3.1.61 \(\int \frac {\sinh ^3(x)}{a+b \text {sech}(x)} \, dx\) [61]

Optimal. Leaf size=61 \[ -\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}-\frac {b \cosh ^2(x)}{2 a^2}+\frac {\cosh ^3(x)}{3 a}+\frac {b \left (a^2-b^2\right ) \log (b+a \cosh (x))}{a^4} \]

[Out]

-(a^2-b^2)*cosh(x)/a^3-1/2*b*cosh(x)^2/a^2+1/3*cosh(x)^3/a+b*(a^2-b^2)*ln(b+a*cosh(x))/a^4

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Rubi [A]
time = 0.12, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {3957, 2916, 12, 786} \begin {gather*} -\frac {b \cosh ^2(x)}{2 a^2}+\frac {b \left (a^2-b^2\right ) \log (a \cosh (x)+b)}{a^4}-\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}+\frac {\cosh ^3(x)}{3 a} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Sinh[x]^3/(a + b*Sech[x]),x]

[Out]

-(((a^2 - b^2)*Cosh[x])/a^3) - (b*Cosh[x]^2)/(2*a^2) + Cosh[x]^3/(3*a) + (b*(a^2 - b^2)*Log[b + a*Cosh[x]])/a^
4

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 786

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegr
and[(d + e*x)^m*(f + g*x)*(a + c*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, m}, x] && IGtQ[p, 0]

Rule 2916

Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)
*(x_)])^(n_.), x_Symbol] :> Dist[1/(b^p*f), Subst[Int[(a + x)^m*(c + (d/b)*x)^n*(b^2 - x^2)^((p - 1)/2), x], x
, b*Sin[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IntegerQ[(p - 1)/2] && NeQ[a^2 - b^2, 0]

Rule 3957

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_.)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.), x_Symbol] :> Int[(g*Co
s[e + f*x])^p*((b + a*Sin[e + f*x])^m/Sin[e + f*x]^m), x] /; FreeQ[{a, b, e, f, g, p}, x] && IntegerQ[m]

Rubi steps

\begin {align*} \int \frac {\sinh ^3(x)}{a+b \text {sech}(x)} \, dx &=-\int \frac {\cosh (x) \sinh ^3(x)}{-b-a \cosh (x)} \, dx\\ &=\frac {\text {Subst}\left (\int \frac {x \left (a^2-x^2\right )}{a (-b+x)} \, dx,x,-a \cosh (x)\right )}{a^3}\\ &=\frac {\text {Subst}\left (\int \frac {x \left (a^2-x^2\right )}{-b+x} \, dx,x,-a \cosh (x)\right )}{a^4}\\ &=\frac {\text {Subst}\left (\int \left (a^2 \left (1-\frac {b^2}{a^2}\right )+\frac {-a^2 b+b^3}{b-x}-b x-x^2\right ) \, dx,x,-a \cosh (x)\right )}{a^4}\\ &=-\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}-\frac {b \cosh ^2(x)}{2 a^2}+\frac {\cosh ^3(x)}{3 a}+\frac {b \left (a^2-b^2\right ) \log (b+a \cosh (x))}{a^4}\\ \end {align*}

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Mathematica [A]
time = 0.09, size = 66, normalized size = 1.08 \begin {gather*} \frac {\left (-9 a^3+12 a b^2\right ) \cosh (x)-3 a^2 b \cosh (2 x)+a^3 \cosh (3 x)+12 a^2 b \log (b+a \cosh (x))-12 b^3 \log (b+a \cosh (x))}{12 a^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Sinh[x]^3/(a + b*Sech[x]),x]

[Out]

((-9*a^3 + 12*a*b^2)*Cosh[x] - 3*a^2*b*Cosh[2*x] + a^3*Cosh[3*x] + 12*a^2*b*Log[b + a*Cosh[x]] - 12*b^3*Log[b
+ a*Cosh[x]])/(12*a^4)

