Optimal. Leaf size=488 \[ -\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}+\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {PolyLog}\left (2,1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {PolyLog}\left (2,1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}+\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {PolyLog}\left (3,1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {PolyLog}\left (3,1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}-\frac {3 i b^3 \text {PolyLog}\left (4,1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{4 c}+\frac {3 i b^3 \text {PolyLog}\left (4,1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{4 c} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.37, antiderivative size = 488, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 7, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.175, Rules used = {6813, 4943,
5109, 5005, 5113, 5117, 6745} \begin {gather*} \frac {3 b^2 \text {Li}_3\left (1-\frac {2 i}{\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i}\right ) \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}\right )\right )}{2 c}-\frac {3 b^2 \text {Li}_3\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {c x+1} \left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i\right )}\right ) \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}\right )\right )}{2 c}+\frac {3 i b \text {Li}_2\left (1-\frac {2 i}{\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i}\right ) \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}\right )\right )^2}{2 c}-\frac {3 i b \text {Li}_2\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {c x+1} \left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i\right )}\right ) \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}\right )\right )^2}{2 c}-\frac {2 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {c x+1}}}\right ) \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}\right )\right )^3}{c}-\frac {3 i b^3 \text {Li}_4\left (1-\frac {2 i}{\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i}\right )}{4 c}+\frac {3 i b^3 \text {Li}_4\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {c x+1} \left (\frac {\sqrt {1-c x}}{\sqrt {c x+1}}+i\right )}\right )}{4 c} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 4943
Rule 5005
Rule 5109
Rule 5113
Rule 5117
Rule 6745
Rule 6813
Rubi steps
\begin {align*} \int \frac {\left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3}{1-c^2 x^2} \, dx &=-\frac {\text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right )^3}{x} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}\\ &=-\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}-\frac {(6 b) \text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right )^2 \coth ^{-1}\left (1-\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}\\ &=-\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}+\frac {(3 b) \text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right )^2 \log \left (\frac {2 i}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}-\frac {(3 b) \text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right )^2 \log \left (\frac {2 x}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}\\ &=-\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}+\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}+\frac {\left (3 i b^2\right ) \text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right ) \text {Li}_2\left (1-\frac {2 i}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}-\frac {\left (3 i b^2\right ) \text {Subst}\left (\int \frac {\left (a+b \cot ^{-1}(x)\right ) \text {Li}_2\left (1-\frac {2 x}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{c}\\ &=-\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}+\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}+\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {Li}_3\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {Li}_3\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}+\frac {\left (3 b^3\right ) \text {Subst}\left (\int \frac {\text {Li}_3\left (1-\frac {2 i}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{2 c}-\frac {\left (3 b^3\right ) \text {Subst}\left (\int \frac {\text {Li}_3\left (1-\frac {2 x}{i+x}\right )}{1+x^2} \, dx,x,\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}{2 c}\\ &=-\frac {2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3 \coth ^{-1}\left (1-\frac {2}{1+\frac {i \sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{c}+\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 i b \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^2 \text {Li}_2\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}+\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {Li}_3\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{2 c}-\frac {3 b^2 \left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right ) \text {Li}_3\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{2 c}-\frac {3 i b^3 \text {Li}_4\left (1-\frac {2 i}{i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}}\right )}{4 c}+\frac {3 i b^3 \text {Li}_4\left (1-\frac {2 \sqrt {1-c x}}{\sqrt {1+c x} \left (i+\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )}\right )}{4 c}\\ \end {align*}
________________________________________________________________________________________
Mathematica [F]
time = 0.21, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a+b \cot ^{-1}\left (\frac {\sqrt {1-c x}}{\sqrt {1+c x}}\right )\right )^3}{1-c^2 x^2} \, dx \end {gather*}
Verification is not applicable to the result.
[In]
[Out]
________________________________________________________________________________________
Maple [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 1604 vs. \(2 (402 ) = 804\).
time = 0.58, size = 1605, normalized size = 3.29
method | result | size |
default | \(\text {Expression too large to display}\) | \(1605\) |
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int -\frac {{\left (a+b\,\mathrm {acot}\left (\frac {\sqrt {1-c\,x}}{\sqrt {c\,x+1}}\right )\right )}^3}{c^2\,x^2-1} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________