3.9.67 \(\int \frac {e^{-3 \tanh ^{-1}(a+b x)}}{x^4} \, dx\) [867]

Optimal. Leaf size=257 \[ -\frac {\left (52-51 a+2 a^2\right ) b^3 \sqrt {1-a-b x}}{6 (1-a) (1+a)^4 \sqrt {1+a+b x}}-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}+\frac {\left (11-18 a+6 a^2\right ) b^3 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {1+a+b x}}{\sqrt {1+a} \sqrt {1-a-b x}}\right )}{(1-a) (1+a)^4 \sqrt {1-a^2}} \]

[Out]

(6*a^2-18*a+11)*b^3*arctanh((1-a)^(1/2)*(b*x+a+1)^(1/2)/(1+a)^(1/2)/(-b*x-a+1)^(1/2))/(1-a)/(1+a)^4/(-a^2+1)^(
1/2)-1/6*(2*a^2-51*a+52)*b^3*(-b*x-a+1)^(1/2)/(1-a)/(1+a)^4/(b*x+a+1)^(1/2)-1/3*(1-a)*(-b*x-a+1)^(1/2)/(1+a)/x
^3/(b*x+a+1)^(1/2)+7/6*b*(-b*x-a+1)^(1/2)/(1+a)^2/x^2/(b*x+a+1)^(1/2)-1/6*(19-16*a)*b^2*(-b*x-a+1)^(1/2)/(1-a)
/(1+a)^3/x/(b*x+a+1)^(1/2)

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Rubi [A]
time = 0.16, antiderivative size = 257, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6298, 100, 156, 157, 12, 95, 214} \begin {gather*} -\frac {\left (2 a^2-51 a+52\right ) b^3 \sqrt {-a-b x+1}}{6 (1-a) (a+1)^4 \sqrt {a+b x+1}}+\frac {\left (6 a^2-18 a+11\right ) b^3 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {a+b x+1}}{\sqrt {a+1} \sqrt {-a-b x+1}}\right )}{(1-a) (a+1)^4 \sqrt {1-a^2}}-\frac {(19-16 a) b^2 \sqrt {-a-b x+1}}{6 (1-a) (a+1)^3 x \sqrt {a+b x+1}}-\frac {(1-a) \sqrt {-a-b x+1}}{3 (a+1) x^3 \sqrt {a+b x+1}}+\frac {7 b \sqrt {-a-b x+1}}{6 (a+1)^2 x^2 \sqrt {a+b x+1}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(E^(3*ArcTanh[a + b*x])*x^4),x]

[Out]

-1/6*((52 - 51*a + 2*a^2)*b^3*Sqrt[1 - a - b*x])/((1 - a)*(1 + a)^4*Sqrt[1 + a + b*x]) - ((1 - a)*Sqrt[1 - a -
 b*x])/(3*(1 + a)*x^3*Sqrt[1 + a + b*x]) + (7*b*Sqrt[1 - a - b*x])/(6*(1 + a)^2*x^2*Sqrt[1 + a + b*x]) - ((19
- 16*a)*b^2*Sqrt[1 - a - b*x])/(6*(1 - a)*(1 + a)^3*x*Sqrt[1 + a + b*x]) + ((11 - 18*a + 6*a^2)*b^3*ArcTanh[(S
qrt[1 - a]*Sqrt[1 + a + b*x])/(Sqrt[1 + a]*Sqrt[1 - a - b*x])])/((1 - a)*(1 + a)^4*Sqrt[1 - a^2])

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 95

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 100

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
 FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 156

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f
))), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]

Rule 157

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f
))), x] + Dist[1/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[(a*d*f*
g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a*h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p
+ 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n, 2*p]

Rule 214

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x/Rt[-a/b, 2]], x] /; FreeQ[{a, b},
x] && NegQ[a/b]

Rule 6298

Int[E^(ArcTanh[(c_.)*((a_) + (b_.)*(x_))]*(n_.))*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Int[(d + e*x)^m*((1
+ a*c + b*c*x)^(n/2)/(1 - a*c - b*c*x)^(n/2)), x] /; FreeQ[{a, b, c, d, e, m, n}, x]