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(208\) vs. \(2(57)=114\).
time = 0.66, size = 209, normalized size = 3.43

method	result	size
risch	\(-\frac {b x}{a^{2}}+\frac {x \,b^{3}}{a^{4}}+\frac {{\mathrm e}^{3 x}}{24 a}-\frac {b \,{\mathrm e}^{2 x}}{8 a^{2}}-\frac {3 \,{\mathrm e}^{x}}{8 a}+\frac {{\mathrm e}^{x} b^{2}}{2 a^{3}}-\frac {3 \,{\mathrm e}^{-x}}{8 a}+\frac {{\mathrm e}^{-x} b^{2}}{2 a^{3}}-\frac {b \,{\mathrm e}^{-2 x}}{8 a^{2}}+\frac {{\mathrm e}^{-3 x}}{24 a}+\frac {b \ln \left ({\mathrm e}^{2 x}+\frac {2 b \,{\mathrm e}^{x}}{a}+1\right )}{a^{2}}-\frac {b^{3} \ln \left ({\mathrm e}^{2 x}+\frac {2 b \,{\mathrm e}^{x}}{a}+1\right )}{a^{4}}\)	\(136\)
default	\(\frac {b \left (a^{3}-a^{2} b -a \,b^{2}+b^{3}\right ) \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-b \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )+a +b \right )}{a^{4} \left (a -b \right )}-\frac {-a^{2}+a b +2 b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {a +b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}-\frac {1}{3 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{3}}-\frac {b \left (a^{2}-b^{2}\right ) \ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{a^{4}}-\frac {a +b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}-\frac {a^{2}-a b -2 b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )+1\right )}+\frac {1}{3 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{3}}-\frac {b \left (a^{2}-b^{2}\right ) \ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{a^{4}}\)	\(209\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinh(x)^3/(a+b*sech(x)),x,method=_RETURNVERBOSE)

[Out]

b*(a^3-a^2*b-a*b^2+b^3)/a^4/(a-b)*ln(a*tanh(1/2*x)^2-b*tanh(1/2*x)^2+a+b)-1/2*(-a^2+a*b+2*b^2)/a^3/(tanh(1/2*x
)-1)-1/2*(a+b)/a^2/(tanh(1/2*x)-1)^2-1/3/a/(tanh(1/2*x)-1)^3-b*(a^2-b^2)/a^4*ln(tanh(1/2*x)-1)-1/2*(a+b)/a^2/(
tanh(1/2*x)+1)^2-1/2*(a^2-a*b-2*b^2)/a^3/(tanh(1/2*x)+1)+1/3/a/(tanh(1/2*x)+1)^3-b*(a^2-b^2)/a^4*ln(tanh(1/2*x
)+1)

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 128 vs. \(2 (57) = 114\).
time = 0.27, size = 128, normalized size = 2.10 \begin {gather*} -\frac {{\left (3 \, a b e^{\left (-x\right )} - a^{2} + 3 \, {\left (3 \, a^{2} - 4 \, b^{2}\right )} e^{\left (-2 \, x\right )}\right )} e^{\left (3 \, x\right )}}{24 \, a^{3}} - \frac {3 \, a b e^{\left (-2 \, x\right )} - a^{2} e^{\left (-3 \, x\right )} + 3 \, {\left (3 \, a^{2} - 4 \, b^{2}\right )} e^{\left (-x\right )}}{24 \, a^{3}} + \frac {{\left (a^{2} b - b^{3}\right )} x}{a^{4}} + \frac {{\left (a^{2} b - b^{3}\right )} \log \left (2 \, b e^{\left (-x\right )} + a e^{\left (-2 \, x\right )} + a\right )}{a^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)^3/(a+b*sech(x)),x, algorithm="maxima")

[Out]

