Optimal. Leaf size=375 \[ \frac {d (b c-a d) e^{-2 (a+b x)^2}}{b^3 \pi }+\frac {d^2 e^{-2 (a+b x)^2} (a+b x)}{3 b^3 \pi }-\frac {(b c-a d)^2 \sqrt {\frac {2}{\pi }} \text {Erf}\left (\sqrt {2} (a+b x)\right )}{b^3}-\frac {5 d^2 \text {Erf}\left (\sqrt {2} (a+b x)\right )}{6 b^3 \sqrt {2 \pi }}-\frac {2 d^2 e^{-(a+b x)^2} \text {Erfc}(a+b x)}{3 b^3 \sqrt {\pi }}-\frac {2 (b c-a d)^2 e^{-(a+b x)^2} \text {Erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d (b c-a d) e^{-(a+b x)^2} (a+b x) \text {Erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d^2 e^{-(a+b x)^2} (a+b x)^2 \text {Erfc}(a+b x)}{3 b^3 \sqrt {\pi }}-\frac {d (b c-a d) \text {Erfc}(a+b x)^2}{2 b^3}+\frac {(b c-a d)^2 (a+b x) \text {Erfc}(a+b x)^2}{b^3}+\frac {d (b c-a d) (a+b x)^2 \text {Erfc}(a+b x)^2}{b^3}+\frac {d^2 (a+b x)^3 \text {Erfc}(a+b x)^2}{3 b^3} \]
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Rubi [A]
time = 0.27, antiderivative size = 375, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 10, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {6503, 6488,
6518, 2236, 6500, 6521, 6509, 30, 2240, 2243} \begin {gather*} -\frac {\sqrt {\frac {2}{\pi }} (b c-a d)^2 \text {Erf}\left (\sqrt {2} (a+b x)\right )}{b^3}+\frac {d (a+b x)^2 (b c-a d) \text {Erfc}(a+b x)^2}{b^3}+\frac {(a+b x) (b c-a d)^2 \text {Erfc}(a+b x)^2}{b^3}-\frac {2 d e^{-(a+b x)^2} (a+b x) (b c-a d) \text {Erfc}(a+b x)}{\sqrt {\pi } b^3}-\frac {d (b c-a d) \text {Erfc}(a+b x)^2}{2 b^3}-\frac {2 e^{-(a+b x)^2} (b c-a d)^2 \text {Erfc}(a+b x)}{\sqrt {\pi } b^3}+\frac {d e^{-2 (a+b x)^2} (b c-a d)}{\pi b^3}-\frac {5 d^2 \text {Erf}\left (\sqrt {2} (a+b x)\right )}{6 \sqrt {2 \pi } b^3}+\frac {d^2 (a+b x)^3 \text {Erfc}(a+b x)^2}{3 b^3}-\frac {2 d^2 e^{-(a+b x)^2} (a+b x)^2 \text {Erfc}(a+b x)}{3 \sqrt {\pi } b^3}-\frac {2 d^2 e^{-(a+b x)^2} \text {Erfc}(a+b x)}{3 \sqrt {\pi } b^3}+\frac {d^2 e^{-2 (a+b x)^2} (a+b x)}{3 \pi b^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2236
Rule 2240
Rule 2243
Rule 6488
Rule 6500
Rule 6503
Rule 6509
Rule 6518
Rule 6521
Rubi steps
