3.1.50 \(\int (b \coth ^m(c+d x))^n \, dx\) [50]

Optimal. Leaf size=57 \[ \frac {\coth (c+d x) \left (b \coth ^m(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (1+m n);\frac {1}{2} (3+m n);\coth ^2(c+d x)\right )}{d (1+m n)} \]

[Out]

coth(d*x+c)*(b*coth(d*x+c)^m)^n*hypergeom([1, 1/2*m*n+1/2],[1/2*m*n+3/2],coth(d*x+c)^2)/d/(m*n+1)

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Rubi [A]
time = 0.03, antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3740, 3557, 371} \begin {gather*} \frac {\coth (c+d x) \left (b \coth ^m(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (m n+1);\frac {1}{2} (m n+3);\coth ^2(c+d x)\right )}{d (m n+1)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*Coth[c + d*x]^m)^n,x]

[Out]

(Coth[c + d*x]*(b*Coth[c + d*x]^m)^n*Hypergeometric2F1[1, (1 + m*n)/2, (3 + m*n)/2, Coth[c + d*x]^2])/(d*(1 +
m*n))

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 3557

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[b/d, Subst[Int[x^n/(b^2 + x^2), x], x, b*Tan[c + d
*x]], x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 3740

Int[(u_.)*((b_.)*((c_.)*tan[(e_.) + (f_.)*(x_)])^(n_))^(p_), x_Symbol] :> Dist[b^IntPart[p]*((b*(c*Tan[e + f*x
])^n)^FracPart[p]/(c*Tan[e + f*x])^(n*FracPart[p])), Int[ActivateTrig[u]*(c*Tan[e + f*x])^(n*p), x], x] /; Fre
eQ[{b, c, e, f, n, p}, x] &&  !IntegerQ[p] &&  !IntegerQ[n] && (EqQ[u, 1] || MatchQ[u, ((d_.)*(trig_)[e + f*x]
)^(m_.) /; FreeQ[{d, m}, x] && MemberQ[{sin, cos, tan, cot, sec, csc}, trig]])

Rubi steps

\begin {align*} \int \left (b \coth ^m(c+d x)\right )^n \, dx &=\left (\coth ^{-m n}(c+d x) \left (b \coth ^m(c+d x)\right )^n\right ) \int \coth ^{m n}(c+d x) \, dx\\ &=-\frac {\left (\coth ^{-m n}(c+d x) \left (b \coth ^m(c+d x)\right )^n\right ) \text {Subst}\left (\int \frac {x^{m n}}{-1+x^2} \, dx,x,\coth (c+d x)\right )}{d}\\ &=\frac {\coth (c+d x) \left (b \coth ^m(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (1+m n);\frac {1}{2} (3+m n);\coth ^2(c+d x)\right )}{d (1+m n)}\\ \end {align*}

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Mathematica [A]
time = 0.04, size = 55, normalized size = 0.96 \begin {gather*} \frac {\coth (c+d x) \left (b \coth ^m(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (1+m n);\frac {1}{2} (3+m n);\coth ^2(c+d x)\right )}{d+d m n} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*Coth[c + d*x]^m)^n,x]

[Out]

(Coth[c + d*x]*(b*Coth[c + d*x]^m)^n*Hypergeometric2F1[1, (1 + m*n)/2, (3 + m*n)/2, Coth[c + d*x]^2])/(d + d*m
*n)

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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \left (b \left (\coth ^{m}\left (d x +c \right )\right )\right )^{n}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*coth(d*x+c)^m)^n,x)

[Out]

int((b*coth(d*x+c)^m)^n,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^m)^n,x, algorithm="maxima")

[Out]

integrate((b*coth(d*x + c)^m)^n, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^m)^n,x, algorithm="fricas")

[Out]

integral((b*coth(d*x + c)^m)^n, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (b \coth ^{m}{\left (c + d x \right )}\right )^{n}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)**m)**n,x)

[Out]

Integral((b*coth(c + d*x)**m)**n, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^m)^n,x, algorithm="giac")

[Out]

integrate((b*coth(d*x + c)^m)^n, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int {\left (b\,{\mathrm {coth}\left (c+d\,x\right )}^m\right )}^n \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*coth(c + d*x)^m)^n,x)

[Out]

int((b*coth(c + d*x)^m)^n, x)

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