3.5.48 \(\int e^{\tanh ^{-1}(a x)} (c-\frac {c}{a x})^4 \, dx\) [448]

Optimal. Leaf size=125 \[ -\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {3 c^4 \text {ArcSin}(a x)}{a}-\frac {c^4 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )}{2 a} \]

[Out]

-1/3*c^4*(-a^2*x^2+1)^(3/2)/a^4/x^3+3/2*c^4*(-a^2*x^2+1)^(3/2)/a^3/x^2-3*c^4*arcsin(a*x)/a-1/2*c^4*arctanh((-a
^2*x^2+1)^(1/2))/a-1/2*c^4*(-a*x+6)*(-a^2*x^2+1)^(1/2)/a^2/x

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Rubi [A]
time = 0.18, antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 9, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.450, Rules used = {6266, 6263, 1821, 827, 858, 222, 272, 65, 214} \begin {gather*} -\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )}{2 a}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {3 c^4 \text {ArcSin}(a x)}{a} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[E^ArcTanh[a*x]*(c - c/(a*x))^4,x]

[Out]

-1/2*(c^4*(6 - a*x)*Sqrt[1 - a^2*x^2])/(a^2*x) - (c^4*(1 - a^2*x^2)^(3/2))/(3*a^4*x^3) + (3*c^4*(1 - a^2*x^2)^
(3/2))/(2*a^3*x^2) - (3*c^4*ArcSin[a*x])/a - (c^4*ArcTanh[Sqrt[1 - a^2*x^2]])/(2*a)

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 222

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 827

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(d + e*x)^(m
+ 1)*(e*f*(m + 2*p + 2) - d*g*(2*p + 1) + e*g*(m + 1)*x)*((a + c*x^2)^p/(e^2*(m + 1)*(m + 2*p + 2))), x] + Di
st[p/(e^2*(m + 1)*(m + 2*p + 2)), Int[(d + e*x)^(m + 1)*(a + c*x^2)^(p - 1)*Simp[g*(2*a*e + 2*a*e*m) + (g*(2*c
*d + 4*c*d*p) - 2*c*e*f*(m + 2*p + 2))*x, x], x], x] /; FreeQ[{a, c, d, e, f, g, m}, x] && NeQ[c*d^2 + a*e^2,
0] && RationalQ[p] && p > 0 && (LtQ[m, -1] || EqQ[p, 1] || (IntegerQ[p] &&  !RationalQ[m])) && NeQ[m, -1] &&
!ILtQ[m + 2*p + 1, 0] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p])

Rule 858

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[g/e, Int[(d
+ e*x)^(m + 1)*(a + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + c*x^2)^p, x], x] /; FreeQ[{a,
c, d, e, f, g, m, p}, x] && NeQ[c*d^2 + a*e^2, 0] &&  !IGtQ[m, 0]

Rule 1821

Int[(Pq_)*((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuotient[Pq, c*x, x],
R = PolynomialRemainder[Pq, c*x, x]}, Simp[R*(c*x)^(m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] + Dist[1/(
a*c*(m + 1)), Int[(c*x)^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*c*(m + 1)*Q - b*R*(m + 2*p + 3)*x, x], x], x]] /;
FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] && LtQ[m, -1] && (IntegerQ[2*p] || NeQ[Expon[Pq, x], 1])

Rule 6263

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_))^(p_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[c^n,
Int[(e + f*x)^m*(c + d*x)^(p - n)*(1 - a^2*x^2)^(n/2), x], x] /; FreeQ[{a, c, d, e, f, m, p}, x] && EqQ[a*c +
d, 0] && IntegerQ[(n - 1)/2] && (IntegerQ[p] || EqQ[p, n/2] || EqQ[p - n/2 - 1, 0]) && IntegerQ[2*p]

Rule 6266

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_))^(p_.), x_Symbol] :> Dist[d^p, Int[u*(1 + c*(x/d))^
p*(E^(n*ArcTanh[a*x])/x^p), x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[c^2 - a^2*d^2, 0] && IntegerQ[p]