\begin {align*} \int (c+d x)^2 \text {erfc}(a+b x)^2 \, dx &=\frac {\text {Subst}\left (\int \left (b^2 c^2 \left (1+\frac {a d (-2 b c+a d)}{b^2 c^2}\right ) \text {erfc}(x)^2+2 b c d \left (1-\frac {a d}{b c}\right ) x \text {erfc}(x)^2+d^2 x^2 \text {erfc}(x)^2\right ) \, dx,x,a+b x\right )}{b^3}\\ &=\frac {d^2 \text {Subst}\left (\int x^2 \text {erfc}(x)^2 \, dx,x,a+b x\right )}{b^3}+\frac {(2 d (b c-a d)) \text {Subst}\left (\int x \text {erfc}(x)^2 \, dx,x,a+b x\right )}{b^3}+\frac {(b c-a d)^2 \text {Subst}\left (\int \text {erfc}(x)^2 \, dx,x,a+b x\right )}{b^3}\\ &=\frac {(b c-a d)^2 (a+b x) \text {erfc}(a+b x)^2}{b^3}+\frac {d (b c-a d) (a+b x)^2 \text {erfc}(a+b x)^2}{b^3}+\frac {d^2 (a+b x)^3 \text {erfc}(a+b x)^2}{3 b^3}+\frac {\left (4 d^2\right ) \text {Subst}\left (\int e^{-x^2} x^3 \text {erfc}(x) \, dx,x,a+b x\right )}{3 b^3 \sqrt {\pi }}+\frac {(4 d (b c-a d)) \text {Subst}\left (\int e^{-x^2} x^2 \text {erfc}(x) \, dx,x,a+b x\right )}{b^3 \sqrt {\pi }}+\frac {\left (4 (b c-a d)^2\right ) \text {Subst}\left (\int e^{-x^2} x \text {erfc}(x) \, dx,x,a+b x\right )}{b^3 \sqrt {\pi }}\\ &=-\frac {2 (b c-a d)^2 e^{-(a+b x)^2} \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d (b c-a d) e^{-(a+b x)^2} (a+b x) \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d^2 e^{-(a+b x)^2} (a+b x)^2 \text {erfc}(a+b x)}{3 b^3 \sqrt {\pi }}+\frac {(b c-a d)^2 (a+b x) \text {erfc}(a+b x)^2}{b^3}+\frac {d (b c-a d) (a+b x)^2 \text {erfc}(a+b x)^2}{b^3}+\frac {d^2 (a+b x)^3 \text {erfc}(a+b x)^2}{3 b^3}-\frac {\left (4 d^2\right ) \text {Subst}\left (\int e^{-2 x^2} x^2 \, dx,x,a+b x\right )}{3 b^3 \pi }-\frac {(4 d (b c-a d)) \text {Subst}\left (\int e^{-2 x^2} x \, dx,x,a+b x\right )}{b^3 \pi }-\frac {\left (4 (b c-a d)^2\right ) \text {Subst}\left (\int e^{-2 x^2} \, dx,x,a+b x\right )}{b^3 \pi }+\frac {\left (4 d^2\right ) \text {Subst}\left (\int e^{-x^2} x \text {erfc}(x) \, dx,x,a+b x\right )}{3 b^3 \sqrt {\pi }}+\frac {(2 d (b c-a d)) \text {Subst}\left (\int e^{-x^2} \text {erfc}(x) \, dx,x,a+b x\right )}{b^3 \sqrt {\pi }}\\ &=\frac {d (b c-a d) e^{-2 (a+b x)^2}}{b^3 \pi }+\frac {d^2 e^{-2 (a+b x)^2} (a+b x)}{3 b^3 \pi }-\frac {(b c-a d)^2 \sqrt {\frac {2}{\pi }} \text {erf}\left (\sqrt {2} (a+b x)\right )}{b^3}-\frac {2 d^2 e^{-(a+b x)^2} \text {erfc}(a+b x)}{3 b^3 \sqrt {\pi }}-\frac {2 (b c-a d)^2 e^{-(a+b x)^2} \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d (b c-a d) e^{-(a+b x)^2} (a+b x) \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d^2 e^{-(a+b x)^2} (a+b x)^2 \text {erfc}(a+b x)}{3 b^3 \sqrt {\pi }}+\frac {(b c-a d)^2 (a+b x) \text {erfc}(a+b x)^2}{b^3}+\frac {d (b c-a d) (a+b x)^2 \text {erfc}(a+b x)^2}{b^3}+\frac {d^2 (a+b x)^3 \text {erfc}(a+b x)^2}{3 b^3}-\frac {(d (b c-a d)) \text {Subst}(\int x \, dx,x,\text {erfc}(a+b x))}{b^3}-\frac {d^2 \text {Subst}\left (\int e^{-2 x^2} \, dx,x,a+b x\right )}{3 b^3 \pi }-\frac {\left (4 d^2\right ) \text {Subst}\left (\int e^{-2 x^2} \, dx,x,a+b x\right )}{3 b^3 \pi }\\ &=\frac {d (b c-a d) e^{-2 (a+b x)^2}}{b^3 \pi }+\frac {d^2 e^{-2 (a+b x)^2} (a+b x)}{3 b^3 \pi }-\frac {d^2 \sqrt {\frac {2}{\pi }} \text {erf}\left (\sqrt {2} (a+b x)\right )}{3 b^3}-\frac {(b c-a d)^2 \sqrt {\frac {2}{\pi }} \text {erf}\left (\sqrt {2} (a+b x)\right )}{b^3}-\frac {d^2 \text {erf}\left (\sqrt {2} (a+b x)\right )}{6 b^3 \sqrt {2 \pi }}-\frac {2 d^2 e^{-(a+b x)^2} \text {erfc}(a+b x)}{3 b^3 \sqrt {\pi }}-\frac {2 (b c-a d)^2 e^{-(a+b x)^2} \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d (b c-a d) e^{-(a+b x)^2} (a+b x) \text {erfc}(a+b x)}{b^3 \sqrt {\pi }}-\frac {2 d^2 e^{-(a+b x)^2} (a+b x)^2 \text {erfc}(a+b x)}{3 b^3 \sqrt {\pi }}-\frac {d (b c-a d) \text {erfc}(a+b x)^2}{2 b^3}+\frac {(b c-a d)^2 (a+b x) \text {erfc}(a+b x)^2}{b^3}+\frac {d (b c-a d) (a+b x)^2 \text {erfc}(a+b x)^2}{b^3}+\frac {d^2 (a+b x)^3 \text {erfc}(a+b x)^2}{3 b^3}\\ \end {align*}
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Mathematica [A]
time = 3.20, size = 610, normalized size = 1.63 \begin {gather*} \frac {-12 b^2 \sqrt {\pi } (c+d x)^2 \left (\sqrt {2} \text {Erf}\left (\sqrt {2} (a+b x)\right )+\text {Erfc}(a+b x) \left (2 e^{-(a+b x)^2}-\sqrt {\pi } (a+b x) \text {Erfc}(a+b x)\right )\right )+6 b d (c+d x) \left (2 e^{-2 (a+b x)^2}+4 e^{-(a+b x)^2} \sqrt {\pi } (a+b x)-2 \pi (a+b x)^2-2 \pi \text {Erf}(a+b x)-4 e^{-(a+b x)^2} \sqrt {\pi } (a+b x) \text {Erf}(a+b x)+4 \pi (a+b x)^2 \text {Erf}(a+b x)+\pi \text {Erf}(a+b x)^2-2 \pi (a+b x)^2 \text {Erf}(a+b x)^2+4 a \sqrt {2 \pi } \text {Erf}\left (\sqrt {2} (a+b x)\right )+4 b \sqrt {2 \pi } x \text {Erf}\left (\sqrt {2} (a+b x)\right )+2 \pi (2+\text {Erfc}(-a-b x) \text {Erfc}(a+b x))-4 \sqrt {\pi } (a+b x) E_{\frac {1}{2}}\left ((a+b x)^2\right )\right )+d^2 \left (24 e^{-(a+b x)^2} \sqrt {\pi }-36 b \pi x+12 a^2 b \pi x+12 a b^2 \pi x^2+4 b^3 \pi x^3-8 e^{-2 (a+b x)^2} (a+b x)-8 e^{-(a+b x)^2} \sqrt {\pi } \left (1+(a+b x)^2\right )+12 a \pi \text {Erf}(a+b x)+12 b \pi x \text {Erf}(a+b x)-8 \pi (a+b x)^3 \text {Erf}(a+b x)+8 e^{-(a+b x)^2} \sqrt {\pi } \left (1+(a+b x)^2\right ) \text {Erf}(a+b x)+6 \pi (a+b x) \text {Erf}(a+b x)^2+4 \pi (a+b x)^3 \text {Erf}(a+b x)^2-5 \sqrt {2 \pi } \text {Erf}\left (\sqrt {2} (a+b x)\right )-12 a^2 \sqrt {2 \pi } \text {Erf}\left (\sqrt {2} (a+b x)\right )-12 b \sqrt {2 \pi } x (2 a+b x) \text {Erf}\left (\sqrt {2} (a+b x)\right )-12 \sqrt {\pi } E_{\frac {3}{2}}\left ((a+b x)^2\right )\right )}{12 b^3 \pi } \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.14, size = 0, normalized size = 0.00 \[\int \left (d x +c \right )^{2} \mathrm {erfc}\left (b x +a \right )^{2}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 472, normalized size = 1.26 \begin {gather*} \frac {4 \, \pi b^{4} d^{2} x^{3} + 12 \, \pi b^{4} c d x^{2} + 12 \, \pi b^{4} c^{2} x - \sqrt {2} \sqrt {\pi } {\left (12 \, b^{2} c^{2} - 24 \, a b c d + {\left (12 \, a^{2} + 5\right )} d^{2}\right )} \sqrt {b^{2}} \operatorname {erf}\left (\frac {\sqrt {2} \sqrt {b^{2}} {\left (b x + a\right )}}{b}\right ) - 4 \, \pi {\left (6 \, a b^{2} c^{2} - 3 \, {\left (2 \, a^{2} + 1\right )} b c d + {\left (2 \, a^{3} + 3 \, a\right )} d^{2}\right )} \sqrt {b^{2}} \operatorname {erf}\left (\frac {\sqrt {b^{2}} {\left (b x + a\right )}}{b}\right ) + 2 \, {\left (2 \, \pi b^{4} d^{2} x^{3} + 6 \, \pi b^{4} c d x^{2} + 6 \, \pi b^{4} c^{2} x + \pi {\left (6 \, a b^{3} c^{2} - 3 \, {\left (2 \, a^{2} + 1\right )} b^{2} c d + {\left (2 \, a^{3} + 3 \, a\right )} b d^{2}\right )}\right )} \operatorname {erf}\left (b x + a\right )^{2} - 8 \, \sqrt {\pi } {\left (b^{3} d^{2} x^{2} + 3 \, b^{3} c^{2} - 3 \, a b^{2} c d + {\left (a^{2} + 1\right )} b d^{2} + {\left (3 \, b^{3} c d - a b^{2} d^{2}\right )} x - {\left (b^{3} d^{2} x^{2} + 3 \, b^{3} c^{2} - 3 \, a b^{2} c d + {\left (a^{2} + 1\right )} b d^{2} + {\left (3 \, b^{3} c d - a b^{2} d^{2}\right )} x\right )} \operatorname {erf}\left (b x + a\right )\right )} e^{\left (-b^{2} x^{2} - 2 \, a b x - a^{2}\right )} - 8 \, {\left (\pi b^{4} d^{2} x^{3} + 3 \, \pi b^{4} c d x^{2} + 3 \, \pi b^{4} c^{2} x\right )} \operatorname {erf}\left (b x + a\right ) + 4 \, {\left (b^{2} d^{2} x + 3 \, b^{2} c d - 2 \, a b d^{2}\right )} e^{\left (-2 \, b^{2} x^{2} - 4 \, a b x - 2 \, a^{2}\right )}}{12 \, \pi b^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (c + d x\right )^{2} \operatorname {erfc}^{2}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\mathrm {erfc}\left (a+b\,x\right )}^2\,{\left (c+d\,x\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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