3.8.65 \(\int \frac {1}{(a+b \cosh (x)+c \sinh (x))^{3/2}} \, dx\) [765]

Optimal. Leaf size=156 \[ -\frac {2 (c \cosh (x)+b \sinh (x))}{\left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}-\frac {2 i E\left (\frac {1}{2} \left (i x-\tan ^{-1}(b,-i c)\right )|\frac {2 \sqrt {b^2-c^2}}{a+\sqrt {b^2-c^2}}\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}{\left (a^2-b^2+c^2\right ) \sqrt {\frac {a+b \cosh (x)+c \sinh (x)}{a+\sqrt {b^2-c^2}}}} \]

[Out]

-2*(c*cosh(x)+b*sinh(x))/(a^2-b^2+c^2)/(a+b*cosh(x)+c*sinh(x))^(1/2)-2*I*(cos(1/2*I*x-1/2*arctan(b,-I*c))^2)^(
1/2)/cos(1/2*I*x-1/2*arctan(b,-I*c))*EllipticE(sin(1/2*I*x-1/2*arctan(b,-I*c)),2^(1/2)*((b^2-c^2)^(1/2)/(a+(b^
2-c^2)^(1/2)))^(1/2))*(a+b*cosh(x)+c*sinh(x))^(1/2)/(a^2-b^2+c^2)/((a+b*cosh(x)+c*sinh(x))/(a+(b^2-c^2)^(1/2))
)^(1/2)

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Rubi [A]
time = 0.08, antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3207, 3198, 2732} \begin {gather*} -\frac {2 (b \sinh (x)+c \cosh (x))}{\left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}-\frac {2 i \sqrt {a+b \cosh (x)+c \sinh (x)} E\left (\frac {1}{2} \left (i x-\tan ^{-1}(b,-i c)\right )|\frac {2 \sqrt {b^2-c^2}}{a+\sqrt {b^2-c^2}}\right )}{\left (a^2-b^2+c^2\right ) \sqrt {\frac {a+b \cosh (x)+c \sinh (x)}{a+\sqrt {b^2-c^2}}}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*Cosh[x] + c*Sinh[x])^(-3/2),x]

[Out]

(-2*(c*Cosh[x] + b*Sinh[x]))/((a^2 - b^2 + c^2)*Sqrt[a + b*Cosh[x] + c*Sinh[x]]) - ((2*I)*EllipticE[(I*x - Arc
Tan[b, (-I)*c])/2, (2*Sqrt[b^2 - c^2])/(a + Sqrt[b^2 - c^2])]*Sqrt[a + b*Cosh[x] + c*Sinh[x]])/((a^2 - b^2 + c
^2)*Sqrt[(a + b*Cosh[x] + c*Sinh[x])/(a + Sqrt[b^2 - c^2])])

Rule 2732

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a + b]/d)*EllipticE[(1/2)*(c - Pi/2
+ d*x), 2*(b/(a + b))], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 3198

Int[Sqrt[cos[(d_.) + (e_.)*(x_)]*(b_.) + (a_) + (c_.)*sin[(d_.) + (e_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a + b*C
os[d + e*x] + c*Sin[d + e*x]]/Sqrt[(a + b*Cos[d + e*x] + c*Sin[d + e*x])/(a + Sqrt[b^2 + c^2])], Int[Sqrt[a/(a
+ Sqrt[b^2 + c^2]) + (Sqrt[b^2 + c^2]/(a + Sqrt[b^2 + c^2]))*Cos[d + e*x - ArcTan[b, c]]], x], x] /; FreeQ[{a
, b, c, d, e}, x] && NeQ[a^2 - b^2 - c^2, 0] && NeQ[b^2 + c^2, 0] &&  !GtQ[a + Sqrt[b^2 + c^2], 0]

Rule 3207

Int[(cos[(d_.) + (e_.)*(x_)]*(b_.) + (a_) + (c_.)*sin[(d_.) + (e_.)*(x_)])^(-3/2), x_Symbol] :> Simp[2*((c*Cos
[d + e*x] - b*Sin[d + e*x])/(e*(a^2 - b^2 - c^2)*Sqrt[a + b*Cos[d + e*x] + c*Sin[d + e*x]])), x] + Dist[1/(a^2
- b^2 - c^2), Int[Sqrt[a + b*Cos[d + e*x] + c*Sin[d + e*x]], x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[a^2 -
b^2 - c^2, 0]

