3.2.28 \(\int (c e+d e x)^3 (a+b \sinh ^{-1}(c+d x))^2 \, dx\) [128]

Optimal. Leaf size=172 \[ -\frac {3 b^2 e^3 (c+d x)^2}{32 d}+\frac {b^2 e^3 (c+d x)^4}{32 d}+\frac {3 b e^3 (c+d x) \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{16 d}-\frac {b e^3 (c+d x)^3 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{8 d}-\frac {3 e^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d} \]

[Out]

-3/32*b^2*e^3*(d*x+c)^2/d+1/32*b^2*e^3*(d*x+c)^4/d-3/32*e^3*(a+b*arcsinh(d*x+c))^2/d+1/4*e^3*(d*x+c)^4*(a+b*ar
csinh(d*x+c))^2/d+3/16*b*e^3*(d*x+c)*(a+b*arcsinh(d*x+c))*(1+(d*x+c)^2)^(1/2)/d-1/8*b*e^3*(d*x+c)^3*(a+b*arcsi
nh(d*x+c))*(1+(d*x+c)^2)^(1/2)/d

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Rubi [A]
time = 0.17, antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {5859, 12, 5776, 5812, 5783, 30} \begin {gather*} \frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d}-\frac {b e^3 \sqrt {(c+d x)^2+1} (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{8 d}+\frac {3 b e^3 \sqrt {(c+d x)^2+1} (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )}{16 d}-\frac {3 e^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{32 d}+\frac {b^2 e^3 (c+d x)^4}{32 d}-\frac {3 b^2 e^3 (c+d x)^2}{32 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(c*e + d*e*x)^3*(a + b*ArcSinh[c + d*x])^2,x]

[Out]

(-3*b^2*e^3*(c + d*x)^2)/(32*d) + (b^2*e^3*(c + d*x)^4)/(32*d) + (3*b*e^3*(c + d*x)*Sqrt[1 + (c + d*x)^2]*(a +
b*ArcSinh[c + d*x]))/(16*d) - (b*e^3*(c + d*x)^3*Sqrt[1 + (c + d*x)^2]*(a + b*ArcSinh[c + d*x]))/(8*d) - (3*e
^3*(a + b*ArcSinh[c + d*x])^2)/(32*d) + (e^3*(c + d*x)^4*(a + b*ArcSinh[c + d*x])^2)/(4*d)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 5776

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[(d*x)^(m + 1)*((a + b*ArcS
inh[c*x])^n/(d*(m + 1))), x] - Dist[b*c*(n/(d*(m + 1))), Int[(d*x)^(m + 1)*((a + b*ArcSinh[c*x])^(n - 1)/Sqrt[
1 + c^2*x^2]), x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] && NeQ[m, -1]

Rule 5783

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(1/(b*c*(n + 1)))*S
imp[Sqrt[1 + c^2*x^2]/Sqrt[d + e*x^2]]*(a + b*ArcSinh[c*x])^(n + 1), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ
[e, c^2*d] && NeQ[n, -1]

Rule 5812

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Simp[
f*(f*x)^(m - 1)*(d + e*x^2)^(p + 1)*((a + b*ArcSinh[c*x])^n/(e*(m + 2*p + 1))), x] + (-Dist[f^2*((m - 1)/(c^2*
(m + 2*p + 1))), Int[(f*x)^(m - 2)*(d + e*x^2)^p*(a + b*ArcSinh[c*x])^n, x], x] - Dist[b*f*(n/(c*(m + 2*p + 1)
))*Simp[(d + e*x^2)^p/(1 + c^2*x^2)^p], Int[(f*x)^(m - 1)*(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1)
, x], x]) /; FreeQ[{a, b, c, d, e, f, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && IGtQ[m, 1] && NeQ[m + 2*p + 1, 0
]

Rule 5859

Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[1/d, Subst[
Int[((d*e - c*f)/d + f*(x/d))^m*(a + b*ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x
]

