3.3.26 \(\int f^{\frac {c}{(a+b x)^2}} x^2 \, dx\) [226]

Optimal. Leaf size=206 \[ \frac {a^2 f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^3}-\frac {a f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^3}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^3}{3 b^3}-\frac {a^2 \sqrt {c} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \sqrt {\log (f)}}{b^3}+\frac {2 c f^{\frac {c}{(a+b x)^2}} (a+b x) \log (f)}{3 b^3}+\frac {a c \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right ) \log (f)}{b^3}-\frac {2 c^{3/2} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \log ^{\frac {3}{2}}(f)}{3 b^3} \]

[Out]

a^2*f^(c/(b*x+a)^2)*(b*x+a)/b^3-a*f^(c/(b*x+a)^2)*(b*x+a)^2/b^3+1/3*f^(c/(b*x+a)^2)*(b*x+a)^3/b^3+2/3*c*f^(c/(
b*x+a)^2)*(b*x+a)*ln(f)/b^3+a*c*Ei(c*ln(f)/(b*x+a)^2)*ln(f)/b^3-2/3*c^(3/2)*erfi(c^(1/2)*ln(f)^(1/2)/(b*x+a))*
ln(f)^(3/2)*Pi^(1/2)/b^3-a^2*erfi(c^(1/2)*ln(f)^(1/2)/(b*x+a))*c^(1/2)*Pi^(1/2)*ln(f)^(1/2)/b^3

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Rubi [A]
time = 0.15, antiderivative size = 206, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 6, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {2258, 2237, 2242, 2235, 2245, 2241} \begin {gather*} -\frac {\sqrt {\pi } a^2 \sqrt {c} \sqrt {\log (f)} \text {Erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right )}{b^3}+\frac {a^2 (a+b x) f^{\frac {c}{(a+b x)^2}}}{b^3}-\frac {2 \sqrt {\pi } c^{3/2} \log ^{\frac {3}{2}}(f) \text {Erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right )}{3 b^3}+\frac {a c \log (f) \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right )}{b^3}+\frac {(a+b x)^3 f^{\frac {c}{(a+b x)^2}}}{3 b^3}-\frac {a (a+b x)^2 f^{\frac {c}{(a+b x)^2}}}{b^3}+\frac {2 c \log (f) (a+b x) f^{\frac {c}{(a+b x)^2}}}{3 b^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[f^(c/(a + b*x)^2)*x^2,x]

[Out]

(a^2*f^(c/(a + b*x)^2)*(a + b*x))/b^3 - (a*f^(c/(a + b*x)^2)*(a + b*x)^2)/b^3 + (f^(c/(a + b*x)^2)*(a + b*x)^3
)/(3*b^3) - (a^2*Sqrt[c]*Sqrt[Pi]*Erfi[(Sqrt[c]*Sqrt[Log[f]])/(a + b*x)]*Sqrt[Log[f]])/b^3 + (2*c*f^(c/(a + b*
x)^2)*(a + b*x)*Log[f])/(3*b^3) + (a*c*ExpIntegralEi[(c*Log[f])/(a + b*x)^2]*Log[f])/b^3 - (2*c^(3/2)*Sqrt[Pi]
*Erfi[(Sqrt[c]*Sqrt[Log[f]])/(a + b*x)]*Log[f]^(3/2))/(3*b^3)

Rule 2235

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2
]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2237

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_)), x_Symbol] :> Simp[(c + d*x)*(F^(a + b*(c + d*x)^n)/d), x]
- Dist[b*n*Log[F], Int[(c + d*x)^n*F^(a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[2/n]
&& ILtQ[n, 0]

Rule 2241

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> Simp[F^a*(ExpIntegralEi[
b*(c + d*x)^n*Log[F]]/(f*n)), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[d*e - c*f, 0]

Rule 2242

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Dist[1/(d*(m + 1))
, Subst[Int[F^(a + b*x^2), x], x, (c + d*x)^(m + 1)], x] /; FreeQ[{F, a, b, c, d, m, n}, x] && EqQ[n, 2*(m + 1
)]

Rule 2245

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[(c + d*x)^(m
+ 1)*(F^(a + b*(c + d*x)^n)/(d*(m + 1))), x] - Dist[b*n*(Log[F]/(m + 1)), Int[(c + d*x)^(m + n)*F^(a + b*(c +
d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[2*((m + 1)/n)] && LtQ[-4, (m + 1)/n, 5] && IntegerQ[n
] && ((GtQ[n, 0] && LtQ[m, -1]) || (GtQ[-n, 0] && LeQ[-n, m + 1]))

Rule 2258

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*(u_), x_Symbol] :> Int[ExpandLinearProduct[F^(a + b*(c + d*
x)^n), u, c, d, x], x] /; FreeQ[{F, a, b, c, d, n}, x] && PolynomialQ[u, x]

