3.6.83 \(\int (a \cosh (x)+b \sinh (x))^4 \, dx\) [583]

Optimal. Leaf size=72 \[ \frac {3}{8} \left (a^2-b^2\right )^2 x+\frac {3}{8} \left (a^2-b^2\right ) (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))+\frac {1}{4} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^3 \]

[Out]

3/8*(a^2-b^2)^2*x+3/8*(a^2-b^2)*(b*cosh(x)+a*sinh(x))*(a*cosh(x)+b*sinh(x))+1/4*(b*cosh(x)+a*sinh(x))*(a*cosh(
x)+b*sinh(x))^3

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Rubi [A]
time = 0.03, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3152, 8} \begin {gather*} \frac {3}{8} x \left (a^2-b^2\right )^2+\frac {3}{8} \left (a^2-b^2\right ) (a \sinh (x)+b \cosh (x)) (a \cosh (x)+b \sinh (x))+\frac {1}{4} (a \sinh (x)+b \cosh (x)) (a \cosh (x)+b \sinh (x))^3 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a*Cosh[x] + b*Sinh[x])^4,x]

[Out]

(3*(a^2 - b^2)^2*x)/8 + (3*(a^2 - b^2)*(b*Cosh[x] + a*Sinh[x])*(a*Cosh[x] + b*Sinh[x]))/8 + ((b*Cosh[x] + a*Si
nh[x])*(a*Cosh[x] + b*Sinh[x])^3)/4

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 3152

Int[(cos[(c_.) + (d_.)*(x_)]*(a_.) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-(b*Cos[c + d*x]
- a*Sin[c + d*x]))*((a*Cos[c + d*x] + b*Sin[c + d*x])^(n - 1)/(d*n)), x] + Dist[(n - 1)*((a^2 + b^2)/n), Int[(
a*Cos[c + d*x] + b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 + b^2, 0] &&  !IntegerQ[
(n - 1)/2] && GtQ[n, 1]

Rubi steps

\begin {align*} \int (a \cosh (x)+b \sinh (x))^4 \, dx &=\frac {1}{4} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^3+\frac {1}{4} \left (3 \left (a^2-b^2\right )\right ) \int (a \cosh (x)+b \sinh (x))^2 \, dx\\ &=\frac {3}{8} \left (a^2-b^2\right ) (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))+\frac {1}{4} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^3+\frac {1}{8} \left (3 \left (a^2-b^2\right )^2\right ) \int 1 \, dx\\ &=\frac {3}{8} \left (a^2-b^2\right )^2 x+\frac {3}{8} \left (a^2-b^2\right ) (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))+\frac {1}{4} (b \cosh (x)+a \sinh (x)) (a \cosh (x)+b \sinh (x))^3\\ \end {align*}

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Mathematica [A]
time = 0.10, size = 87, normalized size = 1.21 \begin {gather*} \frac {1}{32} \left (12 (a-b)^2 (a+b)^2 x+16 a b \left (a^2-b^2\right ) \cosh (2 x)+4 a b \left (a^2+b^2\right ) \cosh (4 x)+8 \left (a^4-b^4\right ) \sinh (2 x)+\left (a^4+6 a^2 b^2+b^4\right ) \sinh (4 x)\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a*Cosh[x] + b*Sinh[x])^4,x]

[Out]

(12*(a - b)^2*(a + b)^2*x + 16*a*b*(a^2 - b^2)*Cosh[2*x] + 4*a*b*(a^2 + b^2)*Cosh[4*x] + 8*(a^4 - b^4)*Sinh[2*
x] + (a^4 + 6*a^2*b^2 + b^4)*Sinh[4*x])/32

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(198\) vs. \(2(66)=132\).
time = 1.14, size = 199, normalized size = 2.76