Rubi steps

\begin {align*} \int (c e+d e x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2 \, dx &=\frac {\text {Subst}\left (\int e^3 x^3 \left (a+b \sinh ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^3 \text {Subst}\left (\int x^3 \left (a+b \sinh ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d}-\frac {\left (b e^3\right ) \text {Subst}\left (\int \frac {x^4 \left (a+b \sinh ^{-1}(x)\right )}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{2 d}\\ &=-\frac {b e^3 (c+d x)^3 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{8 d}+\frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d}+\frac {\left (3 b e^3\right ) \text {Subst}\left (\int \frac {x^2 \left (a+b \sinh ^{-1}(x)\right )}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{8 d}+\frac {\left (b^2 e^3\right ) \text {Subst}\left (\int x^3 \, dx,x,c+d x\right )}{8 d}\\ &=\frac {b^2 e^3 (c+d x)^4}{32 d}+\frac {3 b e^3 (c+d x) \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{16 d}-\frac {b e^3 (c+d x)^3 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{8 d}+\frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d}-\frac {\left (3 b e^3\right ) \text {Subst}\left (\int \frac {a+b \sinh ^{-1}(x)}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{16 d}-\frac {\left (3 b^2 e^3\right ) \text {Subst}(\int x \, dx,x,c+d x)}{16 d}\\ &=-\frac {3 b^2 e^3 (c+d x)^2}{32 d}+\frac {b^2 e^3 (c+d x)^4}{32 d}+\frac {3 b e^3 (c+d x) \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{16 d}-\frac {b e^3 (c+d x)^3 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{8 d}-\frac {3 e^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{32 d}+\frac {e^3 (c+d x)^4 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{4 d}\\ \end {align*}

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Mathematica [A]
time = 0.13, size = 170, normalized size = 0.99 \begin {gather*} \frac {e^3 \left (-3 b^2 (c+d x)^2+\left (8 a^2+b^2\right ) (c+d x)^4+2 a b (c+d x) \left (3-2 (c+d x)^2\right ) \sqrt {1+(c+d x)^2}-6 a b \sinh ^{-1}(c+d x)+2 b (c+d x) \left (8 a (c+d x)^3+3 b \sqrt {1+(c+d x)^2}-2 b (c+d x)^2 \sqrt {1+(c+d x)^2}\right ) \sinh ^{-1}(c+d x)+b^2 \left (-3+8 (c+d x)^4\right ) \sinh ^{-1}(c+d x)^2\right )}{32 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(c*e + d*e*x)^3*(a + b*ArcSinh[c + d*x])^2,x]

[Out]

(e^3*(-3*b^2*(c + d*x)^2 + (8*a^2 + b^2)*(c + d*x)^4 + 2*a*b*(c + d*x)*(3 - 2*(c + d*x)^2)*Sqrt[1 + (c + d*x)^
2] - 6*a*b*ArcSinh[c + d*x] + 2*b*(c + d*x)*(8*a*(c + d*x)^3 + 3*b*Sqrt[1 + (c + d*x)^2] - 2*b*(c + d*x)^2*Sqr
t[1 + (c + d*x)^2])*ArcSinh[c + d*x] + b^2*(-3 + 8*(c + d*x)^4)*ArcSinh[c + d*x]^2))/(32*d)

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Maple [A]
time = 3.54, size = 222, normalized size = 1.29

method	result	size
default	\(\frac {e^{3} \left (d x +c \right )^{4} a^{2}}{4 d}-\frac {e^{3} b^{2} \left (-16 \left (\cosh ^{2}\left (2 \arcsinh \left (d x +c \right )\right )\right ) \arcsinh \left (d x +c \right )^{2}+8 \sinh \left (2 \arcsinh \left (d x +c \right )\right ) \cosh \left (2 \arcsinh \left (d x +c \right )\right ) \arcsinh \left (d x +c \right )+32 \cosh \left (2 \arcsinh \left (d x +c \right )\right ) \arcsinh \left (d x +c \right )^{2}-32 \arcsinh \left (d x +c \right ) \sinh \left (2 \arcsinh \left (d x +c \right )\right )-2 \left (\cosh ^{2}\left (2 \arcsinh \left (d x +c \right )\right )\right )+8 \arcsinh \left (d x +c \right )^{2}+16 \cosh \left (2 \arcsinh \left (d x +c \right )\right )+1\right )}{256 d}+\frac {2 e^{3} a b \left (\frac {\left (d x +c \right )^{4} \arcsinh \left (d x +c \right )}{4}-\frac {\left (d x +c \right )^{3} \sqrt {1+\left (d x +c \right )^{2}}}{16}+\frac {3 \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}}{32}-\frac {3 \arcsinh \left (d x +c \right )}{32}\right )}{d}\)	\(222\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*e*x+c*e)^3*(a+b*arcsinh(d*x+c))^2,x,method=_RETURNVERBOSE)

