3.2.47 \(\int (e+f x)^m (a+b \cot ^{-1}(c+d x))^2 \, dx\) [147]

Optimal. Leaf size=23 \[ \text {Int}\left ((e+f x)^m \left (a+b \cot ^{-1}(c+d x)\right )^2,x\right ) \]

[Out]

Unintegrable((f*x+e)^m*(a+b*arccot(d*x+c))^2,x)

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Rubi [A]
time = 0.04, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int (e+f x)^m \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(e + f*x)^m*(a + b*ArcCot[c + d*x])^2,x]

[Out]

Defer[Subst][Defer[Int][((d*e - c*f)/d + (f*x)/d)^m*(a + b*ArcCot[x])^2, x], x, c + d*x]/d

Rubi steps

\begin {align*} \int (e+f x)^m \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx &=\frac {\text {Subst}\left (\int \left (\frac {d e-c f}{d}+\frac {f x}{d}\right )^m \left (a+b \cot ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ \end {align*}

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Mathematica [A]
time = 4.00, size = 0, normalized size = 0.00 \begin {gather*} \int (e+f x)^m \left (a+b \cot ^{-1}(c+d x)\right )^2 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(e + f*x)^m*(a + b*ArcCot[c + d*x])^2,x]

[Out]

Integrate[(e + f*x)^m*(a + b*ArcCot[c + d*x])^2, x]

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Maple [A]
time = 0.17, size = 0, normalized size = 0.00 \[\int \left (f x +e \right )^{m} \left (a +b \,\mathrm {arccot}\left (d x +c \right )\right )^{2}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x+e)^m*(a+b*arccot(d*x+c))^2,x)

[Out]

int((f*x+e)^m*(a+b*arccot(d*x+c))^2,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^m*(a+b*arccot(d*x+c))^2,x, algorithm="maxima")

[Out]

(f*x + e)^(m + 1)*a^2/(f*(m + 1)) - 1/16*((b^2*f*x + b^2*e)*(f*x + e)^m*log(d^2*x^2 + 2*c*d*x + c^2 + 1)^2 - 4
*(b^2*f*x*arctan2(1, d*x + c)^2 + b^2*arctan2(1, d*x + c)^2*e)*(f*x + e)^m - 16*(f*m + f)*integrate(1/16*(((b^
2*c^2 + b^2)*f*m + (b^2*d^2*f*m + b^2*d^2*f)*x^2 + (b^2*c^2 + b^2)*f + 2*(b^2*c*d*f*m + b^2*c*d*f)*x)*(f*x + e
)^m*log(d^2*x^2 + 2*c*d*x + c^2 + 1)^2 + 4*(b^2*d^2*f*x^2 + b^2*c*d*e + (b^2*c*d*f + b^2*d^2*e)*x)*(f*x + e)^m
*log(d^2*x^2 + 2*c*d*x + c^2 + 1) + 4*(2*b^2*d*arctan2(1, d*x + c)*e + (3*b^2*arctan2(1, d*x + c)^2 + (3*b^2*a
rctan2(1, d*x + c)^2 + 8*a*b*arctan2(1, d*x + c))*c^2 + 8*a*b*arctan2(1, d*x + c))*f*m + ((3*b^2*arctan2(1, d*
x + c)^2 + 8*a*b*arctan2(1, d*x + c))*d^2*f*m + (3*b^2*arctan2(1, d*x + c)^2 + 8*a*b*arctan2(1, d*x + c))*d^2*
f)*x^2 + (3*b^2*arctan2(1, d*x + c)^2 + (3*b^2*arctan2(1, d*x + c)^2 + 8*a*b*arctan2(1, d*x + c))*c^2 + 8*a*b*
arctan2(1, d*x + c))*f + 2*((3*b^2*arctan2(1, d*x + c)^2 + 8*a*b*arctan2(1, d*x + c))*c*d*f*m + (b^2*arctan2(1
, d*x + c) + (3*b^2*arctan2(1, d*x + c)^2 + 8*a*b*arctan2(1, d*x + c))*c)*d*f)*x)*(f*x + e)^m)/((c^2 + 1)*f*m
+ (d^2*f*m + d^2*f)*x^2 + (c^2 + 1)*f + 2*(c*d*f*m + c*d*f)*x), x))/(f*m + f)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^m*(a+b*arccot(d*x+c))^2,x, algorithm="fricas")

[Out]

integral((b^2*arccot(d*x + c)^2 + 2*a*b*arccot(d*x + c) + a^2)*(f*x + e)^m, x)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)**m*(a+b*acot(d*x+c))**2,x)

[Out]

Timed out

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^m*(a+b*arccot(d*x+c))^2,x, algorithm="giac")

[Out]

integrate((b*arccot(d*x + c) + a)^2*(f*x + e)^m, x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int {\left (e+f\,x\right )}^m\,{\left (a+b\,\mathrm {acot}\left (c+d\,x\right )\right )}^2 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e + f*x)^m*(a + b*acot(c + d*x))^2,x)

[Out]

int((e + f*x)^m*(a + b*acot(c + d*x))^2, x)

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