Rubi steps

\begin {align*} \int \frac {1}{(a+b \cosh (x)+c \sinh (x))^{3/2}} \, dx &=-\frac {2 (c \cosh (x)+b \sinh (x))}{\left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}+\frac {\int \sqrt {a+b \cosh (x)+c \sinh (x)} \, dx}{a^2-b^2+c^2}\\ &=-\frac {2 (c \cosh (x)+b \sinh (x))}{\left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}+\frac {\sqrt {a+b \cosh (x)+c \sinh (x)} \int \sqrt {\frac {a}{a+\sqrt {b^2-c^2}}+\frac {\sqrt {b^2-c^2} \cosh \left (x+i \tan ^{-1}(b,-i c)\right )}{a+\sqrt {b^2-c^2}}} \, dx}{\left (a^2-b^2+c^2\right ) \sqrt {\frac {a+b \cosh (x)+c \sinh (x)}{a+\sqrt {b^2-c^2}}}}\\ &=-\frac {2 (c \cosh (x)+b \sinh (x))}{\left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}-\frac {2 i E\left (\frac {1}{2} \left (i x-\tan ^{-1}(b,-i c)\right )|\frac {2 \sqrt {b^2-c^2}}{a+\sqrt {b^2-c^2}}\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}}{\left (a^2-b^2+c^2\right ) \sqrt {\frac {a+b \cosh (x)+c \sinh (x)}{a+\sqrt {b^2-c^2}}}}\\ \end {align*}

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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
time = 5.00, size = 806, normalized size = 5.17 \begin {gather*} \frac {2 \left (a b+\left (b^2-c^2\right ) \cosh (x)\right )-\frac {2 b^3 (a+b \cosh (x)+c \sinh (x))}{b^2-c^2}+\frac {2 a F_1\left (\frac {1}{2};\frac {1}{2},\frac {1}{2};\frac {3}{2};\frac {a+b \cosh (x)+c \sinh (x)}{a+i \sqrt {1-\frac {b^2}{c^2}} c},\frac {a+b \cosh (x)+c \sinh (x)}{a-i \sqrt {1-\frac {b^2}{c^2}} c}\right ) \text {sech}\left (x+\tanh ^{-1}\left (\frac {b}{c}\right )\right ) (a+b \cosh (x)+c \sinh (x)) \sqrt {-\frac {-i \sqrt {1-\frac {b^2}{c^2}} c+b \cosh (x)+c \sinh (x)}{a+i \sqrt {1-\frac {b^2}{c^2}} c}} \sqrt {-\frac {i \sqrt {1-\frac {b^2}{c^2}} c+b \cosh (x)+c \sinh (x)}{a-i \sqrt {1-\frac {b^2}{c^2}} c}}}{\sqrt {1-\frac {b^2}{c^2}}}+\frac {b c \sinh \left (x+\tanh ^{-1}\left (\frac {c}{b}\right )\right )}{\sqrt {1-\frac {c^2}{b^2}}}-\frac {b c F_1\left (-\frac {1}{2};-\frac {1}{2},-\frac {1}{2};\frac {1}{2};\frac {a+b \cosh (x)+c \sinh (x)}{a+b \sqrt {1-\frac {c^2}{b^2}}},\frac {a+b \cosh (x)+c \sinh (x)}{a-b \sqrt {1-\frac {c^2}{b^2}}}\right ) \sinh \left (x+\tanh ^{-1}\left (\frac {c}{b}\right )\right )}{\sqrt {1-\frac {c^2}{b^2}} \sqrt {\frac {b \sqrt {1-\frac {c^2}{b^2}}-b \cosh (x)-c \sinh (x)}{a+b \sqrt {1-\frac {c^2}{b^2}}}} \sqrt {\frac {b \sqrt {1-\frac {c^2}{b^2}}+b \cosh (x)+c \sinh (x)}{-a+b \sqrt {1-\frac {c^2}{b^2}}}}}+\frac {c^2 \left (\frac {2 b^2 (a+b \cosh (x)+c \sinh (x))}{b^2-c^2}-\frac {c \sinh \left (x+\tanh ^{-1}\left (\frac {c}{b}\right )\right )}{\sqrt {1-\frac {c^2}{b^2}}}+\frac {c F_1\left (-\frac {1}{2};-\frac {1}{2},-\frac {1}{2};\frac {1}{2};\frac {a+b \cosh (x)+c \sinh (x)}{a+b \sqrt {1-\frac {c^2}{b^2}}},\frac {a+b \cosh (x)+c \sinh (x)}{a-b \sqrt {1-\frac {c^2}{b^2}}}\right ) \sinh \left (x+\tanh ^{-1}\left (\frac {c}{b}\right )\right )}{\sqrt {1-\frac {c^2}{b^2}} \sqrt {\frac {b \sqrt {1-\frac {c^2}{b^2}}-b \cosh (x)-c \sinh (x)}{a+b \sqrt {1-\frac {c^2}{b^2}}}} \sqrt {\frac {b \sqrt {1-\frac {c^2}{b^2}}+b \cosh (x)+c \sinh (x)}{-a+b \sqrt {1-\frac {c^2}{b^2}}}}}\right )}{b}}{c \left (a^2-b^2+c^2\right ) \sqrt {a+b \cosh (x)+c \sinh (x)}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[(a + b*Cosh[x] + c*Sinh[x])^(-3/2),x]

