Optimal. Leaf size=264 \[ \frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {PolyLog}\left (2,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {PolyLog}\left (2,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {3 i \text {PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac {6 a \text {PolyLog}\left (3,-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 a \text {PolyLog}\left (3,e^{i \csc ^{-1}(a+b x)}\right )}{b^2} \]
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Rubi [A]
time = 0.19, antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 12, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.200, Rules used = {5367, 4512,
4275, 4268, 2611, 2320, 6724, 4269, 3798, 2221, 2317, 2438} \begin {gather*} -\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {3 i \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac {6 a \text {Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 a \text {Li}_3\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 2221
Rule 2317
Rule 2320
Rule 2438
Rule 2611
Rule 3798
Rule 4268
Rule 4269
Rule 4275
Rule 4512
Rule 5367
Rule 6724
Rubi steps
\begin {align*} \int x \csc ^{-1}(a+b x)^3 \, dx &=-\frac {\text {Subst}\left (\int x^3 \cot (x) \csc (x) (-a+\csc (x)) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {3 \text {Subst}\left (\int x^2 (-a+\csc (x))^2 \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}\\ &=\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {3 \text {Subst}\left (\int \left (a^2 x^2-2 a x^2 \csc (x)+x^2 \csc ^2(x)\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}\\ &=-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {3 \text {Subst}\left (\int x^2 \csc ^2(x) \, dx,x,\csc ^{-1}(a+b x)\right )}{2 b^2}+\frac {(3 a) \text {Subst}\left (\int x^2 \csc (x) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {3 \text {Subst}\left (\int x \cot (x) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac {(6 a) \text {Subst}\left (\int x \log \left (1-e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}+\frac {(6 a) \text {Subst}\left (\int x \log \left (1+e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {(6 i) \text {Subst}\left (\int \frac {e^{2 i x} x}{1-e^{2 i x}} \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac {(6 i a) \text {Subst}\left (\int \text {Li}_2\left (-e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}+\frac {(6 i a) \text {Subst}\left (\int \text {Li}_2\left (e^{i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}\\ &=\frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {3 \text {Subst}\left (\int \log \left (1-e^{2 i x}\right ) \, dx,x,\csc ^{-1}(a+b x)\right )}{b^2}-\frac {(6 a) \text {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {(6 a) \text {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,e^{i \csc ^{-1}(a+b x)}\right )}{b^2}\\ &=\frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 a \text {Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 a \text {Li}_3\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {(3 i) \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}\\ &=\frac {3 i \csc ^{-1}(a+b x)^2}{2 b^2}+\frac {3 (a+b x) \sqrt {1-\frac {1}{(a+b x)^2}} \csc ^{-1}(a+b x)^2}{2 b^2}-\frac {a^2 \csc ^{-1}(a+b x)^3}{2 b^2}+\frac {1}{2} x^2 \csc ^{-1}(a+b x)^3-\frac {6 a \csc ^{-1}(a+b x)^2 \tanh ^{-1}\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {3 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}-\frac {6 i a \csc ^{-1}(a+b x) \text {Li}_2\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {3 i \text {Li}_2\left (e^{2 i \csc ^{-1}(a+b x)}\right )}{2 b^2}-\frac {6 a \text {Li}_3\left (-e^{i \csc ^{-1}(a+b x)}\right )}{b^2}+\frac {6 a \text {Li}_3\left (e^{i \csc ^{-1}(a+b x)}\right )}{b^2}\\ \end {align*}
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Mathematica [A]
