Optimal. Leaf size=115 \[ \frac {2 b \tanh ^{-1}(\cosh (x))}{a^3}-\frac {2 b^2 \left (3 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{a^3 \left (a^2+b^2\right )^{3/2}}-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))} \]
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Rubi [A]
time = 0.27, antiderivative size = 115, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {2881, 3134,
3080, 3855, 2739, 632, 212} \begin {gather*} \frac {2 b \tanh ^{-1}(\cosh (x))}{a^3}-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {2 b^2 \left (3 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{a^3 \left (a^2+b^2\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 632
Rule 2739
Rule 2881
Rule 3080
Rule 3134
Rule 3855
Rubi steps
\begin {align*} \int \frac {\text {csch}^2(x)}{(a+b \sinh (x))^2} \, dx &=\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {\int \frac {\text {csch}^2(x) \left (a^2+2 b^2-a b \sinh (x)+b^2 \sinh ^2(x)\right )}{a+b \sinh (x)} \, dx}{a \left (a^2+b^2\right )}\\ &=-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {i \int \frac {\text {csch}(x) \left (2 i b \left (a^2+b^2\right )-i a b^2 \sinh (x)\right )}{a+b \sinh (x)} \, dx}{a^2 \left (a^2+b^2\right )}\\ &=-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {(2 b) \int \text {csch}(x) \, dx}{a^3}+\frac {\left (b^2 \left (3 a^2+2 b^2\right )\right ) \int \frac {1}{a+b \sinh (x)} \, dx}{a^3 \left (a^2+b^2\right )}\\ &=\frac {2 b \tanh ^{-1}(\cosh (x))}{a^3}-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {\left (2 b^2 \left (3 a^2+2 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x-a x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{a^3 \left (a^2+b^2\right )}\\ &=\frac {2 b \tanh ^{-1}(\cosh (x))}{a^3}-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {\left (4 b^2 \left (3 a^2+2 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{4 \left (a^2+b^2\right )-x^2} \, dx,x,2 b-2 a \tanh \left (\frac {x}{2}\right )\right )}{a^3 \left (a^2+b^2\right )}\\ &=\frac {2 b \tanh ^{-1}(\cosh (x))}{a^3}-\frac {2 b^2 \left (3 a^2+2 b^2\right ) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{a^3 \left (a^2+b^2\right )^{3/2}}-\frac {\left (a^2+2 b^2\right ) \coth (x)}{a^2 \left (a^2+b^2\right )}+\frac {b^2 \coth (x)}{a \left (a^2+b^2\right ) (a+b \sinh (x))}\\ \end {align*}
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Mathematica [A]
time = 0.48, size = 118, normalized size = 1.03 \begin {gather*} -\frac {\frac {4 b^2 \left (3 a^2+2 b^2\right ) \text {ArcTan}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {-a^2-b^2}}\right )}{\left (-a^2-b^2\right )^{3/2}}+a \coth \left (\frac {x}{2}\right )+4 b \log \left (\tanh \left (\frac {x}{2}\right )\right )+\frac {2 a b^3 \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}+a \tanh \left (\frac {x}{2}\right )}{2 a^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.72, size = 141, normalized size = 1.23
method | result | size |
default | \(-\frac {\tanh \left (\frac {x}{2}\right )}{2 a^{2}}-\frac {1}{2 a^{2} \tanh \left (\frac {x}{2}\right )}-\frac {2 b \ln \left (\tanh \left (\frac {x}{2}\right )\right )}{a^{3}}-\frac {2 b^{2} \left (\frac {-\frac {b^{2} \tanh \left (\frac {x}{2}\right )}{a^{2}+b^{2}}-\frac {a b}{a^{2}+b^{2}}}{a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-2 b \tanh \left (\frac {x}{2}\right )-a}-\frac {\left (3 a^{2}+2 b^{2}\right ) \arctanh \left (\frac {2 a \tanh \left (\frac {x}{2}\right )-2 b}{2 \sqrt {a^{2}+b^{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}}}\right )}{a^{3}}\) | \(141\) |
risch | \(-\frac {2 \left (-a \,b^{2} {\mathrm e}^{3 x}+a^{2} b \,{\mathrm e}^{2 x}+2 b^{3} {\mathrm e}^{2 x}+2 a^{3} {\mathrm e}^{x}+3 a \,b^{2} {\mathrm e}^{x}-a^{2} b -2 b^{3}\right )}{a^{2} \left ({\mathrm e}^{2 x}-1\right ) \left (a^{2}+b^{2}\right ) \left (b \,{\mathrm e}^{2 x}+2 a \,{\mathrm e}^{x}-b \right )}-\frac {2 b \ln \left ({\mathrm e}^{x}-1\right )}{a^{3}}+\frac {2 b \ln \left ({\mathrm e}^{x}+1\right )}{a^{3}}+\frac {3 b^{2} \ln \left ({\mathrm e}^{x}+\frac {a \left (a^{2}+b^{2}\right )^{\frac {3}{2}}-a^{4}-2 a^{2} b^{2}-b^{4}}{b \left (a^{2}+b^{2}\right )^{\frac {3}{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}} a}+\frac {2 b^{4} \ln \left ({\mathrm e}^{x}+\frac {a \left (a^{2}+b^{2}\right )^{\frac {3}{2}}-a^{4}-2 a^{2} b^{2}-b^{4}}{b \left (a^{2}+b^{2}\right )^{\frac {3}{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}} a^{3}}-\frac {3 b^{2} \ln \left ({\mathrm e}^{x}+\frac {a \left (a^{2}+b^{2}\right )^{\frac {3}{2}}+a^{4}+2 a^{2} b^{2}+b^{4}}{b \left (a^{2}+b^{2}\right )^{\frac {3}{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}} a}-\frac {2 b^{4} \ln \left ({\mathrm e}^{x}+\frac {a \left (a^{2}+b^{2}\right )^{\frac {3}{2}}+a^{4}+2 a^{2} b^{2}+b^{4}}{b \left (a^{2}+b^{2}\right )^{\frac {3}{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}} a^{3}}\) | \(366\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 251 vs.