[Out]

(2*(a*b + (b^2 - c^2)*Cosh[x]) - (2*b^3*(a + b*Cosh[x] + c*Sinh[x]))/(b^2 - c^2) + (2*a*AppellF1[1/2, 1/2, 1/2
, 3/2, (a + b*Cosh[x] + c*Sinh[x])/(a + I*Sqrt[1 - b^2/c^2]*c), (a + b*Cosh[x] + c*Sinh[x])/(a - I*Sqrt[1 - b^
2/c^2]*c)]*Sech[x + ArcTanh[b/c]]*(a + b*Cosh[x] + c*Sinh[x])*Sqrt[-(((-I)*Sqrt[1 - b^2/c^2]*c + b*Cosh[x] + c
*Sinh[x])/(a + I*Sqrt[1 - b^2/c^2]*c))]*Sqrt[-((I*Sqrt[1 - b^2/c^2]*c + b*Cosh[x] + c*Sinh[x])/(a - I*Sqrt[1 -
b^2/c^2]*c))])/Sqrt[1 - b^2/c^2] + (b*c*Sinh[x + ArcTanh[c/b]])/Sqrt[1 - c^2/b^2] - (b*c*AppellF1[-1/2, -1/2,
-1/2, 1/2, (a + b*Cosh[x] + c*Sinh[x])/(a + b*Sqrt[1 - c^2/b^2]), (a + b*Cosh[x] + c*Sinh[x])/(a - b*Sqrt[1 -
c^2/b^2])]*Sinh[x + ArcTanh[c/b]])/(Sqrt[1 - c^2/b^2]*Sqrt[(b*Sqrt[1 - c^2/b^2] - b*Cosh[x] - c*Sinh[x])/(a +
b*Sqrt[1 - c^2/b^2])]*Sqrt[(b*Sqrt[1 - c^2/b^2] + b*Cosh[x] + c*Sinh[x])/(-a + b*Sqrt[1 - c^2/b^2])]) + (c^2*
((2*b^2*(a + b*Cosh[x] + c*Sinh[x]))/(b^2 - c^2) - (c*Sinh[x + ArcTanh[c/b]])/Sqrt[1 - c^2/b^2] + (c*AppellF1[
-1/2, -1/2, -1/2, 1/2, (a + b*Cosh[x] + c*Sinh[x])/(a + b*Sqrt[1 - c^2/b^2]), (a + b*Cosh[x] + c*Sinh[x])/(a -
b*Sqrt[1 - c^2/b^2])]*Sinh[x + ArcTanh[c/b]])/(Sqrt[1 - c^2/b^2]*Sqrt[(b*Sqrt[1 - c^2/b^2] - b*Cosh[x] - c*Si
nh[x])/(a + b*Sqrt[1 - c^2/b^2])]*Sqrt[(b*Sqrt[1 - c^2/b^2] + b*Cosh[x] + c*Sinh[x])/(-a + b*Sqrt[1 - c^2/b^2]
)])))/b)/(c*(a^2 - b^2 + c^2)*Sqrt[a + b*Cosh[x] + c*Sinh[x]])

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1431\) vs. \(2(177)=354\).
time = 3.38, size = 1432, normalized size = 9.18

method	result	size
default	\(\text {Expression too large to display}\)	\(1432\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a+b*cosh(x)+c*sinh(x))^(3/2),x,method=_RETURNVERBOSE)

[Out]