Rubi steps

\begin {align*} \int \frac {e^{-3 \tanh ^{-1}(a+b x)}}{x^4} \, dx &=\int \frac {(1-a-b x)^{3/2}}{x^4 (1+a+b x)^{3/2}} \, dx\\ &=-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}-\frac {\int \frac {7 (1-a) b-6 b^2 x}{x^3 \sqrt {1-a-b x} (1+a+b x)^{3/2}} \, dx}{3 (1+a)}\\ &=-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}+\frac {\int \frac {(19-16 a) (1-a) b^2-14 (1-a) b^3 x}{x^2 \sqrt {1-a-b x} (1+a+b x)^{3/2}} \, dx}{6 (1-a) (1+a)^2}\\ &=-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}-\frac {\int \frac {3 (1-a) \left (11-18 a+6 a^2\right ) b^3-(19-16 a) (1-a) b^4 x}{x \sqrt {1-a-b x} (1+a+b x)^{3/2}} \, dx}{6 (1-a)^2 (1+a)^3}\\ &=-\frac {\left (52-51 a+2 a^2\right ) b^3 \sqrt {1-a-b x}}{6 (1-a) (1+a)^4 \sqrt {1+a+b x}}-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}-\frac {\int \frac {3 (1-a) \left (11-18 a+6 a^2\right ) b^4}{x \sqrt {1-a-b x} \sqrt {1+a+b x}} \, dx}{6 (1-a)^2 (1+a)^4 b}\\ &=-\frac {\left (52-51 a+2 a^2\right ) b^3 \sqrt {1-a-b x}}{6 (1-a) (1+a)^4 \sqrt {1+a+b x}}-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}-\frac {\left (\left (11-18 a+6 a^2\right ) b^3\right ) \int \frac {1}{x \sqrt {1-a-b x} \sqrt {1+a+b x}} \, dx}{2 (1-a) (1+a)^4}\\ &=-\frac {\left (52-51 a+2 a^2\right ) b^3 \sqrt {1-a-b x}}{6 (1-a) (1+a)^4 \sqrt {1+a+b x}}-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}-\frac {\left (\left (11-18 a+6 a^2\right ) b^3\right ) \text {Subst}\left (\int \frac {1}{-1-a-(-1+a) x^2} \, dx,x,\frac {\sqrt {1+a+b x}}{\sqrt {1-a-b x}}\right )}{(1-a) (1+a)^4}\\ &=-\frac {\left (52-51 a+2 a^2\right ) b^3 \sqrt {1-a-b x}}{6 (1-a) (1+a)^4 \sqrt {1+a+b x}}-\frac {(1-a) \sqrt {1-a-b x}}{3 (1+a) x^3 \sqrt {1+a+b x}}+\frac {7 b \sqrt {1-a-b x}}{6 (1+a)^2 x^2 \sqrt {1+a+b x}}-\frac {(19-16 a) b^2 \sqrt {1-a-b x}}{6 (1-a) (1+a)^3 x \sqrt {1+a+b x}}+\frac {\left (11-18 a+6 a^2\right ) b^3 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {1+a+b x}}{\sqrt {1+a} \sqrt {1-a-b x}}\right )}{(1-a) (1+a)^4 \sqrt {1-a^2}}\\ \end {align*}

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Mathematica [A]
time = 0.28, size = 194, normalized size = 0.75 \begin {gather*} \frac {-2 (1-a) (1+a) (1-a-b x)^{5/2}+(3-4 a) b x (1-a-b x)^{5/2}+\frac {\left (11-18 a+6 a^2\right ) b^2 x^2 \left (\sqrt {-1-a} \sqrt {1-a-b x} \left (-1+a^2-5 b x+a b x\right )+6 \sqrt {-1+a} b x \sqrt {1+a+b x} \tanh ^{-1}\left (\frac {\sqrt {-1-a} \sqrt {1-a-b x}}{\sqrt {-1+a} \sqrt {1+a+b x}}\right )\right )}{(-1-a)^{5/2}}}{6 \left (-1+a^2\right )^2 x^3 \sqrt {1+a+b x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(E^(3*ArcTanh[a + b*x])*x^4),x]

[Out]

(-2*(1 - a)*(1 + a)*(1 - a - b*x)^(5/2) + (3 - 4*a)*b*x*(1 - a - b*x)^(5/2) + ((11 - 18*a + 6*a^2)*b^2*x^2*(Sq
rt[-1 - a]*Sqrt[1 - a - b*x]*(-1 + a^2 - 5*b*x + a*b*x) + 6*Sqrt[-1 + a]*b*x*Sqrt[1 + a + b*x]*ArcTanh[(Sqrt[-
1 - a]*Sqrt[1 - a - b*x])/(Sqrt[-1 + a]*Sqrt[1 + a + b*x])]))/(-1 - a)^(5/2))/(6*(-1 + a^2)^2*x^3*Sqrt[1 + a +
 b*x])

