Optimal. Leaf size=29 \[ \frac {4 x \left (x^2+\frac {-1+\frac {e^x}{x}}{e^4+x}\right )}{2+x} \]
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Rubi [B] Leaf count is larger than twice the leaf count of optimal. \(487\) vs. \(2(29)=58\).
time = 1.07, antiderivative size = 487, normalized size of antiderivative = 16.79, number of steps
used = 22, number of rules used = 8, integrand size = 114, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.070, Rules used = {6820, 12,
6874, 90, 153, 2208, 2209, 1634} \begin {gather*} 4 x^2-16 \left (2+e^4\right ) x+16 e^4 x+24 x-\frac {4 e^x}{\left (2-e^4\right ) (x+2)}-\frac {32 e^8}{\left (2-e^4\right )^2 (x+2)}+\frac {136 e^4}{\left (2-e^4\right )^2 (x+2)}-\frac {144}{\left (2-e^4\right )^2 (x+2)}+\frac {8 e^4 \left (1+6 e^{12}-2 e^{16}\right )}{\left (2-e^4\right )^2 \left (x+e^4\right )}-\frac {8 e^{16} \left (3-e^4\right )}{\left (2-e^4\right )^2 \left (x+e^4\right )}+\frac {4 e^x}{\left (2-e^4\right ) \left (x+e^4\right )}+\frac {8 e^{20}}{\left (2-e^4\right )^2 \left (x+e^4\right )}-\frac {24 e^{16}}{\left (2-e^4\right )^2 \left (x+e^4\right )}-\frac {4 e^8}{\left (2-e^4\right )^2 \left (x+e^4\right )}-\frac {16 e^4 \left (9+4 e^4\right ) \log (x+2)}{\left (2-e^4\right )^3}-\frac {768 \left (1-e^4\right ) \log (x+2)}{\left (2-e^4\right )^3}+\frac {128 \left (6-5 e^4\right ) \log (x+2)}{\left (2-e^4\right )^3}+\frac {64 e^8 \log (x+2)}{\left (2-e^4\right )^3}+\frac {16 e^4 \log (x+2)}{\left (2-e^4\right )^3}+\frac {16 e^4 \left (1+18 e^8-11 e^{12}+2 e^{16}\right ) \log \left (x+e^4\right )}{\left (2-e^4\right )^3}-\frac {8 e^{12} \left (12-6 e^4+e^8\right ) \log \left (x+e^4\right )}{\left (2-e^4\right )^3}-\frac {48 e^{12} \left (4-e^4\right ) \log \left (x+e^4\right )}{\left (2-e^4\right )^3}+\frac {8 e^{16} \left (10-3 e^4\right ) \log \left (x+e^4\right )}{\left (2-e^4\right )^3}-\frac {16 e^4 \log \left (x+e^4\right )}{\left (2-e^4\right )^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 90
Rule 153
Rule 1634
Rule 2208
Rule 2209
Rule 6820
Rule 6874
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {4 \left (x^2+6 x^4+2 x^5+e^{4+x} (1+x)+2 e^8 x^2 (3+x)+e^x \left (-2+x^2\right )+2 e^4 \left (-1+6 x^3+2 x^4\right )\right )}{(2+x)^2 \left (e^4+x\right )^2} \, dx\\ &=4 \int \frac {x^2+6 x^4+2 x^5+e^{4+x} (1+x)+2 e^8 x^2 (3+x)+e^x \left (-2+x^2\right )+2 e^4 \left (-1+6 x^3+2 x^4\right )}{(2+x)^2 \left (e^4+x\right )^2} \, dx\\ &=4 \int \left (\frac {x^2}{(2+x)^2 \left (e^4+x\right )^2}+\frac {6 x^4}{(2+x)^2 \left (e^4+x\right )^2}+\frac {2 x^5}{(2+x)^2 \left (e^4+x\right )^2}+\frac {2 e^8 x^2 (3+x)}{(2+x)^2 \left (e^4+x\right )^2}+\frac {e^x \left (-2+e^4+e^4 x+x^2\right )}{(2+x)^2 \left (e^4+x\right )^2}+\frac {2 e^4 \left (-1+6 x^3+2 x^4\right )}{(2+x)^2 \left (e^4+x\right )^2}\right ) \, dx\\ &=4 \int \frac {x^2}{(2+x)^2 \left (e^4+x\right )^2} \, dx+4 \int \frac {e^x \left (-2+e^4+e^4 x+x^2\right )}{(2+x)^2 \left (e^4+x\right )^2} \, dx+8 \int \frac {x^5}{(2+x)^2 \left (e^4+x\right )^2} \, dx+24 \int \frac {x^4}{(2+x)^2 \left (e^4+x\right )^2} \, dx+\left (8 e^4\right ) \int \frac {-1+6 x^3+2 x^4}{(2+x)^2 \left (e^4+x\right )^2} \, dx+\left (8 e^8\right ) \int \frac {x^2 (3+x)}{(2+x)^2 \left (e^4+x\right )^2} \, dx\\ &=4 \int \left (\frac {4}{\left (-2+e^4\right )^2 (2+x)^2}-\frac {4 