[Out]

1/4*e^3*(d*x+c)^4*a^2/d-1/256*e^3*b^2*(-16*cosh(2*arcsinh(d*x+c))^2*arcsinh(d*x+c)^2+8*sinh(2*arcsinh(d*x+c))*
cosh(2*arcsinh(d*x+c))*arcsinh(d*x+c)+32*cosh(2*arcsinh(d*x+c))*arcsinh(d*x+c)^2-32*arcsinh(d*x+c)*sinh(2*arcs
inh(d*x+c))-2*cosh(2*arcsinh(d*x+c))^2+8*arcsinh(d*x+c)^2+16*cosh(2*arcsinh(d*x+c))+1)/d+2*e^3*a*b/d*(1/4*(d*x
+c)^4*arcsinh(d*x+c)-1/16*(d*x+c)^3*(1+(d*x+c)^2)^(1/2)+3/32*(d*x+c)*(1+(d*x+c)^2)^(1/2)-3/32*arcsinh(d*x+c))

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsinh(d*x+c))^2,x, algorithm="maxima")

[Out]

1/4*a^2*d^3*x^4*e^3 + a^2*c*d^2*x^3*e^3 + 3/2*a^2*c^2*d*x^2*e^3 + 3/2*(2*x^2*arcsinh(d*x + c) - d*(3*c^2*arcsi
nh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^3 + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*x/d^2 - (c^2 +
1)*arcsinh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^3 - 3*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*c/d^3
))*a*b*c^2*d*e^3 + 1/3*(6*x^3*arcsinh(d*x + c) - d*(2*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*x^2/d^2 - 15*c^3*arcsi
nh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^4 - 5*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*c*x/d^3 + 9*(
c^2 + 1)*c*arcsinh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^4 + 15*sqrt(d^2*x^2 + 2*c*d*x + c^2 +
1)*c^2/d^4 - 4*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*(c^2 + 1)/d^4))*a*b*c*d^2*e^3 + 1/48*(24*x^4*arcsinh(d*x + c
) - (6*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*x^3/d^2 - 14*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*c*x^2/d^3 + 105*c^4*ar
csinh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^5 + 35*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*c^2*x/d^4
- 90*(c^2 + 1)*c^2*arcsinh(2*(d^2*x + c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^5 - 105*sqrt(d^2*x^2 + 2*c*d
*x + c^2 + 1)*c^3/d^5 - 9*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*(c^2 + 1)*x/d^4 + 9*(c^2 + 1)^2*arcsinh(2*(d^2*x +
c*d)/sqrt(-4*c^2*d^2 + 4*(c^2 + 1)*d^2))/d^5 + 55*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*(c^2 + 1)*c/d^5)*d)*a*b*d
^3*e^3 + a^2*c^3*x*e^3 + 2*((d*x + c)*arcsinh(d*x + c) - sqrt((d*x + c)^2 + 1))*a*b*c^3*e^3/d + 1/4*(b^2*d^3*x
^4*e^3 + 4*b^2*c*d^2*x^3*e^3 + 6*b^2*c^2*d*x^2*e^3 + 4*b^2*c^3*x*e^3)*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c
^2 + 1))^2 - integrate(1/2*(b^2*d^6*x^6*e^3 + 6*b^2*c*d^5*x^5*e^3 + (15*b^2*c^2*d^4 + b^2*d^4)*x^4*e^3 + 4*(5*
b^2*c^3*d^3 + b^2*c*d^3)*x^3*e^3 + 2*(7*b^2*c^4*d^2 + 3*b^2*c^2*d^2)*x^2*e^3 + 4*(b^2*c^5*d + b^2*c^3*d)*x*e^3
+ (b^2*d^5*x^5*e^3 + 5*b^2*c*d^4*x^4*e^3 + 10*b^2*c^2*d^3*x^3*e^3 + 10*b^2*c^3*d^2*x^2*e^3 + 4*b^2*c^4*d*x*e^
