Optimal. Leaf size=130 \[ \frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}-\frac {5 \text {ArcTan}\left (1-\sqrt {2} e^x\right )}{8 \sqrt {2}}+\frac {5 \text {ArcTan}\left (1+\sqrt {2} e^x\right )}{8 \sqrt {2}}+\frac {5 \log \left (1-\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}}-\frac {5 \log \left (1+\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}} \]
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Rubi [A]
time = 0.08, antiderivative size = 130, normalized size of antiderivative = 1.00, number of steps
used = 13, number of rules used = 10, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.714, Rules used = {2320, 12,
474, 468, 303, 1176, 631, 210, 1179, 642} \begin {gather*} -\frac {5 \text {ArcTan}\left (1-\sqrt {2} e^x\right )}{8 \sqrt {2}}+\frac {5 \text {ArcTan}\left (\sqrt {2} e^x+1\right )}{8 \sqrt {2}}-\frac {3 e^{3 x}}{4 \left (e^{4 x}+1\right )}+\frac {e^{3 x}}{\left (e^{4 x}+1\right )^2}+\frac {5 \log \left (-\sqrt {2} e^x+e^{2 x}+1\right )}{16 \sqrt {2}}-\frac {5 \log \left (\sqrt {2} e^x+e^{2 x}+1\right )}{16 \sqrt {2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 210
Rule 303
Rule 468
Rule 474
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 2320
Rubi steps
\begin {align*} \int e^x \text {sech}(2 x) \tanh ^2(2 x) \, dx &=\text {Subst}\left (\int \frac {2 x^2 \left (1-x^4\right )^2}{\left (1+x^4\right )^3} \, dx,x,e^x\right )\\ &=2 \text {Subst}\left (\int \frac {x^2 \left (1-x^4\right )^2}{\left (1+x^4\right )^3} \, dx,x,e^x\right )\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {1}{4} \text {Subst}\left (\int \frac {x^2 \left (4-8 x^4\right )}{\left (1+x^4\right )^2} \, dx,x,e^x\right )\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}+\frac {5}{4} \text {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,e^x\right )\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}-\frac {5}{8} \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,e^x\right )+\frac {5}{8} \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,e^x\right )\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}+\frac {5}{16} \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,e^x\right )+\frac {5}{16} \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,e^x\right )+\frac {5 \text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,e^x\right )}{16 \sqrt {2}}+\frac {5 \text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,e^x\right )}{16 \sqrt {2}}\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}+\frac {5 \log \left (1-\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}}-\frac {5 \log \left (1+\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}}+\frac {5 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} e^x\right )}{8 \sqrt {2}}-\frac {5 \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} e^x\right )}{8 \sqrt {2}}\\ &=\frac {e^{3 x}}{\left (1+e^{4 x}\right )^2}-\frac {3 e^{3 x}}{4 \left (1+e^{4 x}\right )}-\frac {5 \tan ^{-1}\left (1-\sqrt {2} e^x\right )}{8 \sqrt {2}}+\frac {5 \tan ^{-1}\left (1+\sqrt {2} e^x\right )}{8 \sqrt {2}}+\frac {5 \log \left (1-\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}}-\frac {5 \log \left (1+\sqrt {2} e^x+e^{2 x}\right )}{16 \sqrt {2}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 9 vs. order 3 in
optimal.
time = 0.05, size = 58, normalized size = 0.45 \begin {gather*} \frac {e^{3 x}-3 e^{7 x}}{4 \left (1+e^{4 x}\right )^2}-\frac {5}{16} \text {RootSum}\left [1+\text {$\#$1}^4\&,\frac {x-\log \left (e^x-\text {$\#$1}\right )}{\text {$\#$1}}\&\right ] \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
3.
time = 1.56, size = 48, normalized size = 0.37
method | result | size |
risch | \(-\frac {{\mathrm e}^{3 x} \left (3 \,{\mathrm e}^{4 x}-1\right )}{4 \left (1+{\mathrm e}^{4 x}\right )^{2}}+2 \left (\munderset {\textit {\_R} =\RootOf \left (1048576 \textit {\_Z}^{4}+625\right )}{\sum }\textit {\_R} \ln \left ({\mathrm e}^{x}+\frac {32768 \textit {\_R}^{3}}{125}\right )\right )\) | \(48\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.48, size = 105, normalized size = 0.81 \begin {gather*} \frac {5}{16} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, e^{x}\right )}\right ) + \frac {5}{16} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, e^{x}\right )}\right ) - \frac {5}{32} \, \sqrt {2} \log \left (\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) + \frac {5}{32} \, \sqrt {2} \log \left (-\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {3 \, e^{\left (7 \, x\right )} - e^{\left (3 \, x\right )}}{4 \, {\left (e^{\left (8 \, x\right )} + 2 \, e^{\left (4 \, x\right )} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 213 vs.