e^4}{\left (-2+e^4\right )^3 (2+x)}+\frac {e^8}{\left (-2+e^4\right )^2 \left (e^4+x\right )^2}+\frac {4 e^4}{\left (-2+e^4\right )^3 \left (e^4+x\right )}\right ) \, dx+4 \int \left (-\frac {e^x}{\left (-2+e^4\right ) (2+x)^2}+\frac {e^x}{\left (-2+e^4\right ) (2+x)}+\frac {e^x}{\left (-2+e^4\right ) \left (e^4+x\right )^2}-\frac {e^x}{\left (-2+e^4\right ) \left (e^4+x\right )}\right ) \, dx+8 \int \left (-2 \left (2+e^4\right )+x-\frac {32}{\left (-2+e^4\right )^2 (2+x)^2}+\frac {16 \left (-6+5 e^4\right )}{\left (-2+e^4\right )^3 (2+x)}-\frac {e^{20}}{\left (-2+e^4\right )^2 \left (e^4+x\right )^2}+\frac {e^{16} \left (-10+3 e^4\right )}{\left (-2+e^4\right )^3 \left (e^4+x\right )}\right ) \, dx+24 \int \left (1+\frac {16}{\left (-2+e^4\right )^2 (2+x)^2}-\frac {32 \left (-1+e^4\right )}{\left (-2+e^4\right )^3 (2+x)}+\frac {e^{16}}{\left (-2+e^4\right )^2 \left (e^4+x\right )^2}-\frac {2 e^{12} \left (-4+e^4\right )}{\left (-2+e^4\right )^3 \left (e^4+x\right )}\right ) \, dx+\left (8 e^4\right ) \int \left (2-\frac {17}{\left (-2+e^4\right )^2 (2+x)^2}+\frac {2 \left (9+4 e^4\right )}{\left (-2+e^4\right )^3 (2+x)}+\frac {-1-6 e^{12}+2 e^{16}}{\left (-2+e^4\right )^2 \left (e^4+x\right )^2}-\frac {2 \left (1+18 e^8-11 e^{12}+2 e^{16}\right )}{\left (-2+e^4\right )^3 \left (e^4+x\right )}\right ) \, dx+\left (8 e^8\right ) \int \left (\frac {4}{\left (-2+e^4\right )^2 (2+x)^2}-\frac {8}{\left (-2+e^4\right )^3 (2+x)}-\frac {e^8 \left (-3+e^4\right )}{\left (-2+e^4\right )^2 \left (e^4+x\right )^2}+\frac {e^4 \left (12-6 e^4+e^8\right )}{\left (-2+e^4\right )^3 \left (e^4+x\right )}\right ) \, dx\\ &=24 x+16 e^4 x-16 \left (2+e^4\right ) x+4 x^2-\frac {144}{\left (2-e^4\right )^2 (2+x)}+\frac {136 e^4}{\left (2-e^4\right )^2 (2+x)}-\frac {32 e^8}{\left (2-e^4\right )^2 (2+x)}-\frac {4 e^8}{\left (2-e^4\right )^2 \left (e^4+x\right )}-\frac {24 e^{16}}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^{20}}{\left (2-e^4\right )^2 \left (e^4+x\right )}-\frac {8 e^{16} \left (3-e^4\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^4 \left (1+6 e^{12}-2 e^{16}\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {16 e^4 \log (2+x)}{\left (2-e^4\right )^3}+\frac {64 e^8 \log (2+x)}{\left (2-e^4\right )^3}+\frac {128 \left (6-5 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {768 \left (1-e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \left (9+4 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {8 e^{16} \left (10-3 e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {48 e^{12} \left (4-e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {8 e^{12} \left (12-6 e^4+e^8\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {16 e^4 \left (1+18 e^8-11 e^{12}+2 e^{16}\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {4 \int \frac {e^x}{(2+x)^2} \, dx}{2-e^4}-\frac {4 \int \frac {e^x}{2+x} \, dx}{2-e^4}-\frac {4 \int \frac {e^x}{\left (e^4+x\right )^2} \, dx}{2-e^4}+\frac {4 \int \frac {e^x}{e^4+x} \, dx}{2-e^4}\\ &=24 x+16 e^4 x-16 \left (2+e^4\right ) x+4 x^2-\frac {144}{\left (2-e^4\right )^2 (2+x)}+\frac {136 e^4}{\left (2-e^4\right )^2 (2+x)}-\frac {32 e^8}{\left (2-e^4\right )^2 (2+x)}-\frac {4 e^x}{\left (2-e^4\right ) (2+x)}-\frac {4 e^8}{\left (2-e^4\right )^2 \left (e^4+x\right )}-\frac {24 