3.1.39 \(\int \sqrt {\text {ArcCos}(a+b x)} \, dx\) [39]

Optimal. Leaf size=55 \[ \frac {(a+b x) \sqrt {\text {ArcCos}(a+b x)}}{b}-\frac {\sqrt {\frac {\pi }{2}} \text {FresnelC}\left (\sqrt {\frac {2}{\pi }} \sqrt {\text {ArcCos}(a+b x)}\right )}{b} \]

[Out]

-1/2*FresnelC(2^(1/2)/Pi^(1/2)*arccos(b*x+a)^(1/2))*2^(1/2)*Pi^(1/2)/b+(b*x+a)*arccos(b*x+a)^(1/2)/b

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Rubi [A]
time = 0.05, antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4888, 4716, 4810, 3385, 3433} \begin {gather*} \frac {(a+b x) \sqrt {\text {ArcCos}(a+b x)}}{b}-\frac {\sqrt {\frac {\pi }{2}} \text {FresnelC}\left (\sqrt {\frac {2}{\pi }} \sqrt {\text {ArcCos}(a+b x)}\right )}{b} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sqrt[ArcCos[a + b*x]],x]

[Out]

((a + b*x)*Sqrt[ArcCos[a + b*x]])/b - (Sqrt[Pi/2]*FresnelC[Sqrt[2/Pi]*Sqrt[ArcCos[a + b*x]]])/b

Rule 3385

Int[sin[Pi/2 + (e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Cos[f*(x^2/d)],
x], x, Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3433

Int[Cos[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]/(f*Rt[d, 2]))*FresnelC[Sqrt[2/Pi]*Rt[d, 2
]*(e + f*x)], x] /; FreeQ[{d, e, f}, x]

Rule 4716

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Simp[x*(a + b*ArcCos[c*x])^n, x] + Dist[b*c*n, Int[
x*((a + b*ArcCos[c*x])^(n - 1)/Sqrt[1 - c^2*x^2]), x], x] /; FreeQ[{a, b, c}, x] && GtQ[n, 0]

Rule 4810

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[(-(b*c^
(m + 1))^(-1))*Simp[(d + e*x^2)^p/(1 - c^2*x^2)^p], Subst[Int[x^n*Cos[-a/b + x/b]^m*Sin[-a/b + x/b]^(2*p + 1),
x], x, a + b*ArcCos[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && IGtQ[2*p + 2, 0] && IGt
Q[m, 0]

Rule 4888

Int[((a_.) + ArcCos[(c_) + (d_.)*(x_)]*(b_.))^(n_.), x_Symbol] :> Dist[1/d, Subst[Int[(a + b*ArcCos[x])^n, x],
x, c + d*x], x] /; FreeQ[{a, b, c, d, n}, x]

Rubi steps

\begin {align*} \int \sqrt {\cos ^{-1}(a+b x)} \, dx &=\frac {\text {Subst}\left (\int \sqrt {\cos ^{-1}(x)} \, dx,x,a+b x\right )}{b}\\ &=\frac {(a+b x) \sqrt {\cos ^{-1}(a+b x)}}{b}+\frac {\text {Subst}\left (\int \frac {x}{\sqrt {1-x^2} \sqrt {\cos ^{-1}(x)}} \, dx,x,a+b x\right )}{2 b}\\ &=\frac {(a+b x) \sqrt {\cos ^{-1}(a+b x)}}{b}-\frac {\text {Subst}\left (\int \frac {\cos (x)}{\sqrt {x}} \, dx,x,\cos ^{-1}(a+b x)\right )}{2 b}\\ &=\frac {(a+b x) \sqrt {\cos ^{-1}(a+b x)}}{b}-\frac {\text {Subst}\left (\int \cos \left (x^2\right ) \, dx,x,\sqrt {\cos ^{-1}(a+b x)}\right )}{b}\\ &=\frac {(a+b x) \sqrt {\cos ^{-1}(a+b x)}}{b}-\frac {\sqrt {\frac {\pi }{2}} C\left (\sqrt {\frac {2}{\pi }} \sqrt {\cos ^{-1}(a+b x)}\right )}{b}\\ \end {align*}