3)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))/(d^3*x^3 + 3*c*d^2*x^2
+ c^3 + (3*c^2*d + d)*x + (d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + c), x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1477 vs. \(2 (150) = 300\).
time = 0.38, size = 1477, normalized size = 8.59 \begin {gather*} \frac {{\left ({\left (8 \, a^{2} + b^{2}\right )} d^{4} x^{4} + 4 \, {\left (8 \, a^{2} + b^{2}\right )} c d^{3} x^{3} + 3 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{2} - b^{2}\right )} d^{2} x^{2} + 2 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{3} - 3 \, b^{2} c\right )} d x\right )} \cosh \left (1\right )^{3} + 3 \, {\left ({\left (8 \, a^{2} + b^{2}\right )} d^{4} x^{4} + 4 \, {\left (8 \, a^{2} + b^{2}\right )} c d^{3} x^{3} + 3 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{2} - b^{2}\right )} d^{2} x^{2} + 2 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{3} - 3 \, b^{2} c\right )} d x\right )} \cosh \left (1\right )^{2} \sinh \left (1\right ) + 3 \, {\left ({\left (8 \, a^{2} + b^{2}\right )} d^{4} x^{4} + 4 \, {\left (8 \, a^{2} + b^{2}\right )} c d^{3} x^{3} + 3 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{2} - b^{2}\right )} d^{2} x^{2} + 2 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{3} - 3 \, b^{2} c\right )} d x\right )} \cosh \left (1\right ) \sinh \left (1\right )^{2} + {\left ({\left (8 \, a^{2} + b^{2}\right )} d^{4} x^{4} + 4 \, {\left (8 \, a^{2} + b^{2}\right )} c d^{3} x^{3} + 3 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{2} - b^{2}\right )} d^{2} x^{2} + 2 \, {\left (2 \, {\left (8 \, a^{2} + b^{2}\right )} c^{3} - 3 \, b^{2} c\right )} d x\right )} \sinh \left (1\right )^{3} + {\left ({\left (8 \, b^{2} d^{4} x^{4} + 32 \, b^{2} c d^{3} x^{3} + 48 \, b^{2} c^{2} d^{2} x^{2} + 32 \, b^{2} c^{3} d x + 8 \, b^{2} c^{4} - 3 \, b^{2}\right )} \cosh \left (1\right )^{3} + 3 \, {\left (8 \, b^{2} d^{4} x^{4} + 32 \, b^{2} c d^{3} x^{3} + 48 \, b^{2} c^{2} d^{2} x^{2} + 32 \, b^{2} c^{3} d x + 8 \, b^{2} c^{4} - 3 \, b^{2}\right )} \cosh \left (1\right )^{2} \sinh \left (1\right ) + 3 \, {\left (8 \, b^{2} d^{4} x^{4} + 32 \, b^{2} c d^{3} x^{3} + 48 \, b^{2} c^{2} d^{2} x^{2} + 32 \, b^{2} c^{3} d x + 8 \, b^{2} c^{4} - 3 \, b^{2}\right )} \cosh \left (1\right ) \sinh \left (1\right )^{2} + {\left (8 \, b^{2} d^{4} x^{4} + 32 \, b^{2} c d^{3} x^{3} + 48 \, b^{2} c^{2} d^{2} x^{2} + 32 \, b^{2} c^{3} d x + 8 \, b^{2} c^{4} - 3 \, b^{2}\right )} \sinh \left (1\right )^{3}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{2} + 