Optimal. Leaf size=195 \[ -\frac {2 x^3 \text {ArcTan}\left (e^{a+b x}\right )}{b}-\frac {6 \cosh (a+b x)}{b^4}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {3 i x^2 \text {PolyLog}\left (2,-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {PolyLog}\left (2,i e^{a+b x}\right )}{b^2}-\frac {6 i x \text {PolyLog}\left (3,-i e^{a+b x}\right )}{b^3}+\frac {6 i x \text {PolyLog}\left (3,i e^{a+b x}\right )}{b^3}+\frac {6 i \text {PolyLog}\left (4,-i e^{a+b x}\right )}{b^4}-\frac {6 i \text {PolyLog}\left (4,i e^{a+b x}\right )}{b^4}+\frac {6 x \sinh (a+b x)}{b^3}+\frac {x^3 \sinh (a+b x)}{b} \]
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Rubi [A]
time = 0.15, antiderivative size = 195, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 8, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5557, 3377,
2718, 4265, 2611, 6744, 2320, 6724} \begin {gather*} -\frac {2 x^3 \text {ArcTan}\left (e^{a+b x}\right )}{b}+\frac {6 i \text {Li}_4\left (-i e^{a+b x}\right )}{b^4}-\frac {6 i \text {Li}_4\left (i e^{a+b x}\right )}{b^4}-\frac {6 \cosh (a+b x)}{b^4}-\frac {6 i x \text {Li}_3\left (-i e^{a+b x}\right )}{b^3}+\frac {6 i x \text {Li}_3\left (i e^{a+b x}\right )}{b^3}+\frac {6 x \sinh (a+b x)}{b^3}+\frac {3 i x^2 \text {Li}_2\left (-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {Li}_2\left (i e^{a+b x}\right )}{b^2}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {x^3 \sinh (a+b x)}{b} \end {gather*}
Antiderivative was successfully verified.
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Rule 2320
Rule 2611
Rule 2718
Rule 3377
Rule 4265
Rule 5557
Rule 6724
Rule 6744
Rubi steps
\begin {align*} \int x^3 \sinh (a+b x) \tanh (a+b x) \, dx &=\int x^3 \cosh (a+b x) \, dx-\int x^3 \text {sech}(a+b x) \, dx\\ &=-\frac {2 x^3 \tan ^{-1}\left (e^{a+b x}\right )}{b}+\frac {x^3 \sinh (a+b x)}{b}+\frac {(3 i) \int x^2 \log \left (1-i e^{a+b x}\right ) \, dx}{b}-\frac {(3 i) \int x^2 \log \left (1+i e^{a+b x}\right ) \, dx}{b}-\frac {3 \int x^2 \sinh (a+b x) \, dx}{b}\\ &=-\frac {2 x^3 \tan ^{-1}\left (e^{a+b x}\right )}{b}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {3 i x^2 \text {Li}_2\left (-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {Li}_2\left (i e^{a+b x}\right )}{b^2}+\frac {x^3 \sinh (a+b x)}{b}-\frac {(6 i) \int x \text {Li}_2\left (-i e^{a+b x}\right ) \, dx}{b^2}+\frac {(6 i) \int x \text {Li}_2\left (i e^{a+b x}\right ) \, dx}{b^2}+\frac {6 \int x \cosh (a+b x) \, dx}{b^2}\\ &=-\frac {2 x^3 \tan ^{-1}\left (e^{a+b x}\right )}{b}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {3 i x^2 \text {Li}_2\left (-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {Li}_2\left (i e^{a+b x}\right )}{b^2}-\frac {6 i x \text {Li}_3\left (-i e^{a+b x}\right )}{b^3}+\frac {6 i x \text {Li}_3\left (i e^{a+b x}\right )}{b^3}+\frac {6 x \sinh (a+b x)}{b^3}+\frac {x^3 \sinh (a+b x)}{b}+\frac {(6 i) \int \text {Li}_3\left (-i e^{a+b x}\right ) \, dx}{b^3}-\frac {(6 i) \int \text {Li}_3\left (i e^{a+b x}\right ) \, dx}{b^3}-\frac {6 \int \sinh (a+b x) \, dx}{b^3}\\ &=-\frac {2 x^3 \tan ^{-1}\left (e^{a+b x}\right )}{b}-\frac {6 \cosh (a+b x)}{b^4}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {3 i x^2 \text {Li}_2\left (-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {Li}_2\left (i e^{a+b x}\right )}{b^2}-\frac {6 i x \text {Li}_3\left (-i e^{a+b x}\right )}{b^3}+\frac {6 i x \text {Li}_3\left (i e^{a+b x}\right )}{b^3}+\frac {6 x \sinh (a+b x)}{b^3}+\frac {x^3 \sinh (a+b x)}{b}+\frac {(6 i) \text {Subst}\left (\int \frac {\text {Li}_3(-i x)}{x} \, dx,x,e^{a+b x}\right )}{b^4}-\frac {(6 i) \text {Subst}\left (\int \frac {\text {Li}_3(i x)}{x} \, dx,x,e^{a+b x}\right )}{b^4}\\ &=-\frac {2 x^3 \tan ^{-1}\left (e^{a+b x}\right )}{b}-\frac {6 \cosh (a+b x)}{b^4}-\frac {3 x^2 \cosh (a+b x)}{b^2}+\frac {3 i x^2 \text {Li}_2\left (-i e^{a+b x}\right )}{b^2}-\frac {3 i x^2 \text {Li}_2\left (i e^{a+b x}\right )}{b^2}-\frac {6 i x \text {Li}_3\left (-i e^{a+b x}\right )}{b^3}+\frac {6 i x \text {Li}_3\left (i e^{a+b x}\right )}{b^3}+\frac {6 i \text {Li}_4\left (-i e^{a+b x}\right )}{b^4}-\frac {6 i \text {Li}_4\left (i e^{a+b x}\right )}{b^4}+\frac {6 x \sinh (a+b x)}{b^3}+\frac {x^3 \sinh (a+b x)}{b}\\ \end {align*}
