Optimal. Leaf size=201 \[ -\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {60 e^{5/2} \sqrt {d+e x^2}}{1001 d^3 x^{3/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}-\frac {30 e^{13/4} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{1001 d^{13/4} \sqrt {d+e x^2}} \]
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Rubi [A]
time = 0.07, antiderivative size = 201, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {6356, 331, 335,
226} \begin {gather*} -\frac {30 e^{13/4} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{1001 d^{13/4} \sqrt {d+e x^2}}-\frac {60 e^{5/2} \sqrt {d+e x^2}}{1001 d^3 x^{3/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 226
Rule 331
Rule 335
Rule 6356
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{x^{15/2}} \, dx &=-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}+\frac {1}{13} \left (2 \sqrt {e}\right ) \int \frac {1}{x^{13/2} \sqrt {d+e x^2}} \, dx\\ &=-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}-\frac {\left (18 e^{3/2}\right ) \int \frac {1}{x^{9/2} \sqrt {d+e x^2}} \, dx}{143 d}\\ &=-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}+\frac {\left (90 e^{5/2}\right ) \int \frac {1}{x^{5/2} \sqrt {d+e x^2}} \, dx}{1001 d^2}\\ &=-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {60 e^{5/2} \sqrt {d+e x^2}}{1001 d^3 x^{3/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}-\frac {\left (30 e^{7/2}\right ) \int \frac {1}{\sqrt {x} \sqrt {d+e x^2}} \, dx}{1001 d^3}\\ &=-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {60 e^{5/2} \sqrt {d+e x^2}}{1001 d^3 x^{3/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}-\frac {\left (60 e^{7/2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {d+e x^4}} \, dx,x,\sqrt {x}\right )}{1001 d^3}\\ &=-\frac {4 \sqrt {e} \sqrt {d+e x^2}}{143 d x^{11/2}}+\frac {36 e^{3/2} \sqrt {d+e x^2}}{1001 d^2 x^{7/2}}-\frac {60 e^{5/2} \sqrt {d+e x^2}}{1001 d^3 x^{3/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )}{13 x^{13/2}}-\frac {30 e^{13/4} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{1001 d^{13/4} \sqrt {d+e x^2}}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.28, size = 163, normalized size = 0.81 \begin {gather*} \frac {2 \left (-\frac {2 \sqrt {e} x \sqrt {d+e x^2} \left (7 d^2-9 d e x^2+15 e^2 x^4\right )}{d^3}-77 \tanh ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d+e x^2}}\right )-\frac {30 \sqrt {\frac {i \sqrt {d}}{\sqrt {e}}} e^4 \sqrt {1+\frac {d}{e x^2}} x^{15/2} F\left (\left .i \sinh ^{-1}\left (\frac {\sqrt {\frac {i \sqrt {d}}{\sqrt {e}}}}{\sqrt {x}}\right )\right |-1\right )}{d^{7/2} \sqrt {d+e x^2}}\right )}{1001 x^{13/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.29, size = 0, normalized size = 0.00 \[\int \frac {\arctanh \left (\frac {x \sqrt {e}}{\sqrt {e \,x^{2}+d}}\right )}{x^{\frac {15}{2}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.10, size = 355, normalized size = 1.77 \begin {gather*} -\frac {77 \, d^{3} \sqrt {x} \log \left (\frac {2 \, x^{2} \cosh \left (\frac {1}{2}\right )^{2} + 4 \, x^{2} \cosh \left (\frac {1}{2}\right ) \sinh \left (\frac {1}{2}\right ) + 2 \, x^{2} \sinh \left (\frac {1}{2}\right )^{2} + 2 \, {\left (x \cosh \left (\frac {1}{2}\right ) + x \sinh \left (\frac {1}{2}\right )\right )} \sqrt {\frac {{\left (x^{2} + d\right )} \cosh \left (\frac {1}{2}\right ) + {\left (x^{2} - d\right )} \sinh \left (\frac {1}{2}\right )}{\cosh \left (\frac {1}{2}\right ) - \sinh \left (\frac {1}{2}\right )}} + d}{d}\right ) + 4 \, {\left (15 \, x^{5} \cosh \left (\frac {1}{2}\right )^{5} + 75 \, x^{5} \cosh \left (\frac {1}{2}\right ) \sinh \left (\frac {1}{2}\right )^{4} + 15 \, x^{5} \sinh \left (\frac {1}{2}\right )^{5} - 9 \, d x^{3} \cosh \left (\frac {1}{2}\right )^{3} + 7 \, d^{2} x \cosh \left (\frac {1}{2}\right ) + 3 \, {\left (50 \, x^{5} \cosh \left (\frac {1}{2}\right )^{2} - 3 \, d x^{3}\right )} \sinh \left (\frac {1}{2}\right )^{3} + 3 \, {\left (50 \, x^{5} \cosh \left (\frac {1}{2}\right )^{3} - 9 \, d x^{3} \cosh \left (\frac {1}{2}\right )\right )} \sinh \left (\frac {1}{2}\right )^{2} + {\left (75 \, x^{5} \cosh \left (\frac {1}{2}\right )^{4} - 27 \, d x^{3} \cosh \left (\frac {1}{2}\right )^{2} + 7 \, d^{2} x\right )} \sinh \left (\frac {1}{2}\right )\right )} \sqrt {x} \sqrt {\frac {{\left (x^{2} + d\right )} \cosh \left (\frac {1}{2}\right ) + {\left (x^{2} - d\right )} \sinh \left (\frac {1}{2}\right )}{\cosh \left (\frac {1}{2}\right ) - \sinh \left (\frac {1}{2}\right )}} + 60 \, {\left (x^{7} \cosh \left (\frac {1}{2}\right )^{6} + 6 \, x^{7} \cosh \left (\frac {1}{2}\right )^{5} \sinh \left (\frac {1}{2}\right ) + 15 \, x^{7} \cosh \left (\frac {1}{2}\right )^{4} \sinh \left (\frac {1}{2}\right )^{2} + 20 \, x^{7} \cosh \left (\frac {1}{2}\right )^{3} \sinh \left (\frac {1}{2}\right )^{3} + 15 \, x^{7} \cosh \left (\frac {1}{2}\right )^{2} \sinh \left (\frac {1}{2}\right )^{4} + 6 \, x^{7} \cosh \left (\frac {1}{2}\right ) \sinh \left (\frac {1}{2}\right )^{5} + x^{7} \sinh \left (\frac {1}{2}\right )^{6}\right )} {\rm weierstrassPInverse}\left (-\frac {4 \, d}{\cosh \left (\frac {1}{2}\right )^{2} + 2 \, \cosh \left (\frac {1}{2}\right ) \sinh \left (\frac {1}{2}\right ) + \sinh \left (\frac {1}{2}\right )^{2}}, 0, x\right )}{1001 \, d^{3} x^{7}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\mathrm {atanh}\left (\frac {\sqrt {e}\,x}{\sqrt {e\,x^2+d}}\right )}{x^{15/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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