3.7.52 \(\int \frac {1}{(a \coth (x)+b \text {csch}(x))^4} \, dx\) [652]

Optimal. Leaf size=159 \[ \frac {x}{a^4}-\frac {b \left (3 a^2-2 b^2\right ) \text {ArcTan}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^4 (a-b)^{3/2} (a+b)^{3/2}}-\frac {\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 a^3 \left (a^2-b^2\right ) (b+a \cosh (x))}-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2} \]

[Out]

x/a^4-b*(3*a^2-2*b^2)*arctan((a-b)^(1/2)*tanh(1/2*x)/(a+b)^(1/2))/a^4/(a-b)^(3/2)/(a+b)^(3/2)-1/2*(2*a^2-2*b^2
-a*b*cosh(x))*sinh(x)/a^3/(a^2-b^2)/(b+a*cosh(x))-1/3*sinh(x)^3/a/(b+a*cosh(x))^3-1/2*b*sinh(x)^3/a/(a^2-b^2)/
(b+a*cosh(x))^2

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Rubi [A]
time = 0.28, antiderivative size = 159, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.636, Rules used = {4477, 2772, 2943, 2942, 2814, 2738, 211} \begin {gather*} \frac {x}{a^4}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (a \cosh (x)+b)^2}-\frac {b \left (3 a^2-2 b^2\right ) \text {ArcTan}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^4 (a-b)^{3/2} (a+b)^{3/2}}-\frac {\sinh (x) \left (2 \left (a^2-b^2\right )-a b \cosh (x)\right )}{2 a^3 \left (a^2-b^2\right ) (a \cosh (x)+b)}-\frac {\sinh ^3(x)}{3 a (a \cosh (x)+b)^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a*Coth[x] + b*Csch[x])^(-4),x]

[Out]

x/a^4 - (b*(3*a^2 - 2*b^2)*ArcTan[(Sqrt[a - b]*Tanh[x/2])/Sqrt[a + b]])/(a^4*(a - b)^(3/2)*(a + b)^(3/2)) - ((
2*(a^2 - b^2) - a*b*Cosh[x])*Sinh[x])/(2*a^3*(a^2 - b^2)*(b + a*Cosh[x])) - Sinh[x]^3/(3*a*(b + a*Cosh[x])^3)
- (b*Sinh[x]^3)/(2*a*(a^2 - b^2)*(b + a*Cosh[x])^2)

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 2738

Int[((a_) + (b_.)*sin[Pi/2 + (c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x
]}, Dist[2*(e/d), Subst[Int[1/(a + b + (a - b)*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}
, x] && NeQ[a^2 - b^2, 0]

Rule 2772

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[g*(g*C
os[e + f*x])^(p - 1)*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 1))), x] + Dist[g^2*((p - 1)/(b*(m + 1))), Int[(g
*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 1)*Sin[e + f*x], x], x] /; FreeQ[{a, b, e, f, g}, x] && NeQ[a
^2 - b^2, 0] && LtQ[m, -1] && GtQ[p, 1] && IntegersQ[2*m, 2*p]

Rule 2814

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[b*(x/d)
, x] - Dist[(b*c - a*d)/d, Int[1/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d
, 0]

Rule 2942

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.)
+ (f_.)*(x_)]), x_Symbol] :> Simp[g*(g*Cos[e + f*x])^(p - 1)*(a + b*Sin[e + f*x])^(m + 1)*((b*c*(m + p + 1) -
a*d*p + b*d*(m + 1)*Sin[e + f*x])/(b^2*f*(m + 1)*(m + p + 1))), x] + Dist[g^2*((p - 1)/(b^2*(m + 1)*(m + p + 1
))), Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 1)*Simp[b*d*(m + 1) + (b*c*(m + p + 1) - a*d*p)*Si
n[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && GtQ[p, 1] && N
eQ[m + p + 1, 0] && IntegerQ[2*m]

Rule 2943

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.)
+ (f_.)*(x_)]), x_Symbol] :> Simp[(-(b*c - a*d))*(g*Cos[e + f*x])^(p + 1)*((a + b*Sin[e + f*x])^(m + 1)/(f*g*(
a^2 - b^2)*(m + 1))), x] + Dist[1/((a^2 - b^2)*(m + 1)), Int[(g*Cos[e + f*x])^p*(a + b*Sin[e + f*x])^(m + 1)*S
imp[(a*c - b*d)*(m + 1) - (b*c - a*d)*(m + p + 2)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p},
x] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && IntegerQ[2*m]