method	result	size
risch	\(\frac {3 x \,a^{4}}{8}-\frac {3 x \,a^{2} b^{2}}{4}+\frac {3 b^{4} x}{8}+\frac {{\mathrm e}^{4 x} a^{4}}{64}+\frac {{\mathrm e}^{4 x} a^{3} b}{16}+\frac {3 \,{\mathrm e}^{4 x} a^{2} b^{2}}{32}+\frac {{\mathrm e}^{4 x} a \,b^{3}}{16}+\frac {{\mathrm e}^{4 x} b^{4}}{64}+\frac {{\mathrm e}^{2 x} a^{4}}{8}+\frac {{\mathrm e}^{2 x} a^{3} b}{4}-\frac {{\mathrm e}^{2 x} a \,b^{3}}{4}-\frac {{\mathrm e}^{2 x} b^{4}}{8}-\frac {{\mathrm e}^{-2 x} a^{4}}{8}+\frac {{\mathrm e}^{-2 x} a^{3} b}{4}-\frac {{\mathrm e}^{-2 x} a \,b^{3}}{4}+\frac {{\mathrm e}^{-2 x} b^{4}}{8}-\frac {{\mathrm e}^{-4 x} a^{4}}{64}+\frac {{\mathrm e}^{-4 x} a^{3} b}{16}-\frac {3 \,{\mathrm e}^{-4 x} a^{2} b^{2}}{32}+\frac {{\mathrm e}^{-4 x} a \,b^{3}}{16}-\frac {{\mathrm e}^{-4 x} b^{4}}{64}\)	\(199\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*cosh(x)+b*sinh(x))^4,x,method=_RETURNVERBOSE)

[Out]

3/8*x*a^4-3/4*x*a^2*b^2+3/8*b^4*x+1/64*exp(4*x)*a^4+1/16*exp(4*x)*a^3*b+3/32*exp(4*x)*a^2*b^2+1/16*exp(4*x)*a*
b^3+1/64*exp(4*x)*b^4+1/8*exp(2*x)*a^4+1/4*exp(2*x)*a^3*b-1/4*exp(2*x)*a*b^3-1/8*exp(2*x)*b^4-1/8*exp(-2*x)*a^
4+1/4*exp(-2*x)*a^3*b-1/4*exp(-2*x)*a*b^3+1/8*exp(-2*x)*b^4-1/64*exp(-4*x)*a^4+1/16*exp(-4*x)*a^3*b-3/32*exp(-
4*x)*a^2*b^2+1/16*exp(-4*x)*a*b^3-1/64*exp(-4*x)*b^4

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Maxima [A]
time = 0.27, size = 103, normalized size = 1.43 \begin {gather*} a^{3} b \cosh \left (x\right )^{4} + a b^{3} \sinh \left (x\right )^{4} + \frac {1}{64} \, a^{4} {\left (24 \, x + e^{\left (4 \, x\right )} + 8 \, e^{\left (2 \, x\right )} - 8 \, e^{\left (-2 \, x\right )} - e^{\left (-4 \, x\right )}\right )} + \frac {1}{64} \, b^{4} {\left (24 \, x + e^{\left (4 \, x\right )} - 8 \, e^{\left (2 \, x\right )} + 8 \, e^{\left (-2 \, x\right )} - e^{\left (-4 \, x\right )}\right )} - \frac {3}{32} \, a^{2} b^{2} {\left (8 \, x - e^{\left (4 \, x\right )} + e^{\left (-4 \, x\right )}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cosh(x)+b*sinh(x))^4,x, algorithm="maxima")

[Out]

a^3*b*cosh(x)^4 + a*b^3*sinh(x)^4 + 1/64*a^4*(24*x + e^(4*x) + 8*e^(2*x) - 8*e^(-2*x) - e^(-4*x)) + 1/64*b^4*(
24*x + e^(4*x) - 8*e^(2*x) + 8*e^(-2*x) - e^(-4*x)) - 3/32*a^2*b^2*(8*x - e^(4*x) + e^(-4*x))

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 168 vs. \(2 (66) = 132\).
time = 0.35, size = 168, normalized size = 2.33 \begin {gather*} \frac {1}{8} \, {\left (a^{3} b + a b^{3}\right )} \cosh \left (x\right )^{4} + \frac {1}{8} \, {\left (a^{4} + 6 \, a^{2} b^{2} + b^{4}\right )} \cosh \left (x\right ) \sinh \left (x\right )^{3} + \frac {1}{8} \, {\left (a^{3} b + a b^{3}\right )} \sinh \left (x\right )^{4} + \frac {1}{2} \, {\left (a^{3} b - a b^{3}\right )} \cosh \left (x\right )^{2} + \frac {1}{4} \, {\left (2 \, a^{3} b - 2 \, a b^{3} + 3 \, {\left (a^{3} b + a b^{3}\right )} \cosh \left (x\right )^{2}\right )} \sinh \left (x\right )^{2} + \frac {3}{8} \, {\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} x + \frac {1}{8} \, {\left ({\left (a^{4} + 6 \, a^{2} b^{2} + b^{4}\right )} \cosh \left (x\right )^{3} + 4 \, {\left (a^{4} - b^{4}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cosh(x)+b*sinh(x))^4,x, algorithm="fricas")