Rubi steps

\begin {align*} \int e^{\tanh ^{-1}(a x)} \left (c-\frac {c}{a x}\right )^4 \, dx &=\frac {c^4 \int \frac {e^{\tanh ^{-1}(a x)} (1-a x)^4}{x^4} \, dx}{a^4}\\ &=\frac {c^4 \int \frac {(1-a x)^3 \sqrt {1-a^2 x^2}}{x^4} \, dx}{a^4}\\ &=-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}-\frac {c^4 \int \frac {\sqrt {1-a^2 x^2} \left (9 a-9 a^2 x+3 a^3 x^2\right )}{x^3} \, dx}{3 a^4}\\ &=-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}+\frac {c^4 \int \frac {\left (18 a^2+3 a^3 x\right ) \sqrt {1-a^2 x^2}}{x^2} \, dx}{6 a^4}\\ &=-\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {c^4 \int \frac {-6 a^3+36 a^4 x}{x \sqrt {1-a^2 x^2}} \, dx}{12 a^4}\\ &=-\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\left (3 c^4\right ) \int \frac {1}{\sqrt {1-a^2 x^2}} \, dx+\frac {c^4 \int \frac {1}{x \sqrt {1-a^2 x^2}} \, dx}{2 a}\\ &=-\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {3 c^4 \sin ^{-1}(a x)}{a}+\frac {c^4 \text {Subst}\left (\int \frac {1}{x \sqrt {1-a^2 x}} \, dx,x,x^2\right )}{4 a}\\ &=-\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {3 c^4 \sin ^{-1}(a x)}{a}-\frac {c^4 \text {Subst}\left (\int \frac {1}{\frac {1}{a^2}-\frac {x^2}{a^2}} \, dx,x,\sqrt {1-a^2 x^2}\right )}{2 a^3}\\ &=-\frac {c^4 (6-a x) \sqrt {1-a^2 x^2}}{2 a^2 x}-\frac {c^4 \left (1-a^2 x^2\right )^{3/2}}{3 a^4 x^3}+\frac {3 c^4 \left (1-a^2 x^2\right )^{3/2}}{2 a^3 x^2}-\frac {3 c^4 \sin ^{-1}(a x)}{a}-\frac {c^4 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )}{2 a}\\ \end {align*}

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Mathematica [A]
time = 0.12, size = 86, normalized size = 0.69 \begin {gather*} \frac {c^4 \left (-\frac {\sqrt {1-a^2 x^2} \left (2-9 a x+16 a^2 x^2+6 a^3 x^3\right )}{a^3 x^3}-18 \text {ArcSin}(a x)+3 \log (a x)-3 \log \left (1+\sqrt {1-a^2 x^2}\right )\right )}{6 a} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[E^ArcTanh[a*x]*(c - c/(a*x))^4,x]

[Out]

(c^4*(-((Sqrt[1 - a^2*x^2]*(2 - 9*a*x + 16*a^2*x^2 + 6*a^3*x^3))/(a^3*x^3)) - 18*ArcSin[a*x] + 3*Log[a*x] - 3*
Log[1 + Sqrt[1 - a^2*x^2]]))/(6*a)

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Maple [A]
time = 0.75, size = 150, normalized size = 1.20