time = 0.59, size = 314, normalized size = 1.19 \begin {gather*} \frac {3 i \csc ^{-1}(a+b x)^2+3 a \sqrt {\frac {-1+a^2+2 a b x+b^2 x^2}{(a+b x)^2}} \csc ^{-1}(a+b x)^2+3 b x \sqrt {\frac {-1+a^2+2 a b x+b^2 x^2}{(a+b x)^2}} \csc ^{-1}(a+b x)^2-a^2 \csc ^{-1}(a+b x)^3+b^2 x^2 \csc ^{-1}(a+b x)^3+6 a \csc ^{-1}(a+b x)^2 \log \left (1-e^{i \csc ^{-1}(a+b x)}\right )-6 a \csc ^{-1}(a+b x)^2 \log \left (1+e^{i \csc ^{-1}(a+b x)}\right )-6 \csc ^{-1}(a+b x) \log \left (1-e^{2 i \csc ^{-1}(a+b x)}\right )+12 i a \csc ^{-1}(a+b x) \text {PolyLog}\left (2,-e^{i \csc ^{-1}(a+b x)}\right )-12 i a \csc ^{-1}(a+b x) \text {PolyLog}\left (2,e^{i \csc ^{-1}(a+b x)}\right )+3 i \text {PolyLog}\left (2,e^{2 i \csc ^{-1}(a+b x)}\right )-12 a \text {PolyLog}\left (3,-e^{i \csc ^{-1}(a+b x)}\right )+12 a \text {PolyLog}\left (3,e^{i \csc ^{-1}(a+b x)}\right )}{2 b^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 6.13, size = 425, normalized size = 1.61
method | result | size |
derivativedivides | \(\frac {-\frac {\mathrm {arccsc}\left (b x +a \right )^{2} \left (2 \,\mathrm {arccsc}\left (b x +a \right ) a \left (b x +a \right )-\mathrm {arccsc}\left (b x +a \right ) \left (b x +a \right )^{2}-3 \sqrt {\frac {\left (b x +a \right )^{2}-1}{\left (b x +a \right )^{2}}}\, \left (b x +a \right )+3 i\right )}{2}-3 a \mathrm {arccsc}\left (b x +a \right )^{2} \ln \left (1+\frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 a \mathrm {arccsc}\left (b x +a \right )^{2} \ln \left (1-\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-3 \,\mathrm {arccsc}\left (b x +a \right ) \ln \left (1+\frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+6 i a \,\mathrm {arccsc}\left (b x +a \right ) \polylog \left (2, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-6 a \polylog \left (3, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-3 \,\mathrm {arccsc}\left (b x +a \right ) \ln \left (1-\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-6 i a \,\mathrm {arccsc}\left (b x +a \right ) \polylog \left (2, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+6 a \polylog \left (3, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 i \mathrm {arccsc}\left (b x +a \right )^{2}+3 i \polylog \left (2, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 i \polylog \left (2, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )}{b^{2}}\) | \(425\) |
default | \(\frac {-\frac {\mathrm {arccsc}\left (b x +a \right )^{2} \left (2 \,\mathrm {arccsc}\left (b x +a \right ) a \left (b x +a \right )-\mathrm {arccsc}\left (b x +a \right ) \left (b x +a \right )^{2}-3 \sqrt {\frac {\left (b x +a \right )^{2}-1}{\left (b x +a \right )^{2}}}\, \left (b x +a \right )+3 i\right )}{2}-3 a \mathrm {arccsc}\left (b x +a \right )^{2} \ln \left (1+\frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 a \mathrm {arccsc}\left (b x +a \right )^{2} \ln \left (1-\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-3 \,\mathrm {arccsc}\left (b x +a \right ) \ln \left (1+\frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+6 i a \,\mathrm {arccsc}\left (b x +a \right ) \polylog \left (2, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-6 a \polylog \left (3, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-3 \,\mathrm {arccsc}\left (b x +a \right ) \ln \left (1-\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )-6 i a \,\mathrm {arccsc}\left (b x +a \right ) \polylog \left (2, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+6 a \polylog \left (3, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 i \mathrm {arccsc}\left (b x +a \right )^{2}+3 i \polylog \left (2, -\frac {i}{b x +a}-\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )+3 i \polylog \left (2, \frac {i}{b x +a}+\sqrt {1-\frac {1}{\left (b x +a \right )^{2}}}\right )}{b^{2}}\) | \(425\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x \operatorname {acsc}^{3}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x\,{\mathrm {asin}\left (\frac {1}{a+b\,x}\right )}^3 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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