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(3699\) vs. \(2(223)=446\).
time = 0.09, size = 3700, normalized size = 14.40

method result size
risch \(-\frac {\left (b^{2} x^{2}+2 a b x +a^{2}-1\right ) \left (2 a^{2} b^{2} x^{2}-2 a^{3} b x -27 a \,b^{2} x^{2}+2 a^{4}+9 a^{2} b x +28 b^{2} x^{2}+2 a b x -4 a^{2}-9 b x +2\right )}{6 \left (1+a \right )^{3} x^{3} \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}\, \left (a^{2}-1\right )}+\frac {4 b^{2} \sqrt {-b^{2} \left (x +\frac {1+a}{b}\right )^{2}+2 b \left (x +\frac {1+a}{b}\right )}}{\left (a^{2}-1\right ) \left (1+a \right )^{3} \left (x +\frac {1}{b}+\frac {a}{b}\right )}-\frac {4 b^{2} \sqrt {-b^{2} \left (x +\frac {1+a}{b}\right )^{2}+2 b \left (x +\frac {1+a}{b}\right )}\, a}{\left (a^{2}-1\right ) \left (1+a \right )^{3} \left (x +\frac {1}{b}+\frac {a}{b}\right )}-\frac {3 b^{3} \ln \left (\frac {-2 a^{2}+2-2 a b x +2 \sqrt {-a^{2}+1}\, \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}{x}\right ) a^{2}}{\left (a^{2}-1\right ) \left (1+a \right )^{3} \sqrt {-a^{2}+1}}+\frac {9 b^{3} \ln \left (\frac {-2 a^{2}+2-2 a b x +2 \sqrt {-a^{2}+1}\, \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}{x}\right ) a}{\left (a^{2}-1\right ) \left (1+a \right )^{3} \sqrt {-a^{2}+1}}-\frac {11 b^{3} \ln \left (\frac {-2 a^{2}+2-2 a b x +2 \sqrt {-a^{2}+1}\, \sqrt {-b^{2} x^{2}-2 a b x -a^{2}+1}}{x}\right )}{2 \left (a^{2}-1\right ) \left (1+a \right )^{3} \sqrt {-a^{2}+1}}\) \(474\)
default \(\text {Expression too large to display}\) \(3700\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^4,x,method=_RETURNVERBOSE)

[Out]