-1/24*(3*a*b*e^(-x) - a^2 + 3*(3*a^2 - 4*b^2)*e^(-2*x))*e^(3*x)/a^3 - 1/24*(3*a*b*e^(-2*x) - a^2*e^(-3*x) + 3*
(3*a^2 - 4*b^2)*e^(-x))/a^3 + (a^2*b - b^3)*x/a^4 + (a^2*b - b^3)*log(2*b*e^(-x) + a*e^(-2*x) + a)/a^4

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 490 vs. \(2 (57) = 114\).
time = 0.37, size = 490, normalized size = 8.03 \begin {gather*} \frac {a^{3} \cosh \left (x\right )^{6} + a^{3} \sinh \left (x\right )^{6} - 3 \, a^{2} b \cosh \left (x\right )^{5} + 3 \, {\left (2 \, a^{3} \cosh \left (x\right ) - a^{2} b\right )} \sinh \left (x\right )^{5} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \left (x\right )^{3} - 3 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )^{4} + 3 \, {\left (5 \, a^{3} \cosh \left (x\right )^{2} - 5 \, a^{2} b \cosh \left (x\right ) - 3 \, a^{3} + 4 \, a b^{2}\right )} \sinh \left (x\right )^{4} - 3 \, a^{2} b \cosh \left (x\right ) + 2 \, {\left (10 \, a^{3} \cosh \left (x\right )^{3} - 15 \, a^{2} b \cosh \left (x\right )^{2} - 12 \, {\left (a^{2} b - b^{3}\right )} x - 6 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )^{3} + a^{3} - 3 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )^{2} + 3 \, {\left (5 \, a^{3} \cosh \left (x\right )^{4} - 10 \, a^{2} b \cosh \left (x\right )^{3} - 3 \, a^{3} + 4 \, a b^{2} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \left (x\right ) - 6 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )^{2}\right )} \sinh \left (x\right )^{2} + 24 \, {\left ({\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )^{3} + 3 \, {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right )^{2} \sinh \left (x\right ) + 3 \, {\left (a^{2} b - b^{3}\right )} \cosh \left (x\right ) \sinh \left (x\right )^{2} + {\left (a^{2} b - b^{3}\right )} \sinh \left (x\right )^{3}\right )} \log \left (\frac {2 \, {\left (a \cosh \left (x\right ) + b\right )}}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) + 3 \, {\left (2 \, a^{3} \cosh \left (x\right )^{5} - 5 \, a^{2} b \cosh \left (x\right )^{4} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \left (x\right )^{2} - 4 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )^{3} - a^{2} b - 2 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )}{24 \, {\left (a^{4} \cosh \left (x\right )^{3} + 3 \, a^{4} \cosh \left (x\right )^{2} \sinh \left (x\right ) + 3 \, a^{4} \cosh \left (x\right ) \sinh \left (x\right )^{2} + a^{4} \sinh \left (x\right )^{3}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)^3/(a+b*sech(x)),x, algorithm="fricas")

[Out]