Rubi steps

\begin {align*} \int f^{\frac {c}{(a+b x)^2}} x^2 \, dx &=\int \left (\frac {a^2 f^{\frac {c}{(a+b x)^2}}}{b^2}-\frac {2 a f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^2}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^2}\right ) \, dx\\ &=\frac {\int f^{\frac {c}{(a+b x)^2}} (a+b x)^2 \, dx}{b^2}-\frac {(2 a) \int f^{\frac {c}{(a+b x)^2}} (a+b x) \, dx}{b^2}+\frac {a^2 \int f^{\frac {c}{(a+b x)^2}} \, dx}{b^2}\\ &=\frac {a^2 f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^3}-\frac {a f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^3}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^3}{3 b^3}+\frac {(2 c \log (f)) \int f^{\frac {c}{(a+b x)^2}} \, dx}{3 b^2}-\frac {(2 a c \log (f)) \int \frac {f^{\frac {c}{(a+b x)^2}}}{a+b x} \, dx}{b^2}+\frac {\left (2 a^2 c \log (f)\right ) \int \frac {f^{\frac {c}{(a+b x)^2}}}{(a+b x)^2} \, dx}{b^2}\\ &=\frac {a^2 f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^3}-\frac {a f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^3}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^3}{3 b^3}+\frac {2 c f^{\frac {c}{(a+b x)^2}} (a+b x) \log (f)}{3 b^3}+\frac {a c \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right ) \log (f)}{b^3}-\frac {\left (2 a^2 c \log (f)\right ) \text {Subst}\left (\int f^{c x^2} \, dx,x,\frac {1}{a+b x}\right )}{b^3}+\frac {\left (4 c^2 \log ^2(f)\right ) \int \frac {f^{\frac {c}{(a+b x)^2}}}{(a+b x)^2} \, dx}{3 b^2}\\ &=\frac {a^2 f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^3}-\frac {a f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^3}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^3}{3 b^3}-\frac {a^2 \sqrt {c} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \sqrt {\log (f)}}{b^3}+\frac {2 c f^{\frac {c}{(a+b x)^2}} (a+b x) \log (f)}{3 b^3}+\frac {a c \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right ) \log (f)}{b^3}-\frac {\left (4 c^2 \log ^2(f)\right ) \text {Subst}\left (\int f^{c x^2} \, dx,x,\frac {1}{a+b x}\right )}{3 b^3}\\ &=\frac {a^2 f^{\frac {c}{(a+b x)^2}} (a+b x)}{b^3}-\frac {a f^{\frac {c}{(a+b x)^2}} (a+b x)^2}{b^3}+\frac {f^{\frac {c}{(a+b x)^2}} (a+b x)^3}{3 b^3}-\frac {a^2 \sqrt {c} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \sqrt {\log (f)}}{b^3}+\frac {2 c f^{\frac {c}{(a+b x)^2}} (a+b x) \log (f)}{3 b^3}+\frac {a c \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right ) \log (f)}{b^3}-\frac {2 c^{3/2} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \log ^{\frac {3}{2}}(f)}{3 b^3}\\ \end {align*}

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Mathematica [A]
time = 0.08, size = 131, normalized size = 0.64 \begin {gather*} \frac {a f^{\frac {c}{(a+b x)^2}} \left (a^2+2 c \log (f)\right )}{3 b^3}+\frac {3 a c \text {Ei}\left (\frac {c \log (f)}{(a+b x)^2}\right ) \log (f)-\sqrt {c} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {c} \sqrt {\log (f)}}{a+b x}\right ) \sqrt {\log (f)} \left (3 a^2+2 c \log (f)\right )+b f^{\frac {c}{(a+b x)^2}} x \left (b^2 x^2+2 c \log (f)\right )}{3 b^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[f^(c/(a + b*x)^2)*x^2,x]

[Out]

(a*f^(c/(a + b*x)^2)*(a^2 + 2*c*Log[f]))/(3*b^3) + (3*a*c*ExpIntegralEi[(c*Log[f])/(a + b*x)^2]*Log[f] - Sqrt[
c]*Sqrt[Pi]*Erfi[(Sqrt[c]*Sqrt[Log[f]])/(a + b*x)]*Sqrt[Log[f]]*(3*a^2 + 2*c*Log[f]) + b*f^(c/(a + b*x)^2)*x*(
b^2*x^2 + 2*c*Log[f]))/(3*b^3)