2 \, {\left ({\left (8 \, a b d^{4} x^{4} + 32 \, a b c d^{3} x^{3} + 48 \, a b c^{2} d^{2} x^{2} + 32 \, a b c^{3} d x + 8 \, a b c^{4} - 3 \, a b\right )} \cosh \left (1\right )^{3} + 3 \, {\left (8 \, a b d^{4} x^{4} + 32 \, a b c d^{3} x^{3} + 48 \, a b c^{2} d^{2} x^{2} + 32 \, a b c^{3} d x + 8 \, a b c^{4} - 3 \, a b\right )} \cosh \left (1\right )^{2} \sinh \left (1\right ) + 3 \, {\left (8 \, a b d^{4} x^{4} + 32 \, a b c d^{3} x^{3} + 48 \, a b c^{2} d^{2} x^{2} + 32 \, a b c^{3} d x + 8 \, a b c^{4} - 3 \, a b\right )} \cosh \left (1\right ) \sinh \left (1\right )^{2} + {\left (8 \, a b d^{4} x^{4} + 32 \, a b c d^{3} x^{3} + 48 \, a b c^{2} d^{2} x^{2} + 32 \, a b c^{3} d x + 8 \, a b c^{4} - 3 \, a b\right )} \sinh \left (1\right )^{3} - \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1} {\left ({\left (2 \, b^{2} d^{3} x^{3} + 6 \, b^{2} c d^{2} x^{2} + 2 \, b^{2} c^{3} - 3 \, b^{2} c + 3 \, {\left (2 \, b^{2} c^{2} - b^{2}\right )} d x\right )} \cosh \left (1\right )^{3} + 3 \, {\left (2 \, b^{2} d^{3} x^{3} + 6 \, b^{2} c d^{2} x^{2} + 2 \, b^{2} c^{3} - 3 \, b^{2} c + 3 \, {\left (2 \, b^{2} c^{2} - b^{2}\right )} d x\right )} \cosh \left (1\right )^{2} \sinh \left (1\right ) + 3 \, {\left (2 \, b^{2} d^{3} x^{3} + 6 \, b^{2} c d^{2} x^{2} + 2 \, b^{2} c^{3} - 3 \, b^{2} c + 3 \, {\left (2 \, b^{2} c^{2} - b^{2}\right )} d x\right )} \cosh \left (1\right ) \sinh \left (1\right )^{2} + {\left (2 \, b^{2} d^{3} x^{3} + 6 \, b^{2} c d^{2} x^{2} + 2 \, b^{2} c^{3} - 3 \, b^{2} c + 3 \, {\left (2 \, b^{2} c^{2} - b^{2}\right )} d x\right )} \sinh \left (1\right )^{3}\right )}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right ) - 2 \, \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1} {\left ({\left (2 \, a b d^{3} x^{3} + 6 \, a b c d^{2} x^{2} + 2 \, a b c^{3} - 3 \, a b c + 3 \, {\left (2 \, a b c^{2} - a b\right )} d x\right )} \cosh \left (1\right )^{3} + 3 \, {\left (2 \, a b d^{3} x^{3} + 6 \, a b c d^{2} x^{2} + 2 \, a b c^{3} - 3 \, a b c + 3 \, {\left (2 \, a b c^{2} - a b\right )} d x\right )} \cosh \left (1\right )^{2} \sinh \left (1\right ) + 3 \, {\left (2 \, a b d^{3} x^{3} + 6 \, a b c d^{2} x^{2} + 2 \, a b c^{3} - 3 \, a b c + 3 \, {\left (2 \, a b c^{2} - a b\right )} d x\right )} \cosh \left (1\right ) \sinh \left (1\right )^{2} + {\left (2 \, a b d^{3} x^{3} + 6 \, a b c d^{2} x^{2} + 2 \, a b c^{3} - 3 \, a b c + 3 \, {\left (2 \, a b c^{2} - a b\right )} d x\right )} \sinh \left (1\right )^{3}\right )}}{32 \, d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsinh(d*x+c))^2,x, algorithm="fricas")