1/2*(2*(b^2-c^2)^(1/2)*arctanh((b^2-c^2)*cosh(x)/((a^2+b^2-c^2)*(b^2-c^2))^(1/2))*(-a^2/(b^2-c^2)^(1/2)*sinh(x
)+a^3/(b^2-c^2))^(1/2)*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*sinh(x)+a*((-b^2+c^2)/(b^2-c^2)^(1/2)*sinh(x)^3+a*sin
h(x)^2)^(1/2)*((a^2+b^2-c^2)*(b^2-c^2))^(1/2)*ln((cosh(x)*sinh(x)*(-2*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*b^4+4*
((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*b^2*c^2-2*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*c^4)+cosh(x)*(2*((a^2+b^2-c^2)*(
b-c)*(b+c))^(1/2)*(b^2-c^2)^(1/2)*a*b^2-2*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*(b^2-c^2)^(1/2)*a*c^2)+sinh(x)*(2*
b^6-6*b^4*c^2+6*b^2*c^4-2*c^6)+2*((-b^2+c^2)/(b^2-c^2)^(1/2)*sinh(x)^3+a*sinh(x)^2)^(1/2)*(b^2-c^2)^(3/2)*(-a^
2/(b^2-c^2)^(1/2)*sinh(x)+a^3/(b^2-c^2))^(1/2)*b^2-2*((-b^2+c^2)/(b^2-c^2)^(1/2)*sinh(x)^3+a*sinh(x)^2)^(1/2)*
(b^2-c^2)^(3/2)*(-a^2/(b^2-c^2)^(1/2)*sinh(x)+a^3/(b^2-c^2))^(1/2)*c^2+2*(b^2-c^2)^(3/2)*a^3-2*a^3*b^2*(b^2-c^
2)^(1/2)+2*a^3*c^2*(b^2-c^2)^(1/2)-2*(b^2-c^2)^(1/2)*a*b^4+4*(b^2-c^2)^(1/2)*a*b^2*c^2-2*(b^2-c^2)^(1/2)*a*c^4
)/(b^2*cosh(x)-c^2*cosh(x)-((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2))/(b^2-c^2)^(3/2))-a*((-b^2+c^2)/(b^2-c^2)^(1/2)*s
inh(x)^3+a*sinh(x)^2)^(1/2)*((a^2+b^2-c^2)*(b^2-c^2))^(1/2)*ln((cosh(x)*sinh(x)*(2*((a^2+b^2-c^2)*(b-c)*(b+c))
^(1/2)*b^4-4*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*b^2*c^2+2*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*c^4)+cosh(x)*(-2*((
a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*(b^2-c^2)^(1/2)*a*b^2+2*((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)*(b^2-c^2)^(1/2)*a*c^
2)+sinh(x)*(2*b^6-6*b^4*c^2+6*b^2*c^4-2*c^6)+2*((-b^2+c^2)/(b^2-c^2)^(1/2)*sinh(x)^3+a*sinh(x)^2)^(1/2)*(b^2-c
^2)^(3/2)*(-a^2/(b^2-c^2)^(1/2)*sinh(x)+a^3/(b^2-c^2))^(1/2)*b^2-2*((-b^2+c^2)/(b^2-c^2)^(1/2)*sinh(x)^3+a*sin
h(x)^2)^(1/2)*(b^2-c^2)^(3/2)*(-a^2/(b^2-c^2)^(1/2)*sinh(x)+a^3/(b^2-c^2))^(1/2)*c^2+2*(b^2-c^2)^(3/2)*a^3-2*a
^3*b^2*(b^2-c^2)^(1/2)+2*a^3*c^2*(b^2-c^2)^(1/2)-2*(b^2-c^2)^(1/2)*a*b^4+4*(b^2-c^2)^(1/2)*a*b^2*c^2-2*(b^2-c^
2)^(1/2)*a*c^4)/(b^2*cosh(x)-c^2*cosh(x)+((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2))/(b^2-c^2)^(3/2)))/((-b^2+c^2)/(b^2
-c^2)^(1/2)*sinh(x)+a)^(1/2)/((a^2+b^2-c^2)*(b^2-c^2))^(1/2)/(-a^2/(b^2-c^2)^(1/2)*sinh(x)+a^3/(b^2-c^2))^(1/2
)/((a^2+b^2-c^2)*(b-c)*(b+c))^(1/2)/sinh(x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cosh(x)+c*sinh(x))^(3/2),x, algorithm="maxima")

[Out]

integrate((b*cosh(x) + c*sinh(x) + a)^(-3/2), x)