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Mathematica [A]
time = 1.02, size = 211, normalized size = 1.08 \begin {gather*} -\frac {i \left (-6 i \cosh (a+b x)-3 i b^2 x^2 \cosh (a+b x)+b^3 x^3 \log \left (1-i e^{a+b x}\right )-b^3 x^3 \log \left (1+i e^{a+b x}\right )-3 b^2 x^2 \text {PolyLog}\left (2,-i e^{a+b x}\right )+3 b^2 x^2 \text {PolyLog}\left (2,i e^{a+b x}\right )+6 b x \text {PolyLog}\left (3,-i e^{a+b x}\right )-6 b x \text {PolyLog}\left (3,i e^{a+b x}\right )-6 \text {PolyLog}\left (4,-i e^{a+b x}\right )+6 \text {PolyLog}\left (4,i e^{a+b x}\right )+6 i b x \sinh (a+b x)+i b^3 x^3 \sinh (a+b x)\right )}{b^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 1.41, size = 0, normalized size = 0.00 \[\int x^{3} \mathrm {sech}\left (b x +a \right ) \left (\sinh ^{2}\left (b x +a \right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 609 vs. \(2 (162) = 324\).
time = 0.38, size = 609, normalized size = 3.12 \begin {gather*} -\frac {b^{3} x^{3} + 3 \, b^{2} x^{2} - {\left (b^{3} x^{3} - 3 \, b^{2} x^{2} + 6 \, b x - 6\right )} \cosh \left (b x + a\right )^{2} - 2 \, {\left (b^{3} x^{3} - 3 \, b^{2} x^{2} + 6 \, b x - 6\right )} \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) - {\left (b^{3} x^{3} - 3 \, b^{2} x^{2} + 6 \, b x - 6\right )} \sinh \left (b x + a\right )^{2} + 6 \, b x + 6 \, {\left (i \, b^{2} x^{2} \cosh \left (b x + a\right ) + i \, b^{2} x^{2} \sinh \left (b x + a\right )\right )} {\rm Li}_2\left (i \, \cosh \left (b x + a\right ) + i \, \sinh \left (b x + a\right )\right ) + 6 \, {\left (-i \, b^{2} x^{2} \cosh \left (b x + a\right ) - i \, b^{2} x^{2} \sinh \left (b x + a\right )\right )} {\rm Li}_2\left (-i \, \cosh \left (b x + a\right ) - i \, \sinh \left (b x + a\right )\right ) + 2 \, {\left (-i \, a^{3} \cosh \left (b x + a\right ) - i \, a^{3} \sinh \left (b x + a\right )\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) + i\right ) + 2 \, {\left (i \, a^{3} \cosh \left (b x + a\right ) + i \, a^{3} \sinh \left (b x + a\right )\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) - i\right ) + 2 \, {\left ({\left (-i \, b^{3} x^{3} - i \, a^{3}\right )} \cosh \left (b x + a\right ) + {\left (-i \, b^{3} x^{3} - i \, a^{3}\right )} \sinh \left (b x + a\right )\right )} \log \left (i \, \cosh \left (b x + a\right ) + i \, \sinh \left (b x + a\right ) + 1\right ) + 2 \, {\left ({\left (i \, b^{3} x^{3} + i \, a^{3}\right )} \cosh \left (b x + a\right ) + {\left (i \, b^{3} x^{3} + i \, a^{3}\right )} \sinh \left (b x + a\right )\right )} \log \left (-i \, \cosh \left (b x + a\right ) - i \, \sinh \left (b x + a\right ) + 1\right ) + 12 \, {\left (i \, \cosh \left (b x + a\right ) + i \, \sinh \left (b x + a\right )\right )} {\rm polylog}\left (4, i \, \cosh \left (b x + a\right ) + i \, \sinh \left (b x + a\right )\right ) + 12 \, {\left (-i \, \cosh \left (b x + a\right ) - i \, \sinh \left (b x + a\right )\right )} {\rm polylog}\left (4, -i \, \cosh \left (b x + a\right ) - i \, \sinh \left (b x + a\right )\right ) + 12 \, {\left (-i \, b x \cosh \left (b x + a\right ) - i \, b x \sinh \left (b x + a\right )\right )} {\rm polylog}\left (3, i \, \cosh \left (b x + a\right ) + i \, \sinh \left (b x + a\right )\right ) + 12 \, {\left (i \, b x \cosh \left (b x + a\right ) + i \, b x \sinh \left (b x + a\right )\right )} {\rm polylog}\left (3, -i \, \cosh \left (b x + a\right ) - i \, \sinh \left (b x + a\right )\right ) + 6}{2 \, {\left (b^{4} \cosh \left (b x + a\right ) + b^{4} \sinh \left (b x + a\right )\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{3} \sinh ^{2}{\left (a + b x \right )} \operatorname {sech}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^3\,{\mathrm {sinh}\left (a+b\,x\right )}^2}{\mathrm {cosh}\left (a+b\,x\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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