Optimal. Leaf size=416 \[ -\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d (a+b \text {ArcSin}(c+d x))^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {ArcSin}(c+d x))^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {ArcSin}(c+d x))^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1-(c+d x)^2}}{b^3 d (a+b \text {ArcSin}(c+d x))}+\frac {25 e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{6 b^3 d (a+b \text {ArcSin}(c+d x))}-\frac {e^4 \text {CosIntegral}\left (\frac {a+b \text {ArcSin}(c+d x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{48 b^4 d}+\frac {27 e^4 \text {CosIntegral}\left (\frac {3 (a+b \text {ArcSin}(c+d x))}{b}\right ) \sin \left (\frac {3 a}{b}\right )}{32 b^4 d}-\frac {125 e^4 \text {CosIntegral}\left (\frac {5 (a+b \text {ArcSin}(c+d x))}{b}\right ) \sin \left (\frac {5 a}{b}\right )}{96 b^4 d}+\frac {e^4 \cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \text {ArcSin}(c+d x)}{b}\right )}{48 b^4 d}-\frac {27 e^4 \cos \left (\frac {3 a}{b}\right ) \text {Si}\left (\frac {3 (a+b \text {ArcSin}(c+d x))}{b}\right )}{32 b^4 d}+\frac {125 e^4 \cos \left (\frac {5 a}{b}\right ) \text {Si}\left (\frac {5 (a+b \text {ArcSin}(c+d x))}{b}\right )}{96 b^4 d} \]
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Rubi [A]
time = 0.56, antiderivative size = 416, normalized size of antiderivative = 1.00, number of steps
used = 24, number of rules used = 8, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {4889, 12,
4729, 4807, 4727, 3384, 3380, 3383} \begin {gather*} -\frac {e^4 \sin \left (\frac {a}{b}\right ) \text {CosIntegral}\left (\frac {a+b \text {ArcSin}(c+d x)}{b}\right )}{48 b^4 d}+\frac {27 e^4 \sin \left (\frac {3 a}{b}\right ) \text {CosIntegral}\left (\frac {3 (a+b \text {ArcSin}(c+d x))}{b}\right )}{32 b^4 d}-\frac {125 e^4 \sin \left (\frac {5 a}{b}\right ) \text {CosIntegral}\left (\frac {5 (a+b \text {ArcSin}(c+d x))}{b}\right )}{96 b^4 d}+\frac {e^4 \cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \text {ArcSin}(c+d x)}{b}\right )}{48 b^4 d}-\frac {27 e^4 \cos \left (\frac {3 a}{b}\right ) \text {Si}\left (\frac {3 (a+b \text {ArcSin}(c+d x))}{b}\right )}{32 b^4 d}+\frac {125 e^4 \cos \left (\frac {5 a}{b}\right ) \text {Si}\left (\frac {5 (a+b \text {ArcSin}(c+d x))}{b}\right )}{96 b^4 d}+\frac {25 e^4 \sqrt {1-(c+d x)^2} (c+d x)^4}{6 b^3 d (a+b \text {ArcSin}(c+d x))}-\frac {2 e^4 \sqrt {1-(c+d x)^2} (c+d x)^2}{b^3 d (a+b \text {ArcSin}(c+d x))}+\frac {5 e^4 (c+d x)^5}{6 b^2 d (a+b \text {ArcSin}(c+d x))^2}-\frac {2 e^4 (c+d x)^3}{3 b^2 d (a+b \text {ArcSin}(c+d x))^2}-\frac {e^4 \sqrt {1-(c+d x)^2} (c+d x)^4}{3 b d (a+b \text {ArcSin}(c+d x))^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 3380
Rule 3383
Rule 3384
Rule 4727
Rule 4729
Rule 4807
Rule 4889
Rubi steps
\begin {align*} \int \frac {(c e+d e x)^4}{\left (a+b \sin ^{-1}(c+d x)\right )^4} \, dx &=\frac {\text {Subst}\left (\int \frac {e^4 x^4}{\left (a+b \sin ^{-1}(x)\right )^4} \, dx,x,c+d x\right )}{d}\\ &=\frac {e^4 \text {Subst}\left (\int \frac {x^4}{\left (a+b \sin ^{-1}(x)\right )^4} \, dx,x,c+d x\right )}{d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}+\frac {\left (4 e^4\right ) \text {Subst}\left (\int \frac {x^3}{\sqrt {1-x^2} \left (a+b \sin ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{3 b d}-\frac {\left (5 e^4\right ) \text {Subst}\left (\int \frac {x^5}{\sqrt {1-x^2} \left (a+b \sin ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{3 b d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {\left (2 e^4\right ) \text {Subst}\left (\int \frac {x^2}{\left (a+b \sin ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{b^2 d}-\frac {\left (25 e^4\right ) \text {Subst}\left (\int \frac {x^4}{\left (a+b \sin ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{6 b^2 d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1-(c+d