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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.22, size = 798, normalized size = 5.12 \begin {gather*} \frac {2 \, {\left ({\left (2 \, \sqrt {2} a^{2} \cosh \left (x\right ) + \sqrt {2} {\left (a b + a c\right )} \cosh \left (x\right )^{2} + \sqrt {2} {\left (a b + a c\right )} \sinh \left (x\right )^{2} + 2 \, {\left (\sqrt {2} a^{2} + \sqrt {2} {\left (a b + a c\right )} \cosh \left (x\right )\right )} \sinh \left (x\right ) + \sqrt {2} {\left (a b - a c\right )}\right )} \sqrt {b + c} {\rm weierstrassPInverse}\left (\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2} + 3 \, c^{2}\right )}}{3 \, {\left (b^{2} + 2 \, b c + c^{2}\right )}}, -\frac {8 \, {\left (8 \, a^{3} - 9 \, a b^{2} + 9 \, a c^{2}\right )}}{27 \, {\left (b^{3} + 3 \, b^{2} c + 3 \, b c^{2} + c^{3}\right )}}, \frac {3 \, {\left (b + c\right )} \cosh \left (x\right ) + 3 \, {\left (b + c\right )} \sinh \left (x\right ) + 2 \, a}{3 \, {\left (b + c\right )}}\right ) - 3 \, {\left (\sqrt {2} {\left (b^{2} + 2 \, b c + c^{2}\right )} \cosh \left (x\right )^{2} + \sqrt {2} {\left (b^{2} + 2 \, b c + c^{2}\right )} \sinh \left (x\right )^{2} + 2 \, \sqrt {2} {\left (a b + a c\right )} \cosh \left (x\right ) + 2 \, {\left (\sqrt {2} {\left (b^{2} + 2 \, b c + c^{2}\right )} \cosh \left (x\right ) + \sqrt {2} {\left (a b + a c\right )}\right )} \sinh \left (x\right ) + \sqrt {2} {\left (b^{2} - c^{2}\right )}\right )} \sqrt {b + c} {\rm weierstrassZeta}\left (\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2} + 3 \, c^{2}\right )}}{3 \, {\left (b^{2} + 2 \, b c + c^{2}\right )}}, -\frac {8 \, {\left (8 \, a^{3} - 9 \, a b^{2} + 9 \, a c^{2}\right )}}{27 \, {\left (b^{3} + 3 \, b^{2} c + 3 \, b c^{2} + c^{3}\right )}}, {\rm weierstrassPInverse}\left (\frac {4 \, {\left (4 \, a^{2} - 3 \, b^{2} + 3 \, c^{2}\right )}}{3 \, {\left (b^{2} + 2 \, b c + c^{2}\right )}}, -\frac {8 \, {\left (8 \, a^{3} - 9 \, a b^{2} + 9 \, a c^{2}\right )}}{27 \, {\left (b^{3} + 3 \, b^{2} c + 3 \, b c^{2} + c^{3}\right )}}, \frac {3 \, {\left (b + c\right )} \cosh \left (x\right ) + 3 \, {\left (b + c\right )} \sinh \left (x\right ) + 2 \, a}{3 \, {\left (b + c\right )}}\right )\right ) - 6 \, {\left ({\left (b^{2} + 2 \, b c + c^{2}\right )} \cosh \left (x\right )^{2} + {\left (b^{2} + 2 \, b c + c^{2}\right )} \sinh \left (x\right )^{2} + {\left (a b + a c\right )} \cosh \left (x\right ) + {\left (a b + a c + 2 \, {\left (b^{2} + 2 \, b c + c^{2}\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )\right )} \sqrt {b \cosh \left (x\right ) + c \sinh \left (x\right ) + a}\right )}}{3 \, {\left (a^{2} b^{2} - b^{4} - c^{4} - {\left (a^{2} - 2 \, b^{2}\right )} c^{2} + {\left (a^{2} b^{2} - b^{4} + a^{2} c^{2} + 2 \, b c^{3} + c^{4} + 2 \, {\left (a^{2} b - b^{3}\right )} c\right )} \cosh \left (x\right )^{2} + {\left (a^{2} b^{2} - b^{4} + a^{2} c^{2} + 2 \, b c^{3} + c^{4} + 2 \, {\left (a^{2} b - b^{3}\right )} c\right )} \sinh \left (x\right )^{2} + 2 \, {\left (a^{3} b - a b^{3} + a b c^{2} + a c^{3} + {\left (a^{3} - a b^{2}\right )} c\right )} \cosh \left (x\right ) + 2 \, {\left (a^{3} b - a b^{3} + a b c^{2} + a c^{3} + {\left (a^{3} - a b^{2}\right )} c + {\left (a^{2} b^{2} - b^{4} + a^{2} c^{2} + 2 \, b c^{3} + c^{4} + 2 \, {\left (a^{2} b - b^{3}\right )} c\right )} \cosh \left (x\right )\right )} \sinh \left (x\right )\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cosh(x)+c*sinh(x))^(3/2),x, algorithm="fricas")

