3.5.47 \(\int e^{\text {ArcSin}(a x)^2} x \, dx\) [447]

Optimal. Leaf size=49 \[ \frac {e \sqrt {\pi } \text {Erf}(1-i \text {ArcSin}(a x))}{8 a^2}+\frac {e \sqrt {\pi } \text {Erf}(1+i \text {ArcSin}(a x))}{8 a^2} \]

[Out]

1/8*I*exp(1)*erfi(-I+arcsin(a*x))*Pi^(1/2)/a^2-1/8*I*exp(1)*erfi(I+arcsin(a*x))*Pi^(1/2)/a^2

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Rubi [A]
time = 0.05, antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4920, 12, 4562, 2266, 2235} \begin {gather*} \frac {e \sqrt {\pi } \text {Erf}(1-i \text {ArcSin}(a x))}{8 a^2}+\frac {e \sqrt {\pi } \text {Erf}(1+i \text {ArcSin}(a x))}{8 a^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[E^ArcSin[a*x]^2*x,x]

[Out]

(E*Sqrt[Pi]*Erf[1 - I*ArcSin[a*x]])/(8*a^2) + (E*Sqrt[Pi]*Erf[1 + I*ArcSin[a*x]])/(8*a^2)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2235

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[F^a*Sqrt[Pi]*(Erfi[(c + d*x)*Rt[b*Log[F], 2
]]/(2*d*Rt[b*Log[F], 2])), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2266

Int[(F_)^((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[F^(a - b^2/(4*c)), Int[F^((b + 2*c*x)^2/(4*c))
, x], x] /; FreeQ[{F, a, b, c}, x]

Rule 4562

Int[Cos[v_]^(n_.)*(F_)^(u_)*Sin[v_]^(m_.), x_Symbol] :> Int[ExpandTrigToExp[F^u, Sin[v]^m*Cos[v]^n, x], x] /;
FreeQ[F, x] && (LinearQ[u, x] || PolyQ[u, x, 2]) && (LinearQ[v, x] || PolyQ[v, x, 2]) && IGtQ[m, 0] && IGtQ[n,
0]

Rule 4920

Int[(u_.)*(f_)^(ArcSin[(a_.) + (b_.)*(x_)]^(n_.)*(c_.)), x_Symbol] :> Dist[1/b, Subst[Int[(u /. x -> -a/b + Si
n[x]/b)*f^(c*x^n)*Cos[x], x], x, ArcSin[a + b*x]], x] /; FreeQ[{a, b, c, f}, x] && IGtQ[n, 0]

Rubi steps

\begin {align*} \int e^{\sin ^{-1}(a x)^2} x \, dx &=\frac {\text {Subst}\left (\int \frac {e^{x^2} \cos (x) \sin (x)}{a} \, dx,x,\sin ^{-1}(a x)\right )}{a}\\ &=\frac {\text {Subst}\left (\int e^{x^2} \cos (x) \sin (x) \, dx,x,\sin ^{-1}(a x)\right )}{a^2}\\ &=\frac {\text {Subst}\left (\int \left (\frac {1}{4} i e^{-2 i x+x^2}-\frac {1}{4} i e^{2 i x+x^2}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a^2}\\ &=\frac {i \text {Subst}\left (\int e^{-2 i x+x^2} \, dx,x,\sin ^{-1}(a x)\right )}{4 a^2}-\frac {i \text {Subst}\left (\int e^{2 i x+x^2} \, dx,x,\sin ^{-1}(a x)\right )}{4 a^2}\\ &=\frac {(i e) \text {Subst}\left (\int e^{\frac {1}{4} (-2 i+2 x)^2} \, dx,x,\sin ^{-1}(a x)\right )}{4 a^2}-\frac {(i e) \text {Subst}\left (\int e^{\frac {1}{4} (2 i+2 x)^2} \, dx,x,\sin ^{-1}(a x)\right )}{4 a^2}\\ &=\frac {e \sqrt {\pi } \text {erf}\left (1-i \sin ^{-1}(a x)\right )}{8 a^2}+\frac {e \sqrt {\pi } \text {erf}\left (1+i \sin ^{-1}(a x)\right )}{8 a^2}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 36, normalized size = 0.73 \begin {gather*} \frac {e \sqrt {\pi } (\text {Erf}(1-i \text {ArcSin}(a x))+\text {Erf}(1+i \text {ArcSin}(a x)))}{8 a^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[E^ArcSin[a*x]^2*x,x]

[Out]

(E*Sqrt[Pi]*(Erf[1 - I*ArcSin[a*x]] + Erf[1 + I*ArcSin[a*x]]))/(8*a^2)

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int {\mathrm e}^{\arcsin \left (a x \right )^{2}} x\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(arcsin(a*x)^2)*x,x)

[Out]

int(exp(arcsin(a*x)^2)*x,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arcsin(a*x)^2)*x,x, algorithm="maxima")

[Out]

integrate(x*e^(arcsin(a*x)^2), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arcsin(a*x)^2)*x,x, algorithm="fricas")

[Out]

integral(x*e^(arcsin(a*x)^2), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x e^{\operatorname {asin}^{2}{\left (a x \right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(asin(a*x)**2)*x,x)

[Out]

Integral(x*exp(asin(a*x)**2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(arcsin(a*x)^2)*x,x, algorithm="giac")

[Out]

integrate(x*e^(arcsin(a*x)^2), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x\,{\mathrm {e}}^{{\mathrm {asin}\left (a\,x\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*exp(asin(a*x)^2),x)

[Out]

int(x*exp(asin(a*x)^2), x)

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