Optimal. Leaf size=89 \[ \frac {1}{2} b \cosh (2 a) \text {Chi}(2 b x)+\frac {1}{2} b \cosh (4 a) \text {Chi}(4 b x)-\frac {\sinh (2 a+2 b x)}{4 x}-\frac {\sinh (4 a+4 b x)}{8 x}+\frac {1}{2} b \sinh (2 a) \text {Shi}(2 b x)+\frac {1}{2} b \sinh (4 a) \text {Shi}(4 b x) \]
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Rubi [A]
time = 0.14, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 5, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {5556, 3378,
3384, 3379, 3382} \begin {gather*} \frac {1}{2} b \cosh (2 a) \text {Chi}(2 b x)+\frac {1}{2} b \cosh (4 a) \text {Chi}(4 b x)+\frac {1}{2} b \sinh (2 a) \text {Shi}(2 b x)+\frac {1}{2} b \sinh (4 a) \text {Shi}(4 b x)-\frac {\sinh (2 a+2 b x)}{4 x}-\frac {\sinh (4 a+4 b x)}{8 x} \end {gather*}
Antiderivative was successfully verified.
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Rule 3378
Rule 3379
Rule 3382
Rule 3384
Rule 5556
Rubi steps
\begin {align*} \int \frac {\cosh ^3(a+b x) \sinh (a+b x)}{x^2} \, dx &=\int \left (\frac {\sinh (2 a+2 b x)}{4 x^2}+\frac {\sinh (4 a+4 b x)}{8 x^2}\right ) \, dx\\ &=\frac {1}{8} \int \frac {\sinh (4 a+4 b x)}{x^2} \, dx+\frac {1}{4} \int \frac {\sinh (2 a+2 b x)}{x^2} \, dx\\ &=-\frac {\sinh (2 a+2 b x)}{4 x}-\frac {\sinh (4 a+4 b x)}{8 x}+\frac {1}{2} b \int \frac {\cosh (2 a+2 b x)}{x} \, dx+\frac {1}{2} b \int \frac {\cosh (4 a+4 b x)}{x} \, dx\\ &=-\frac {\sinh (2 a+2 b x)}{4 x}-\frac {\sinh (4 a+4 b x)}{8 x}+\frac {1}{2} (b \cosh (2 a)) \int \frac {\cosh (2 b x)}{x} \, dx+\frac {1}{2} (b \cosh (4 a)) \int \frac {\cosh (4 b x)}{x} \, dx+\frac {1}{2} (b \sinh (2 a)) \int \frac {\sinh (2 b x)}{x} \, dx+\frac {1}{2} (b \sinh (4 a)) \int \frac {\sinh (4 b x)}{x} \, dx\\ &=\frac {1}{2} b \cosh (2 a) \text {Chi}(2 b x)+\frac {1}{2} b \cosh (4 a) \text {Chi}(4 b x)-\frac {\sinh (2 a+2 b x)}{4 x}-\frac {\sinh (4 a+4 b x)}{8 x}+\frac {1}{2} b \sinh (2 a) \text {Shi}(2 b x)+\frac {1}{2} b \sinh (4 a) \text {Shi}(4 b x)\\ \end {align*}
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Mathematica [A]
time = 0.14, size = 80, normalized size = 0.90 \begin {gather*} \frac {4 b x \cosh (2 a) \text {Chi}(2 b x)+4 b x \cosh (4 a) \text {Chi}(4 b x)-2 \sinh (2 (a+b x))-\sinh (4 (a+b x))+4 b x \sinh (2 a) \text {Shi}(2 b x)+4 b x \sinh (4 a) \text {Shi}(4 b x)}{8 x} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 4.75, size = 110, normalized size = 1.24
method | result | size |
risch | \(\frac {{\mathrm e}^{-4 b x -4 a}}{16 x}-\frac {b \,{\mathrm e}^{-4 a} \expIntegral \left (1, 4 b x \right )}{4}+\frac {{\mathrm e}^{-2 b x -2 a}}{8 x}-\frac {b \,{\mathrm e}^{-2 a} \expIntegral \left (1, 2 b x \right )}{4}-\frac {{\mathrm e}^{2 b x +2 a}}{8 x}-\frac {b \,{\mathrm e}^{2 a} \expIntegral \left (1, -2 b x \right )}{4}-\frac {{\mathrm e}^{4 b x +4 a}}{16 x}-\frac {b \,{\mathrm e}^{4 a} \expIntegral \left (1, -4 b x \right )}{4}\) | \(110\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.32, size = 53, normalized size = 0.60 \begin {gather*} \frac {1}{4} \, b e^{\left (-4 \, a\right )} \Gamma \left (-1, 4 \, b x\right ) + \frac {1}{4} \, b e^{\left (-2 \, a\right )} \Gamma \left (-1, 2 \, b x\right ) + \frac {1}{4} \, b e^{\left (2 \, a\right )} \Gamma \left (-1, -2 \, b x\right ) + \frac {1}{4} \, b e^{\left (4 \, a\right )} \Gamma \left (-1, -4 \, b x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.44, size = 139, normalized size = 1.56 \begin {gather*} -\frac {2 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{3} - {\left (b x {\rm Ei}\left (4 \, b x\right ) + b x {\rm Ei}\left (-4 \, b x\right )\right )} \cosh \left (4 \, a\right ) - {\left (b x {\rm Ei}\left (2 \, b x\right ) + b x {\rm Ei}\left (-2 \, b x\right )\right )} \cosh \left (2 \, a\right ) + 2 \, {\left (\cosh \left (b x + a\right )^{3} + \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right ) - {\left (b x {\rm Ei}\left (4 \, b x\right ) - b x {\rm Ei}\left (-4 \, b x\right )\right )} \sinh \left (4 \, a\right ) - {\left (b x {\rm Ei}\left (2 \, b x\right ) - b x {\rm Ei}\left (-2 \, b x\right )\right )} \sinh \left (2 \, a\right )}{4 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sinh {\left (a + b x \right )} \cosh ^{3}{\left (a + b x \right )}}{x^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.39, size = 100, normalized size = 1.12 \begin {gather*} \frac {4 \, b x {\rm Ei}\left (4 \, b x\right ) e^{\left (4 \, a\right )} + 4 \, b x {\rm Ei}\left (2 \, b x\right ) e^{\left (2 \, a\right )} + 4 \, b x {\rm Ei}\left (-2 \, b x\right ) e^{\left (-2 \, a\right )} + 4 \, b x {\rm Ei}\left (-4 \, b x\right ) e^{\left (-4 \, a\right )} - e^{\left (4 \, b x + 4 \, a\right )} - 2 \, e^{\left (2 \, b x + 2 \, a\right )} + 2 \, e^{\left (-2 \, b x - 2 \, a\right )} + e^{\left (-4 \, b x - 4 \, a\right )}}{16 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\mathrm {cosh}\left (a+b\,x\right )}^3\,\mathrm {sinh}\left (a+b\,x\right )}{x^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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