Optimal. Leaf size=142 \[ a \left (a^4+10 a^2 b^2+5 b^4\right ) x+\frac {b \left (5 a^4+10 a^2 b^2+b^4\right ) \log (\cosh (c+d x))}{d}-\frac {4 a b^2 \left (a^2+b^2\right ) \tanh (c+d x)}{d}-\frac {b \left (3 a^2+b^2\right ) (a+b \tanh (c+d x))^2}{2 d}-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d}-\frac {b (a+b \tanh (c+d x))^4}{4 d} \]
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Rubi [A]
time = 0.15, antiderivative size = 142, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3563, 3609,
3606, 3556} \begin {gather*} -\frac {b \left (3 a^2+b^2\right ) (a+b \tanh (c+d x))^2}{2 d}-\frac {4 a b^2 \left (a^2+b^2\right ) \tanh (c+d x)}{d}+\frac {b \left (5 a^4+10 a^2 b^2+b^4\right ) \log (\cosh (c+d x))}{d}+a x \left (a^4+10 a^2 b^2+5 b^4\right )-\frac {b (a+b \tanh (c+d x))^4}{4 d}-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 3556
Rule 3563
Rule 3606
Rule 3609
Rubi steps
\begin {align*} \int (a+b \tanh (c+d x))^5 \, dx &=-\frac {b (a+b \tanh (c+d x))^4}{4 d}+\int (a+b \tanh (c+d x))^3 \left (a^2+b^2+2 a b \tanh (c+d x)\right ) \, dx\\ &=-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d}-\frac {b (a+b \tanh (c+d x))^4}{4 d}+\int (a+b \tanh (c+d x))^2 \left (a \left (a^2+3 b^2\right )+b \left (3 a^2+b^2\right ) \tanh (c+d x)\right ) \, dx\\ &=-\frac {b \left (3 a^2+b^2\right ) (a+b \tanh (c+d x))^2}{2 d}-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d}-\frac {b (a+b \tanh (c+d x))^4}{4 d}+\int (a+b \tanh (c+d x)) \left (a^4+6 a^2 b^2+b^4+4 a b \left (a^2+b^2\right ) \tanh (c+d x)\right ) \, dx\\ &=a \left (a^4+10 a^2 b^2+5 b^4\right ) x-\frac {4 a b^2 \left (a^2+b^2\right ) \tanh (c+d x)}{d}-\frac {b \left (3 a^2+b^2\right ) (a+b \tanh (c+d x))^2}{2 d}-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d}-\frac {b (a+b \tanh (c+d x))^4}{4 d}+\left (b \left (5 a^4+10 a^2 b^2+b^4\right )\right ) \int \tanh (c+d x) \, dx\\ &=a \left (a^4+10 a^2 b^2+5 b^4\right ) x+\frac {b \left (5 a^4+10 a^2 b^2+b^4\right ) \log (\cosh (c+d x))}{d}-\frac {4 a b^2 \left (a^2+b^2\right ) \tanh (c+d x)}{d}-\frac {b \left (3 a^2+b^2\right ) (a+b \tanh (c+d x))^2}{2 d}-\frac {2 a b (a+b \tanh (c+d x))^3}{3 d}-\frac {b (a+b \tanh (c+d x))^4}{4 d}\\ \end {align*}
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Mathematica [A]
time = 0.46, size = 114, normalized size = 0.80 \begin {gather*} -\frac {6 (a+b)^5 \log (1-\tanh (c+d x))-6 (a-b)^5 \log (1+\tanh (c+d x))+60 a b^2 \left (2 a^2+b^2\right ) \tanh (c+d x)+6 b^3 \left (10 a^2+b^2\right ) \tanh ^2(c+d x)+20 a b^4 \tanh ^3(c+d x)+3 b^5 \tanh ^4(c+d x)}{12 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.27, size = 182, normalized size = 1.28
