3.3.75 \(\int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \sinh ^{-1}(a+b x)} \, dx\) [275]

Optimal. Leaf size=11 \[ \frac {\log \left (\sinh ^{-1}(a+b x)\right )}{b} \]

[Out]

ln(arcsinh(b*x+a))/b

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Rubi [A]
time = 0.05, antiderivative size = 11, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {5860, 5782} \begin {gather*} \frac {\log \left (\sinh ^{-1}(a+b x)\right )}{b} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2]*ArcSinh[a + b*x]),x]

[Out]

Log[ArcSinh[a + b*x]]/b

Rule 5782

Int[1/(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))*Sqrt[(d_) + (e_.)*(x_)^2]), x_Symbol] :> Simp[(1/(b*c))*Simp[Sqrt[1
+ c^2*x^2]/Sqrt[d + e*x^2]]*Log[a + b*ArcSinh[c*x]], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d]

Rule 5860

Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((A_.) + (B_.)*(x_) + (C_.)*(x_)^2)^(p_.), x_Symbol] :> D
ist[1/d, Subst[Int[(C/d^2 + (C/d^2)*x^2)^p*(a + b*ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, A,
B, C, n, p}, x] && EqQ[B*(1 + c^2) - 2*A*c*d, 0] && EqQ[2*c*C - B*d, 0]

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {1+a^2+2 a b x+b^2 x^2} \sinh ^{-1}(a+b x)} \, dx &=\frac {\text {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \sinh ^{-1}(x)} \, dx,x,a+b x\right )}{b}\\ &=\frac {\log \left (\sinh ^{-1}(a+b x)\right )}{b}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 11, normalized size = 1.00 \begin {gather*} \frac {\log \left (\sinh ^{-1}(a+b x)\right )}{b} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2]*ArcSinh[a + b*x]),x]

[Out]

Log[ArcSinh[a + b*x]]/b

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Maple [A]
time = 3.03, size = 12, normalized size = 1.09

method	result	size
default	\(\frac {\ln \left (\arcsinh \left (b x +a \right )\right )}{b}\)	\(12\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/arcsinh(b*x+a)/(b^2*x^2+2*a*b*x+a^2+1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

ln(arcsinh(b*x+a))/b

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsinh(b*x+a)/(b^2*x^2+2*a*b*x+a^2+1)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*arcsinh(b*x + a)), x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 30 vs. \(2 (11) = 22\).
time = 0.35, size = 30, normalized size = 2.73 \begin {gather*} \frac {\log \left (\log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )\right )}{b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsinh(b*x+a)/(b^2*x^2+2*a*b*x+a^2+1)^(1/2),x, algorithm="fricas")

[Out]

log(log(b*x + a + sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)))/b

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 22 vs. \(2 (8) = 16\).
time = 0.65, size = 22, normalized size = 2.00 \begin {gather*} \begin {cases} \frac {\log {\left (\operatorname {asinh}{\left (a + b x \right )} \right )}}{b} & \text {for}\: b \neq 0 \\\frac {x}{\sqrt {a^{2} + 1} \operatorname {asinh}{\left (a \right )}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/asinh(b*x+a)/(b**2*x**2+2*a*b*x+a**2+1)**(1/2),x)

[Out]

Piecewise((log(asinh(a + b*x))/b, Ne(b, 0)), (x/(sqrt(a**2 + 1)*asinh(a)), True))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/arcsinh(b*x+a)/(b^2*x^2+2*a*b*x+a^2+1)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*arcsinh(b*x + a)), x)

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Mupad [B]
time = 0.22, size = 11, normalized size = 1.00 \begin {gather*} \frac {\ln \left (\mathrm {asinh}\left (a+b\,x\right )\right )}{b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(asinh(a + b*x)*(a^2 + b^2*x^2 + 2*a*b*x + 1)^(1/2)),x)

[Out]

log(asinh(a + b*x))/b

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