[Out]

1/8*(a^3*b + a*b^3)*cosh(x)^4 + 1/8*(a^4 + 6*a^2*b^2 + b^4)*cosh(x)*sinh(x)^3 + 1/8*(a^3*b + a*b^3)*sinh(x)^4
+ 1/2*(a^3*b - a*b^3)*cosh(x)^2 + 1/4*(2*a^3*b - 2*a*b^3 + 3*(a^3*b + a*b^3)*cosh(x)^2)*sinh(x)^2 + 3/8*(a^4 -
2*a^2*b^2 + b^4)*x + 1/8*((a^4 + 6*a^2*b^2 + b^4)*cosh(x)^3 + 4*(a^4 - b^4)*cosh(x))*sinh(x)

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 265 vs. \(2 (71) = 142\).
time = 0.16, size = 265, normalized size = 3.68 \begin {gather*} \frac {3 a^{4} x \sinh ^{4}{\left (x \right )}}{8} - \frac {3 a^{4} x \sinh ^{2}{\left (x \right )} \cosh ^{2}{\left (x \right )}}{4} + \frac {3 a^{4} x \cosh ^{4}{\left (x \right )}}{8} - \frac {3 a^{4} \sinh ^{3}{\left (x \right )} \cosh {\left (x \right )}}{8} + \frac {5 a^{4} \sinh {\left (x \right )} \cosh ^{3}{\left (x \right )}}{8} + a^{3} b \cosh ^{4}{\left (x \right )} - \frac {3 a^{2} b^{2} x \sinh ^{4}{\left (x \right )}}{4} + \frac {3 a^{2} b^{2} x \sinh ^{2}{\left (x \right )} \cosh ^{2}{\left (x \right )}}{2} - \frac {3 a^{2} b^{2} x \cosh ^{4}{\left (x \right )}}{4} + \frac {3 a^{2} b^{2} \sinh ^{3}{\left (x \right )} \cosh {\left (x \right )}}{4} + \frac {3 a^{2} b^{2} \sinh {\left (x \right )} \cosh ^{3}{\left (x \right )}}{4} + a b^{3} \sinh ^{4}{\left (x \right )} + \frac {3 b^{4} x \sinh ^{4}{\left (x \right )}}{8} - \frac {3 b^{4} x \sinh ^{2}{\left (x \right )} \cosh ^{2}{\left (x \right )}}{4} + \frac {3 b^{4} x \cosh ^{4}{\left (x \right )}}{8} + \frac {5 b^{4} \sinh ^{3}{\left (x \right )} \cosh {\left (x \right )}}{8} - \frac {3 b^{4} \sinh {\left (x \right )} \cosh ^{3}{\left (x \right )}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cosh(x)+b*sinh(x))**4,x)

[Out]

3*a**4*x*sinh(x)**4/8 - 3*a**4*x*sinh(x)**2*cosh(x)**2/4 + 3*a**4*x*cosh(x)**4/8 - 3*a**4*sinh(x)**3*cosh(x)/8
+ 5*a**4*sinh(x)*cosh(x)**3/8 + a**3*b*cosh(x)**4 - 3*a**2*b**2*x*sinh(x)**4/4 + 3*a**2*b**2*x*sinh(x)**2*cos
h(x)**2/2 - 3*a**2*b**2*x*cosh(x)**4/4 + 3*a**2*b**2*sinh(x)**3*cosh(x)/4 + 3*a**2*b**2*sinh(x)*cosh(x)**3/4 +
a*b**3*sinh(x)**4 + 3*b**4*x*sinh(x)**4/8 - 3*b**4*x*sinh(x)**2*cosh(x)**2/4 + 3*b**4*x*cosh(x)**4/8 + 5*b**4
*sinh(x)**3*cosh(x)/8 - 3*b**4*sinh(x)*cosh(x)**3/8

