3.2.75 \(\int \cos (\frac {1}{2} b^2 \pi x^2) \text {FresnelC}(b x) \, dx\) [175]

Optimal. Leaf size=13 \[ \frac {\text {FresnelC}(b x)^2}{2 b} \]

[Out]

1/2*FresnelC(b*x)^2/b

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Rubi [A]
time = 0.01, antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {6576, 30} \begin {gather*} \frac {\text {FresnelC}(b x)^2}{2 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Cos[(b^2*Pi*x^2)/2]*FresnelC[b*x],x]

[Out]

FresnelC[b*x]^2/(2*b)

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 6576

Int[Cos[(d_.)*(x_)^2]*FresnelC[(b_.)*(x_)]^(n_.), x_Symbol] :> Dist[Pi*(b/(2*d)), Subst[Int[x^n, x], x, Fresne
lC[b*x]], x] /; FreeQ[{b, d, n}, x] && EqQ[d^2, (Pi^2/4)*b^4]

Rubi steps

\begin {align*} \int \cos \left (\frac {1}{2} b^2 \pi x^2\right ) C(b x) \, dx &=\frac {\text {Subst}(\int x \, dx,x,C(b x))}{b}\\ &=\frac {C(b x)^2}{2 b}\\ \end {align*}

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Mathematica [A]
time = 0.01, size = 13, normalized size = 1.00 \begin {gather*} \frac {\text {FresnelC}(b x)^2}{2 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Cos[(b^2*Pi*x^2)/2]*FresnelC[b*x],x]

[Out]

FresnelC[b*x]^2/(2*b)

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Maple [A]
time = 0.19, size = 12, normalized size = 0.92

method	result	size
derivativedivides	\(\frac {\FresnelC \left (b x \right )^{2}}{2 b}\)	\(12\)
default	\(\frac {\FresnelC \left (b x \right )^{2}}{2 b}\)	\(12\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(1/2*b^2*Pi*x^2)*FresnelC(b*x),x,method=_RETURNVERBOSE)

[Out]

1/2*FresnelC(b*x)^2/b

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Maxima [A]
time = 0.26, size = 11, normalized size = 0.85 \begin {gather*} \frac {\operatorname {C}\left (b x\right )^{2}}{2 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="maxima")

[Out]

1/2*fresnel_cos(b*x)^2/b

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Fricas [A]
time = 0.37, size = 11, normalized size = 0.85 \begin {gather*} \frac {\operatorname {C}\left (b x\right )^{2}}{2 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="fricas")

[Out]

1/2*fresnel_cos(b*x)^2/b

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Sympy [A]
time = 0.10, size = 10, normalized size = 0.77 \begin {gather*} \begin {cases} \frac {C^{2}\left (b x\right )}{2 b} & \text {for}\: b \neq 0 \\0 & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(1/2*b**2*pi*x**2)*fresnelc(b*x),x)

[Out]

Piecewise((fresnelc(b*x)**2/(2*b), Ne(b, 0)), (0, True))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(1/2*b^2*pi*x^2)*fresnel_cos(b*x),x, algorithm="giac")

[Out]

integrate(cos(1/2*pi*b^2*x^2)*fresnel_cos(b*x), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.08 \begin {gather*} \int \mathrm {FresnelC}\left (b\,x\right )\,\cos \left (\frac {\Pi \,b^2\,x^2}{2}\right ) \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelC(b*x)*cos((Pi*b^2*x^2)/2),x)

[Out]

int(FresnelC(b*x)*cos((Pi*b^2*x^2)/2), x)

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