Optimal. Leaf size=23 \[ \frac {18 (5-x) x}{\left (2-\frac {e^{5/4}}{\log (x)}\right )^4} \]
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Rubi [C] Result contains higher order function than in optimal. Order 4 vs. order 3 in
optimal.
time = 1.37, antiderivative size = 909, normalized size of antiderivative = 39.52, number of steps
used = 74, number of rules used = 9, integrand size = 98, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.092, Rules used = {6820, 12,
6874, 2357, 2367, 2336, 2209, 2346, 2334} \begin {gather*} -\frac {9}{32} (5-2 x)^2-\frac {15}{256} e^{\frac {15}{4}+\frac {e^{5/4}}{2}} \left (24-e^{5/4}\right ) \text {Ei}\left (\frac {1}{2} \left (2 \log (x)-e^{5/4}\right )\right )-\frac {45}{32} e^{\frac {1}{2} \left (5+e^{5/4}\right )} \left (6-e^{5/4}\right ) \text {Ei}\left (\frac {1}{2} \left (2 \log (x)-e^{5/4}\right )\right )-\frac {45}{16} e^{\frac {5}{4}+\frac {e^{5/4}}{2}} \left (4-3 e^{5/4}\right ) \text {Ei}\left (\frac {1}{2} \left (2 \log (x)-e^{5/4}\right )\right )-\frac {15}{256} e^{5+\frac {e^{5/4}}{2}} \text {Ei}\left (\frac {1}{2} \left (2 \log (x)-e^{5/4}\right )\right )+\frac {45}{4} e^{\frac {5}{4}+\frac {e^{5/4}}{2}} \text {Ei}\left (\frac {1}{2} \left (2 \log (x)-e^{5/4}\right )\right )+\frac {3}{16} e^{\frac {15}{4}+e^{5/4}} \left (12-e^{5/4}\right ) \text {Ei}\left (2 \log (x)-e^{5/4}\right )+\frac {9}{4} e^{\frac {5}{2}+e^{5/4}} \left (3-e^{5/4}\right ) \text {Ei}\left (2 \log (x)-e^{5/4}\right )+\frac {9}{4} e^{\frac {5}{4}+e^{5/4}} \left (2-3 e^{5/4}\right ) \text {Ei}\left (2 \log (x)-e^{5/4}\right )+\frac {3}{16} e^{5+e^{5/4}} \text {Ei}\left (2 \log (x)-e^{5/4}\right )-\frac {9}{2} e^{\frac {5}{4}+e^{5/4}} \text {Ei}\left (2 \log (x)-e^{5/4}\right )-\frac {3 e^5 (5-x) x}{16 \left (e^{5/4}-2 \log (x)\right )}+\frac {45 e^{15/4} \left (24-e^{5/4}\right ) x}{128 \left (e^{5/4}-2 \log (x)\right )}+\frac {45 e^{5/2} \left (6-e^{5/4}\right ) x}{16 \left (e^{5/4}-2 \log (x)\right )}+\frac {105 e^5 x}{128 \left (e^{5/4}-2 \log (x)\right )}-\frac {9 e^{5/4} x \left (5 \left (4-3 e^{5/4}\right )-2 \left (2-3 e^{5/4}\right ) x\right )}{8 \left (e^{5/4}-2 \log (x)\right )}-\frac {9 e^{5/2} x \left (5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x\right )}{8 \left (e^{5/4}-2 \log (x)\right )}-\frac {3 e^{15/4} x \left (5 \left (24-e^{5/4}\right )-2 \left (12-e^{5/4}\right ) x\right )}{32 \left (e^{5/4}-2 \log (x)\right )}+\frac {3 e^5 (5-x) x}{16 \left (e^{5/4}-2 \log (x)\right )^2}-\frac {15 e^{15/4} \left (24-e^{5/4}\right ) x}{64 \left (e^{5/4}-2 \log (x)\right )^2}-\frac {45 e^5 x}{64 \left (e^{5/4}-2 \log (x)\right )^2}+\frac {9 e^{5/2} x \left (5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x\right )}{8 \left (e^{5/4}-2 \log (x)\right )^2}+\frac {3 e^{15/4} x \left (5 \left (24-e^{5/4}\right )-2 \left (12-e^{5/4}\right ) x\right )}{32 \left (e^{5/4}-2 \log (x)\right )^2}-\frac {3 e^5 (5-x) x}{8 \left (e^{5/4}-2 \log (x)\right )^3}+\frac {15 e^5 x}{16 \left (e^{5/4}-2 \log (x)\right )^3}-\frac {3 e^{15/4} x \left (5 \left (24-e^{5/4}\right )-2 \left (12-e^{5/4}\right ) x\right )}{16 \left (e^{5/4}-2 \log (x)\right )^3}+\frac {9 e^5 (5-x) x}{8 \left (e^{5/4}-2 \log (x)\right )^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2209
Rule 2334
Rule 2336
Rule 2346
Rule 2357
Rule 2367
Rule 6820
Rule 6874
Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {18 \log ^3(x) \left (-4 e^{5/4} (-5+x)-e^{5/4} (-5+2 x) \log (x)-(10-4 x) \log ^2(x)\right )}{\left (e^{5/4}-2 \log (x)\right )^5} \, dx\\ &=18 \int \frac {\log ^3(x) \left (-4 e^{5/4} (-5+x)-e^{5/4} (-5+2 x) \log (x)-(10-4 x) \log ^2(x)\right )}{\left (e^{5/4}-2 \log (x)\right )^5} \, dx\\ &=18 \int \left (\frac {1}{16} (5-2 x)-\frac {e^5 (-5+x)}{2 \left (e^{5/4}-2 \log (x)\right )^5}+\frac {-5 e^{15/4} \left (24-e^{5/4}\right )+2 e^{15/4} \left (12-e^{5/4}\right ) x}{16 \left (e^{5/4}-2 \log (x)\right )^4}+\frac {e^{5/2} \left (5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x\right )}{4 \left (e^{5/4}-2 \log (x)\right )^3}+\frac {-5 e^{5/4} \left (4-3 e^{5/4}\right )+2 e^{5/4} \left (2-3 e^{5/4}\right ) x}{8 \left (e^{5/4}-2 \log (x)\right )^2}+\frac {e^{5/4} (-5+2 x)}{4 \left (e^{5/4}-2 \log (x)\right )}\right ) \, dx\\ &=-\frac {9}{32} (5-2 x)^2+\frac {9}{8} \int \frac {-5 e^{15/4} \left (24-e^{5/4}\right )+2 e^{15/4} \left (12-e^{5/4}\right ) x}{\left (e^{5/4}-2 \log (x)\right )^4} \, dx+\frac {9}{4} \int \frac {-5 e^{5/4} \left (4-3 e^{5/4}\right )+2 e^{5/4} \left (2-3 e^{5/4}\right ) x}{\left (e^{5/4}-2 \log (x)\right )^2} \, dx+\frac {1}{2} \left (9 e^{5/4}\right ) \int \frac {-5+2 x}{e^{5/4}-2 \log (x)} \, dx+\frac {1}{2} \left (9 e^{5/2}\right ) \int \frac {5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x}{\left (e^{5/4}-2 \log (x)\right )^3} \, dx-\left (9 e^5\right ) \int \frac {-5+x}{\left (e^{5/4}-2 \log (x)\right )^5} \, dx\\ &=-\frac {9}{32} (5-2 x)^2+\frac {9 e^5 (5-x) x}{8 \left (e^{5/4}-2 \log (x)\right )^4}-\frac {3 e^{15/4} x \left (5 \left (24-e^{5/4}\right )-2 \left (12-e^{5/4}\right ) x\right )}{16 \left (e^{5/4}-2 \log (x)\right )^3}+\frac {9 e^{5/2} x \left (5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x\right )}{8 \left (e^{5/4}-2 \log (x)\right )^2}-\frac {9 e^{5/4} x \left (5 \left (4-3 e^{5/4}\right )-2 \left (2-3 e^{5/4}\right ) x\right )}{8 \left (e^{5/4}-2 \log (x)\right )}-\frac {3}{8} \int \frac {-5 e^{15/4} \left (24-e^{5/4}\right )+2 e^{15/4} \left (12-e^{5/4}\right ) x}{\left (e^{5/4}-2 \log (x)\right )^3} \, dx-\frac {9}{4} \int \frac {-5 e^{5/4} \left (4-3 e^{5/4}\right )+2 e^{5/4} \left (2-3 e^{5/4}\right ) x}{e^{5/4}-2 \log (x)} \, dx+\frac {1}{2} \left (9 e^{5/4}\right ) \int \left (-\frac {5}{e^{5/4}-2 \log (x)}+\frac {2 x}{e^{5/4}-2 \log (x)}\right ) \, dx-\frac {1}{4} \left (9 e^{5/2}\right ) \int \frac {5 \left (6-e^{5/4}\right )-2 \left (3-e^{5/4}\right ) x}{\left (e^{5/4}-2 \log (x)\right )^2} \, dx+\frac {1}{4} \left (9 e^5\right ) \int \frac {-5+x}{\left (e^{5/4}-2 \log (x)\right )^4} \, dx+\frac {1}{8} \left (45 e^5\right ) \int \frac {1}{\left (e^{5/4}-2 \log (x)\right )^4} \, dx-\frac {1}{8} \left (45 e^{5/4} \left (4-3 e^{5/4}\right )\right ) \int \frac {1}{e^{5/4}-2 \log (x)} \, dx+\frac {1}{8} \left (45 e^{5/2} \left (6-e^{5/4}\right )\right ) \int \frac {1}{\left (e^{5/4}-2 \log (x)\right )^2} \, dx-\frac {1}{16} \left (15 e^{15/4} \left (24-e^{5/4}\right )\right ) \int \frac {1}{\left (e^{5/4}-2 \log (x)\right )^3} \, dx\\ &=\text {Rest of rules removed due to large latex content} \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.09, size = 22, normalized size = 0.96 \begin {gather*} -\frac {18 (-5+x) x \log ^4(x)}{\left (e^{5/4}-2 \log (x)\right )^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.67, size = 1258, normalized size = 54.70
method | result | size |
norman | \(\frac {90 x \ln \left (x \right )^{4}-18 x^{2} \ln \left (x \right )^{4}}{\left ({\mathrm e}^{\frac {5}{4}}-2 \ln \left (x \right )\right )^{4}}\) | \(28\) |
risch | \(-\frac {9 x^{2}}{8}+\frac {45 x}{8}+\frac {9 \,{\mathrm e}^{\frac {5}{4}} x \left ({\mathrm e}^{\frac {15}{4}} x -8 \ln \left (x \right ) {\mathrm e}^{\frac {5}{2}} x +24 \,{\mathrm e}^{\frac {5}{4}} \ln \left (x \right )^{2} x -32 x \ln \left (x \right )^{3}-5 \,{\mathrm e}^{\frac {15}{4}}+40 \ln \left (x \right ) {\mathrm e}^{\frac {5}{2}}-120 \ln \left (x \right )^{2} {\mathrm e}^{\frac {5}{4}}+160 \ln \left (x \right )^{3}\right )}{8 \left ({\mathrm e}^{\frac {5}{4}}-2 \ln \left (x \right )\right )^{4}}\) | \(76\) |
default | \(\text {Expression too large to display}\) | \(1258\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 48 vs.
\(2 (17) = 34\).
time = 0.33, size = 48, normalized size = 2.09 \begin {gather*} \frac {18 \, {\left (x^{2} - 5 \, x\right )} \log \left (x\right )^{4}}{32 \, e^{\frac {5}{4}} \log \left (x\right )^{3} - 16 \, \log \left (x\right )^{4} - 24 \, e^{\frac {5}{2}} \log \left (x\right )^{2} + 8 \, e^{\frac {15}{4}} \log \left (x\right ) - e^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: AttributeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 87 vs.