6/(1+a)^5*b^2*(-1/(-a^2+1)/x*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-3*b*a/(-a^2+1)*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)
-b*a*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)
*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b*a/(b
^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(
-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)))-4*b^2/(-a^2+1)*(-1/8*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x
-a^2+1)^(3/2)-3/16*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1
/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))))
+4/(1+a)^5*b^2*(1/b/(x+(1+a)/b)^2*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(5/2)+3*b*(1/3*(-b^2*(x+(1+a)/b)^2+2*b*
(x+(1+a)/b))^(3/2)+b*(-1/4*(-2*b^2*(x+(1+a)/b)+2*b)/b^2*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(1/2)+1/2/(b^2)^(
1/2)*arctan((b^2)^(1/2)*(x+(1+a)/b-1/b)/(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(1/2)))))+1/(1+a)^3*(-1/3/(-a^2+1
)/x^3*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)+1/3*b*a/(-a^2+1)*(-1/2/(-a^2+1)/x^2*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-1/2*b*
a/(-a^2+1)*(-1/(-a^2+1)/x*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-3*b*a/(-a^2+1)*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-b*
a*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*ar
ctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b*a/(b^2)
^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^
2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)))-4*b^2/(-a^2+1)*(-1/8*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^
2+1)^(3/2)-3/16*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*
(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))))-3/
2*b^2/(-a^2+1)*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-b*a*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/
2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)
))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b*a/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2
+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x))))-2/3*b^2/
(-a^2+1)*(-1/(-a^2+1)/x*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-3*b*a/(-a^2+1)*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-b*a*
(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*arct
an((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b*a/(b^2)^(
1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+
1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)))-4*b^2/(-a^2+1)*(-1/8*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+
1)^(3/2)-3/16*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-
4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))))))+10/
(1+a)^6*b^3*(1/3*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(3/2)+b*(-1/4*(-2*b^2*(x+(1+a)/b)+2*b)/b^2*(-b^2*(x+(1+a
)/b)^2+2*b*(x+(1+a)/b))^(1/2)+1/2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+(1+a)/b-1/b)/(-b^2*(x+(1+a)/b)^2+2*b*(x+(1
+a)/b))^(1/2))))+1/(1+a)^4*b*(-1/b/(x+(1+a)/b)^3*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(5/2)-2*b*(1/b/(x+(1+a)/
b)^2*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(5/2)+3*b*(1/3*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(3/2)+b*(-1/4*(-
2*b^2*(x+(1+a)/b)+2*b)/b^2*(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(1/2)+1/2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+(1
+a)/b-1/b)/(-b^2*(x+(1+a)/b)^2+2*b*(x+(1+a)/b))^(1/2))))))-10/(1+a)^6*b^3*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-
b*a*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(1/2)*
arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b*a/(b^
2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-
a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)))-3/(1+a)^4*b*(-1/2/(-a^2+1)/x^2*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2
)-1/2*b*a/(-a^2+1)*(-1/(-a^2+1)/x*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-3*b*a/(-a^2+1)*(1/3*(-b^2*x^2-2*a*b*x-a^2+1)^
(3/2)-b*a*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^
(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)))+(-a^2+1)*((-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-b
*a/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+1/b*a)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))-(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*
x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)))-4*b^2/(-a^2+1)*(-1/8*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*
a*b*x-a^2+1)^(3/2)-3/16*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2*(-1/4*(-2*b^2*x-2*a*b)/b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1
/2)-1/8*(-4*b^2*(-a^2+1)-4*b^2*a^2)/b^2/(b^2)^(...

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^4,x, algorithm="maxima")

[Out]

integrate((-(b*x + a)^2 + 1)^(3/2)/((b*x + a + 1)^3*x^4), x)

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Fricas [A]
time = 0.44, size = 697, normalized size = 2.71 \begin {gather*} \left [-\frac {3 \, {\left ({\left (6 \, a^{2} - 18 \, a + 11\right )} b^{4} x^{4} + {\left (6 \, a^{3} - 12 \, a^{2} - 7 \, a + 11\right )} b^{3} x^{3}\right )} \sqrt {-a^{2} + 1} \log \left (\frac {{\left (2 \, a^{2} - 1\right )} b^{2} x^{2} + 2 \, a^{4} + 4 \, {\left (a^{3} - a\right )} b x + 2 \, \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (a b x + a^{2} - 1\right )} \sqrt {-a^{2} + 1} - 4 \, a^{2} + 2}{x^{2}}\right ) - 2 \, {\left (2 \, a^{7} + {\left (2 \, a^{4} - 51 \, a^{3} + 50 \, a^{2} + 51 \, a - 52\right )} b^{3} x^{3} + 2 \, a^{6} - 6 \, a^{5} - {\left (16 \, a^{4} - 3 \, a^{3} - 35 \, a^{2} + 3 \, a + 19\right )} b^{2} x^{2} - 6 \, a^{4} + 6 \, a^{3} + 7 \, {\left (a^{5} + a^{4} - 2 \, a^{3} - 2 \, a^{2} + a + 1\right )} b x + 6 \, a^{2} - 2 \, a - 2\right )} \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{12 \, {\left ({\left (a^{7} + 3 \, a^{6} + a^{5} - 5 \, a^{4} - 5 \, a^{3} + a^{2} + 3 \, a + 1\right )} b x^{4} + {\left (a^{8} + 4 \, a^{7} + 4 \, a^{6} - 4 \, a^{5} - 10 \, a^{4} - 4 \, a^{3} + 4 \, a^{2} + 4 \, a + 1\right )} x^{3}\right )}}, \frac {3 \, {\left ({\left (6 \, a^{2} - 18 \, a + 11\right )} b^{4} x^{4} + {\left (6 \, a^{3} - 12 \, a^{2} - 7 \, a + 11\right )} b^{3} x^{3}\right )} \sqrt {a^{2} - 1} \arctan \left (\frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (a b x + a^{2} - 1\right )} \sqrt {a^{2} - 1}}{{\left (a^{2} - 1\right )} b^{2} x^{2} + a^{4} + 2 \, {\left (a^{3} - a\right )} b x - 2 \, a^{2} + 1}\right ) + {\left (2 \, a^{7} + {\left (2 \, a^{4} - 51 \, a^{3} + 50 \, a^{2} + 51 \, a - 52\right )} b^{3} x^{3} + 2 \, a^{6} - 6 \, a^{5} - {\left (16 \, a^{4} - 3 \, a^{3} - 35 \, a^{2} + 3 \, a + 19\right )} b^{2} x^{2} - 6 \, a^{4} + 6 \, a^{3} + 7 \, {\left (a^{5} + a^{4} - 2 \, a^{3} - 2 \, a^{2} + a + 1\right )} b x + 6 \, a^{2} - 2 \, a - 2\right )} \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{6 \, {\left ({\left (a^{7} + 3 \, a^{6} + a^{5} - 5 \, a^{4} - 5 \, a^{3} + a^{2} + 3 \, a + 1\right )} b x^{4} + {\left (a^{8} + 4 \, a^{7} + 4 \, a^{6} - 4 \, a^{5} - 10 \, a^{4} - 4 \, a^{3} + 4 \, a^{2} + 4 \, a + 1\right )} x^{3}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^4,x, algorithm="fricas")