Rule 4477

Int[(cot[(c_.) + (d_.)*(x_)]^(n_.)*(a_.) + csc[(c_.) + (d_.)*(x_)]^(n_.)*(b_.))^(p_)*(u_.), x_Symbol] :> Int[A
ctivateTrig[u]*Csc[c + d*x]^(n*p)*(b + a*Cos[c + d*x]^n)^p, x] /; FreeQ[{a, b, c, d}, x] && IntegersQ[n, p]

Rubi steps

\begin {align*} \int \frac {1}{(a \coth (x)+b \text {csch}(x))^4} \, dx &=\int \frac {\sinh ^4(x)}{(i b+i a \cosh (x))^4} \, dx\\ &=-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {i \int \frac {\cosh (x) \sinh ^2(x)}{(i b+i a \cosh (x))^3} \, dx}{a}\\ &=-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2}+\frac {i \int \frac {(2 i a+i b \cosh (x)) \sinh ^2(x)}{(i b+i a \cosh (x))^2} \, dx}{2 a \left (a^2-b^2\right )}\\ &=-\frac {\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 a^3 \left (a^2-b^2\right ) (b+a \cosh (x))}-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2}-\frac {i \int \frac {a b-2 \left (a^2-b^2\right ) \cosh (x)}{i b+i a \cosh (x)} \, dx}{2 a^3 \left (a^2-b^2\right )}\\ &=\frac {x}{a^4}-\frac {\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 a^3 \left (a^2-b^2\right ) (b+a \cosh (x))}-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2}-\frac {\left (i b \left (3 a^2-2 b^2\right )\right ) \int \frac {1}{i b+i a \cosh (x)} \, dx}{2 a^4 \left (a^2-b^2\right )}\\ &=\frac {x}{a^4}-\frac {\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 a^3 \left (a^2-b^2\right ) (b+a \cosh (x))}-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2}-\frac {\left (i b \left (3 a^2-2 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{i a+i b-(-i a+i b) x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{a^4 \left (a^2-b^2\right )}\\ &=\frac {x}{a^4}-\frac {b \left (3 a^2-2 b^2\right ) \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^4 (a-b)^{3/2} (a+b)^{3/2}}-\frac {\left (2 \left (a^2-b^2\right )-a b \cosh (x)\right ) \sinh (x)}{2 a^3 \left (a^2-b^2\right ) (b+a \cosh (x))}-\frac {\sinh ^3(x)}{3 a (b+a \cosh (x))^3}-\frac {b \sinh ^3(x)}{2 a \left (a^2-b^2\right ) (b+a \cosh (x))^2}\\ \end {align*}

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Mathematica [A]
time = 0.32, size = 150, normalized size = 0.94 \begin {gather*} \frac {\left (2 a \left (a^2-b^2\right )+7 a b (b+a \cosh (x))-\frac {a \left (8 a^2-11 b^2\right ) (b+a \cosh (x))^2}{(a-b) (a+b)}+6 x (b+a \cosh (x))^3 \text {csch}(x)-\frac {6 b \left (-3 a^2+2 b^2\right ) \text {ArcTan}\left (\frac {(-a+b) \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right ) (b+a \cosh (x))^3 \text {csch}(x)}{\left (a^2-b^2\right )^{3/2}}\right ) \sinh (x)}{6 a^4 (b+a \cosh (x))^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a*Coth[x] + b*Csch[x])^(-4),x]

[Out]

((2*a*(a^2 - b^2) + 7*a*b*(b + a*Cosh[x]) - (a*(8*a^2 - 11*b^2)*(b + a*Cosh[x])^2)/((a - b)*(a + b)) + 6*x*(b
+ a*Cosh[x])^3*Csch[x] - (6*b*(-3*a^2 + 2*b^2)*ArcTan[((-a + b)*Tanh[x/2])/Sqrt[a^2 - b^2]]*(b + a*Cosh[x])^3*
Csch[x])/(a^2 - b^2)^(3/2))*Sinh[x])/(6*a^4*(b + a*Cosh[x])^3)