method	result	size
risch	\(\frac {\left (16 a^{4} x^{4}-9 a^{3} x^{3}-14 a^{2} x^{2}+9 a x -2\right ) c^{4}}{6 x^{3} \sqrt {-a^{2} x^{2}+1}\, a^{4}}+\frac {\left (-a^{3} \sqrt {-a^{2} x^{2}+1}-\frac {3 a^{4} \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{\sqrt {a^{2}}}-\frac {a^{3} \arctanh \left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right ) c^{4}}{a^{4}}\)	\(128\)
default	\(\frac {c^{4} \left (-a^{3} \sqrt {-a^{2} x^{2}+1}-\frac {3 a^{4} \arctan \left (\frac {\sqrt {a^{2}}\, x}{\sqrt {-a^{2} x^{2}+1}}\right )}{\sqrt {a^{2}}}-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {8 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}-3 a \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \arctanh \left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )-2 a^{3} \arctanh \left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )\right )}{a^{4}}\)	\(150\)
meijerg	\(-\frac {c^{4} \left (-2 \sqrt {\pi }+2 \sqrt {\pi }\, \sqrt {-a^{2} x^{2}+1}\right )}{2 a \sqrt {\pi }}-\frac {3 c^{4} \arcsin \left (a x \right )}{a}+\frac {c^{4} \left (-2 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )+\left (-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }\right )}{a \sqrt {\pi }}-\frac {2 c^{4} \sqrt {-a^{2} x^{2}+1}}{a^{2} x}+\frac {3 c^{4} \left (-\frac {\sqrt {\pi }\, \left (-4 a^{2} x^{2}+8\right )}{8 a^{2} x^{2}}+\frac {\sqrt {\pi }\, \sqrt {-a^{2} x^{2}+1}}{a^{2} x^{2}}+\sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {-a^{2} x^{2}+1}}{2}\right )-\frac {\left (1-2 \ln \left (2\right )+2 \ln \left (x \right )+\ln \left (-a^{2}\right )\right ) \sqrt {\pi }}{2}+\frac {\sqrt {\pi }}{x^{2} a^{2}}\right )}{2 a \sqrt {\pi }}-\frac {c^{4} \left (2 a^{2} x^{2}+1\right ) \sqrt {-a^{2} x^{2}+1}}{3 a^{4} x^{3}}\)	\(263\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)/(-a^2*x^2+1)^(1/2)*(c-c/a/x)^4,x,method=_RETURNVERBOSE)

[Out]

c^4/a^4*(-a^3*(-a^2*x^2+1)^(1/2)-3*a^4/(a^2)^(1/2)*arctan((a^2)^(1/2)*x/(-a^2*x^2+1)^(1/2))-1/3*(-a^2*x^2+1)^(
1/2)/x^3-8/3*a^2*(-a^2*x^2+1)^(1/2)/x-3*a*(-1/2*(-a^2*x^2+1)^(1/2)/x^2-1/2*a^2*arctanh(1/(-a^2*x^2+1)^(1/2)))-
2*a^3*arctanh(1/(-a^2*x^2+1)^(1/2)))

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Maxima [A]
time = 0.47, size = 190, normalized size = 1.52 \begin {gather*} -\frac {3 \, c^{4} \arcsin \left (a x\right )}{a} - \frac {2 \, c^{4} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right )}{a} - \frac {\sqrt {-a^{2} x^{2} + 1} c^{4}}{a} + \frac {3 \, {\left (a^{2} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) + \frac {\sqrt {-a^{2} x^{2} + 1}}{x^{2}}\right )} c^{4}}{2 \, a^{3}} - \frac {2 \, \sqrt {-a^{2} x^{2} + 1} c^{4}}{a^{2} x} - \frac {{\left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1} a^{2}}{x} + \frac {\sqrt {-a^{2} x^{2} + 1}}{x^{3}}\right )} c^{4}}{3 \, a^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(c-c/a/x)^4,x, algorithm="maxima")

[Out]

-3*c^4*arcsin(a*x)/a - 2*c^4*log(2*sqrt(-a^2*x^2 + 1)/abs(x) + 2/abs(x))/a - sqrt(-a^2*x^2 + 1)*c^4/a + 3/2*(a
^2*log(2*sqrt(-a^2*x^2 + 1)/abs(x) + 2/abs(x)) + sqrt(-a^2*x^2 + 1)/x^2)*c^4/a^3 - 2*sqrt(-a^2*x^2 + 1)*c^4/(a
^2*x) - 1/3*(2*sqrt(-a^2*x^2 + 1)*a^2/x + sqrt(-a^2*x^2 + 1)/x^3)*c^4/a^4

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Fricas [A]
time = 0.35, size = 132, normalized size = 1.06 \begin {gather*} \frac {36 \, a^{3} c^{4} x^{3} \arctan \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{a x}\right ) + 3 \, a^{3} c^{4} x^{3} \log \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{x}\right ) - 6 \, a^{3} c^{4} x^{3} - {\left (6 \, a^{3} c^{4} x^{3} + 16 \, a^{2} c^{4} x^{2} - 9 \, a c^{4} x + 2 \, c^{4}\right )} \sqrt {-a^{2} x^{2} + 1}}{6 \, a^{4} x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(c-c/a/x)^4,x, algorithm="fricas")

