Optimal. Leaf size=32 \[ \frac {-\frac {x}{5}+\log (3+x)}{2 \left (-1+\frac {3}{x}-x^2-3 \log (2)\right )} \]
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Rubi [F]
time = 180.02, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \text {\$Aborted} \end {gather*}
Verification is not applicable to the result.
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Rubi steps
Aborted
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(113\) vs. \(2(32)=64\).
time = 0.74, size = 113, normalized size = 3.53 \begin {gather*} \frac {x \left (x \left (2717+68 \log ^3(8)+4 \log ^4(8)+\log (8) (319-3 \log (64))-6 \log ^2(8) (-25+\log (64))+30 \log (64)\right )-5 \left (2717+379 \log (8)+144 \log ^2(8)+56 \log ^3(8)+4 \log ^4(8)\right ) \log (3+x)\right )}{10 (11+\log (8)) \left (-3+x+x^3+x \log (8)\right ) \left (247+12 \log (8)+12 \log ^2(8)+4 \log ^3(8)\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(340\) vs.
\(2(28)=56\).
time = 1.22, size = 341, normalized size = 10.66
method | result | size |
norman | \(\frac {-\frac {x \ln \left (3+x \right )}{2}+\frac {x^{2}}{10}}{x^{3}+3 x \ln \left (2\right )+x -3}\) | \(28\) |
risch | \(-\frac {x \ln \left (3+x \right )}{2 \left (x^{3}+3 x \ln \left (2\right )+x -3\right )}+\frac {x^{2}}{10 x^{3}+30 x \ln \left (2\right )+10 x -30}\) | \(40\) |
derivativedivides | \(-\frac {\ln \left (3+x \right )}{2 \left (3 \ln \left (2\right )+11\right )}+\frac {\ln \left (2\right ) \left (3+x \right )^{2}}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {11 \left (3+x \right )^{2}}{30 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}-\frac {3 \ln \left (2\right ) \left (3+x \right )}{5 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}-\frac {11 \left (3+x \right )}{5 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {9 \ln \left (2\right )}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {33}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {\ln \left (3+x \right ) \left (3+x \right ) \left (\left (3+x \right )^{2}-10-9 x \right )}{2 \left (\left (3+x \right )^{3}+3 \left (3+x \right ) \ln \left (2\right )-9 \left (3+x \right )^{2}-9 \ln \left (2\right )+51+28 x \right ) \left (3 \ln \left (2\right )+11\right )}\) | \(341\) |
default | \(-\frac {\ln \left (3+x \right )}{2 \left (3 \ln \left (2\right )+11\right )}+\frac {\ln \left (2\right ) \left (3+x \right )^{2}}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {11 \left (3+x \right )^{2}}{30 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}-\frac {3 \ln \left (2\right ) \left (3+x \right )}{5 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}-\frac {11 \left (3+x \right )}{5 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {9 \ln \left (2\right )}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {33}{10 \left (3 \ln \left (2\right )+11\right ) \left (\frac {\left (3+x \right )^{3}}{3}+\left (3+x \right ) \ln \left (2\right )-3 \left (3+x \right )^{2}-3 \ln \left (2\right )+17+\frac {28 x}{3}\right )}+\frac {\ln \left (3+x \right ) \left (3+x \right ) \left (\left (3+x \right )^{2}-10-9 x \right )}{2 \left (\left (3+x \right )^{3}+3 \left (3+x \right ) \ln \left (2\right )-9 \left (3+x \right )^{2}-9 \ln \left (2\right )+51+28 x \right ) \left (3 \ln \left (2\right )+11\right )}\) | \(341\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.49, size = 28, normalized size = 0.88 \begin {gather*} \frac {x^{2} - 5 \, x \log \left (x + 3\right )}{10 \, {\left (x^{3} + x {\left (3 \, \log \left (2\right ) + 1\right )} - 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 26, normalized size = 0.81 \begin {gather*} \frac {x^{2} - 5 \, x \log \left (x + 3\right )}{10 \, {\left (x^{3} + 3 \, x \log \left (2\right ) + x - 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.67, size = 41, normalized size = 1.28 \begin {gather*} \frac {x^{2}}{10 x^{3} + x \left (10 + 30 \log {\left (2 \right )}\right ) - 30} - \frac {x \log {\left (x + 3 \right )}}{2 x^{3} + 2 x + 6 x \log {\left (2 \right )} - 6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.43, size = 39, normalized size = 1.22 \begin {gather*} \frac {x^{2}}{10 \, {\left (x^{3} + 3 \, x \log \left (2\right ) + x - 3\right )}} - \frac {x \log \left (x + 3\right )}{2 \, {\left (x^{3} + 3 \, x \log \left (2\right ) + x - 3\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 9.36, size = 27, normalized size = 0.84 \begin {gather*} \frac {x\,\left (x-5\,\ln \left (x+3\right )\right )}{10\,\left (x+3\,x\,\ln \left (2\right )+x^3-3\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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