Optimal. Leaf size=355 \[ \frac {14 \sqrt {1+(a+b x)^2}}{9 b^3}-\frac {6 a^2 \sqrt {1+(a+b x)^2}}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2}}{4 b^3}-\frac {2 \left (1+(a+b x)^2\right )^{3/2}}{27 b^3}-\frac {3 a \sinh ^{-1}(a+b x)}{4 b^3}-\frac {4 (a+b x) \sinh ^{-1}(a+b x)}{3 b^3}+\frac {6 a^2 (a+b x) \sinh ^{-1}(a+b x)}{b^3}-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}+\frac {2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {(a+b x)^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {a \sinh ^{-1}(a+b x)^3}{2 b^3}+\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3 \]
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Rubi [A]
time = 0.32, antiderivative size = 355, normalized size of antiderivative = 1.00, number of steps
used = 18, number of rules used = 11, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.917, Rules used = {5859, 5828,
5843, 3398, 3377, 2718, 3392, 30, 2715, 8, 2713} \begin {gather*} \frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}-\frac {6 a^2 \sqrt {(a+b x)^2+1}}{b^3}+\frac {6 a^2 (a+b x) \sinh ^{-1}(a+b x)}{b^3}-\frac {3 a^2 \sqrt {(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a \sqrt {(a+b x)^2+1} (a+b x)}{4 b^3}-\frac {2 \left ((a+b x)^2+1\right )^{3/2}}{27 b^3}+\frac {14 \sqrt {(a+b x)^2+1}}{9 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}-\frac {\sqrt {(a+b x)^2+1} (a+b x)^2 \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {3 a \sqrt {(a+b x)^2+1} (a+b x) \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {4 (a+b x) \sinh ^{-1}(a+b x)}{3 b^3}-\frac {a \sinh ^{-1}(a+b x)^3}{2 b^3}+\frac {2 \sqrt {(a+b x)^2+1} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a \sinh ^{-1}(a+b x)}{4 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 30
Rule 2713
Rule 2715
Rule 2718
Rule 3377
Rule 3392
Rule 3398
Rule 5828
Rule 5843
Rule 5859
Rubi steps
\begin {align*} \int x^2 \sinh ^{-1}(a+b x)^3 \, dx &=\frac {\text {Subst}\left (\int \left (-\frac {a}{b}+\frac {x}{b}\right )^2 \sinh ^{-1}(x)^3 \, dx,x,a+b x\right )}{b}\\ &=\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3-\text {Subst}\left (\int \frac {\left (-\frac {a}{b}+\frac {x}{b}\right )^3 \sinh ^{-1}(x)^2}{\sqrt {1+x^2}} \, dx,x,a+b x\right )\\ &=\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3-\text {Subst}\left (\int x^2 \left (-\frac {a}{b}+\frac {\sinh (x)}{b}\right )^3 \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3-\text {Subst}\left (\int \left (-\frac {a^3 x^2}{b^3}+\frac {3 a^2 x^2 \sinh (x)}{b^3}-\frac {3 a x^2 \sinh ^2(x)}{b^3}+\frac {x^2 \sinh ^3(x)}{b^3}\right ) \, dx,x,\sinh ^{-1}(a+b x)\right )\\ &=\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3-\frac {\text {Subst}\left (\int x^2 \sinh ^3(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^3}+\frac {(3 a) \text {Subst}\left (\int x^2 \sinh ^2(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^3}-\frac {\left (3 a^2\right ) \text {Subst}\left (\int x^2 \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^3}\\ &=-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}-\frac {3 a^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {(a+b x)^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}+\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3-\frac {2 \text {Subst}\left (\int \sinh ^3(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{9 b^3}+\frac {2 \text {Subst}\left (\int x^2 \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{3 b^3}-\frac {(3 a) \text {Subst}\left (\int x^2 \, dx,x,\sinh ^{-1}(a+b x)\right )}{2 b^3}+\frac {(3 a) \text {Subst}\left (\int \sinh ^2(x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{2 b^3}+\frac {\left (6 a^2\right ) \text {Subst}\left (\int x \cosh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^3}\\ &=\frac {3 a (a+b x) \sqrt {1+(a+b x)^2}}{4 b^3}+\frac {6 a^2 (a+b x) \sinh ^{-1}(a+b x)}{b^3}-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}+\frac {2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {(a+b x)^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {a \sinh ^{-1}(a+b x)^3}{2 b^3}+\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3+\frac {2 \text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\sqrt {1+(a+b x)^2}\right )}{9 b^3}-\frac {4 \text {Subst}\left (\int x \cosh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{3 b^3}-\frac {(3 a) \text {Subst}\left (\int 1 \, dx,x,\sinh ^{-1}(a+b x)\right )}{4 b^3}-\frac {\left (6 a^2\right ) \text {Subst}\left (\int \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{b^3}\\ &=\frac {2 \sqrt {1+(a+b x)^2}}{9 b^3}-\frac {6 