\(2 (17) = 34\).
time = 0.43, size = 87, normalized size = 3.78 \begin {gather*} \frac {18 \, x^{2} \log \left (x\right )^{4}}{32 \, e^{\frac {5}{4}} \log \left (x\right )^{3} - 16 \, \log \left (x\right )^{4} - 24 \, e^{\frac {5}{2}} \log \left (x\right )^{2} + 8 \, e^{\frac {15}{4}} \log \left (x\right ) - e^{5}} - \frac {90 \, x \log \left (x\right )^{4}}{32 \, e^{\frac {5}{4}} \log \left (x\right )^{3} - 16 \, \log \left (x\right )^{4} - 24 \, e^{\frac {5}{2}} \log \left (x\right )^{2} + 8 \, e^{\frac {15}{4}} \log \left (x\right ) - e^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.23, size = 738, normalized size = 32.09 \begin {gather*} \frac {-\frac {3\,x\,\left (5\,{\mathrm {e}}^{5/4}-8\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^4}{32}+\frac {3\,x\,\left (25\,{\mathrm {e}}^{5/2}-140\,{\mathrm {e}}^{5/4}-40\,x\,{\mathrm {e}}^{5/2}+112\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^3}{128}+\frac {3\,x\,\left (300\,{\mathrm {e}}^{5/2}-240\,{\mathrm {e}}^{5/4}-25\,{\mathrm {e}}^{15/4}-240\,x\,{\mathrm {e}}^{5/2}+96\,x\,{\mathrm {e}}^{5/4}+40\,x\,{\mathrm {e}}^{15/4}\right )\,{\ln \left (x\right )}^2}{256}+\frac {3\,x\,\left (25\,{\mathrm {e}}^5+1200\,{\mathrm {e}}^{5/2}+960\,{\mathrm {e}}^{5/4}-400\,{\mathrm {e}}^{15/4}-40\,x\,{\mathrm {e}}^5-480\,x\,{\mathrm {e}}^{5/2}-192\,x\,{\mathrm {e}}^{5/4}+320\,x\,{\mathrm {e}}^{15/4}\right )\,\ln \left (x\right )}{1024}+\frac {3\,x\,\left (100\,{\mathrm {e}}^5-400\,{\mathrm {e}}^{15/4}-5\,{\mathrm {e}}^{25/4}-80\,x\,{\mathrm {e}}^5+160\,x\,{\mathrm {e}}^{15/4}+8\,x\,{\mathrm {e}}^{25/4}\right )}{2048}}{{\ln \left (x\right )}^2-{\mathrm {e}}^{5/4}\,\ln \left (x\right )+\frac {{\mathrm {e}}^{5/2}}{4}}+x\,\left (\frac {45\,{\mathrm {e}}^{5/4}}{4}-\frac {135\,{\mathrm {e}}^{5/2}}{32}-\frac {15\,{\mathrm {e}}^5}{1024}+\frac {15\,{\mathrm {e}}^{15/4}}{32}+\frac {45}{8}\right )-\frac {-\frac {3\,x\,\left (5\,{\mathrm {e}}^{5/4}-16\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^4}{32}+\frac {3\,x\,\left (25\,{\mathrm {e}}^{5/2}-220\,{\mathrm {e}}^{5/4}-80\,x\,{\mathrm {e}}^{5/2}+352\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^3}{128}+\frac {3\,x\,\left (450\,{\mathrm {e}}^{5/2}-1080\,{\mathrm {e}}^{5/4}-25\,{\mathrm {e}}^{15/4}-720\,x\,{\mathrm {e}}^{5/2}+864\,x\,{\mathrm {e}}^{5/4}+80\,x\,{\mathrm {e}}^{15/4}\right )\,{\ln \left (x\right )}^2}{256}+\frac {3\,x\,\left (25\,{\mathrm {e}}^5+3600\,{\mathrm {e}}^{5/2}-960\,{\mathrm {e}}^{5/4}-600\,{\mathrm {e}}^{15/4}-80\,x\,{\mathrm {e}}^5-2880\,x\,{\mathrm {e}}^{5/2}+384\,x\,{\mathrm {e}}^{5/4}+960\,x\,{\mathrm {e}}^{15/4}\right )\,\ln \left (x\right )}{1024}+\frac {3\,x\,\left (150\,{\mathrm {e}}^5+2400\,{\mathrm {e}}^{5/2}+1920\,{\mathrm {e}}^{5/4}-1200\,{\mathrm {e}}^{15/4}-5\,{\mathrm {e}}^{25/4}-240\,x\,{\mathrm {e}}^5-960\,x\,{\mathrm {e}}^{5/2}-384\,x\,{\mathrm {e}}^{5/4}+960\,x\,{\mathrm {e}}^{15/4}+16\,x\,{\mathrm {e}}^{25/4}\right )}{2048}}{\frac {{\mathrm {e}}^{5/4}}{2}-\ln \left (x\right )}-{\ln \left (x\right )}^2\,\left (\frac {45\,x\,{\mathrm {e}}^{5/4}\,\left ({\mathrm {e}}^{5/4}-16\right )}{128}-\frac {9\,x^2\,{\mathrm {e}}^{5/4}\,\left ({\mathrm {e}}^{5/4}-8\right )}{8}\right )-\frac {-\frac {3\,x\,\left (5\,{\mathrm {e}}^{5/4}-4\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^4}{16}+\frac {3\,x\,\left (25\,{\mathrm {e}}^{5/2}-60\,{\mathrm {e}}^{5/4}-20\,x\,{\mathrm {e}}^{5/2}+24\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^3}{64}+\frac {3\,x\,\left (150\,{\mathrm {e}}^{5/2}+120\,{\mathrm {e}}^{5/4}-25\,{\mathrm {e}}^{15/4}-60\,x\,{\mathrm {e}}^{5/2}-24\,x\,{\mathrm {e}}^{5/4}+20\,x\,{\mathrm {e}}^{15/4}\right )\,{\ln \left (x\right )}^2}{128}+\frac {15\,x\,\left (5\,{\mathrm {e}}^5-40\,{\mathrm {e}}^{15/4}-4\,x\,{\mathrm {e}}^5+16\,x\,{\mathrm {e}}^{15/4}\right )\,\ln \left (x\right )}{512}+\frac {3\,x\,\left (50\,{\mathrm {e}}^5-5\,{\mathrm {e}}^{25/4}-20\,x\,{\mathrm {e}}^5+4\,x\,{\mathrm {e}}^{25/4}\right )}{1024}}{-{\ln \left (x\right )}^3+\frac {3\,{\mathrm {e}}^{5/4}\,{\ln \left (x\right )}^2}{2}-\frac {3\,{\mathrm {e}}^{5/2}\,\ln \left (x\right )}{4}+\frac {{\mathrm {e}}^{15/4}}{8}}-x^2\,\left (\frac {9\,{\mathrm {e}}^{5/4}}{2}-\frac {27\,{\mathrm {e}}^{5/2}}{8}-\frac {3\,{\mathrm {e}}^5}{64}+\frac {3\,{\mathrm {e}}^{15/4}}{4}+\frac {9}{8}\right )+\frac {-\frac {9\,x\,\left (5\,{\mathrm {e}}^{5/4}-2\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^4}{16}+\frac {9\,x\,\left (25\,{\mathrm {e}}^{5/2}+20\,{\mathrm {e}}^{5/4}-10\,x\,{\mathrm {e}}^{5/2}-4\,x\,{\mathrm {e}}^{5/4}\right )\,{\ln \left (x\right )}^3}{64}+\frac {45\,x\,{\mathrm {e}}^{15/4}\,\left (2\,x-5\right )\,{\ln \left (x\right )}^2}{128}-\frac {45\,x\,{\mathrm {e}}^5\,\left (2\,x-5\right )\,\ln \left (x\right )}{512}+\frac {9\,x\,{\mathrm {e}}^{25/4}\,\left (2\,x-5\right )}{1024}}{{\ln \left (x\right )}^4-2\,{\mathrm {e}}^{5/4}\,{\ln \left (x\right )}^3+\frac {3\,{\mathrm {e}}^{5/2}\,{\ln \left (x\right )}^2}{2}-\frac {{\mathrm {e}}^{15/4}\,\ln \left (x\right )}{2}+\frac {{\mathrm {e}}^5}{16}}+\ln \left (x\right )\,\left (\frac {15\,x\,{\mathrm {e}}^{5/4}\,{\left ({\mathrm {e}}^{5/4}-12\right )}^2}{128}-\frac {3\,x^2\,{\mathrm {e}}^{5/4}\,{\left ({\mathrm {e}}^{5/4}-6\right )}^2}{8}\right )+{\ln \left (x\right )}^3\,\left (\frac {15\,x\,{\mathrm {e}}^{5/4}}{32}-\frac {3\,x^2\,{\mathrm {e}}^{5/4}}{2}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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