[Out]

[-1/12*(3*((6*a^2 - 18*a + 11)*b^4*x^4 + (6*a^3 - 12*a^2 - 7*a + 11)*b^3*x^3)*sqrt(-a^2 + 1)*log(((2*a^2 - 1)*
b^2*x^2 + 2*a^4 + 4*(a^3 - a)*b*x + 2*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(a*b*x + a^2 - 1)*sqrt(-a^2 + 1) - 4*
a^2 + 2)/x^2) - 2*(2*a^7 + (2*a^4 - 51*a^3 + 50*a^2 + 51*a - 52)*b^3*x^3 + 2*a^6 - 6*a^5 - (16*a^4 - 3*a^3 - 3
5*a^2 + 3*a + 19)*b^2*x^2 - 6*a^4 + 6*a^3 + 7*(a^5 + a^4 - 2*a^3 - 2*a^2 + a + 1)*b*x + 6*a^2 - 2*a - 2)*sqrt(
-b^2*x^2 - 2*a*b*x - a^2 + 1))/((a^7 + 3*a^6 + a^5 - 5*a^4 - 5*a^3 + a^2 + 3*a + 1)*b*x^4 + (a^8 + 4*a^7 + 4*a
^6 - 4*a^5 - 10*a^4 - 4*a^3 + 4*a^2 + 4*a + 1)*x^3), 1/6*(3*((6*a^2 - 18*a + 11)*b^4*x^4 + (6*a^3 - 12*a^2 - 7
*a + 11)*b^3*x^3)*sqrt(a^2 - 1)*arctan(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(a*b*x + a^2 - 1)*sqrt(a^2 - 1)/((a^
2 - 1)*b^2*x^2 + a^4 + 2*(a^3 - a)*b*x - 2*a^2 + 1)) + (2*a^7 + (2*a^4 - 51*a^3 + 50*a^2 + 51*a - 52)*b^3*x^3
+ 2*a^6 - 6*a^5 - (16*a^4 - 3*a^3 - 35*a^2 + 3*a + 19)*b^2*x^2 - 6*a^4 + 6*a^3 + 7*(a^5 + a^4 - 2*a^3 - 2*a^2
+ a + 1)*b*x + 6*a^2 - 2*a - 2)*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1))/((a^7 + 3*a^6 + a^5 - 5*a^4 - 5*a^3 + a^2
+ 3*a + 1)*b*x^4 + (a^8 + 4*a^7 + 4*a^6 - 4*a^5 - 10*a^4 - 4*a^3 + 4*a^2 + 4*a + 1)*x^3)]

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (- \left (a + b x - 1\right ) \left (a + b x + 1\right )\right )^{\frac {3}{2}}}{x^{4} \left (a + b x + 1\right )^{3}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)**3*(1-(b*x+a)**2)**(3/2)/x**4,x)

[Out]

Integral((-(a + b*x - 1)*(a + b*x + 1))**(3/2)/(x**4*(a + b*x + 1)**3), x)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 1839 vs. \(2 (216) = 432\).
time = 0.45, size = 1839, normalized size = 7.16 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^4,x, algorithm="giac")

[Out]