[Out]

1/6*(36*a^3*c^4*x^3*arctan((sqrt(-a^2*x^2 + 1) - 1)/(a*x)) + 3*a^3*c^4*x^3*log((sqrt(-a^2*x^2 + 1) - 1)/x) - 6
*a^3*c^4*x^3 - (6*a^3*c^4*x^3 + 16*a^2*c^4*x^2 - 9*a*c^4*x + 2*c^4)*sqrt(-a^2*x^2 + 1))/(a^4*x^3)

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Sympy [A]
time = 7.03, size = 355, normalized size = 2.84 \begin {gather*} a c^{4} \left (\begin {cases} \frac {x^{2}}{2} & \text {for}\: a^{2} = 0 \\- \frac {\sqrt {- a^{2} x^{2} + 1}}{a^{2}} & \text {otherwise} \end {cases}\right ) - 3 c^{4} \left (\begin {cases} \sqrt {\frac {1}{a^{2}}} \operatorname {asin}{\left (x \sqrt {a^{2}} \right )} & \text {for}\: a^{2} > 0 \\\sqrt {- \frac {1}{a^{2}}} \operatorname {asinh}{\left (x \sqrt {- a^{2}} \right )} & \text {for}\: a^{2} < 0 \end {cases}\right ) + \frac {2 c^{4} \left (\begin {cases} - \operatorname {acosh}{\left (\frac {1}{a x} \right )} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\i \operatorname {asin}{\left (\frac {1}{a x} \right )} & \text {otherwise} \end {cases}\right )}{a} + \frac {2 c^{4} \left (\begin {cases} - \frac {i \sqrt {a^{2} x^{2} - 1}}{x} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\- \frac {\sqrt {- a^{2} x^{2} + 1}}{x} & \text {otherwise} \end {cases}\right )}{a^{2}} - \frac {3 c^{4} \left (\begin {cases} - \frac {a^{2} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{2} + \frac {a}{2 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{2 a x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {i a^{2} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{2} - \frac {i a \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{2 x} & \text {otherwise} \end {cases}\right )}{a^{3}} + \frac {c^{4} \left (\begin {cases} - \frac {2 i a^{2} \sqrt {a^{2} x^{2} - 1}}{3 x} - \frac {i \sqrt {a^{2} x^{2} - 1}}{3 x^{3}} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\- \frac {2 a^{2} \sqrt {- a^{2} x^{2} + 1}}{3 x} - \frac {\sqrt {- a^{2} x^{2} + 1}}{3 x^{3}} & \text {otherwise} \end {cases}\right )}{a^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a**2*x**2+1)**(1/2)*(c-c/a/x)**4,x)

[Out]

a*c**4*Piecewise((x**2/2, Eq(a**2, 0)), (-sqrt(-a**2*x**2 + 1)/a**2, True)) - 3*c**4*Piecewise((sqrt(a**(-2))*
asin(x*sqrt(a**2)), a**2 > 0), (sqrt(-1/a**2)*asinh(x*sqrt(-a**2)), a**2 < 0)) + 2*c**4*Piecewise((-acosh(1/(a
*x)), 1/Abs(a**2*x**2) > 1), (I*asin(1/(a*x)), True))/a + 2*c**4*Piecewise((-I*sqrt(a**2*x**2 - 1)/x, Abs(a**2
*x**2) > 1), (-sqrt(-a**2*x**2 + 1)/x, True))/a**2 - 3*c**4*Piecewise((-a**2*acosh(1/(a*x))/2 + a/(2*x*sqrt(-1
+ 1/(a**2*x**2))) - 1/(2*a*x**3*sqrt(-1 + 1/(a**2*x**2))), 1/Abs(a**2*x**2) > 1), (I*a**2*asin(1/(a*x))/2 - I
*a*sqrt(1 - 1/(a**2*x**2))/(2*x), True))/a**3 + c**4*Piecewise((-2*I*a**2*sqrt(a**2*x**2 - 1)/(3*x) - I*sqrt(a
**2*x**2 - 1)/(3*x**3), Abs(a**2*x**2) > 1), (-2*a**2*sqrt(-a**2*x**2 + 1)/(3*x) - sqrt(-a**2*x**2 + 1)/(3*x**
3), True))/a**4

