Optimal. Leaf size=278 \[ -\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{16 (1-a x)^4 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{12 (1-a x)^3 \left (c-a^2 c x^2\right )^{7/2}}-\frac {3 a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1-a x)^2 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{8 (1-a x) \left (c-a^2 c x^2\right )^{7/2}}+\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1+a x) \left (c-a^2 c x^2\right )^{7/2}}-\frac {5 a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7 \tanh ^{-1}(a x)}{32 \left (c-a^2 c x^2\right )^{7/2}} \]
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Rubi [A]
time = 0.16, antiderivative size = 278, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {6327, 6328, 46,
213} \begin {gather*} -\frac {a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2}}{8 (1-a x) \left (c-a^2 c x^2\right )^{7/2}}+\frac {a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2}}{32 (a x+1) \left (c-a^2 c x^2\right )^{7/2}}-\frac {3 a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2}}{32 (1-a x)^2 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2}}{12 (1-a x)^3 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2}}{16 (1-a x)^4 \left (c-a^2 c x^2\right )^{7/2}}-\frac {5 a^6 x^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} \tanh ^{-1}(a x)}{32 \left (c-a^2 c x^2\right )^{7/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 46
Rule 213
Rule 6327
Rule 6328
Rubi steps
\begin {align*} \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (c-a^2 c x^2\right )^{7/2}} \, dx &=\frac {\left (\left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7\right ) \int \frac {e^{3 \coth ^{-1}(a x)}}{\left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7} \, dx}{\left (c-a^2 c x^2\right )^{7/2}}\\ &=\frac {\left (a^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7\right ) \int \frac {1}{(-1+a x)^5 (1+a x)^2} \, dx}{\left (c-a^2 c x^2\right )^{7/2}}\\ &=\frac {\left (a^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7\right ) \int \left (\frac {1}{4 (-1+a x)^5}-\frac {1}{4 (-1+a x)^4}+\frac {3}{16 (-1+a x)^3}-\frac {1}{8 (-1+a x)^2}-\frac {1}{32 (1+a x)^2}+\frac {5}{32 \left (-1+a^2 x^2\right )}\right ) \, dx}{\left (c-a^2 c x^2\right )^{7/2}}\\ &=-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{16 (1-a x)^4 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{12 (1-a x)^3 \left (c-a^2 c x^2\right )^{7/2}}-\frac {3 a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1-a x)^2 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{8 (1-a x) \left (c-a^2 c x^2\right )^{7/2}}+\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1+a x) \left (c-a^2 c x^2\right )^{7/2}}+\frac {\left (5 a^7 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7\right ) \int \frac {1}{-1+a^2 x^2} \, dx}{32 \left (c-a^2 c x^2\right )^{7/2}}\\ &=-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{16 (1-a x)^4 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{12 (1-a x)^3 \left (c-a^2 c x^2\right )^{7/2}}-\frac {3 a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1-a x)^2 \left (c-a^2 c x^2\right )^{7/2}}-\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{8 (1-a x) \left (c-a^2 c x^2\right )^{7/2}}+\frac {a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7}{32 (1+a x) \left (c-a^2 c x^2\right )^{7/2}}-\frac {5 a^6 \left (1-\frac {1}{a^2 x^2}\right )^{7/2} x^7 \tanh ^{-1}(a x)}{32 \left (c-a^2 c x^2\right )^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.06, size = 99, normalized size = 0.36 \begin {gather*} \frac {\sqrt {1-\frac {1}{a^2 x^2}} x \left (32-15 a x-35 a^2 x^2+45 a^3 x^3-15 a^4 x^4+15 (-1+a x)^4 (1+a x) \tanh ^{-1}(a x)\right )}{96 c^3 (-1+a x)^4 (1+a x) \sqrt {c-a^2 c x^2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.10, size = 241, normalized size = 0.87
method | result | size |
default | \(-\frac {\sqrt {-c \left (a^{2} x^{2}-1\right )}\, \left (15 \ln \left (a x +1\right ) a^{5} x^{5}-15 x^{5} \ln \left (a x -1\right ) a^{5}-45 \ln \left (a x +1\right ) a^{4} x^{4}+45 x^{4} \ln \left (a x -1\right ) a^{4}-30 a^{4} x^{4}+30 \ln \left (a x +1\right ) a^{3} x^{3}-30 x^{3} \ln \left (a x -1\right ) a^{3}+90 a^{3} x^{3}+30 \ln \left (a x +1\right ) a^{2} x^{2}-30 x^{2} \ln \left (a x -1\right ) a^{2}-70 a^{2} x^{2}-45 \ln \left (a x +1\right ) a x +45 x \ln \left (a x -1\right ) a -30 a x +15 \ln \left (a x +1\right )-15 \ln \left (a x -1\right )+64\right )}{192 \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}} \left (a x -1\right )^{2} \left (a x +1\right )^{2} \left (a^{2} x^{2}-1\right ) c^{4} a}\) | \(241\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.37, size = 190, normalized size = 0.68 \begin {gather*} -\frac {15 \, {\left (a^{6} x^{5} - 3 \, a^{5} x^{4} + 2 \, a^{4} x^{3} + 2 \, a^{3} x^{2} - 3 \, a^{2} x + a\right )} \sqrt {-c} \log \left (\frac {a^{2} c x^{2} - 2 \, \sqrt {-a^{2} c} \sqrt {-c} x + c}{a^{2} x^{2} - 1}\right ) - 2 \, {\left (15 \, a^{4} x^{4} - 45 \, a^{3} x^{3} + 35 \, a^{2} x^{2} + 15 \, a x - 32\right )} \sqrt {-a^{2} c}}{192 \, {\left (a^{7} c^{4} x^{5} - 3 \, a^{6} c^{4} x^{4} + 2 \, a^{5} c^{4} x^{3} + 2 \, a^{4} c^{4} x^{2} - 3 \, a^{3} c^{4} x + a^{2} c^{4}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{{\left (c-a^2\,c\,x^2\right )}^{7/2}\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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