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Maple [A]
time = 1.13, size = 206, normalized size = 1.30

method	result	size
default	\(-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{a^{4}}+\frac {\ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{a^{4}}+\frac {\frac {2 \left (-\frac {\left (2 a^{3}-a^{2} b -3 a \,b^{2}+2 b^{3}\right ) a \left (\tanh ^{5}\left (\frac {x}{2}\right )\right )}{2 \left (a +b \right )}-\frac {2 a \left (5 a^{2}-3 b^{2}\right ) \left (\tanh ^{3}\left (\frac {x}{2}\right )\right )}{3}-\frac {\left (2 a^{3}+a^{2} b -3 a \,b^{2}-2 b^{3}\right ) a \tanh \left (\frac {x}{2}\right )}{2 \left (a -b \right )}\right )}{\left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-b \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )+a +b \right )^{3}}-\frac {b \left (3 a^{2}-2 b^{2}\right ) \arctan \left (\frac {\tanh \left (\frac {x}{2}\right ) \left (a -b \right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{\left (a^{2}-b^{2}\right ) \sqrt {\left (a +b \right ) \left (a -b \right )}}}{a^{4}}\)	\(206\)
risch	\(\frac {x}{a^{4}}+\frac {15 \,{\mathrm e}^{5 x} a^{4} b -18 a^{2} b^{3} {\mathrm e}^{5 x}+12 a^{5} {\mathrm e}^{4 x}+27 a^{3} b^{2} {\mathrm e}^{4 x}-54 a \,b^{4} {\mathrm e}^{4 x}+48 \,{\mathrm e}^{3 x} a^{4} b -34 a^{2} b^{3} {\mathrm e}^{3 x}-44 \,{\mathrm e}^{3 x} b^{5}+12 a^{5} {\mathrm e}^{2 x}+36 a^{3} b^{2} {\mathrm e}^{2 x}-78 a \,b^{4} {\mathrm e}^{2 x}+33 a^{4} b \,{\mathrm e}^{x}-48 a^{2} b^{3} {\mathrm e}^{x}+8 a^{5}-11 a^{3} b^{2}}{3 a^{4} \left (a^{2}-b^{2}\right ) \left ({\mathrm e}^{2 x} a +2 \,{\mathrm e}^{x} b +a \right )^{3}}-\frac {3 b \ln \left ({\mathrm e}^{x}+\frac {b \sqrt {-a^{2}+b^{2}}+a^{2}-b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{2 \sqrt {-a^{2}+b^{2}}\, \left (a +b \right ) \left (a -b \right ) a^{2}}+\frac {b^{3} \ln \left ({\mathrm e}^{x}+\frac {b \sqrt {-a^{2}+b^{2}}+a^{2}-b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right ) \left (a -b \right ) a^{4}}+\frac {3 b \ln \left ({\mathrm e}^{x}+\frac {b \sqrt {-a^{2}+b^{2}}-a^{2}+b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{2 \sqrt {-a^{2}+b^{2}}\, \left (a +b \right ) \left (a -b \right ) a^{2}}-\frac {b^{3} \ln \left ({\mathrm e}^{x}+\frac {b \sqrt {-a^{2}+b^{2}}-a^{2}+b^{2}}{\sqrt {-a^{2}+b^{2}}\, a}\right )}{\sqrt {-a^{2}+b^{2}}\, \left (a +b \right ) \left (a -b \right ) a^{4}}\)	\(468\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a*coth(x)+b*csch(x))^4,x,method=_RETURNVERBOSE)

[Out]

-1/a^4*ln(tanh(1/2*x)-1)+1/a^4*ln(tanh(1/2*x)+1)+2/a^4*((-1/2*(2*a^3-a^2*b-3*a*b^2+2*b^3)*a/(a+b)*tanh(1/2*x)^
5-2/3*a*(5*a^2-3*b^2)*tanh(1/2*x)^3-1/2*(2*a^3+a^2*b-3*a*b^2-2*b^3)*a/(a-b)*tanh(1/2*x))/(a*tanh(1/2*x)^2-b*ta
nh(1/2*x)^2+a+b)^3-1/2*b*(3*a^2-2*b^2)/(a^2-b^2)/((a+b)*(a-b))^(1/2)*arctan(tanh(1/2*x)*(a-b)/((a+b)*(a-b))^(1
/2)))

