Optimal. Leaf size=151 \[ \frac {2 \sqrt {e (c+d x)} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e}-\frac {8 b \sqrt {1-c-d x} (e (c+d x))^{3/2} \left (a+b \cosh ^{-1}(c+d x)\right ) \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};(c+d x)^2\right )}{3 d e^2 \sqrt {-1+c+d x}}-\frac {16 b^2 (e (c+d x))^{5/2} \, _3F_2\left (1,\frac {5}{4},\frac {5}{4};\frac {7}{4},\frac {9}{4};(c+d x)^2\right )}{15 d e^3} \]
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Rubi [A]
time = 0.19, antiderivative size = 151, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 3, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {5996, 5883,
5949} \begin {gather*} -\frac {16 b^2 (e (c+d x))^{5/2} \, _3F_2\left (1,\frac {5}{4},\frac {5}{4};\frac {7}{4},\frac {9}{4};(c+d x)^2\right )}{15 d e^3}-\frac {8 b \sqrt {-c-d x+1} (e (c+d x))^{3/2} \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};(c+d x)^2\right ) \left (a+b \cosh ^{-1}(c+d x)\right )}{3 d e^2 \sqrt {c+d x-1}}+\frac {2 \sqrt {e (c+d x)} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e} \end {gather*}
Antiderivative was successfully verified.
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Rule 5883
Rule 5949
Rule 5996
Rubi steps
\begin {align*} \int \frac {\left (a+b \cosh ^{-1}(c+d x)\right )^2}{\sqrt {c e+d e x}} \, dx &=\frac {\text {Subst}\left (\int \frac {\left (a+b \cosh ^{-1}(x)\right )^2}{\sqrt {e x}} \, dx,x,c+d x\right )}{d}\\ &=\frac {2 \sqrt {e (c+d x)} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e}-\frac {(4 b) \text {Subst}\left (\int \frac {\sqrt {e x} \left (a+b \cosh ^{-1}(x)\right )}{\sqrt {-1+x} \sqrt {1+x}} \, dx,x,c+d x\right )}{d e}\\ &=\frac {2 \sqrt {e (c+d x)} \left (a+b \cosh ^{-1}(c+d x)\right )^2}{d e}-\frac {8 b (e (c+d x))^{3/2} \sqrt {1-(c+d x)^2} \left (a+b \cosh ^{-1}(c+d x)\right ) \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};(c+d x)^2\right )}{3 d e^2 \sqrt {-1+c+d x} \sqrt {1+c+d x}}-\frac {16 b^2 (e (c+d x))^{5/2} \, _3F_2\left (1,\frac {5}{4},\frac {5}{4};\frac {7}{4},\frac {9}{4};(c+d x)^2\right )}{15 d e^3}\\ \end {align*}
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Mathematica [A]
time = 0.21, size = 140, normalized size = 0.93 \begin {gather*} \frac {2 \sqrt {e (c+d x)} \left (15 \left (a+b \cosh ^{-1}(c+d x)\right )^2-4 b (c+d x) \left (\frac {5 \sqrt {1-(c+d x)^2} \left (a+b \cosh ^{-1}(c+d x)\right ) \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};(c+d x)^2\right )}{\sqrt {-1+c+d x} \sqrt {1+c+d x}}+2 b (c+d x) \, _3F_2\left (1,\frac {5}{4},\frac {5}{4};\frac {7}{4},\frac {9}{4};(c+d x)^2\right )\right )\right )}{15 d e} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {\left (a +b \,\mathrm {arccosh}\left (d x +c \right )\right )^{2}}{\sqrt {d e x +c e}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b \operatorname {acosh}{\left (c + d x \right )}\right )^{2}}{\sqrt {e \left (c + d x\right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (a+b\,\mathrm {acosh}\left (c+d\,x\right )\right )}^2}{\sqrt {c\,e+d\,e\,x}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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