3.6.12 \(\int \frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x} \, dx\) [512]

Optimal. Leaf size=21 \[ \text {Int}\left (\frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x},x\right ) \]

[Out]

CannotIntegrate(csch(b*x+a)^3*sech(b*x+a)/x,x)

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Rubi [A]
time = 0.21, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(Csch[a + b*x]^3*Sech[a + b*x])/x,x]

[Out]

Defer[Int][(Csch[a + b*x]^3*Sech[a + b*x])/x, x]

Rubi steps

\begin {align*} \int \frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x} \, dx &=\int \frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x} \, dx\\ \end {align*}

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Mathematica [A]
time = 34.18, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\text {csch}^3(a+b x) \text {sech}(a+b x)}{x} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(Csch[a + b*x]^3*Sech[a + b*x])/x,x]

[Out]

Integrate[(Csch[a + b*x]^3*Sech[a + b*x])/x, x]

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Maple [A]
time = 1.37, size = 0, normalized size = 0.00 \[\int \frac {\mathrm {csch}\left (b x +a \right )^{3} \mathrm {sech}\left (b x +a \right )}{x}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csch(b*x+a)^3*sech(b*x+a)/x,x)

[Out]

int(csch(b*x+a)^3*sech(b*x+a)/x,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)^3*sech(b*x+a)/x,x, algorithm="maxima")

[Out]

-((2*b*x*e^(2*a) - e^(2*a))*e^(2*b*x) + 1)/(b^2*x^2*e^(4*b*x + 4*a) - 2*b^2*x^2*e^(2*b*x + 2*a) + b^2*x^2) + 1
6*integrate(1/16*(b^2*x^2 - 1)/(b^2*x^3*e^(b*x + a) + b^2*x^3), x) - 16*integrate(1/16*(b^2*x^2 - 1)/(b^2*x^3*
e^(b*x + a) - b^2*x^3), x) - 16*integrate(1/8/(x*e^(2*b*x + 2*a) + x), x)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)^3*sech(b*x+a)/x,x, algorithm="fricas")

[Out]

integral(csch(b*x + a)^3*sech(b*x + a)/x, x)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\operatorname {csch}^{3}{\left (a + b x \right )} \operatorname {sech}{\left (a + b x \right )}}{x}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)**3*sech(b*x+a)/x,x)

[Out]

Integral(csch(a + b*x)**3*sech(a + b*x)/x, x)

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csch(b*x+a)^3*sech(b*x+a)/x,x, algorithm="giac")

[Out]

integrate(csch(b*x + a)^3*sech(b*x + a)/x, x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.05 \begin {gather*} \int \frac {1}{x\,\mathrm {cosh}\left (a+b\,x\right )\,{\mathrm {sinh}\left (a+b\,x\right )}^3} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*cosh(a + b*x)*sinh(a + b*x)^3),x)

[Out]

int(1/(x*cosh(a + b*x)*sinh(a + b*x)^3), x)

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