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*coth(x)+b*csch(x))^4,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(4*b^2-4*a^2>0)', see `assume?`
for more de

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 2875 vs. \(2 (141) = 282\).
time = 0.43, size = 5830, normalized size = 36.67 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*coth(x)+b*csch(x))^4,x, algorithm="fricas")

[Out]

[1/6*(6*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x)^6 + 6*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*sinh(x)^6 + 16*a^7 - 38*a^5*
b^2 + 22*a^3*b^4 + 6*(5*a^6*b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*cosh(x)^5 + 6*(5*a
^6*b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x) + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*s
inh(x)^5 + 6*(4*a^7 + 5*a^5*b^2 - 27*a^3*b^4 + 18*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x)*cosh(x)
^4 + 6*(4*a^7 + 5*a^5*b^2 - 27*a^3*b^4 + 18*a*b^6 + 15*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x)^2 + 3*(a^7 + 2*a^
5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x + 5*(5*a^6*b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*cosh
(x))*sinh(x)^4 + 4*(24*a^6*b - 41*a^4*b^3 - 5*a^2*b^5 + 22*b^7 + 6*(3*a^6*b - 4*a^4*b^3 - a^2*b^5 + 2*b^7)*x)*
cosh(x)^3 + 4*(24*a^6*b - 41*a^4*b^3 - 5*a^2*b^5 + 22*b^7 + 30*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x)^3 + 15*(5
*a^6*b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*cosh(x)^2 + 6*(3*a^6*b - 4*a^4*b^3 - a^2*
b^5 + 2*b^7)*x + 6*(4*a^7 + 5*a^5*b^2 - 27*a^3*b^4 + 18*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x)*c
osh(x))*sinh(x)^3 + 6*(4*a^7 + 8*a^5*b^2 - 38*a^3*b^4 + 26*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x
)*cosh(x)^2 + 6*(4*a^7 + 8*a^5*b^2 - 38*a^3*b^4 + 26*a*b^6 + 15*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x)^4 + 10*(
5*a^6*b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*cosh(x)^3 + 6*(4*a^7 + 5*a^5*b^2 - 27*a^
3*b^4 + 18*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x)*cosh(x)^2 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4
*a*b^6)*x + 2*(24*a^6*b - 41*a^4*b^3 - 5*a^2*b^5 + 22*b^7 + 6*(3*a^6*b - 4*a^4*b^3 - a^2*b^5 + 2*b^7)*x)*cosh(
x))*sinh(x)^2 - 3*((3*a^5*b - 2*a^3*b^3)*cosh(x)^6 + (3*a^5*b - 2*a^3*b^3)*sinh(x)^6 + 3*a^5*b - 2*a^3*b^3 + 6
*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x)^5 + 6*(3*a^4*b^2 - 2*a^2*b^4 + (3*a^5*b - 2*a^3*b^3)*cosh(x))*sinh(x)^5 + 3*(
3*a^5*b + 10*a^3*b^3 - 8*a*b^5)*cosh(x)^4 + 3*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5 + 5*(3*a^5*b - 2*a^3*b^3)*cosh(x
)^2 + 10*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x))*sinh(x)^4 + 4*(9*a^4*b^2 - 4*b^6)*cosh(x)^3 + 4*(9*a^4*b^2 - 4*b^6 +
5*(3*a^5*b - 2*a^3*b^3)*cosh(x)^3 + 15*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x)^2 + 3*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5)
