Optimal. Leaf size=95 \[ -\frac {a^2 \text {FresnelC}(a+b x)}{2 b^2}+\frac {1}{2} x^2 \text {FresnelC}(a+b x)+\frac {S(a+b x)}{2 b^2 \pi }+\frac {a \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{b^2 \pi }-\frac {(a+b x) \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi } \]
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Rubi [A]
time = 0.05, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.875, Rules used = {6564, 3515,
3433, 3461, 2717, 3467, 3432} \begin {gather*} -\frac {a^2 \text {FresnelC}(a+b x)}{2 b^2}+\frac {S(a+b x)}{2 \pi b^2}+\frac {a \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{\pi b^2}-\frac {(a+b x) \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{2 \pi b^2}+\frac {1}{2} x^2 \text {FresnelC}(a+b x) \end {gather*}
Antiderivative was successfully verified.
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Rule 2717
Rule 3432
Rule 3433
Rule 3461
Rule 3467
Rule 3515
Rule 6564
Rubi steps
\begin {align*} \int x C(a+b x) \, dx &=\frac {1}{2} x^2 C(a+b x)-\frac {1}{2} b \int x^2 \cos \left (\frac {1}{2} \pi (a+b x)^2\right ) \, dx\\ &=\frac {1}{2} x^2 C(a+b x)-\frac {\text {Subst}\left (\int \left (a^2 \cos \left (\frac {\pi x^2}{2}\right )-2 a x \cos \left (\frac {\pi x^2}{2}\right )+x^2 \cos \left (\frac {\pi x^2}{2}\right )\right ) \, dx,x,a+b x\right )}{2 b^2}\\ &=\frac {1}{2} x^2 C(a+b x)-\frac {\text {Subst}\left (\int x^2 \cos \left (\frac {\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2}+\frac {a \text {Subst}\left (\int x \cos \left (\frac {\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{b^2}-\frac {a^2 \text {Subst}\left (\int \cos \left (\frac {\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2}\\ &=-\frac {a^2 C(a+b x)}{2 b^2}+\frac {1}{2} x^2 C(a+b x)-\frac {(a+b x) \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi }+\frac {a \text {Subst}\left (\int \cos \left (\frac {\pi x}{2}\right ) \, dx,x,(a+b x)^2\right )}{2 b^2}+\frac {\text {Subst}\left (\int \sin \left (\frac {\pi x^2}{2}\right ) \, dx,x,a+b x\right )}{2 b^2 \pi }\\ &=-\frac {a^2 C(a+b x)}{2 b^2}+\frac {1}{2} x^2 C(a+b x)+\frac {S(a+b x)}{2 b^2 \pi }+\frac {a \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{b^2 \pi }-\frac {(a+b x) \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi }\\ \end {align*}
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Mathematica [A]
time = 0.10, size = 59, normalized size = 0.62 \begin {gather*} \frac {\left (-a^2 \pi +b^2 \pi x^2\right ) \text {FresnelC}(a+b x)+S(a+b x)+(a-b x) \sin \left (\frac {1}{2} \pi (a+b x)^2\right )}{2 b^2 \pi } \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.38, size = 79, normalized size = 0.83
method | result | size |
derivativedivides | \(\frac {\FresnelC \left (b x +a \right ) \left (-a \left (b x +a \right )+\frac {\left (b x +a \right )^{2}}{2}\right )+\frac {a \sin \left (\frac {\pi \left (b x +a \right )^{2}}{2}\right )}{\pi }-\frac {\left (b x +a \right ) \sin \left (\frac {\pi \left (b x +a \right )^{2}}{2}\right )}{2 \pi }+\frac {\mathrm {S}\left (b x +a \right )}{2 \pi }}{b^{2}}\) | \(79\) |
default | \(\frac {\FresnelC \left (b x +a \right ) \left (-a \left (b x +a \right )+\frac {\left (b x +a \right )^{2}}{2}\right )+\frac {a \sin \left (\frac {\pi \left (b x +a \right )^{2}}{2}\right )}{\pi }-\frac {\left (b x +a \right ) \sin \left (\frac {\pi \left (b x +a \right )^{2}}{2}\right )}{2 \pi }+\frac {\mathrm {S}\left (b x +a \right )}{2 \pi }}{b^{2}}\) | \(79\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] Result contains complex when optimal does not.
time = 0.82, size = 311, normalized size = 3.27 \begin {gather*} \frac {1}{2} \, x^{2} \operatorname {C}\left (b x + a\right ) + \frac {{\left (8 \, {\left (-i \, \pi e^{\left (\frac {1}{2} i \, \pi b^{2} x^{2} + i \, \pi a b x + \frac {1}{2} i \, \pi a^{2}\right )} + i \, \pi e^{\left (-\frac {1}{2} i \, \pi b^{2} x^{2} - i \, \pi a b x - \frac {1}{2} i \, \pi a^{2}\right )}\right )} a b x + 8 \, {\left (-i \, \pi e^{\left (\frac {1}{2} i \, \pi b^{2} x^{2} + i \, \pi a b x + \frac {1}{2} i \, \pi a^{2}\right )} + i \, \pi e^{\left (-\frac {1}{2} i \, \pi b^{2} x^{2} - i \, \pi a b x - \frac {1}{2} i \, \pi a^{2}\right )}\right )} a^{2} - \sqrt {2 \, \pi b^{2} x^{2} + 4 \, \pi a b x + 2 \, \pi a^{2}} {\left ({\left (-\left (i - 1\right ) \, \sqrt {2} \pi ^{\frac {3}{2}} {\left (\operatorname {erf}\left (\sqrt {\frac {1}{2} i \, \pi b^{2} x^{2} + i \, \pi a b x + \frac {1}{2} i \, \pi a^{2}}\right ) - 1\right )} + \left (i + 1\right ) \, \sqrt {2} \pi ^{\frac {3}{2}} {\left (\operatorname {erf}\left (\sqrt {-\frac {1}{2} i \, \pi b^{2} x^{2} - i \, \pi a b x - \frac {1}{2} i \, \pi a^{2}}\right ) - 1\right )}\right )} a^{2} + \left (2 i + 2\right ) \, \sqrt {2} \Gamma \left (\frac {3}{2}, \frac {1}{2} i \, \pi b^{2} x^{2} + i \, \pi a b x + \frac {1}{2} i \, \pi a^{2}\right ) - \left (2 i - 2\right ) \, \sqrt {2} \Gamma \left (\frac {3}{2}, -\frac {1}{2} i \, \pi b^{2} x^{2} - i \, \pi a b x - \frac {1}{2} i \, \pi a^{2}\right )\right )}\right )} b}{16 \, {\left (\pi ^{2} b^{4} x + \pi ^{2} a b^{3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 104, normalized size = 1.09 \begin {gather*} \frac {\pi b^{3} x^{2} \operatorname {C}\left (b x + a\right ) - \pi a^{2} \sqrt {b^{2}} \operatorname {C}\left (\frac {\sqrt {b^{2}} {\left (b x + a\right )}}{b}\right ) - {\left (b^{2} x - a b\right )} \sin \left (\frac {1}{2} \, \pi b^{2} x^{2} + \pi a b x + \frac {1}{2} \, \pi a^{2}\right ) + \sqrt {b^{2}} \operatorname {S}\left (\frac {\sqrt {b^{2}} {\left (b x + a\right )}}{b}\right )}{2 \, \pi b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x C\left (a + b x\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x\,\mathrm {FresnelC}\left (a+b\,x\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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