3.1.82 \(\int \frac {S(b x) \sin (\frac {1}{2} b^2 \pi x^2)}{x^3} \, dx\) [82]

Optimal. Leaf size=102 \[ -\frac {b}{4 x}+\frac {b \cos \left (b^2 \pi x^2\right )}{4 x}+\frac {b^2 \pi S\left (\sqrt {2} b x\right )}{2 \sqrt {2}}-\frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x^2}+\frac {1}{2} b^2 \pi \text {Int}\left (\frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{x},x\right ) \]

[Out]

-1/4*b/x+1/4*b*cos(b^2*Pi*x^2)/x-1/2*FresnelS(b*x)*sin(1/2*b^2*Pi*x^2)/x^2+1/4*b^2*Pi*FresnelS(b*x*2^(1/2))*2^
(1/2)+1/2*b^2*Pi*Unintegrable(cos(1/2*b^2*Pi*x^2)*FresnelS(b*x)/x,x)

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Rubi [A]
time = 0.04, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^3} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(FresnelS[b*x]*Sin[(b^2*Pi*x^2)/2])/x^3,x]

[Out]

-1/4*b/x + (b*Cos[b^2*Pi*x^2])/(4*x) + (b^2*Pi*FresnelS[Sqrt[2]*b*x])/(2*Sqrt[2]) - (FresnelS[b*x]*Sin[(b^2*Pi
*x^2)/2])/(2*x^2) + (b^2*Pi*Defer[Int][(Cos[(b^2*Pi*x^2)/2]*FresnelS[b*x])/x, x])/2

Rubi steps

\begin {align*} \int \frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^3} \, dx &=-\frac {b}{4 x}-\frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x^2}-\frac {1}{4} b \int \frac {\cos \left (b^2 \pi x^2\right )}{x^2} \, dx+\frac {1}{2} \left (b^2 \pi \right ) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{x} \, dx\\ &=-\frac {b}{4 x}+\frac {b \cos \left (b^2 \pi x^2\right )}{4 x}-\frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x^2}+\frac {1}{2} \left (b^2 \pi \right ) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{x} \, dx+\frac {1}{2} \left (b^3 \pi \right ) \int \sin \left (b^2 \pi x^2\right ) \, dx\\ &=-\frac {b}{4 x}+\frac {b \cos \left (b^2 \pi x^2\right )}{4 x}+\frac {b^2 \pi S\left (\sqrt {2} b x\right )}{2 \sqrt {2}}-\frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x^2}+\frac {1}{2} \left (b^2 \pi \right ) \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{x} \, dx\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{x^3} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(FresnelS[b*x]*Sin[(b^2*Pi*x^2)/2])/x^3,x]

[Out]

Integrate[(FresnelS[b*x]*Sin[(b^2*Pi*x^2)/2])/x^3, x]

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Maple [A]
time = 0.02, size = 0, normalized size = 0.00 \[\int \frac {\mathrm {S}\left (b x \right ) \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{x^{3}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelS(b*x)*sin(1/2*b^2*Pi*x^2)/x^3,x)

[Out]

int(FresnelS(b*x)*sin(1/2*b^2*Pi*x^2)/x^3,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnel_sin(b*x)*sin(1/2*b^2*pi*x^2)/x^3,x, algorithm="maxima")

[Out]

integrate(fresnel_sin(b*x)*sin(1/2*pi*b^2*x^2)/x^3, x)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnel_sin(b*x)*sin(1/2*b^2*pi*x^2)/x^3,x, algorithm="fricas")

[Out]

integral(fresnel_sin(b*x)*sin(1/2*pi*b^2*x^2)/x^3, x)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sin {\left (\frac {\pi b^{2} x^{2}}{2} \right )} S\left (b x\right )}{x^{3}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnels(b*x)*sin(1/2*b**2*pi*x**2)/x**3,x)

[Out]

Integral(sin(pi*b**2*x**2/2)*fresnels(b*x)/x**3, x)

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnel_sin(b*x)*sin(1/2*b^2*pi*x^2)/x^3,x, algorithm="giac")

[Out]

integrate(fresnel_sin(b*x)*sin(1/2*pi*b^2*x^2)/x^3, x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\mathrm {FresnelS}\left (b\,x\right )\,\sin \left (\frac {\Pi \,b^2\,x^2}{2}\right )}{x^3} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((FresnelS(b*x)*sin((Pi*b^2*x^2)/2))/x^3,x)

[Out]

int((FresnelS(b*x)*sin((Pi*b^2*x^2)/2))/x^3, x)

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