*cosh(x))*sinh(x)^3 + 3*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5)*cosh(x)^2 + 3*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5 + 5*(3*
a^5*b - 2*a^3*b^3)*cosh(x)^4 + 20*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x)^3 + 6*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5)*cosh(
x)^2 + 4*(9*a^4*b^2 - 4*b^6)*cosh(x))*sinh(x)^2 + 6*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x) + 6*(3*a^4*b^2 - 2*a^2*b^4
+ (3*a^5*b - 2*a^3*b^3)*cosh(x)^5 + 5*(3*a^4*b^2 - 2*a^2*b^4)*cosh(x)^4 + 2*(3*a^5*b + 10*a^3*b^3 - 8*a*b^5)*
cosh(x)^3 + 2*(9*a^4*b^2 - 4*b^6)*cosh(x)^2 + (3*a^5*b + 10*a^3*b^3 - 8*a*b^5)*cosh(x))*sinh(x))*sqrt(-a^2 + b
^2)*log((a^2*cosh(x)^2 + a^2*sinh(x)^2 + 2*a*b*cosh(x) - a^2 + 2*b^2 + 2*(a^2*cosh(x) + a*b)*sinh(x) + 2*sqrt(
-a^2 + b^2)*(a*cosh(x) + a*sinh(x) + b))/(a*cosh(x)^2 + a*sinh(x)^2 + 2*b*cosh(x) + 2*(a*cosh(x) + b)*sinh(x)
+ a)) + 6*(a^7 - 2*a^5*b^2 + a^3*b^4)*x + 6*(11*a^6*b - 27*a^4*b^3 + 16*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b
^5)*x)*cosh(x) + 6*(11*a^6*b - 27*a^4*b^3 + 16*a^2*b^5 + 6*(a^7 - 2*a^5*b^2 + a^3*b^4)*x*cosh(x)^5 + 5*(5*a^6*
b - 11*a^4*b^3 + 6*a^2*b^5 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x)*cosh(x)^4 + 4*(4*a^7 + 5*a^5*b^2 - 27*a^3*b^4
+ 18*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x)*cosh(x)^3 + 2*(24*a^6*b - 41*a^4*b^3 - 5*a^2*b^5 + 2
2*b^7 + 6*(3*a^6*b - 4*a^4*b^3 - a^2*b^5 + 2*b^7)*x)*cosh(x)^2 + 6*(a^6*b - 2*a^4*b^3 + a^2*b^5)*x + 2*(4*a^7
+ 8*a^5*b^2 - 38*a^3*b^4 + 26*a*b^6 + 3*(a^7 + 2*a^5*b^2 - 7*a^3*b^4 + 4*a*b^6)*x)*cosh(x))*sinh(x))/(a^11 - 2
*a^9*b^2 + a^7*b^4 + (a^11 - 2*a^9*b^2 + a^7*b^4)*cosh(x)^6 + (a^11 - 2*a^9*b^2 + a^7*b^4)*sinh(x)^6 + 6*(a^10
*b - 2*a^8*b^3 + a^6*b^5)*cosh(x)^5 + 6*(a^10*b - 2*a^8*b^3 + a^6*b^5 + (a^11 - 2*a^9*b^2 + a^7*b^4)*cosh(x))*
sinh(x)^5 + 3*(a^11 + 2*a^9*b^2 - 7*a^7*b^4 + 4*a^5*b^6)*cosh(x)^4 + 3*(a^11 + 2*a^9*b^2 - 7*a^7*b^4 + 4*a^5*b
^6 + 5*(a^11 - 2*a^9*b^2 + a^7*b^4)*cosh(x)^2 + 10*(a^10*b - 2*a^8*b^3 + a^6*b^5)*cosh(x))*sinh(x)^4 + 4*(3*a^
10*b - 4*a^8*b^3 - a^6*b^5 + 2*a^4*b^7)*cosh(x)^3 + 4*(3*a^10*b - 4*a^8*b^3 - a^6*b^5 + 2*a^4*b^7 + 5*(a^11 -
2*a^9*b^2 + a^7*b^4)*cosh(x)^3 + 15*(a^10*b - 2*a^8*b^3 + a^6*b^5)*cosh(x)^2 + 3*(a^11 + 2*a^9*b^2 - 7*a^7*b^4
+ 4*a^5*b^6)*cosh(x))*sinh(x)^3 + 3*(a^11 + 2*a^9*b^2 - 7*a^7*b^4 + 4*a^5*b^6)*cosh(x)^2 + 3*(a^11 + 2*a^9*b^
2 - 7*a^7*b^4 + 4*a^5*b^6 + 5*(a^11 - 2*a^9*b^2 + a^7*b^4)*cosh(x)^4 + 20*(a^10*b - 2*a^8*b^3 + a^6*b^5)*cosh(
x)^3 + 6*(a^11 + 2*a^9*b^2 - 7*a^7*b^4 + 4*a^5*b^6)*cosh(x)^2 + 4*(3*a^10*b - 4*a^8*b^3 - a^6*b^5 + 2*a^4*b^7)
*cosh(x))*sinh(x)^2 + 6*(a^10*b - 2*a^8*b^3 + a^6*b^5)*cosh(x) + 6*(a^10*b - 2*a^8*b^3 + a^6*b^5 + (a^11 - 2*a
^9*b^2 + a^7*b^4)*cosh(x)^5 + 5*(a^10*b - 2*a^8*b^3 + a^6*b^5)*cosh(x)^4 + 2*(a^11 + 2*a^9*b^2 - 7*a^7*b^4 + 4
*a^5*b^6)*cosh(x)^3 + 2*(3*a^10*b - 4*a^8*b^3 - a^6*b^5 + 2*a^4*b^7)*cosh(x)^2 + (a^11 + 2*a^9*b^2 - 7*a^7*b^4
+ 4*a^5*b^6)*cosh(x))*sinh(x)), 1/3*(3*(a^7 - ...