\(2 (111) = 222\).
time = 0.50, size = 251, normalized size = 2.18 \begin {gather*} \frac {{\left (3 \, a^{2} b^{2} + 2 \, b^{4}\right )} \log \left (\frac {b e^{\left (-x\right )} - a - \sqrt {a^{2} + b^{2}}}{b e^{\left (-x\right )} - a + \sqrt {a^{2} + b^{2}}}\right )}{{\left (a^{5} + a^{3} b^{2}\right )} \sqrt {a^{2} + b^{2}}} + \frac {2 \, {\left (a b^{2} e^{\left (-3 \, x\right )} - a^{2} b - 2 \, b^{3} - {\left (2 \, a^{3} + 3 \, a b^{2}\right )} e^{\left (-x\right )} + {\left (a^{2} b + 2 \, b^{3}\right )} e^{\left (-2 \, x\right )}\right )}}{a^{4} b + a^{2} b^{3} + 2 \, {\left (a^{5} + a^{3} b^{2}\right )} e^{\left (-x\right )} - 2 \, {\left (a^{4} b + a^{2} b^{3}\right )} e^{\left (-2 \, x\right )} - 2 \, {\left (a^{5} + a^{3} b^{2}\right )} e^{\left (-3 \, x\right )} + {\left (a^{4} b + a^{2} b^{3}\right )} e^{\left (-4 \, x\right )}} + \frac {2 \, b \log \left (e^{\left (-x\right )} + 1\right )}{a^{3}} - \frac {2 \, b \log \left (e^{\left (-x\right )} - 1\right )}{a^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1740 vs.
\(2 (111) = 222\).
time = 0.53, size = 1740, normalized size = 15.13 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\operatorname {csch}^{2}{\left (x \right )}}{\left (a + b \sinh {\left (x \right )}\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.43, size = 205, normalized size = 1.78 \begin {gather*} \frac {{\left (3 \, a^{2} b^{2} + 2 \, b^{4}\right )} \log \left (\frac {{\left | 2 \, b e^{x} + 2 \, a - 2 \, \sqrt {a^{2} + b^{2}} \right |}}{{\left | 2 \, b e^{x} + 2 \, a + 2 \, \sqrt {a^{2} + b^{2}} \right |}}\right )}{{\left (a^{5} + a^{3} b^{2}\right )} \sqrt {a^{2} + b^{2}}} + \frac {2 \, {\left (a b^{2} e^{\left (3 \, x\right )} - a^{2} b e^{\left (2 \, x\right )} - 2 \, b^{3} e^{\left (2 \, x\right )} - 2 \, a^{3} e^{x} - 3 \, a b^{2} e^{x} + a^{2} b + 2 \, b^{3}\right )}}{{\left (a^{4} + a^{2} b^{2}\right )} {\left (b e^{\left (4 \, x\right )} + 2 \, a e^{\left (3 \, x\right )} - 2 \, b e^{\left (2 \, x\right )} - 2 \, a e^{x} + b\right )}} + \frac {2 \, b \log \left (e^{x} + 1\right )}{a^{3}} - \frac {2 \, b \log \left ({\left | e^{x} - 1 \right |}\right )}{a^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 3.39, size = 1017, normalized size = 8.84 \begin {gather*} \frac {\frac {2\,\left (25\,a^8\,b^6+90\,a^6\,b^8+96\,a^4\,b^{10}+32\,a^2\,b^{12}\right )}{a^4\,b^2\,\left (25\,a^6\,b^3+65\,a^4\,b^5+56\,a^2\,b^7+16\,b^9\right )}-\frac {2\,{\mathrm {e}}^x\,\left (50\,a^9\,b^6+155\,a^7\,b^8+152\,a^5\,b^{10}+48\,a^3\,b^{12}\right )}{a^4\,b^3\,\left (25\,a^6\,b^3+65\,a^4\,b^5+56\,a^2\,b^7+16\,b^9\right )}-\frac {2\,{\mathrm {e}}^{2\,x}\,\left (25\,a^8\,b^6+90\,a^6\,b^8+96\,a^4\,b^{10}+32\,a^2\,b^{12}\right )}{a^4\,b^2\,\left (25\,a^6\,b^3+65\,a^4\,b^5+56\,a^2\,b^7+16\,b^9\right )}+\frac {2\,{\mathrm {e}}^{3\,x}\,\left (25\,a^7\,b^8+40\,a^5\,b^{10}+16\,a^3\,b^{12}\right )}{a^4\,b^3\,\left (25\,a^6\,b^3+65\,a^4\,b^5+56\,a^2\,b^7+16\,b^9\right )}}{b-2\,a\,{\mathrm {e}}^x+2\,a\,{\mathrm {e}}^{3\,x}-2\,b\,{\mathrm {e}}^{2\,x}+b\,{\mathrm {e}}^{4\,x}}-\frac {2\,b\,\ln \left ({\mathrm {e}}^x-1\right )}{a^3}+\frac {2\,b\,\ln \left ({\mathrm {e}}^x+1\right )}{a^3}+\frac {b^2\,\ln \left (-\frac {64\,\left (3\,a^2+2\,b^2\right )\,\left (-8\,{\mathrm {e}}^x\,a^3+4\,a^2\,b-7\,{\mathrm {e}}^x\,a\,b^2+4\,b^3\right )}{a^6\,b\,{\left (a^2+b^2\right )}^2}-\frac {32\,\left (3\,a^2+2\,b^2\right )\,\left (8\,a^9\,b-8\,b^7\,\sqrt {{\left (a^2+b^2\right )}^3}+3\,a^3\,b^7+13\,a^5\,b^5+18\,a^7\,b^3-16\,a^{10}\,{\mathrm {e}}^x-24\,a^2\,b^5\,\sqrt {{\left (a^2+b^2\right )}^3}-18\,a^4\,b^3\,\sqrt {{\left (a^2+b^2\right )}^3}-9\,a^4\,b^6\,{\mathrm {e}}^x-33\,a^6\,b^4\,{\mathrm {e}}^x-40\,a^8\,b^2\,{\mathrm {e}}^x+41\,a^3\,b^4\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}+30\,a^5\,b^2\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}+14\,a\,b^6\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}\right )}{a^6\,b\,\sqrt {{\left (a^2+b^2\right )}^3}\,{\left (a^2+b^2\right )}^4}\right )\,\sqrt {{\left (a^2+b^2\right )}^3}\,\left (3\,a^2+2\,b^2\right )}{a^9+3\,a^7\,b^2+3\,a^5\,b^4+a^3\,b^6}-\frac {b^2\,\ln \left (\frac {32\,\left (3\,a^2+2\,b^2\right )\,\left (8\,a^9\,b+8\,b^7\,\sqrt {{\left (a^2+b^2\right )}^3}+3\,a^3\,b^7+13\,a^5\,b^5+18\,a^7\,b^3-16\,a^{10}\,{\mathrm {e}}^x+24\,a^2\,b^5\,\sqrt {{\left (a^2+b^2\right )}^3}+18\,a^4\,b^3\,\sqrt {{\left (a^2+b^2\right )}^3}-9\,a^4\,b^6\,{\mathrm {e}}^x-33\,a^6\,b^4\,{\mathrm {e}}^x-40\,a^8\,b^2\,{\mathrm {e}}^x-41\,a^3\,b^4\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}-30\,a^5\,b^2\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}-14\,a\,b^6\,{\mathrm {e}}^x\,\sqrt {{\left (a^2+b^2\right )}^3}\right )}{a^6\,b\,\sqrt {{\left (a^2+b^2\right )}^3}\,{\left (a^2+b^2\right )}^4}-\frac {64\,\left (3\,a^2+2\,b^2\right )\,\left (-8\,{\mathrm {e}}^x\,a^3+4\,a^2\,b-7\,{\mathrm {e}}^x\,a\,b^2+4\,b^3\right )}{a^6\,b\,{\left (a^2+b^2\right )}^2}\right )\,\sqrt {{\left (a^2+b^2\right )}^3}\,\left (3\,a^2+2\,b^2\right )}{a^9+3\,a^7\,b^2+3\,a^5\,b^4+a^3\,b^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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