a^2 \sqrt {1+(a+b x)^2}}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2}}{4 b^3}-\frac {2 \left (1+(a+b x)^2\right )^{3/2}}{27 b^3}-\frac {3 a \sinh ^{-1}(a+b x)}{4 b^3}-\frac {4 (a+b x) \sinh ^{-1}(a+b x)}{3 b^3}+\frac {6 a^2 (a+b x) \sinh ^{-1}(a+b x)}{b^3}-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}+\frac {2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {(a+b x)^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {a \sinh ^{-1}(a+b x)^3}{2 b^3}+\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3+\frac {4 \text {Subst}\left (\int \sinh (x) \, dx,x,\sinh ^{-1}(a+b x)\right )}{3 b^3}\\ &=\frac {14 \sqrt {1+(a+b x)^2}}{9 b^3}-\frac {6 a^2 \sqrt {1+(a+b x)^2}}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2}}{4 b^3}-\frac {2 \left (1+(a+b x)^2\right )^{3/2}}{27 b^3}-\frac {3 a \sinh ^{-1}(a+b x)}{4 b^3}-\frac {4 (a+b x) \sinh ^{-1}(a+b x)}{3 b^3}+\frac {6 a^2 (a+b x) \sinh ^{-1}(a+b x)}{b^3}-\frac {3 a (a+b x)^2 \sinh ^{-1}(a+b x)}{2 b^3}+\frac {2 (a+b x)^3 \sinh ^{-1}(a+b x)}{9 b^3}+\frac {2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {3 a^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{b^3}+\frac {3 a (a+b x) \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{2 b^3}-\frac {(a+b x)^2 \sqrt {1+(a+b x)^2} \sinh ^{-1}(a+b x)^2}{3 b^3}-\frac {a \sinh ^{-1}(a+b x)^3}{2 b^3}+\frac {a^3 \sinh ^{-1}(a+b x)^3}{3 b^3}+\frac {1}{3} x^3 \sinh ^{-1}(a+b x)^3\\ \end {align*}
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Mathematica [A]
time = 0.13, size = 175, normalized size = 0.49 \begin {gather*} \frac {\left (160-575 a^2+65 a b x-8 b^2 x^2\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}+3 \left (170 a^3+132 a^2 b x+8 b x \left (-6+b^2 x^2\right )-15 a \left (5+2 b^2 x^2\right )\right ) \sinh ^{-1}(a+b x)-18 \sqrt {1+a^2+2 a b x+b^2 x^2} \left (-4+11 a^2-5 a b x+2 b^2 x^2\right ) \sinh ^{-1}(a+b x)^2+18 \left (-3 a+2 a^3+2 b^3 x^3\right ) \sinh ^{-1}(a+b x)^3}{108 b^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int x^{2} \arcsinh \left (b x +a \right )^{3}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 225, normalized size = 0.63 \begin {gather*} \frac {18 \, {\left (2 \, b^{3} x^{3} + 2 \, a^{3} - 3 \, a\right )} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{3} - 18 \, {\left (2 \, b^{2} x^{2} - 5 \, a b x + 11 \, a^{2} - 4\right )} \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{2} + 3 \, {\left (8 \, b^{3} x^{3} - 30 \, a b^{2} x^{2} + 170 \, a^{3} + 12 \, {\left (11 \, a^{2} - 4\right )} b x - 75 \, a\right )} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right ) - {\left (8 \, b^{2} x^{2} - 65 \, a b x + 575 \, a^{2} - 160\right )} \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{108 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.45, size = 432, normalized size = 1.22 \begin {gather*} \begin {cases} \frac {a^{3} \operatorname {asinh}^{3}{\left (a + b x \right )}}{3 b^{3}} + \frac {85 a^{3} \operatorname {asinh}{\left (a + b x \right )}}{18 b^{3}} + \frac {11 a^{2} x \operatorname {asinh}{\left (a + b x \right )}}{3 b^{2}} - \frac {11 a^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname {asinh}^{2}{\left (a + b x \right )}}{6 b^{3}} - \frac {575 a^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{108 b^{3}} - \frac {5 a x^{2} \operatorname {asinh}{\left (a + b x \right )}}{6 b} + \frac {5 a x \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname {asinh}^{2}{\left (a + b x \right )}}{6 b^{2}} + \frac {65 a x \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{108 b^{2}} - \frac {a \operatorname {asinh}^{3}{\left (a + b x \right )}}{2 b^{3}} - \frac {25 a \operatorname {asinh}{\left (a + b x \right )}}{12 b^{3}} + \frac {x^{3} \operatorname {asinh}^{3}{\left (a + b x \right )}}{3} + \frac {2 x^{3} \operatorname {asinh}{\left (a + b x \right )}}{9} - \frac {x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname {asinh}^{2}{\left (a + b x \right )}}{3 b} - \frac {2 x^{2} \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{27 b} - \frac {4 x \operatorname {asinh}{\left (a + b x \right )}}{3 b^{2}} + \frac {2 \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname {asinh}^{2}{\left (a + b x \right )}}{3 b^{3}} + \frac {40 \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{27 b^{3}} & \text {for}\: b \neq 0 \\\frac {x^{3} \operatorname {asinh}^{3}{\left (a \right )}}{3} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^2\,{\mathrm {asinh}\left (a+b\,x\right )}^3 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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