e^{16}}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^{20}}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {4 e^x}{\left (2-e^4\right ) \left (e^4+x\right )}-\frac {8 e^{16} \left (3-e^4\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^4 \left (1+6 e^{12}-2 e^{16}\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}-\frac {4 \text {Ei}(2+x)}{e^2 \left (2-e^4\right )}+\frac {4 e^{-e^4} \text {Ei}\left (e^4+x\right )}{2-e^4}+\frac {16 e^4 \log (2+x)}{\left (2-e^4\right )^3}+\frac {64 e^8 \log (2+x)}{\left (2-e^4\right )^3}+\frac {128 \left (6-5 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {768 \left (1-e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \left (9+4 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {8 e^{16} \left (10-3 e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {48 e^{12} \left (4-e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {8 e^{12} \left (12-6 e^4+e^8\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {16 e^4 \left (1+18 e^8-11 e^{12}+2 e^{16}\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {4 \int \frac {e^x}{2+x} \, dx}{2-e^4}-\frac {4 \int \frac {e^x}{e^4+x} \, dx}{2-e^4}\\ &=24 x+16 e^4 x-16 \left (2+e^4\right ) x+4 x^2-\frac {144}{\left (2-e^4\right )^2 (2+x)}+\frac {136 e^4}{\left (2-e^4\right )^2 (2+x)}-\frac {32 e^8}{\left (2-e^4\right )^2 (2+x)}-\frac {4 e^x}{\left (2-e^4\right ) (2+x)}-\frac {4 e^8}{\left (2-e^4\right )^2 \left (e^4+x\right )}-\frac {24 e^{16}}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^{20}}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {4 e^x}{\left (2-e^4\right ) \left (e^4+x\right )}-\frac {8 e^{16} \left (3-e^4\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {8 e^4 \left (1+6 e^{12}-2 e^{16}\right )}{\left (2-e^4\right )^2 \left (e^4+x\right )}+\frac {16 e^4 \log (2+x)}{\left (2-e^4\right )^3}+\frac {64 e^8 \log (2+x)}{\left (2-e^4\right )^3}+\frac {128 \left (6-5 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {768 \left (1-e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \left (9+4 e^4\right ) \log (2+x)}{\left (2-e^4\right )^3}-\frac {16 e^4 \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {8 e^{16} \left (10-3 e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {48 e^{12} \left (4-e^4\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}-\frac {8 e^{12} \left (12-6 e^4+e^8\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}+\frac {16 e^4 \left (1+18 e^8-11 e^{12}+2 e^{16}\right ) \log \left (e^4+x\right )}{\left (2-e^4\right )^3}\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 3.23, size = 40, normalized size = 1.38 \begin {gather*} \frac {4 \left (e^x+x \left (-9-4 x+x^3\right )+e^4 \left (-8-4 x+x^3\right )\right )}{(2+x) \left (e^4+x\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 2.53, size = 1090, normalized size = 37.59
method | result | size |
norman | \(\frac {-4 x +4 x^{4}+4 x^{3} {\mathrm e}^{4}+4 \,{\mathrm e}^{x}}{\left (2+x \right ) \left (x +{\mathrm e}^{4}\right )}\) | \(33\) |
risch | \(4 x^{2}-8 x +\frac {-32 \,{\mathrm e}^{4}-36 x}{x \,{\mathrm e}^{4}+x^{2}+2 \,{\mathrm e}^{4}+2 x}+\frac {4 \,{\mathrm e}^{x}}{x \,{\mathrm e}^{4}+x^{2}+2 \,{\mathrm e}^{4}+2 x}\) | \(57\) |
default | \(\text {Expression too large to display}\) | \(1090\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 912 vs.