x)^2}}{b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac {25 e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{6 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac {\left (2 e^4\right ) \text {Subst}\left (\int \left (-\frac {\sin (x)}{4 (a+b x)}+\frac {3 \sin (3 x)}{4 (a+b x)}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{b^3 d}-\frac {\left (25 e^4\right ) \text {Subst}\left (\int \left (-\frac {\sin (x)}{8 (a+b x)}+\frac {9 \sin (3 x)}{16 (a+b x)}-\frac {5 \sin (5 x)}{16 (a+b x)}\right ) \, dx,x,\sin ^{-1}(c+d x)\right )}{6 b^3 d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1-(c+d x)^2}}{b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac {25 e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{6 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}-\frac {e^4 \text {Subst}\left (\int \frac {\sin (x)}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}+\frac {\left (25 e^4\right ) \text {Subst}\left (\int \frac {\sin (x)}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{48 b^3 d}+\frac {\left (125 e^4\right ) \text {Subst}\left (\int \frac {\sin (5 x)}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{96 b^3 d}+\frac {\left (3 e^4\right ) \text {Subst}\left (\int \frac {\sin (3 x)}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}-\frac {\left (75 e^4\right ) \text {Subst}\left (\int \frac {\sin (3 x)}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{32 b^3 d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1-(c+d x)^2}}{b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac {25 e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{6 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}-\frac {\left (e^4 \cos \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}+\frac {\left (25 e^4 \cos \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{48 b^3 d}+\frac {\left (3 e^4 \cos \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}-\frac {\left (75 e^4 \cos \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{32 b^3 d}+\frac {\left (125 e^4 \cos \left (\frac {5 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {5 a}{b}+5 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{96 b^3 d}+\frac {\left (e^4 \sin \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}-\frac {\left (25 e^4 \sin \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {a}{b}+x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{48 b^3 d}-\frac {\left (3 e^4 \sin \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{2 b^3 d}+\frac {\left (75 e^4 \sin \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {3 a}{b}+3 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{32 b^3 d}-\frac {\left (125 e^4 \sin \left (\frac {5 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {5 a}{b}+5 x\right )}{a+b x} \, dx,x,\sin ^{-1}(c+d x)\right )}{96 b^3 d}\\ &=-\frac {e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{3 b d \left (a+b \sin ^{-1}(c+d x)\right )^3}-\frac {2 e^4 (c+d x)^3}{3 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}+\frac {5 e^4 (c+d x)^5}{6 b^2 d \left (a+b \sin ^{-1}(c+d x)\right )^2}-\frac {2 e^4 (c+d x)^2 \sqrt {1-(c+d x)^2}}{b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}+\frac {25 e^4 (c+d x)^4 \sqrt {1-(c+d x)^2}}{6 b^3 d \left (a+b \sin ^{-1}(c+d x)\right )}-\frac {e^4 \text {Ci}\left (\frac {a}{b}+\sin ^{-1}(c+d x)\right ) \sin \left (\frac {a}{b}\right )}{48 b^4 d}+\frac {27 e^4 \text {Ci}\left (\frac {3 a}{b}+3 \sin ^{-1}(c+d x)\right ) \sin \left (\frac {3 a}{b}\right )}{32 b^4 d}-\frac {125 e^4 \text {Ci}\left (\frac {5 a}{b}+5 \sin ^{-1}(c+d x)\right ) \sin \left (\frac {5 a}{b}\right )}{96 b^4 d}+\frac {e^4 \cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\sin ^{-1}(c+d x)\right )}{48 b^4 d}-\frac {27 e^4 \cos \left (\frac {3 a}{b}\right ) \text {Si}\left (\frac {3 a}{b}+3 \sin ^{-1}(c+d x)\right )}{32 b^4 d}+\frac {125 e^4 \cos \left (\frac {5 a}{b}\right ) \text {Si}\left (\frac {5 a}{b}+5 \sin ^{-1}(c+d x)\right )}{96 b^4 d}\\ \end {align*}