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Mathematica [C] Result contains complex when optimal does not.
time = 0.03, size = 90, normalized size = 1.64 \begin {gather*} -\frac {-\frac {\sqrt {\text {ArcCos}(a+b x)} \text {Gamma}\left (\frac {3}{2},-i \text {ArcCos}(a+b x)\right )}{2 \sqrt {-i \text {ArcCos}(a+b x)}}-\frac {\sqrt {\text {ArcCos}(a+b x)} \text {Gamma}\left (\frac {3}{2},i \text {ArcCos}(a+b x)\right )}{2 \sqrt {i \text {ArcCos}(a+b x)}}}{b} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[ArcCos[a + b*x]],x]

[Out]

-((-1/2*(Sqrt[ArcCos[a + b*x]]*Gamma[3/2, (-I)*ArcCos[a + b*x]])/Sqrt[(-I)*ArcCos[a + b*x]] - (Sqrt[ArcCos[a +
b*x]]*Gamma[3/2, I*ArcCos[a + b*x]])/(2*Sqrt[I*ArcCos[a + b*x]]))/b)

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Maple [A]
time = 0.17, size = 66, normalized size = 1.20

method	result	size
default	\(\frac {-\FresnelC \left (\frac {\sqrt {2}\, \sqrt {\arccos \left (b x +a \right )}}{\sqrt {\pi }}\right ) \sqrt {2}\, \sqrt {\arccos \left (b x +a \right )}\, \sqrt {\pi }+2 \arccos \left (b x +a \right ) b x +2 \arccos \left (b x +a \right ) a}{2 b \sqrt {\arccos \left (b x +a \right )}}\)	\(66\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arccos(b*x+a)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/2/b/arccos(b*x+a)^(1/2)*(-FresnelC(2^(1/2)/Pi^(1/2)*arccos(b*x+a)^(1/2))*2^(1/2)*arccos(b*x+a)^(1/2)*Pi^(1/2
)+2*arccos(b*x+a)*b*x+2*arccos(b*x+a)*a)

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a)^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {\operatorname {acos}{\left (a + b x \right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(acos(b*x+a)**(1/2),x)

[Out]

Integral(sqrt(acos(a + b*x)), x)

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Giac [C] Result contains complex when optimal does not.
time = 0.44, size = 95, normalized size = 1.73 \begin {gather*} \frac {\left (i + 1\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (\left (\frac {1}{2} i - \frac {1}{2}\right ) \, \sqrt {2} \sqrt {\arccos \left (b x + a\right )}\right )}{8 \, b} - \frac {\left (i - 1\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (-\left (\frac {1}{2} i + \frac {1}{2}\right ) \, \sqrt {2} \sqrt {\arccos \left (b x + a\right )}\right )}{8 \, b} + \frac {\sqrt {\arccos \left (b x + a\right )} e^{\left (i \, \arccos \left (b x + a\right )\right )}}{2 \, b} + \frac {\sqrt {\arccos \left (b x + a\right )} e^{\left (-i \, \arccos \left (b x + a\right )\right )}}{2 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccos(b*x+a)^(1/2),x, algorithm="giac")

[Out]

(1/8*I + 1/8)*sqrt(2)*sqrt(pi)*erf((1/2*I - 1/2)*sqrt(2)*sqrt(arccos(b*x + a)))/b - (1/8*I - 1/8)*sqrt(2)*sqrt
(pi)*erf(-(1/2*I + 1/2)*sqrt(2)*sqrt(arccos(b*x + a)))/b + 1/2*sqrt(arccos(b*x + a))*e^(I*arccos(b*x + a))/b +
1/2*sqrt(arccos(b*x + a))*e^(-I*arccos(b*x + a))/b

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \sqrt {\mathrm {acos}\left (a+b\,x\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(acos(a + b*x)^(1/2),x)

[Out]

int(acos(a + b*x)^(1/2), x)

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