\(2 (93) = 186\).
time = 0.35, size = 213, normalized size = 1.64 \begin {gather*} -\frac {20 \, {\left (\sqrt {2} e^{\left (8 \, x\right )} + 2 \, \sqrt {2} e^{\left (4 \, x\right )} + \sqrt {2}\right )} \arctan \left (-\sqrt {2} e^{x} + \sqrt {2} \sqrt {\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1} - 1\right ) + 20 \, {\left (\sqrt {2} e^{\left (8 \, x\right )} + 2 \, \sqrt {2} e^{\left (4 \, x\right )} + \sqrt {2}\right )} \arctan \left (-\sqrt {2} e^{x} + \frac {1}{2} \, \sqrt {2} \sqrt {-4 \, \sqrt {2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4} + 1\right ) + 5 \, {\left (\sqrt {2} e^{\left (8 \, x\right )} + 2 \, \sqrt {2} e^{\left (4 \, x\right )} + \sqrt {2}\right )} \log \left (4 \, \sqrt {2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4\right ) - 5 \, {\left (\sqrt {2} e^{\left (8 \, x\right )} + 2 \, \sqrt {2} e^{\left (4 \, x\right )} + \sqrt {2}\right )} \log \left (-4 \, \sqrt {2} e^{x} + 4 \, e^{\left (2 \, x\right )} + 4\right ) + 24 \, e^{\left (7 \, x\right )} - 8 \, e^{\left (3 \, x\right )}}{32 \, {\left (e^{\left (8 \, x\right )} + 2 \, e^{\left (4 \, x\right )} + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int e^{x} \tanh ^{2}{\left (2 x \right )} \operatorname {sech}{\left (2 x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.41, size = 99, normalized size = 0.76 \begin {gather*} \frac {5}{16} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, e^{x}\right )}\right ) + \frac {5}{16} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, e^{x}\right )}\right ) - \frac {5}{32} \, \sqrt {2} \log \left (\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) + \frac {5}{32} \, \sqrt {2} \log \left (-\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {3 \, e^{\left (7 \, x\right )} - e^{\left (3 \, x\right )}}{4 \, {\left (e^{\left (4 \, x\right )} + 1\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.09, size = 112, normalized size = 0.86 \begin {gather*} \frac {{\mathrm {e}}^{3\,x}}{2\,{\mathrm {e}}^{4\,x}+{\mathrm {e}}^{8\,x}+1}-\frac {3\,{\mathrm {e}}^{3\,x}}{4\,\left ({\mathrm {e}}^{4\,x}+1\right )}+\sqrt {2}\,\ln \left (\frac {25}{16}+\sqrt {2}\,{\mathrm {e}}^x\,\left (-\frac {25}{32}-\frac {25}{32}{}\mathrm {i}\right )\right )\,\left (\frac {5}{32}+\frac {5}{32}{}\mathrm {i}\right )+\sqrt {2}\,\ln \left (\frac {25}{16}+\sqrt {2}\,{\mathrm {e}}^x\,\left (-\frac {25}{32}+\frac {25}{32}{}\mathrm {i}\right )\right )\,\left (\frac {5}{32}-\frac {5}{32}{}\mathrm {i}\right )+\sqrt {2}\,\ln \left (\frac {25}{16}+\sqrt {2}\,{\mathrm {e}}^x\,\left (\frac {25}{32}-\frac {25}{32}{}\mathrm {i}\right )\right )\,\left (-\frac {5}{32}+\frac {5}{32}{}\mathrm {i}\right )+\sqrt {2}\,\ln \left (\frac {25}{16}+\sqrt {2}\,{\mathrm {e}}^x\,\left (\frac {25}{32}+\frac {25}{32}{}\mathrm {i}\right )\right )\,\left (-\frac {5}{32}-\frac {5}{32}{}\mathrm {i}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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