+9 x+\log (x))} \, dx-\frac {189}{22} \int \frac {1}{(22+9 x) (22+9 x+\log (x))} \, dx+\int \frac {1+9 x}{x (22+9 x) \log (x)} \, dx-\int \frac {\log (22+9 x+\log (x))}{x \log ^2(x)} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.10, size = 22, normalized size = 0.92 \begin {gather*} -\frac {\log (2)}{\log (x)}+\frac {\log (22+9 x+\log (x))}{\log (x)} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 2.10, size = 16, normalized size = 0.67
method | result | size |
risch | \(\frac {\ln \left (\frac {\ln \left (x \right )}{2}+\frac {9 x}{2}+11\right )}{\ln \left (x \right )}\) | \(16\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.51, size = 19, normalized size = 0.79 \begin {gather*} -\frac {\log \left (2\right ) - \log \left (9 \, x + \log \left (x\right ) + 22\right )}{\log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 15, normalized size = 0.62 \begin {gather*} \frac {\log \left (\frac {9}{2} \, x + \frac {1}{2} \, \log \left (x\right ) + 11\right )}{\log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.41, size = 22, normalized size = 0.92 \begin {gather*} -\frac {\log \left (2\right )}{\log \left (x\right )} + \frac {\log \left (9 \, x + \log \left (x\right ) + 22\right )}{\log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.42, size = 19, normalized size = 0.79 \begin {gather*} -\frac {\ln \left (2\right )-\ln \left (9\,x+\ln \left (x\right )+22\right )}{\ln \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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