\(2 (27) = 54\).
time = 0.34, size = 912, normalized size = 31.45 \begin {gather*} 4 \, x^{2} - 16 \, x {\left (e^{4} + 2\right )} + 8 \, {\left (\frac {{\left (e^{12} - 6 \, e^{8}\right )} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {4 \, {\left (3 \, e^{4} - 2\right )} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {x {\left (e^{12} + 8\right )} + 2 \, e^{12} + 8 \, e^{4}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}}\right )} e^{8} + 24 \, {\left (\frac {4 \, e^{4} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {4 \, e^{4} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {x {\left (e^{8} + 4\right )} + 2 \, e^{8} + 4 \, e^{4}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}}\right )} e^{8} + 16 \, {\left (x - \frac {2 \, {\left (e^{16} - 4 \, e^{12}\right )} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {32 \, {\left (e^{4} - 1\right )} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {x {\left (e^{16} + 16\right )} + 2 \, e^{16} + 16 \, e^{4}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}}\right )} e^{4} + 48 \, {\left (\frac {{\left (e^{12} - 6 \, e^{8}\right )} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {4 \, {\left (3 \, e^{4} - 2\right )} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {x {\left (e^{12} + 8\right )} + 2 \, e^{12} + 8 \, e^{4}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}}\right )} e^{4} + 8 \, {\left (\frac {2 \, x + e^{4} + 2}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}} - \frac {2 \, \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {2 \, \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8}\right )} e^{4} + 24 \, x + \frac {8 \, {\left (3 \, e^{20} - 10 \, e^{16}\right )} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {48 \, {\left (e^{16} - 4 \, e^{12}\right )} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {16 \, e^{4} \log \left (x + e^{4}\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {128 \, {\left (5 \, e^{4} - 6\right )} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {768 \, {\left (e^{4} - 1\right )} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} - \frac {16 \, e^{4} \log \left (x + 2\right )}{e^{12} - 6 \, e^{8} + 12 \, e^{4} - 8} + \frac {8 \, {\left (x {\left (e^{20} + 32\right )} + 2 \, e^{20} + 32 \, e^{4}\right )}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}} - \frac {24 \, {\left (x {\left (e^{16} + 16\right )} + 2 \, e^{16} + 16 \, e^{4}\right )}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}} - \frac {4 \, {\left (x {\left (e^{8} + 4\right )} + 2 \, e^{8} + 4 \, e^{4}\right )}}{x^{2} {\left (e^{8} - 4 \, e^{4} + 4\right )} + x {\left (e^{12} - 2 \, e^{8} - 4 \, e^{4} + 8\right )} + 2 \, e^{12} - 8 \, e^{8} + 8 \, e^{4}} + \frac {4 \, e^{x}}{x^{2} + x {\left (e^{4} + 2\right )} + 2 \, e^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.52, size = 42, normalized size = 1.45 \begin {gather*} \frac {4 \, {\left (x^{4} - 4 \, x^{2} + {\left (x^{3} - 4 \, x - 8\right )} e^{4} - 9 \, x + e^{x}\right )}}{x^{2} + {\left (x + 2\right )} e^{4} + 2 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 54 vs.
\(2 (22) = 44\).
time = 0.43, size = 54, normalized size = 1.86 \begin {gather*} 4 x^{2} - 8 x + \frac {- 36 x - 32 e^{4}}{x^{2} + x \left (2 + e^{4}\right ) + 2 e^{4}} + \frac {4 e^{x}}{x^{2} + 2 x + x e^{4} + 2 e^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.47, size = 48, normalized size = 1.66 \begin {gather*} \frac {4 \, {\left (x^{4} + x^{3} e^{4} - 4 \, x^{2} - 4 \, x e^{4} - 9 \, x - 8 \, e^{4} + e^{x}\right )}}{x^{2} + x e^{4} + 2 \, x + 2 \, e^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 6.10, size = 55, normalized size = 1.90 \begin {gather*} \frac {4\,{\mathrm {e}}^x}{x^2+\left ({\mathrm {e}}^4+2\right )\,x+2\,{\mathrm {e}}^4}-8\,x-\frac {36\,x+32\,{\mathrm {e}}^4}{x^2+\left ({\mathrm {e}}^4+2\right )\,x+2\,{\mathrm {e}}^4}+4\,x^2 \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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