3.1.34 \(\int \frac {1}{\sqrt [3]{b \sinh (c+d x)}} \, dx\) [34]

Optimal. Leaf size=60 \[ \frac {3 \cosh (c+d x) \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {4}{3};-\sinh ^2(c+d x)\right ) (b \sinh (c+d x))^{2/3}}{2 b d \sqrt {\cosh ^2(c+d x)}} \]

[Out]

3/2*cosh(d*x+c)*hypergeom([1/3, 1/2],[4/3],-sinh(d*x+c)^2)*(b*sinh(d*x+c))^(2/3)/b/d/(cosh(d*x+c)^2)^(1/2)

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Rubi [A]
time = 0.01, antiderivative size = 60, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2722} \begin {gather*} \frac {3 \cosh (c+d x) (b \sinh (c+d x))^{2/3} \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {4}{3};-\sinh ^2(c+d x)\right )}{2 b d \sqrt {\cosh ^2(c+d x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*Sinh[c + d*x])^(-1/3),x]

[Out]

(3*Cosh[c + d*x]*Hypergeometric2F1[1/3, 1/2, 4/3, -Sinh[c + d*x]^2]*(b*Sinh[c + d*x])^(2/3))/(2*b*d*Sqrt[Cosh[
c + d*x]^2])

Rule 2722

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*((b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1
)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt [3]{b \sinh (c+d x)}} \, dx &=\frac {3 \cosh (c+d x) \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {4}{3};-\sinh ^2(c+d x)\right ) (b \sinh (c+d x))^{2/3}}{2 b d \sqrt {\cosh ^2(c+d x)}}\\ \end {align*}

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Mathematica [A]
time = 0.03, size = 57, normalized size = 0.95 \begin {gather*} \frac {3 \sqrt {\cosh ^2(c+d x)} \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {4}{3};-\sinh ^2(c+d x)\right ) \tanh (c+d x)}{2 d \sqrt [3]{b \sinh (c+d x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*Sinh[c + d*x])^(-1/3),x]

[Out]

(3*Sqrt[Cosh[c + d*x]^2]*Hypergeometric2F1[1/3, 1/2, 4/3, -Sinh[c + d*x]^2]*Tanh[c + d*x])/(2*d*(b*Sinh[c + d*
x])^(1/3))

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Maple [F]
time = 0.26, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (b \sinh \left (d x +c \right )\right )^{\frac {1}{3}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*sinh(d*x+c))^(1/3),x)

[Out]

int(1/(b*sinh(d*x+c))^(1/3),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(1/3),x, algorithm="maxima")

[Out]

integrate((b*sinh(d*x + c))^(-1/3), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(1/3),x, algorithm="fricas")

[Out]

integral((b*sinh(d*x + c))^(2/3)/(b*sinh(d*x + c)), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\sqrt [3]{b \sinh {\left (c + d x \right )}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))**(1/3),x)

[Out]

Integral((b*sinh(c + d*x))**(-1/3), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*sinh(d*x+c))^(1/3),x, algorithm="giac")

[Out]

integrate((b*sinh(d*x + c))^(-1/3), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {1}{{\left (b\,\mathrm {sinh}\left (c+d\,x\right )\right )}^{1/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*sinh(c + d*x))^(1/3),x)

[Out]

int(1/(b*sinh(c + d*x))^(1/3), x)

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