method | result | size |
derivativedivides | \(\frac {-\frac {b^{5} \left (\tanh ^{4}\left (d x +c \right )\right )}{4}-5 a^{2} b^{3} \left (\tanh ^{2}\left (d x +c \right )\right )-\frac {5 a \,b^{4} \left (\tanh ^{3}\left (d x +c \right )\right )}{3}-5 a \,b^{4} \tanh \left (d x +c \right )-10 a^{3} b^{2} \tanh \left (d x +c \right )-\frac {b^{5} \left (\tanh ^{2}\left (d x +c \right )\right )}{2}-\frac {\left (a^{5}+5 a^{4} b +10 a^{3} b^{2}+10 a^{2} b^{3}+5 a \,b^{4}+b^{5}\right ) \ln \left (\tanh \left (d x +c \right )-1\right )}{2}+\frac {\left (a^{5}-5 a^{4} b +10 a^{3} b^{2}-10 a^{2} b^{3}+5 a \,b^{4}-b^{5}\right ) \ln \left (\tanh \left (d x +c \right )+1\right )}{2}}{d}\) | \(182\) |
default | \(\frac {-\frac {b^{5} \left (\tanh ^{4}\left (d x +c \right )\right )}{4}-5 a^{2} b^{3} \left (\tanh ^{2}\left (d x +c \right )\right )-\frac {5 a \,b^{4} \left (\tanh ^{3}\left (d x +c \right )\right )}{3}-5 a \,b^{4} \tanh \left (d x +c \right )-10 a^{3} b^{2} \tanh \left (d x +c \right )-\frac {b^{5} \left (\tanh ^{2}\left (d x +c \right )\right )}{2}-\frac {\left (a^{5}+5 a^{4} b +10 a^{3} b^{2}+10 a^{2} b^{3}+5 a \,b^{4}+b^{5}\right ) \ln \left (\tanh \left (d x +c \right )-1\right )}{2}+\frac {\left (a^{5}-5 a^{4} b +10 a^{3} b^{2}-10 a^{2} b^{3}+5 a \,b^{4}-b^{5}\right ) \ln \left (\tanh \left (d x +c \right )+1\right )}{2}}{d}\) | \(182\) |
risch | \(a^{5} x -5 a^{4} x b +10 a^{3} b^{2} x -10 a^{2} b^{3} x +5 a \,b^{4} x -b^{5} x -\frac {10 b \,a^{4} c}{d}-\frac {20 b^{3} a^{2} c}{d}-\frac {2 b^{5} c}{d}+\frac {4 b^{2} \left (15 a^{3} {\mathrm e}^{6 d x +6 c}+15 a^{2} b \,{\mathrm e}^{6 d x +6 c}+15 a \,b^{2} {\mathrm e}^{6 d x +6 c}+3 b^{3} {\mathrm e}^{6 d x +6 c}+45 a^{3} {\mathrm e}^{4 d x +4 c}+30 a^{2} b \,{\mathrm e}^{4 d x +4 c}+30 a \,b^{2} {\mathrm e}^{4 d x +4 c}+3 b^{3} {\mathrm e}^{4 d x +4 c}+45 a^{3} {\mathrm e}^{2 d x +2 c}+15 a^{2} b \,{\mathrm e}^{2 d x +2 c}+25 a \,b^{2} {\mathrm e}^{2 d x +2 c}+3 b^{3} {\mathrm e}^{2 d x +2 c}+15 a^{3}+10 a \,b^{2}\right )}{3 d \left (1+{\mathrm e}^{2 d x +2 c}\right )^{4}}+\frac {5 b \ln \left (1+{\mathrm e}^{2 d x +2 c}\right ) a^{4}}{d}+\frac {10 b^{3} \ln \left (1+{\mathrm e}^{2 d x +2 c}\right ) a^{2}}{d}+\frac {b^{5} \ln \left (1+{\mathrm e}^{2 d x +2 c}\right )}{d}\) | \(346\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 310 vs.
\(2 (136) = 272\).