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 263 vs. \(2 (108) = 216\).
time = 0.44, size = 263, normalized size = 2.10 \begin {gather*} \frac {{\left (c^{4} - \frac {9 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} c^{4}}{a^{2} x} + \frac {33 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} c^{4}}{a^{4} x^{2}}\right )} a^{6} x^{3}}{24 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} {\left | a \right |}} - \frac {3 \, c^{4} \arcsin \left (a x\right ) \mathrm {sgn}\left (a\right )}{{\left | a \right |}} - \frac {c^{4} \log \left (\frac {{\left | -2 \, \sqrt {-a^{2} x^{2} + 1} {\left | a \right |} - 2 \, a \right |}}{2 \, a^{2} {\left | x \right |}}\right )}{2 \, {\left | a \right |}} - \frac {\sqrt {-a^{2} x^{2} + 1} c^{4}}{a} - \frac {\frac {33 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} c^{4}}{x} - \frac {9 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} c^{4}}{a^{2} x^{2}} + \frac {{\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} c^{4}}{a^{4} x^{3}}}{24 \, a^{2} {\left | a \right |}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)*(c-c/a/x)^4,x, algorithm="giac")

[Out]

1/24*(c^4 - 9*(sqrt(-a^2*x^2 + 1)*abs(a) + a)*c^4/(a^2*x) + 33*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^2*c^4/(a^4*x^2)
)*a^6*x^3/((sqrt(-a^2*x^2 + 1)*abs(a) + a)^3*abs(a)) - 3*c^4*arcsin(a*x)*sgn(a)/abs(a) - 1/2*c^4*log(1/2*abs(-
2*sqrt(-a^2*x^2 + 1)*abs(a) - 2*a)/(a^2*abs(x)))/abs(a) - sqrt(-a^2*x^2 + 1)*c^4/a - 1/24*(33*(sqrt(-a^2*x^2 +
1)*abs(a) + a)*c^4/x - 9*(sqrt(-a^2*x^2 + 1)*abs(a) + a)^2*c^4/(a^2*x^2) + (sqrt(-a^2*x^2 + 1)*abs(a) + a)^3*
c^4/(a^4*x^3))/(a^2*abs(a))

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Mupad [B]
time = 0.05, size = 137, normalized size = 1.10 \begin {gather*} \frac {3\,c^4\,\sqrt {1-a^2\,x^2}}{2\,a^3\,x^2}-\frac {c^4\,\sqrt {1-a^2\,x^2}}{a}-\frac {8\,c^4\,\sqrt {1-a^2\,x^2}}{3\,a^2\,x}-\frac {3\,c^4\,\mathrm {asinh}\left (x\,\sqrt {-a^2}\right )}{\sqrt {-a^2}}-\frac {c^4\,\sqrt {1-a^2\,x^2}}{3\,a^4\,x^3}+\frac {c^4\,\mathrm {atan}\left (\sqrt {1-a^2\,x^2}\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2\,a} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((c - c/(a*x))^4*(a*x + 1))/(1 - a^2*x^2)^(1/2),x)

[Out]

(c^4*atan((1 - a^2*x^2)^(1/2)*1i)*1i)/(2*a) - (3*c^4*asinh(x*(-a^2)^(1/2)))/(-a^2)^(1/2) - (c^4*(1 - a^2*x^2)^
(1/2))/a - (8*c^4*(1 - a^2*x^2)^(1/2))/(3*a^2*x) + (3*c^4*(1 - a^2*x^2)^(1/2))/(2*a^3*x^2) - (c^4*(1 - a^2*x^2
)^(1/2))/(3*a^4*x^3)

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