[Out]

1/32*(((8*a^2 + b^2)*d^4*x^4 + 4*(8*a^2 + b^2)*c*d^3*x^3 + 3*(2*(8*a^2 + b^2)*c^2 - b^2)*d^2*x^2 + 2*(2*(8*a^2
+ b^2)*c^3 - 3*b^2*c)*d*x)*cosh(1)^3 + 3*((8*a^2 + b^2)*d^4*x^4 + 4*(8*a^2 + b^2)*c*d^3*x^3 + 3*(2*(8*a^2 + b
^2)*c^2 - b^2)*d^2*x^2 + 2*(2*(8*a^2 + b^2)*c^3 - 3*b^2*c)*d*x)*cosh(1)^2*sinh(1) + 3*((8*a^2 + b^2)*d^4*x^4 +
4*(8*a^2 + b^2)*c*d^3*x^3 + 3*(2*(8*a^2 + b^2)*c^2 - b^2)*d^2*x^2 + 2*(2*(8*a^2 + b^2)*c^3 - 3*b^2*c)*d*x)*co
sh(1)*sinh(1)^2 + ((8*a^2 + b^2)*d^4*x^4 + 4*(8*a^2 + b^2)*c*d^3*x^3 + 3*(2*(8*a^2 + b^2)*c^2 - b^2)*d^2*x^2 +
2*(2*(8*a^2 + b^2)*c^3 - 3*b^2*c)*d*x)*sinh(1)^3 + ((8*b^2*d^4*x^4 + 32*b^2*c*d^3*x^3 + 48*b^2*c^2*d^2*x^2 +
32*b^2*c^3*d*x + 8*b^2*c^4 - 3*b^2)*cosh(1)^3 + 3*(8*b^2*d^4*x^4 + 32*b^2*c*d^3*x^3 + 48*b^2*c^2*d^2*x^2 + 32*
b^2*c^3*d*x + 8*b^2*c^4 - 3*b^2)*cosh(1)^2*sinh(1) + 3*(8*b^2*d^4*x^4 + 32*b^2*c*d^3*x^3 + 48*b^2*c^2*d^2*x^2
+ 32*b^2*c^3*d*x + 8*b^2*c^4 - 3*b^2)*cosh(1)*sinh(1)^2 + (8*b^2*d^4*x^4 + 32*b^2*c*d^3*x^3 + 48*b^2*c^2*d^2*x
^2 + 32*b^2*c^3*d*x + 8*b^2*c^4 - 3*b^2)*sinh(1)^3)*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))^2 + 2*((8
*a*b*d^4*x^4 + 32*a*b*c*d^3*x^3 + 48*a*b*c^2*d^2*x^2 + 32*a*b*c^3*d*x + 8*a*b*c^4 - 3*a*b)*cosh(1)^3 + 3*(8*a*
b*d^4*x^4 + 32*a*b*c*d^3*x^3 + 48*a*b*c^2*d^2*x^2 + 32*a*b*c^3*d*x + 8*a*b*c^4 - 3*a*b)*cosh(1)^2*sinh(1) + 3*
(8*a*b*d^4*x^4 + 32*a*b*c*d^3*x^3 + 48*a*b*c^2*d^2*x^2 + 32*a*b*c^3*d*x + 8*a*b*c^4 - 3*a*b)*cosh(1)*sinh(1)^2
+ (8*a*b*d^4*x^4 + 32*a*b*c*d^3*x^3 + 48*a*b*c^2*d^2*x^2 + 32*a*b*c^3*d*x + 8*a*b*c^4 - 3*a*b)*sinh(1)^3 - sq
rt(d^2*x^2 + 2*c*d*x + c^2 + 1)*((2*b^2*d^3*x^3 + 6*b^2*c*d^2*x^2 + 2*b^2*c^3 - 3*b^2*c + 3*(2*b^2*c^2 - b^2)*
d*x)*cosh(1)^3 + 3*(2*b^2*d^3*x^3 + 6*b^2*c*d^2*x^2 + 2*b^2*c^3 - 3*b^2*c + 3*(2*b^2*c^2 - b^2)*d*x)*cosh(1)^2
*sinh(1) + 3*(2*b^2*d^3*x^3 + 6*b^2*c*d^2*x^2 + 2*b^2*c^3 - 3*b^2*c + 3*(2*b^2*c^2 - b^2)*d*x)*cosh(1)*sinh(1)
^2 + (2*b^2*d^3*x^3 + 6*b^2*c*d^2*x^2 + 2*b^2*c^3 - 3*b^2*c + 3*(2*b^2*c^2 - b^2)*d*x)*sinh(1)^3))*log(d*x + c
+ sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)) - 2*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)*((2*a*b*d^3*x^3 + 6*a*b*c*d^2*x^2
+ 2*a*b*c^3 - 3*a*b*c + 3*(2*a*b*c^2 - a*b)*d*x)*cosh(1)^3 + 3*(2*a*b*d^3*x^3 + 6*a*b*c*d^2*x^2 + 2*a*b*c^3 -
3*a*b*c + 3*(2*a*b*c^2 - a*b)*d*x)*cosh(1)^2*sinh(1) + 3*(2*a*b*d^3*x^3 + 6*a*b*c*d^2*x^2 + 2*a*b*c^3 - 3*a*b*
c + 3*(2*a*b*c^2 - a*b)*d*x)*cosh(1)*sinh(1)^2 + (2*a*b*d^3*x^3 + 6*a*b*c*d^2*x^2 + 2*a*b*c^3 - 3*a*b*c + 3*(2
*a*b*c^2 - a*b)*d*x)*sinh(1)^3))/d