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Mathematica [A]
time = 1.10, size = 414, normalized size = 1.00 \begin {gather*} \frac {e^4 \left (-\frac {32 b^3 (c+d x)^4 \sqrt {1-(c+d x)^2}}{(a+b \text {ArcSin}(c+d x))^3}+\frac {16 b^2 \left (-4 (c+d x)^3+5 (c+d x)^5\right )}{(a+b \text {ArcSin}(c+d x))^2}+\frac {16 b \sqrt {1-(c+d x)^2} \left (-12 (c+d x)^2+25 (c+d x)^4\right )}{a+b \text {ArcSin}(c+d x)}+384 \left (-\text {CosIntegral}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right ) \sin \left (\frac {a}{b}\right )+\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right )+544 \left (3 \text {CosIntegral}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right ) \sin \left (\frac {a}{b}\right )-\text {CosIntegral}\left (3 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right ) \sin \left (\frac {3 a}{b}\right )-3 \cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )+\cos \left (\frac {3 a}{b}\right ) \text {Si}\left (3 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right )\right )-125 \left (10 \text {CosIntegral}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right ) \sin \left (\frac {a}{b}\right )-5 \text {CosIntegral}\left (3 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right ) \sin \left (\frac {3 a}{b}\right )+\text {CosIntegral}\left (5 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right ) \sin \left (\frac {5 a}{b}\right )-10 \cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )+5 \cos \left (\frac {3 a}{b}\right ) \text {Si}\left (3 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right )-\cos \left (\frac {5 a}{b}\right ) \text {Si}\left (5 \left (\frac {a}{b}+\text {ArcSin}(c+d x)\right )\right )\right )\right )}{96 b^4 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1137\) vs.
\(2(390)=780\).
time = 0.36, size = 1138, normalized size = 2.74
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(1138\) |
default | \(\text {Expression too large to display}\) | \(1138\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} e^{4} \left (\int \frac {c^{4}}{a^{4} + 4 a^{3} b \operatorname {asin}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asin}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asin}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asin}^{4}{\left (c + d x \right )}}\, dx + \int \frac {d^{4} x^{4}}{a^{4} + 4 a^{3} b \operatorname {asin}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asin}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asin}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asin}^{4}{\left (c + d x \right )}}\, dx + \int \frac {4 c d^{3} x^{3}}{a^{4} + 4 a^{3} b \operatorname {asin}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asin}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asin}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asin}^{4}{\left (c + d x \right )}}\, dx + \int \frac {6 c^{2} d^{2} x^{2}}{a^{4} + 4 a^{3} b \operatorname {asin}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asin}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asin}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asin}^{4}{\left (c + d x \right )}}\, dx + \int \frac {4 c^{3} d x}{a^{4} + 4 a^{3} b \operatorname {asin}{\left (c + d x \right )} + 6 a^{2} b^{2} \operatorname {asin}^{2}{\left (c + d x \right )} + 4 a b^{3} \operatorname {asin}^{3}{\left (c + d x \right )} + b^{4} \operatorname {asin}^{4}{\left (c + d x \right )}}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 5870 vs.
\(2 (390) = 780\).
time = 0.82, size = 5870, normalized size = 14.11 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (c\,e+d\,e\,x\right )}^4}{{\left (a+b\,\mathrm {asin}\left (c+d\,x\right )\right )}^4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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