1/24*(a^3*cosh(x)^6 + a^3*sinh(x)^6 - 3*a^2*b*cosh(x)^5 + 3*(2*a^3*cosh(x) - a^2*b)*sinh(x)^5 - 24*(a^2*b - b^
3)*x*cosh(x)^3 - 3*(3*a^3 - 4*a*b^2)*cosh(x)^4 + 3*(5*a^3*cosh(x)^2 - 5*a^2*b*cosh(x) - 3*a^3 + 4*a*b^2)*sinh(
x)^4 - 3*a^2*b*cosh(x) + 2*(10*a^3*cosh(x)^3 - 15*a^2*b*cosh(x)^2 - 12*(a^2*b - b^3)*x - 6*(3*a^3 - 4*a*b^2)*c
osh(x))*sinh(x)^3 + a^3 - 3*(3*a^3 - 4*a*b^2)*cosh(x)^2 + 3*(5*a^3*cosh(x)^4 - 10*a^2*b*cosh(x)^3 - 3*a^3 + 4*
a*b^2 - 24*(a^2*b - b^3)*x*cosh(x) - 6*(3*a^3 - 4*a*b^2)*cosh(x)^2)*sinh(x)^2 + 24*((a^2*b - b^3)*cosh(x)^3 +
3*(a^2*b - b^3)*cosh(x)^2*sinh(x) + 3*(a^2*b - b^3)*cosh(x)*sinh(x)^2 + (a^2*b - b^3)*sinh(x)^3)*log(2*(a*cosh
(x) + b)/(cosh(x) - sinh(x))) + 3*(2*a^3*cosh(x)^5 - 5*a^2*b*cosh(x)^4 - 24*(a^2*b - b^3)*x*cosh(x)^2 - 4*(3*a
^3 - 4*a*b^2)*cosh(x)^3 - a^2*b - 2*(3*a^3 - 4*a*b^2)*cosh(x))*sinh(x))/(a^4*cosh(x)^3 + 3*a^4*cosh(x)^2*sinh(
x) + 3*a^4*cosh(x)*sinh(x)^2 + a^4*sinh(x)^3)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sinh ^{3}{\left (x \right )}}{a + b \operatorname {sech}{\left (x \right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)**3/(a+b*sech(x)),x)

[Out]

Integral(sinh(x)**3/(a + b*sech(x)), x)

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Giac [A]
time = 0.39, size = 87, normalized size = 1.43 \begin {gather*} \frac {a^{2} {\left (e^{\left (-x\right )} + e^{x}\right )}^{3} - 3 \, a b {\left (e^{\left (-x\right )} + e^{x}\right )}^{2} - 12 \, a^{2} {\left (e^{\left (-x\right )} + e^{x}\right )} + 12 \, b^{2} {\left (e^{\left (-x\right )} + e^{x}\right )}}{24 \, a^{3}} + \frac {{\left (a^{2} b - b^{3}\right )} \log \left ({\left | a {\left (e^{\left (-x\right )} + e^{x}\right )} + 2 \, b \right |}\right )}{a^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)^3/(a+b*sech(x)),x, algorithm="giac")

[Out]

1/24*(a^2*(e^(-x) + e^x)^3 - 3*a*b*(e^(-x) + e^x)^2 - 12*a^2*(e^(-x) + e^x) + 12*b^2*(e^(-x) + e^x))/a^3 + (a^
2*b - b^3)*log(abs(a*(e^(-x) + e^x) + 2*b))/a^4

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Mupad [B]
time = 1.60, size = 123, normalized size = 2.02 \begin {gather*} \frac {{\mathrm {e}}^{-3\,x}}{24\,a}+\frac {{\mathrm {e}}^{3\,x}}{24\,a}-\frac {x\,\left (a^2\,b-b^3\right )}{a^4}-\frac {{\mathrm {e}}^x\,\left (3\,a^2-4\,b^2\right )}{8\,a^3}-\frac {b\,{\mathrm {e}}^{-2\,x}}{8\,a^2}-\frac {b\,{\mathrm {e}}^{2\,x}}{8\,a^2}+\frac {\ln \left (a+2\,b\,{\mathrm {e}}^x+a\,{\mathrm {e}}^{2\,x}\right )\,\left (a^2\,b-b^3\right )}{a^4}-\frac {{\mathrm {e}}^{-x}\,\left (3\,a^2-4\,b^2\right )}{8\,a^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinh(x)^3/(a + b/cosh(x)),x)

[Out]

exp(-3*x)/(24*a) + exp(3*x)/(24*a) - (x*(a^2*b - b^3))/a^4 - (exp(x)*(3*a^2 - 4*b^2))/(8*a^3) - (b*exp(-2*x))/
(8*a^2) - (b*exp(2*x))/(8*a^2) + (log(a + 2*b*exp(x) + a*exp(2*x))*(a^2*b - b^3))/a^4 - (exp(-x)*(3*a^2 - 4*b^
2))/(8*a^3)

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