[Out]

2/3*((2*sqrt(2)*a^2*cosh(x) + sqrt(2)*(a*b + a*c)*cosh(x)^2 + sqrt(2)*(a*b + a*c)*sinh(x)^2 + 2*(sqrt(2)*a^2 +
sqrt(2)*(a*b + a*c)*cosh(x))*sinh(x) + sqrt(2)*(a*b - a*c))*sqrt(b + c)*weierstrassPInverse(4/3*(4*a^2 - 3*b^
2 + 3*c^2)/(b^2 + 2*b*c + c^2), -8/27*(8*a^3 - 9*a*b^2 + 9*a*c^2)/(b^3 + 3*b^2*c + 3*b*c^2 + c^3), 1/3*(3*(b +
c)*cosh(x) + 3*(b + c)*sinh(x) + 2*a)/(b + c)) - 3*(sqrt(2)*(b^2 + 2*b*c + c^2)*cosh(x)^2 + sqrt(2)*(b^2 + 2*
b*c + c^2)*sinh(x)^2 + 2*sqrt(2)*(a*b + a*c)*cosh(x) + 2*(sqrt(2)*(b^2 + 2*b*c + c^2)*cosh(x) + sqrt(2)*(a*b +
a*c))*sinh(x) + sqrt(2)*(b^2 - c^2))*sqrt(b + c)*weierstrassZeta(4/3*(4*a^2 - 3*b^2 + 3*c^2)/(b^2 + 2*b*c + c
^2), -8/27*(8*a^3 - 9*a*b^2 + 9*a*c^2)/(b^3 + 3*b^2*c + 3*b*c^2 + c^3), weierstrassPInverse(4/3*(4*a^2 - 3*b^2
+ 3*c^2)/(b^2 + 2*b*c + c^2), -8/27*(8*a^3 - 9*a*b^2 + 9*a*c^2)/(b^3 + 3*b^2*c + 3*b*c^2 + c^3), 1/3*(3*(b +
c)*cosh(x) + 3*(b + c)*sinh(x) + 2*a)/(b + c))) - 6*((b^2 + 2*b*c + c^2)*cosh(x)^2 + (b^2 + 2*b*c + c^2)*sinh(
x)^2 + (a*b + a*c)*cosh(x) + (a*b + a*c + 2*(b^2 + 2*b*c + c^2)*cosh(x))*sinh(x))*sqrt(b*cosh(x) + c*sinh(x) +
a))/(a^2*b^2 - b^4 - c^4 - (a^2 - 2*b^2)*c^2 + (a^2*b^2 - b^4 + a^2*c^2 + 2*b*c^3 + c^4 + 2*(a^2*b - b^3)*c)*
cosh(x)^2 + (a^2*b^2 - b^4 + a^2*c^2 + 2*b*c^3 + c^4 + 2*(a^2*b - b^3)*c)*sinh(x)^2 + 2*(a^3*b - a*b^3 + a*b*c
^2 + a*c^3 + (a^3 - a*b^2)*c)*cosh(x) + 2*(a^3*b - a*b^3 + a*b*c^2 + a*c^3 + (a^3 - a*b^2)*c + (a^2*b^2 - b^4
+ a^2*c^2 + 2*b*c^3 + c^4 + 2*(a^2*b - b^3)*c)*cosh(x))*sinh(x))

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (a + b \cosh {\left (x \right )} + c \sinh {\left (x \right )}\right )^{\frac {3}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cosh(x)+c*sinh(x))**(3/2),x)

[Out]

Integral((a + b*cosh(x) + c*sinh(x))**(-3/2), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a+b*cosh(x)+c*sinh(x))^(3/2),x, algorithm="giac")

[Out]

integrate((b*cosh(x) + c*sinh(x) + a)^(-3/2), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (a+b\,\mathrm {cosh}\left (x\right )+c\,\mathrm {sinh}\left (x\right )\right )}^{3/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(a + b*cosh(x) + c*sinh(x))^(3/2),x)

[Out]

int(1/(a + b*cosh(x) + c*sinh(x))^(3/2), x)

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