time = 0.48, size = 310, normalized size = 2.18 \begin {gather*} \frac {5}{3} \, a b^{4} {\left (3 \, x + \frac {3 \, c}{d} - \frac {4 \, {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + 2\right )}}{d {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} + b^{5} {\left (x + \frac {c}{d} + \frac {\log \left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}{d} + \frac {4 \, {\left (e^{\left (-2 \, d x - 2 \, c\right )} + e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )}\right )}}{d {\left (4 \, e^{\left (-2 \, d x - 2 \, c\right )} + 6 \, e^{\left (-4 \, d x - 4 \, c\right )} + 4 \, e^{\left (-6 \, d x - 6 \, c\right )} + e^{\left (-8 \, d x - 8 \, c\right )} + 1\right )}}\right )} + 10 \, a^{2} b^{3} {\left (x + \frac {c}{d} + \frac {\log \left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}{d} + \frac {2 \, e^{\left (-2 \, d x - 2 \, c\right )}}{d {\left (2 \, e^{\left (-2 \, d x - 2 \, c\right )} + e^{\left (-4 \, d x - 4 \, c\right )} + 1\right )}}\right )} + 10 \, a^{3} b^{2} {\left (x + \frac {c}{d} - \frac {2}{d {\left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}}\right )} + a^{5} x + \frac {5 \, a^{4} b \log \left (\cosh \left (d x + c\right )\right )}{d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 2739 vs.
\(2 (136) = 272\).
time = 0.65, size = 2739, normalized size = 19.29 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.16, size = 211, normalized size = 1.49 \begin {gather*} \begin {cases} a^{5} x + 5 a^{4} b x - \frac {5 a^{4} b \log {\left (\tanh {\left (c + d x \right )} + 1 \right )}}{d} + 10 a^{3} b^{2} x - \frac {10 a^{3} b^{2} \tanh {\left (c + d x \right )}}{d} + 10 a^{2} b^{3} x - \frac {10 a^{2} b^{3} \log {\left (\tanh {\left (c + d x \right )} + 1 \right )}}{d} - \frac {5 a^{2} b^{3} \tanh ^{2}{\left (c + d x \right )}}{d} + 5 a b^{4} x - \frac {5 a b^{4} \tanh ^{3}{\left (c + d x \right )}}{3 d} - \frac {5 a b^{4} \tanh {\left (c + d x \right )}}{d} + b^{5} x - \frac {b^{5} \log {\left (\tanh {\left (c + d x \right )} + 1 \right )}}{d} - \frac {b^{5} \tanh ^{4}{\left (c + d x \right )}}{4 d} - \frac {b^{5} \tanh ^{2}{\left (c + d x \right )}}{2 d} & \text {for}\: d \neq 0 \\x \left (a + b \tanh {\left (c \right )}\right )^{5} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.43, size = 224, normalized size = 1.58 \begin {gather*} \frac {3 \, {\left (a^{5} - 5 \, a^{4} b + 10 \, a^{3} b^{2} - 10 \, a^{2} b^{3} + 5 \, a b^{4} - b^{5}\right )} {\left (d x + c\right )} + 3 \, {\left (5 \, a^{4} b + 10 \, a^{2} b^{3} + b^{5}\right )} \log \left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right ) + \frac {4 \, {\left (15 \, a^{3} b^{2} + 10 \, a b^{4} + 3 \, {\left (5 \, a^{3} b^{2} + 5 \, a^{2} b^{3} + 5 \, a b^{4} + b^{5}\right )} e^{\left (6 \, d x + 6 \, c\right )} + 3 \, {\left (15 \, a^{3} b^{2} + 10 \, a^{2} b^{3} + 10 \, a b^{4} + b^{5}\right )} e^{\left (4 \, d x + 4 \, c\right )} + {\left (45 \, a^{3} b^{2} + 15 \, a^{2} b^{3} + 25 \, a b^{4} + 3 \, b^{5}\right )} e^{\left (2 \, d x + 2 \, c\right )}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{4}}}{3 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.16, size = 153, normalized size = 1.08 \begin {gather*} x\,\left (a^5+5\,a^4\,b+10\,a^3\,b^2+10\,a^2\,b^3+5\,a\,b^4+b^5\right )-\frac {5\,\mathrm {tanh}\left (c+d\,x\right )\,\left (2\,a^3\,b^2+a\,b^4\right )}{d}-\frac {b^5\,{\mathrm {tanh}\left (c+d\,x\right )}^4}{4\,d}-\frac {\ln \left (\mathrm {tanh}\left (c+d\,x\right )+1\right )\,\left (5\,a^4\,b+10\,a^2\,b^3+b^5\right )}{d}-\frac {{\mathrm {tanh}\left (c+d\,x\right )}^2\,\left (10\,a^2\,b^3+b^5\right )}{2\,d}-\frac {5\,a\,b^4\,{\mathrm {tanh}\left (c+d\,x\right )}^3}{3\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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