Optimal. Leaf size=14 \[ -\frac {1}{b \tanh ^{-1}(\tanh (a+b x))} \]
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Rubi [A]
time = 0.00, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {2188, 30}
\begin {gather*} -\frac {1}{b \tanh ^{-1}(\tanh (a+b x))} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2188
Rubi steps
\begin {align*} \int \frac {1}{\tanh ^{-1}(\tanh (a+b x))^2} \, dx &=\frac {\text {Subst}\left (\int \frac {1}{x^2} \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{b}\\ &=-\frac {1}{b \tanh ^{-1}(\tanh (a+b x))}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 14, normalized size = 1.00 \begin {gather*} -\frac {1}{b \tanh ^{-1}(\tanh (a+b x))} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.06, size = 15, normalized size = 1.07
method | result | size |
derivativedivides | \(-\frac {1}{b \arctanh \left (\tanh \left (b x +a \right )\right )}\) | \(15\) |
default | \(-\frac {1}{b \arctanh \left (\tanh \left (b x +a \right )\right )}\) | \(15\) |
risch | \(\frac {4 i}{b \left (-\pi \,\mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )+\pi \,\mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2}-\pi \mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right )^{2} \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )+2 \pi \,\mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{2}-\pi \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{3}+\pi \,\mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2}-\pi \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{3}-4 i \ln \left ({\mathrm e}^{b x +a}\right )\right )}\) | \(274\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.47, size = 12, normalized size = 0.86 \begin {gather*} -\frac {1}{{\left (b x + a\right )} b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.32, size = 13, normalized size = 0.93 \begin {gather*} -\frac {1}{b^{2} x + a b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 24.85, size = 20, normalized size = 1.43 \begin {gather*} \begin {cases} - \frac {1}{b \operatorname {atanh}{\left (\tanh {\left (a + b x \right )} \right )}} & \text {for}\: b \neq 0 \\\frac {x}{\operatorname {atanh}^{2}{\left (\tanh {\left (a \right )} \right )}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.38, size = 12, normalized size = 0.86 \begin {gather*} -\frac {1}{{\left (b x + a\right )} b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.08, size = 14, normalized size = 1.00 \begin {gather*} -\frac {1}{b\,\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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