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Maple [A]
time = 0.03, size = 175, normalized size = 0.85

method	result	size
risch	\(\frac {f^{\frac {c}{\left (b x +a \right )^{2}}} x^{3}}{3}+\frac {a^{3} f^{\frac {c}{\left (b x +a \right )^{2}}}}{3 b^{3}}+\frac {2 \ln \left (f \right ) c \,f^{\frac {c}{\left (b x +a \right )^{2}}} x}{3 b^{2}}+\frac {2 \ln \left (f \right ) c \,f^{\frac {c}{\left (b x +a \right )^{2}}} a}{3 b^{3}}-\frac {2 \ln \left (f \right )^{2} c^{2} \sqrt {\pi }\, \erf \left (\frac {\sqrt {-c \ln \left (f \right )}}{b x +a}\right )}{3 b^{3} \sqrt {-c \ln \left (f \right )}}-\frac {a^{2} \ln \left (f \right ) c \sqrt {\pi }\, \erf \left (\frac {\sqrt {-c \ln \left (f \right )}}{b x +a}\right )}{b^{3} \sqrt {-c \ln \left (f \right )}}-\frac {a \ln \left (f \right ) c \expIntegral \left (1, -\frac {c \ln \left (f \right )}{\left (b x +a \right )^{2}}\right )}{b^{3}}\)	\(175\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(c/(b*x+a)^2)*x^2,x,method=_RETURNVERBOSE)

[Out]

1/3*f^(c/(b*x+a)^2)*x^3+1/3/b^3*a^3*f^(c/(b*x+a)^2)+2/3/b^2*ln(f)*c*f^(c/(b*x+a)^2)*x+2/3/b^3*ln(f)*c*f^(c/(b*
x+a)^2)*a-2/3/b^3*ln(f)^2*c^2*Pi^(1/2)/(-c*ln(f))^(1/2)*erf((-c*ln(f))^(1/2)/(b*x+a))-1/b^3*a^2*ln(f)*c*Pi^(1/
2)/(-c*ln(f))^(1/2)*erf((-c*ln(f))^(1/2)/(b*x+a))-1/b^3*a*ln(f)*c*Ei(1,-c*ln(f)/(b*x+a)^2)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c/(b*x+a)^2)*x^2,x, algorithm="maxima")

[Out]

1/3*(b^2*x^3 + 2*c*x*log(f))*f^(c/(b^2*x^2 + 2*a*b*x + a^2))/b^2 - integrate(2/3*(3*a*b^2*c*x^2*log(f) + a^3*c
*log(f) + (3*a^2*b*c*log(f) - 2*b*c^2*log(f)^2)*x)*f^(c/(b^2*x^2 + 2*a*b*x + a^2))/(b^5*x^3 + 3*a*b^4*x^2 + 3*
a^2*b^3*x + a^3*b^2), x)

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Fricas [A]
time = 0.36, size = 128, normalized size = 0.62 \begin {gather*} \frac {3 \, a c {\rm Ei}\left (\frac {c \log \left (f\right )}{b^{2} x^{2} + 2 \, a b x + a^{2}}\right ) \log \left (f\right ) + \sqrt {\pi } {\left (3 \, a^{2} b + 2 \, b c \log \left (f\right )\right )} \sqrt {-\frac {c \log \left (f\right )}{b^{2}}} \operatorname {erf}\left (\frac {b \sqrt {-\frac {c \log \left (f\right )}{b^{2}}}}{b x + a}\right ) + {\left (b^{3} x^{3} + a^{3} + 2 \, {\left (b c x + a c\right )} \log \left (f\right )\right )} f^{\frac {c}{b^{2} x^{2} + 2 \, a b x + a^{2}}}}{3 \, b^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c/(b*x+a)^2)*x^2,x, algorithm="fricas")

[Out]

1/3*(3*a*c*Ei(c*log(f)/(b^2*x^2 + 2*a*b*x + a^2))*log(f) + sqrt(pi)*(3*a^2*b + 2*b*c*log(f))*sqrt(-c*log(f)/b^
2)*erf(b*sqrt(-c*log(f)/b^2)/(b*x + a)) + (b^3*x^3 + a^3 + 2*(b*c*x + a*c)*log(f))*f^(c/(b^2*x^2 + 2*a*b*x + a
^2)))/b^3

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int f^{\frac {c}{\left (a + b x\right )^{2}}} x^{2}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f**(c/(b*x+a)**2)*x**2,x)

[Out]

Integral(f**(c/(a + b*x)**2)*x**2, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(f^(c/(b*x+a)^2)*x^2,x, algorithm="giac")

[Out]

integrate(f^(c/(b*x + a)^2)*x^2, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int f^{\frac {c}{{\left (a+b\,x\right )}^2}}\,x^2 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(f^(c/(a + b*x)^2)*x^2,x)

[Out]

int(f^(c/(a + b*x)^2)*x^2, x)

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