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 916 vs. \(2 (155) = 310\).
time = 0.58, size = 916, normalized size = 5.33 \begin {gather*} \begin {cases} a^{2} c^{3} e^{3} x + \frac {3 a^{2} c^{2} d e^{3} x^{2}}{2} + a^{2} c d^{2} e^{3} x^{3} + \frac {a^{2} d^{3} e^{3} x^{4}}{4} + \frac {a b c^{4} e^{3} \operatorname {asinh}{\left (c + d x \right )}}{2 d} + 2 a b c^{3} e^{3} x \operatorname {asinh}{\left (c + d x \right )} - \frac {a b c^{3} e^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{8 d} + 3 a b c^{2} d e^{3} x^{2} \operatorname {asinh}{\left (c + d x \right )} - \frac {3 a b c^{2} e^{3} x \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{8} + 2 a b c d^{2} e^{3} x^{3} \operatorname {asinh}{\left (c + d x \right )} - \frac {3 a b c d e^{3} x^{2} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{8} + \frac {3 a b c e^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16 d} + \frac {a b d^{3} e^{3} x^{4} \operatorname {asinh}{\left (c + d x \right )}}{2} - \frac {a b d^{2} e^{3} x^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{8} + \frac {3 a b e^{3} x \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1}}{16} - \frac {3 a b e^{3} \operatorname {asinh}{\left (c + d x \right )}}{16 d} + \frac {b^{2} c^{4} e^{3} \operatorname {asinh}^{2}{\left (c + d x \right )}}{4 d} + b^{2} c^{3} e^{3} x \operatorname {asinh}^{2}{\left (c + d x \right )} + \frac {b^{2} c^{3} e^{3} x}{8} - \frac {b^{2} c^{3} e^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{8 d} + \frac {3 b^{2} c^{2} d e^{3} x^{2} \operatorname {asinh}^{2}{\left (c + d x \right )}}{2} + \frac {3 b^{2} c^{2} d e^{3} x^{2}}{16} - \frac {3 b^{2} c^{2} e^{3} x \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{8} + b^{2} c d^{2} e^{3} x^{3} \operatorname {asinh}^{2}{\left (c + d x \right )} + \frac {b^{2} c d^{2} e^{3} x^{3}}{8} - \frac {3 b^{2} c d e^{3} x^{2} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{8} - \frac {3 b^{2} c e^{3} x}{16} + \frac {3 b^{2} c e^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{16 d} + \frac {b^{2} d^{3} e^{3} x^{4} \operatorname {asinh}^{2}{\left (c + d x \right )}}{4} + \frac {b^{2} d^{3} e^{3} x^{4}}{32} - \frac {b^{2} d^{2} e^{3} x^{3} \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{8} - \frac {3 b^{2} d e^{3} x^{2}}{32} + \frac {3 b^{2} e^{3} x \sqrt {c^{2} + 2 c d x + d^{2} x^{2} + 1} \operatorname {asinh}{\left (c + d x \right )}}{16} - \frac {3 b^{2} e^{3} \operatorname {asinh}^{2}{\left (c + d x \right )}}{32 d} & \text {for}\: d \neq 0 \\c^{3} e^{3} x \left (a + b \operatorname {asinh}{\left (c \right )}\right )^{2} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)**3*(a+b*asinh(d*x+c))**2,x)