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 208 vs. \(2 (66) = 132\).
time = 0.40, size = 208, normalized size = 2.89 \begin {gather*} \frac {1}{64} \, a^{4} e^{\left (4 \, x\right )} + \frac {1}{16} \, a^{3} b e^{\left (4 \, x\right )} + \frac {3}{32} \, a^{2} b^{2} e^{\left (4 \, x\right )} + \frac {1}{16} \, a b^{3} e^{\left (4 \, x\right )} + \frac {1}{64} \, b^{4} e^{\left (4 \, x\right )} + \frac {1}{8} \, a^{4} e^{\left (2 \, x\right )} + \frac {1}{4} \, a^{3} b e^{\left (2 \, x\right )} - \frac {1}{4} \, a b^{3} e^{\left (2 \, x\right )} - \frac {1}{8} \, b^{4} e^{\left (2 \, x\right )} + \frac {3}{8} \, {\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} x - \frac {1}{64} \, {\left (18 \, a^{4} e^{\left (4 \, x\right )} - 36 \, a^{2} b^{2} e^{\left (4 \, x\right )} + 18 \, b^{4} e^{\left (4 \, x\right )} + 8 \, a^{4} e^{\left (2 \, x\right )} - 16 \, a^{3} b e^{\left (2 \, x\right )} + 16 \, a b^{3} e^{\left (2 \, x\right )} - 8 \, b^{4} e^{\left (2 \, x\right )} + a^{4} - 4 \, a^{3} b + 6 \, a^{2} b^{2} - 4 \, a b^{3} + b^{4}\right )} e^{\left (-4 \, x\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*cosh(x)+b*sinh(x))^4,x, algorithm="giac")

[Out]

1/64*a^4*e^(4*x) + 1/16*a^3*b*e^(4*x) + 3/32*a^2*b^2*e^(4*x) + 1/16*a*b^3*e^(4*x) + 1/64*b^4*e^(4*x) + 1/8*a^4
*e^(2*x) + 1/4*a^3*b*e^(2*x) - 1/4*a*b^3*e^(2*x) - 1/8*b^4*e^(2*x) + 3/8*(a^4 - 2*a^2*b^2 + b^4)*x - 1/64*(18*
a^4*e^(4*x) - 36*a^2*b^2*e^(4*x) + 18*b^4*e^(4*x) + 8*a^4*e^(2*x) - 16*a^3*b*e^(2*x) + 16*a*b^3*e^(2*x) - 8*b^
4*e^(2*x) + a^4 - 4*a^3*b + 6*a^2*b^2 - 4*a*b^3 + b^4)*e^(-4*x)

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Mupad [B]
time = 1.56, size = 143, normalized size = 1.99 \begin {gather*} \mathrm {cosh}\left (x\right )\,{\mathrm {sinh}\left (x\right )}^3\,\left (-\frac {3\,a^4}{8}+\frac {3\,a^2\,b^2}{4}+\frac {5\,b^4}{8}\right )-{\mathrm {cosh}\left (x\right )}^4\,\left (a\,b^3-a^3\,b\right )+{\mathrm {cosh}\left (x\right )}^3\,\mathrm {sinh}\left (x\right )\,\left (\frac {5\,a^4}{8}+\frac {3\,a^2\,b^2}{4}-\frac {3\,b^4}{8}\right )+\frac {3\,x\,{\mathrm {cosh}\left (x\right )}^4\,{\left (a^2-b^2\right )}^2}{8}+\frac {3\,x\,{\mathrm {sinh}\left (x\right )}^4\,{\left (a^2-b^2\right )}^2}{8}+2\,a\,b^3\,{\mathrm {cosh}\left (x\right )}^2\,{\mathrm {sinh}\left (x\right )}^2-\frac {3\,x\,{\mathrm {cosh}\left (x\right )}^2\,{\mathrm {sinh}\left (x\right )}^2\,{\left (a^2-b^2\right )}^2}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*cosh(x) + b*sinh(x))^4,x)

[Out]

cosh(x)*sinh(x)^3*((5*b^4)/8 - (3*a^4)/8 + (3*a^2*b^2)/4) - cosh(x)^4*(a*b^3 - a^3*b) + cosh(x)^3*sinh(x)*((5*
a^4)/8 - (3*b^4)/8 + (3*a^2*b^2)/4) + (3*x*cosh(x)^4*(a^2 - b^2)^2)/8 + (3*x*sinh(x)^4*(a^2 - b^2)^2)/8 + 2*a*
b^3*cosh(x)^2*sinh(x)^2 - (3*x*cosh(x)^2*sinh(x)^2*(a^2 - b^2)^2)/4

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