Optimal. Leaf size=58 \[ -\frac {2 e^{4 c (a+b x)} \sinh (a c+b c x)}{b c \left (1-e^{2 c (a+b x)}\right )^2 \sqrt {\sinh ^2(a c+b c x)}} \]
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Rubi [A]
time = 0.10, antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {6852, 2320, 12,
270} \begin {gather*} -\frac {2 e^{4 c (a+b x)} \sinh (a c+b c x)}{b c \left (1-e^{2 c (a+b x)}\right )^2 \sqrt {\sinh ^2(a c+b c x)}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 270
Rule 2320
Rule 6852
Rubi steps
\begin {align*} \int \frac {e^{c (a+b x)}}{\sinh ^2(a c+b c x)^{3/2}} \, dx &=\frac {\sinh (a c+b c x) \int e^{c (a+b x)} \text {csch}^3(a c+b c x) \, dx}{\sqrt {\sinh ^2(a c+b c x)}}\\ &=\frac {\sinh (a c+b c x) \text {Subst}\left (\int \frac {8 x^3}{\left (-1+x^2\right )^3} \, dx,x,e^{c (a+b x)}\right )}{b c \sqrt {\sinh ^2(a c+b c x)}}\\ &=\frac {(8 \sinh (a c+b c x)) \text {Subst}\left (\int \frac {x^3}{\left (-1+x^2\right )^3} \, dx,x,e^{c (a+b x)}\right )}{b c \sqrt {\sinh ^2(a c+b c x)}}\\ &=-\frac {2 e^{4 c (a+b x)} \sinh (a c+b c x)}{b c \left (1-e^{2 c (a+b x)}\right )^2 \sqrt {\sinh ^2(a c+b c x)}}\\ \end {align*}
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Mathematica [A]
time = 0.05, size = 46, normalized size = 0.79 \begin {gather*} -\frac {4 e^{5 c (a+b x)} \sqrt {\sinh ^2(c (a+b x))}}{b c \left (-1+e^{2 c (a+b x)}\right )^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 9.78, size = 69, normalized size = 1.19
method | result | size |
risch | \(-\frac {2 \left (2 \,{\mathrm e}^{2 c \left (b x +a \right )}-1\right ) {\mathrm e}^{-c \left (b x +a \right )}}{c b \sqrt {\left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right )^{2} {\mathrm e}^{-2 c \left (b x +a \right )}}\, \left ({\mathrm e}^{2 c \left (b x +a \right )}-1\right )}\) | \(69\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.48, size = 84, normalized size = 1.45 \begin {gather*} -\frac {4 \, e^{\left (2 \, b c x + 2 \, a c\right )}}{b c {\left (e^{\left (4 \, b c x + 4 \, a c\right )} - 2 \, e^{\left (2 \, b c x + 2 \, a c\right )} + 1\right )}} + \frac {2}{b c {\left (e^{\left (4 \, b c x + 4 \, a c\right )} - 2 \, e^{\left (2 \, b c x + 2 \, a c\right )} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 121 vs.
\(2 (52) = 104\).
time = 0.35, size = 121, normalized size = 2.09 \begin {gather*} -\frac {2 \, {\left (\cosh \left (b c x + a c\right ) + 3 \, \sinh \left (b c x + a c\right )\right )}}{b c \cosh \left (b c x + a c\right )^{3} + 3 \, b c \cosh \left (b c x + a c\right ) \sinh \left (b c x + a c\right )^{2} + b c \sinh \left (b c x + a c\right )^{3} - b c \cosh \left (b c x + a c\right ) + 3 \, {\left (b c \cosh \left (b c x + a c\right )^{2} - b c\right )} \sinh \left (b c x + a c\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} e^{a c} \int \frac {e^{b c x}}{\left (\sinh ^{2}{\left (a c + b c x \right )}\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.43, size = 87, normalized size = 1.50 \begin {gather*} -\frac {2 \, {\left (2 \, e^{\left (2 \, b c x + 2 \, a c\right )} \mathrm {sgn}\left (e^{\left (b c x + a c\right )} - e^{\left (-b c x - a c\right )}\right ) - \mathrm {sgn}\left (e^{\left (b c x + a c\right )} - e^{\left (-b c x - a c\right )}\right )\right )}}{b c {\left (e^{\left (2 \, b c x + 2 \, a c\right )} - 1\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.59, size = 76, normalized size = 1.31 \begin {gather*} -\frac {4\,{\mathrm {e}}^{a\,c+b\,c\,x}\,\left (2\,{\mathrm {e}}^{2\,a\,c+2\,b\,c\,x}-1\right )\,\sqrt {{\left (\frac {{\mathrm {e}}^{a\,c+b\,c\,x}}{2}-\frac {{\mathrm {e}}^{-a\,c-b\,c\,x}}{2}\right )}^2}}{b\,c\,{\left ({\mathrm {e}}^{2\,a\,c+2\,b\,c\,x}-1\right )}^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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