8*b^4/((a^4*abs(b) + 4*a^3*abs(b) + 6*a^2*abs(b) + 4*a*abs(b) + abs(b))*((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*a
bs(b) + b)/(b^2*x + a*b) + 1)) + (6*a^2*b^4 - 18*a*b^4 + 11*b^4)*arctan(((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*a
bs(b) + b)*a/(b^2*x + a*b) - 1)/sqrt(a^2 - 1))/((a^5*abs(b) + 3*a^4*abs(b) + 2*a^3*abs(b) - 2*a^2*abs(b) - 3*a
*abs(b) - abs(b))*sqrt(a^2 - 1)) + 1/3*(12*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a^7*b^4/(b^2*x +
a*b)^2 + 6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^4*a^7*b^4/(b^2*x + a*b)^4 + 6*a^7*b^4 - 24*(sqrt(-b
^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)*a^6*b^4/(b^2*x + a*b) - 72*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b)
+ b)^2*a^6*b^4/(b^2*x + a*b)^2 - 36*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^6*b^4/(b^2*x + a*b)^3
- 36*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^4*a^6*b^4/(b^2*x + a*b)^4 - 12*(sqrt(-b^2*x^2 - 2*a*b*x -
 a^2 + 1)*abs(b) + b)^5*a^6*b^4/(b^2*x + a*b)^5 - 36*a^6*b^4 + 171*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b)
+ b)*a^5*b^4/(b^2*x + a*b) + 84*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a^5*b^4/(b^2*x + a*b)^2 + 21
6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^5*b^4/(b^2*x + a*b)^3 + 54*(sqrt(-b^2*x^2 - 2*a*b*x - a^
2 + 1)*abs(b) + b)^4*a^5*b^4/(b^2*x + a*b)^4 + 45*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^5*a^5*b^4/(b
^2*x + a*b)^5 + 22*a^5*b^4 - 120*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)*a^4*b^4/(b^2*x + a*b) - 252*(
sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a^4*b^4/(b^2*x + a*b)^2 - 156*(sqrt(-b^2*x^2 - 2*a*b*x - a^2
+ 1)*abs(b) + b)^3*a^4*b^4/(b^2*x + a*b)^3 - 153*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^4*a^4*b^4/(b^
2*x + a*b)^4 - 12*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^5*a^4*b^4/(b^2*x + a*b)^5 + 9*a^4*b^4 - 36*(
sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)*a^3*b^4/(b^2*x + a*b) + 192*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)
*abs(b) + b)^2*a^3*b^4/(b^2*x + a*b)^2 + 90*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^3*b^4/(b^2*x +
 a*b)^3 + 78*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^4*a^3*b^4/(b^2*x + a*b)^4 - 18*(sqrt(-b^2*x^2 - 2
*a*b*x - a^2 + 1)*abs(b) + b)^5*a^3*b^4/(b^2*x + a*b)^5 + 2*a^3*b^4 - 6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*ab
s(b) + b)*a^2*b^4/(b^2*x + a*b) + 54*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a^2*b^4/(b^2*x + a*b)^2
 - 100*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^2*b^4/(b^2*x + a*b)^3 + 54*(sqrt(-b^2*x^2 - 2*a*b*x
 - a^2 + 1)*abs(b) + b)^4*a^2*b^4/(b^2*x + a*b)^4 - 6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^5*a^2*b^
4/(b^2*x + a*b)^5 + 12*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a*b^4/(b^2*x + a*b)^2 - 36*(sqrt(-b^2
*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a*b^4/(b^2*x + a*b)^3 + 12*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b)
+ b)^4*a*b^4/(b^2*x + a*b)^4 - 8*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*b^4/(b^2*x + a*b)^3)/((a^8*
abs(b) + 3*a^7*abs(b) + 2*a^6*abs(b) - 2*a^5*abs(b) - 3*a^4*abs(b) - a^3*abs(b))*((sqrt(-b^2*x^2 - 2*a*b*x - a
^2 + 1)*abs(b) + b)^2*a/(b^2*x + a*b)^2 + a - 2*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)/(b^2*x + a*b))
^3)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (1-{\left (a+b\,x\right )}^2\right )}^{3/2}}{x^4\,{\left (a+b\,x+1\right )}^3} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - (a + b*x)^2)^(3/2)/(x^4*(a + b*x + 1)^3),x)

[Out]

int((1 - (a + b*x)^2)^(3/2)/(x^4*(a + b*x + 1)^3), x)

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