3.7.70 \(\int \frac {1}{(-\coth (x)+\text {csch}(x))^2} \, dx\) [670]

Optimal. Leaf size=14 \[ x+\frac {2 \sinh (x)}{1-\cosh (x)} \]

[Out]

x+2*sinh(x)/(1-cosh(x))

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Rubi [A]
time = 0.04, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {4477, 2759, 8} \begin {gather*} x+\frac {2 \sinh (x)}{1-\cosh (x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(-Coth[x] + Csch[x])^(-2),x]

[Out]

x + (2*Sinh[x])/(1 - Cosh[x])

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 2759

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[2*g*(g
*Cos[e + f*x])^(p - 1)*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(2*m + p + 1))), x] + Dist[g^2*((p - 1)/(b^2*(2*m +
p + 1))), Int[(g*Cos[e + f*x])^(p - 2)*(a + b*Sin[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, g}, x] && Eq
Q[a^2 - b^2, 0] && LeQ[m, -2] && GtQ[p, 1] && NeQ[2*m + p + 1, 0] &&  !ILtQ[m + p + 1, 0] && IntegersQ[2*m, 2*
p]

Rule 4477

Int[(cot[(c_.) + (d_.)*(x_)]^(n_.)*(a_.) + csc[(c_.) + (d_.)*(x_)]^(n_.)*(b_.))^(p_)*(u_.), x_Symbol] :> Int[A
ctivateTrig[u]*Csc[c + d*x]^(n*p)*(b + a*Cos[c + d*x]^n)^p, x] /; FreeQ[{a, b, c, d}, x] && IntegersQ[n, p]

Rubi steps

\begin {align*} \int \frac {1}{(-\coth (x)+\text {csch}(x))^2} \, dx &=-\int \frac {\sinh ^2(x)}{(i-i \cosh (x))^2} \, dx\\ &=\frac {2 \sinh (x)}{1-\cosh (x)}+\int 1 \, dx\\ &=x+\frac {2 \sinh (x)}{1-\cosh (x)}\\ \end {align*}

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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
time = 0.01, size = 24, normalized size = 1.71 \begin {gather*} -2 \coth \left (\frac {x}{2}\right ) \, _2F_1\left (-\frac {1}{2},1;\frac {1}{2};\tanh ^2\left (\frac {x}{2}\right )\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(-Coth[x] + Csch[x])^(-2),x]

[Out]

-2*Coth[x/2]*Hypergeometric2F1[-1/2, 1, 1/2, Tanh[x/2]^2]

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Maple [A]
time = 1.04, size = 26, normalized size = 1.86

method	result	size
risch	\(x -\frac {4}{{\mathrm e}^{x}-1}\)	\(11\)
default	\(-\ln \left (\tanh \left (\frac {x}{2}\right )-1\right )-\frac {2}{\tanh \left (\frac {x}{2}\right )}+\ln \left (\tanh \left (\frac {x}{2}\right )+1\right )\)	\(26\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-coth(x)+csch(x))^2,x,method=_RETURNVERBOSE)

[Out]

-ln(tanh(1/2*x)-1)-2/tanh(1/2*x)+ln(tanh(1/2*x)+1)

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Maxima [A]
time = 0.27, size = 12, normalized size = 0.86 \begin {gather*} x + \frac {4}{e^{\left (-x\right )} - 1} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-coth(x)+csch(x))^2,x, algorithm="maxima")

[Out]

x + 4/(e^(-x) - 1)

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Fricas [A]
time = 0.35, size = 22, normalized size = 1.57 \begin {gather*} \frac {x \cosh \left (x\right ) + x \sinh \left (x\right ) - x - 4}{\cosh \left (x\right ) + \sinh \left (x\right ) - 1} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-coth(x)+csch(x))^2,x, algorithm="fricas")

[Out]

(x*cosh(x) + x*sinh(x) - x - 4)/(cosh(x) + sinh(x) - 1)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (- \coth {\left (x \right )} + \operatorname {csch}{\left (x \right )}\right )^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-coth(x)+csch(x))**2,x)

[Out]

Integral((-coth(x) + csch(x))**(-2), x)

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Giac [A]
time = 0.40, size = 10, normalized size = 0.71 \begin {gather*} x - \frac {4}{e^{x} - 1} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-coth(x)+csch(x))^2,x, algorithm="giac")

[Out]

x - 4/(e^x - 1)

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Mupad [B]
time = 1.67, size = 10, normalized size = 0.71 \begin {gather*} x-\frac {4}{{\mathrm {e}}^x-1} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(coth(x) - 1/sinh(x))^2,x)

[Out]

x - 4/(exp(x) - 1)

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