[Out]

Piecewise((a**2*c**3*e**3*x + 3*a**2*c**2*d*e**3*x**2/2 + a**2*c*d**2*e**3*x**3 + a**2*d**3*e**3*x**4/4 + a*b*
c**4*e**3*asinh(c + d*x)/(2*d) + 2*a*b*c**3*e**3*x*asinh(c + d*x) - a*b*c**3*e**3*sqrt(c**2 + 2*c*d*x + d**2*x
**2 + 1)/(8*d) + 3*a*b*c**2*d*e**3*x**2*asinh(c + d*x) - 3*a*b*c**2*e**3*x*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1
)/8 + 2*a*b*c*d**2*e**3*x**3*asinh(c + d*x) - 3*a*b*c*d*e**3*x**2*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)/8 + 3*a
*b*c*e**3*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)/(16*d) + a*b*d**3*e**3*x**4*asinh(c + d*x)/2 - a*b*d**2*e**3*x*
*3*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)/8 + 3*a*b*e**3*x*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)/16 - 3*a*b*e**3*
asinh(c + d*x)/(16*d) + b**2*c**4*e**3*asinh(c + d*x)**2/(4*d) + b**2*c**3*e**3*x*asinh(c + d*x)**2 + b**2*c**
3*e**3*x/8 - b**2*c**3*e**3*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)*asinh(c + d*x)/(8*d) + 3*b**2*c**2*d*e**3*x**
2*asinh(c + d*x)**2/2 + 3*b**2*c**2*d*e**3*x**2/16 - 3*b**2*c**2*e**3*x*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)*a
sinh(c + d*x)/8 + b**2*c*d**2*e**3*x**3*asinh(c + d*x)**2 + b**2*c*d**2*e**3*x**3/8 - 3*b**2*c*d*e**3*x**2*sqr
t(c**2 + 2*c*d*x + d**2*x**2 + 1)*asinh(c + d*x)/8 - 3*b**2*c*e**3*x/16 + 3*b**2*c*e**3*sqrt(c**2 + 2*c*d*x +
d**2*x**2 + 1)*asinh(c + d*x)/(16*d) + b**2*d**3*e**3*x**4*asinh(c + d*x)**2/4 + b**2*d**3*e**3*x**4/32 - b**2
*d**2*e**3*x**3*sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)*asinh(c + d*x)/8 - 3*b**2*d*e**3*x**2/32 + 3*b**2*e**3*x*
sqrt(c**2 + 2*c*d*x + d**2*x**2 + 1)*asinh(c + d*x)/16 - 3*b**2*e**3*asinh(c + d*x)**2/(32*d), Ne(d, 0)), (c**
3*e**3*x*(a + b*asinh(c))**2, True))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)^3*(a+b*arcsinh(d*x+c))^2,x, algorithm="giac")

[Out]

integrate((d*e*x + c*e)^3*(b*arcsinh(d*x + c) + a)^2, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\left (c\,e+d\,e\,x\right )}^3\,{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^2 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*e + d*e*x)^3*(a + b*asinh(c + d*x))^2,x)

[Out]

int((c*e + d*e*x)^3*(a + b*asinh(c + d*x))^2, x)

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