3.4.66 \(\int \frac {e^{n \text {ArcTan}(a x)} x^m}{(c+a^2 c x^2)^2} \, dx\) [366]

Optimal. Leaf size=51 \[ \frac {x^{1+m} F_1\left (1+m;2-\frac {i n}{2},2+\frac {i n}{2};2+m;i a x,-i a x\right )}{c^2 (1+m)} \]

[Out]

x^(1+m)*AppellF1(1+m,2+1/2*I*n,2-1/2*I*n,2+m,-I*a*x,I*a*x)/c^2/(1+m)

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Rubi [A]
time = 0.06, antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {5190, 138} \begin {gather*} \frac {x^{m+1} F_1\left (m+1;2-\frac {i n}{2},\frac {i n}{2}+2;m+2;i a x,-i a x\right )}{c^2 (m+1)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(E^(n*ArcTan[a*x])*x^m)/(c + a^2*c*x^2)^2,x]

[Out]

(x^(1 + m)*AppellF1[1 + m, 2 - (I/2)*n, 2 + (I/2)*n, 2 + m, I*a*x, (-I)*a*x])/(c^2*(1 + m))

Rule 138

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_Symbol] :> Simp[c^n*e^p*((b*x)^(m +
1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2, (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p},
x] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])

Rule 5190

Int[E^(ArcTan[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[x^m*(1 - I
*a*x)^(p + I*(n/2))*(1 + I*a*x)^(p - I*(n/2)), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[d, a^2*c] && (Int
egerQ[p] || GtQ[c, 0])

Rubi steps

\begin {align*} \int \frac {e^{n \tan ^{-1}(a x)} x^m}{\left (c+a^2 c x^2\right )^2} \, dx &=\frac {\int x^m (1-i a x)^{-2+\frac {i n}{2}} (1+i a x)^{-2-\frac {i n}{2}} \, dx}{c^2}\\ &=\frac {x^{1+m} F_1\left (1+m;2-\frac {i n}{2},2+\frac {i n}{2};2+m;i a x,-i a x\right )}{c^2 (1+m)}\\ \end {align*}

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Mathematica [F]
time = 0.35, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {e^{n \text {ArcTan}(a x)} x^m}{\left (c+a^2 c x^2\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(E^(n*ArcTan[a*x])*x^m)/(c + a^2*c*x^2)^2,x]

[Out]

Integrate[(E^(n*ArcTan[a*x])*x^m)/(c + a^2*c*x^2)^2, x]

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Maple [F]
time = 0.03, size = 0, normalized size = 0.00 \[\int \frac {{\mathrm e}^{n \arctan \left (a x \right )} x^{m}}{\left (a^{2} c \,x^{2}+c \right )^{2}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(n*arctan(a*x))*x^m/(a^2*c*x^2+c)^2,x)

[Out]

int(exp(n*arctan(a*x))*x^m/(a^2*c*x^2+c)^2,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctan(a*x))*x^m/(a^2*c*x^2+c)^2,x, algorithm="maxima")

[Out]

integrate(x^m*e^(n*arctan(a*x))/(a^2*c*x^2 + c)^2, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctan(a*x))*x^m/(a^2*c*x^2+c)^2,x, algorithm="fricas")

[Out]

integral(x^m*e^(n*arctan(a*x))/(a^4*c^2*x^4 + 2*a^2*c^2*x^2 + c^2), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {x^{m} e^{n \operatorname {atan}{\left (a x \right )}}}{a^{4} x^{4} + 2 a^{2} x^{2} + 1}\, dx}{c^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*atan(a*x))*x**m/(a**2*c*x**2+c)**2,x)

[Out]

Integral(x**m*exp(n*atan(a*x))/(a**4*x**4 + 2*a**2*x**2 + 1), x)/c**2

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctan(a*x))*x^m/(a^2*c*x^2+c)^2,x, algorithm="giac")

[Out]

sage0*x

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {x^m\,{\mathrm {e}}^{n\,\mathrm {atan}\left (a\,x\right )}}{{\left (c\,a^2\,x^2+c\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^m*exp(n*atan(a*x)))/(c + a^2*c*x^2)^2,x)

[Out]

int((x^m*exp(n*atan(a*x)))/(c + a^2*c*x^2)^2, x)

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