Optimal. Leaf size=116 \[ \frac {1}{6} i b x^3+\frac {1}{2} x^2 \text {ArcTan}(c-(i-c) \coth (a+b x))-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i x \text {PolyLog}\left (2,-i c e^{2 a+2 b x}\right )}{4 b}+\frac {i \text {PolyLog}\left (3,-i c e^{2 a+2 b x}\right )}{8 b^2} \]
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Rubi [A]
time = 0.14, antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {5305, 2215,
2221, 2611, 2320, 6724} \begin {gather*} \frac {1}{2} x^2 \text {ArcTan}(c-(-c+i) \coth (a+b x))+\frac {i \text {Li}_3\left (-i c e^{2 a+2 b x}\right )}{8 b^2}-\frac {i x \text {Li}_2\left (-i c e^{2 a+2 b x}\right )}{4 b}-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )+\frac {1}{6} i b x^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 2215
Rule 2221
Rule 2320
Rule 2611
Rule 5305
Rule 6724
Rubi steps
\begin {align*} \int x \tan ^{-1}(c-(i-c) \coth (a+b x)) \, dx &=\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))-\frac {1}{2} b \int \frac {x^2}{i-c e^{2 a+2 b x}} \, dx\\ &=\frac {1}{6} i b x^3+\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))+\frac {1}{2} (i b c) \int \frac {e^{2 a+2 b x} x^2}{i-c e^{2 a+2 b x}} \, dx\\ &=\frac {1}{6} i b x^3+\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )+\frac {1}{2} i \int x \log \left (1+i c e^{2 a+2 b x}\right ) \, dx\\ &=\frac {1}{6} i b x^3+\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i x \text {Li}_2\left (-i c e^{2 a+2 b x}\right )}{4 b}+\frac {i \int \text {Li}_2\left (-i c e^{2 a+2 b x}\right ) \, dx}{4 b}\\ &=\frac {1}{6} i b x^3+\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i x \text {Li}_2\left (-i c e^{2 a+2 b x}\right )}{4 b}+\frac {i \text {Subst}\left (\int \frac {\text {Li}_2(-i c x)}{x} \, dx,x,e^{2 a+2 b x}\right )}{8 b^2}\\ &=\frac {1}{6} i b x^3+\frac {1}{2} x^2 \tan ^{-1}(c-(i-c) \coth (a+b x))-\frac {1}{4} i x^2 \log \left (1+i c e^{2 a+2 b x}\right )-\frac {i x \text {Li}_2\left (-i c e^{2 a+2 b x}\right )}{4 b}+\frac {i \text {Li}_3\left (-i c e^{2 a+2 b x}\right )}{8 b^2}\\ \end {align*}
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Mathematica [A]
time = 1.17, size = 102, normalized size = 0.88 \begin {gather*} \frac {1}{2} x^2 \text {ArcTan}(c+(-i+c) \coth (a+b x))-\frac {i \left (2 b^2 x^2 \log \left (1-\frac {i e^{-2 (a+b x)}}{c}\right )-2 b x \text {PolyLog}\left (2,\frac {i e^{-2 (a+b x)}}{c}\right )-\text {PolyLog}\left (3,\frac {i e^{-2 (a+b x)}}{c}\right )\right )}{8 b^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.51, size = 1451, normalized size = 12.51
method | result | size |
risch | \(\text {Expression too large to display}\) | \(1451\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 1.18, size = 107, normalized size = 0.92 \begin {gather*} -{\left (\frac {2 \, x^{3}}{3 i \, c + 3} - \frac {2 \, b^{2} x^{2} \log \left (i \, c e^{\left (2 \, b x + 2 \, a\right )} + 1\right ) + 2 \, b x {\rm Li}_2\left (-i \, c e^{\left (2 \, b x + 2 \, a\right )}\right ) - {\rm Li}_{3}(-i \, c e^{\left (2 \, b x + 2 \, a\right )})}{-2 \, b^{3} {\left (-i \, c - 1\right )}}\right )} b {\left (c - i\right )} + \frac {1}{2} \, x^{2} \arctan \left ({\left (c - i\right )} \coth \left (b x + a\right ) + c\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 247 vs. \(2 (83) = 166\).
time = 4.66, size = 247, normalized size = 2.13 \begin {gather*} \frac {2 i \, b^{3} x^{3} + 3 i \, b^{2} x^{2} \log \left (-\frac {{\left (c e^{\left (2 \, b x + 2 \, a\right )} - i\right )} e^{\left (-2 \, b x - 2 \, a\right )}}{c - i}\right ) + 2 i \, a^{3} - 6 i \, b x {\rm Li}_2\left (\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right ) - 6 i \, b x {\rm Li}_2\left (-\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right ) - 3 i \, a^{2} \log \left (\frac {2 \, c e^{\left (b x + a\right )} + i \, \sqrt {-4 i \, c}}{2 \, c}\right ) - 3 i \, a^{2} \log \left (\frac {2 \, c e^{\left (b x + a\right )} - i \, \sqrt {-4 i \, c}}{2 \, c}\right ) - 3 \, {\left (i \, b^{2} x^{2} - i \, a^{2}\right )} \log \left (\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )} + 1\right ) - 3 \, {\left (i \, b^{2} x^{2} - i \, a^{2}\right )} \log \left (-\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )} + 1\right ) + 6 i \, {\rm polylog}\left (3, \frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right ) + 6 i \, {\rm polylog}\left (3, -\frac {1}{2} \, \sqrt {-4 i \, c} e^{\left (b x + a\right )}\right )}{12 \, b^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: CoercionFailed} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x\,\mathrm {atan}\left (c+\mathrm {coth}\left (a+b\,x\right )\,\left (c-\mathrm {i}\right )\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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