Optimal. Leaf size=88 \[ \frac {3 e^{2 \text {ArcTan}(a x)}}{40 a c^3}+\frac {e^{2 \text {ArcTan}(a x)} (1+2 a x)}{10 a c^3 \left (1+a^2 x^2\right )^2}+\frac {3 e^{2 \text {ArcTan}(a x)} (1+a x)}{20 a c^3 \left (1+a^2 x^2\right )} \]
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Rubi [A]
time = 0.06, antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {5178, 5179}
\begin {gather*} \frac {3 (a x+1) e^{2 \text {ArcTan}(a x)}}{20 a c^3 \left (a^2 x^2+1\right )}+\frac {(2 a x+1) e^{2 \text {ArcTan}(a x)}}{10 a c^3 \left (a^2 x^2+1\right )^2}+\frac {3 e^{2 \text {ArcTan}(a x)}}{40 a c^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 5178
Rule 5179
Rubi steps
\begin {align*} \int \frac {e^{2 \tan ^{-1}(a x)}}{\left (c+a^2 c x^2\right )^3} \, dx &=\frac {e^{2 \tan ^{-1}(a x)} (1+2 a x)}{10 a c^3 \left (1+a^2 x^2\right )^2}+\frac {3 \int \frac {e^{2 \tan ^{-1}(a x)}}{\left (c+a^2 c x^2\right )^2} \, dx}{5 c}\\ &=\frac {e^{2 \tan ^{-1}(a x)} (1+2 a x)}{10 a c^3 \left (1+a^2 x^2\right )^2}+\frac {3 e^{2 \tan ^{-1}(a x)} (1+a x)}{20 a c^3 \left (1+a^2 x^2\right )}+\frac {3 \int \frac {e^{2 \tan ^{-1}(a x)}}{c+a^2 c x^2} \, dx}{20 c^2}\\ &=\frac {3 e^{2 \tan ^{-1}(a x)}}{40 a c^3}+\frac {e^{2 \tan ^{-1}(a x)} (1+2 a x)}{10 a c^3 \left (1+a^2 x^2\right )^2}+\frac {3 e^{2 \tan ^{-1}(a x)} (1+a x)}{20 a c^3 \left (1+a^2 x^2\right )}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.10, size = 86, normalized size = 0.98 \begin {gather*} \frac {4 e^{2 \text {ArcTan}(a x)} (1+2 a x)+3 (1-i a x)^i (1+i a x)^{-i} \left (1+a^2 x^2\right ) \left (3+2 a x+a^2 x^2\right )}{40 a c^3 \left (1+a^2 x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 57, normalized size = 0.65
method | result | size |
gosper | \(\frac {{\mathrm e}^{2 \arctan \left (a x \right )} \left (3 a^{4} x^{4}+6 a^{3} x^{3}+12 a^{2} x^{2}+14 a x +13\right )}{40 \left (a^{2} x^{2}+1\right )^{2} c^{3} a}\) | \(57\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 2.51, size = 68, normalized size = 0.77 \begin {gather*} \frac {{\left (3 \, a^{4} x^{4} + 6 \, a^{3} x^{3} + 12 \, a^{2} x^{2} + 14 \, a x + 13\right )} e^{\left (2 \, \arctan \left (a x\right )\right )}}{40 \, {\left (a^{5} c^{3} x^{4} + 2 \, a^{3} c^{3} x^{2} + a c^{3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 231 vs.
\(2 (78) = 156\).
time = 4.11, size = 231, normalized size = 2.62 \begin {gather*} \begin {cases} \frac {3 a^{4} x^{4} e^{2 \operatorname {atan}{\left (a x \right )}}}{40 a^{5} c^{3} x^{4} + 80 a^{3} c^{3} x^{2} + 40 a c^{3}} + \frac {6 a^{3} x^{3} e^{2 \operatorname {atan}{\left (a x \right )}}}{40 a^{5} c^{3} x^{4} + 80 a^{3} c^{3} x^{2} + 40 a c^{3}} + \frac {12 a^{2} x^{2} e^{2 \operatorname {atan}{\left (a x \right )}}}{40 a^{5} c^{3} x^{4} + 80 a^{3} c^{3} x^{2} + 40 a c^{3}} + \frac {14 a x e^{2 \operatorname {atan}{\left (a x \right )}}}{40 a^{5} c^{3} x^{4} + 80 a^{3} c^{3} x^{2} + 40 a c^{3}} + \frac {13 e^{2 \operatorname {atan}{\left (a x \right )}}}{40 a^{5} c^{3} x^{4} + 80 a^{3} c^{3} x^{2} + 40 a c^{3}} & \text {for}\: a \neq 0 \\\frac {x}{c^{3}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.62, size = 79, normalized size = 0.90 \begin {gather*} \frac {3\,{\mathrm {e}}^{2\,\mathrm {atan}\left (a\,x\right )}}{40\,a\,c^3}+\frac {3\,{\mathrm {e}}^{2\,\mathrm {atan}\left (a\,x\right )}\,\left (a\,x+1\right )}{20\,a\,c^3\,\left (a^2\,x^2+1\right )}+\frac {{\mathrm {e}}^{2\,\mathrm {atan}\left (a\,x\right )}\,\left (2\,a\,x+1\right )}{10\,a\,c^3\,{\left (a^2\,x^2+1\right )}^2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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