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (a \coth {\left (x \right )} + b \operatorname {csch}{\left (x \right )}\right )^{4}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*coth(x)+b*csch(x))**4,x)

[Out]

Integral((a*coth(x) + b*csch(x))**(-4), x)

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Giac [A]
time = 0.42, size = 242, normalized size = 1.52 \begin {gather*} -\frac {{\left (3 \, a^{2} b - 2 \, b^{3}\right )} \arctan \left (\frac {a e^{x} + b}{\sqrt {a^{2} - b^{2}}}\right )}{{\left (a^{6} - a^{4} b^{2}\right )} \sqrt {a^{2} - b^{2}}} + \frac {15 \, a^{4} b e^{\left (5 \, x\right )} - 18 \, a^{2} b^{3} e^{\left (5 \, x\right )} + 12 \, a^{5} e^{\left (4 \, x\right )} + 27 \, a^{3} b^{2} e^{\left (4 \, x\right )} - 54 \, a b^{4} e^{\left (4 \, x\right )} + 48 \, a^{4} b e^{\left (3 \, x\right )} - 34 \, a^{2} b^{3} e^{\left (3 \, x\right )} - 44 \, b^{5} e^{\left (3 \, x\right )} + 12 \, a^{5} e^{\left (2 \, x\right )} + 36 \, a^{3} b^{2} e^{\left (2 \, x\right )} - 78 \, a b^{4} e^{\left (2 \, x\right )} + 33 \, a^{4} b e^{x} - 48 \, a^{2} b^{3} e^{x} + 8 \, a^{5} - 11 \, a^{3} b^{2}}{3 \, {\left (a^{6} - a^{4} b^{2}\right )} {\left (a e^{\left (2 \, x\right )} + 2 \, b e^{x} + a\right )}^{3}} + \frac {x}{a^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*coth(x)+b*csch(x))^4,x, algorithm="giac")

[Out]

-(3*a^2*b - 2*b^3)*arctan((a*e^x + b)/sqrt(a^2 - b^2))/((a^6 - a^4*b^2)*sqrt(a^2 - b^2)) + 1/3*(15*a^4*b*e^(5*
x) - 18*a^2*b^3*e^(5*x) + 12*a^5*e^(4*x) + 27*a^3*b^2*e^(4*x) - 54*a*b^4*e^(4*x) + 48*a^4*b*e^(3*x) - 34*a^2*b
^3*e^(3*x) - 44*b^5*e^(3*x) + 12*a^5*e^(2*x) + 36*a^3*b^2*e^(2*x) - 78*a*b^4*e^(2*x) + 33*a^4*b*e^x - 48*a^2*b
^3*e^x + 8*a^5 - 11*a^3*b^2)/((a^6 - a^4*b^2)*(a*e^(2*x) + 2*b*e^x + a)^3) + x/a^4

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (\frac {b}{\mathrm {sinh}\left (x\right )}+a\,\mathrm {coth}\left (x\right )\right )}^4} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b/sinh(x) + a*coth(x))^4,x)

[Out]

int(1/(b/sinh(x) + a*coth(x))^4, x)

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