Optimal. Leaf size=164 \[ \frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {\sqrt {b} e e^{\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {Erf}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {b} e e^{-\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {Erfi}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d} \]
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Rubi [A]
time = 0.31, antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps
used = 11, number of rules used = 9, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.391, Rules used = {5859, 12,
5777, 5819, 3393, 3388, 2211, 2236, 2235} \begin {gather*} -\frac {\sqrt {\frac {\pi }{2}} \sqrt {b} e e^{\frac {2 a}{b}} \text {Erf}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {\frac {\pi }{2}} \sqrt {b} e e^{-\frac {2 a}{b}} \text {Erfi}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}+\frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2211
Rule 2235
Rule 2236
Rule 3388
Rule 3393
Rule 5777
Rule 5819
Rule 5859
Rubi steps
\begin {align*} \int (c e+d e x) \sqrt {a+b \sinh ^{-1}(c+d x)} \, dx &=\frac {\text {Subst}\left (\int e x \sqrt {a+b \sinh ^{-1}(x)} \, dx,x,c+d x\right )}{d}\\ &=\frac {e \text {Subst}\left (\int x \sqrt {a+b \sinh ^{-1}(x)} \, dx,x,c+d x\right )}{d}\\ &=\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {(b e) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2} \sqrt {a+b \sinh ^{-1}(x)}} \, dx,x,c+d x\right )}{4 d}\\ &=\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {(b e) \text {Subst}\left (\int \frac {\sinh ^2(x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 d}\\ &=\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}+\frac {(b e) \text {Subst}\left (\int \left (\frac {1}{2 \sqrt {a+b x}}-\frac {\cosh (2 x)}{2 \sqrt {a+b x}}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 d}\\ &=\frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {(b e) \text {Subst}\left (\int \frac {\cosh (2 x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{8 d}\\ &=\frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {(b e) \text {Subst}\left (\int \frac {e^{-2 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{16 d}-\frac {(b e) \text {Subst}\left (\int \frac {e^{2 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{16 d}\\ &=\frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {e \text {Subst}\left (\int e^{\frac {2 a}{b}-\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{8 d}-\frac {e \text {Subst}\left (\int e^{-\frac {2 a}{b}+\frac {2 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{8 d}\\ &=\frac {e \sqrt {a+b \sinh ^{-1}(c+d x)}}{4 d}+\frac {e (c+d x)^2 \sqrt {a+b \sinh ^{-1}(c+d x)}}{2 d}-\frac {\sqrt {b} e e^{\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erf}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d}-\frac {\sqrt {b} e e^{-\frac {2 a}{b}} \sqrt {\frac {\pi }{2}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{16 d}\\ \end {align*}
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Mathematica [A]
time = 0.08, size = 140, normalized size = 0.85 \begin {gather*} \frac {e e^{-\frac {2 a}{b}} \sqrt {a+b \sinh ^{-1}(c+d x)} \left (\sqrt {\frac {a}{b}+\sinh ^{-1}(c+d x)} \Gamma \left (\frac {3}{2},-\frac {2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )+e^{\frac {4 a}{b}} \sqrt {-\frac {a+b \sinh ^{-1}(c+d x)}{b}} \Gamma \left (\frac {3}{2},\frac {2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )\right )}{8 \sqrt {2} d \sqrt {-\frac {\left (a+b \sinh ^{-1}(c+d x)\right )^2}{b^2}}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \left (d e x +c e \right ) \sqrt {a +b \arcsinh \left (d x +c \right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} e \left (\int c \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}}\, dx + \int d x \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \left (c\,e+d\,e\,x\right )\,\sqrt {a+b\,\mathrm {asinh}\left (c+d\,x\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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