Optimal. Leaf size=218 \[ \frac {a x}{2 b^2}-\frac {x^2}{4 b}+\frac {\cos (2 a+2 b x)}{2 b^3}-\frac {\text {CosIntegral}(2 a+2 b x)}{b^3}+\frac {a^2 \text {CosIntegral}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}-\frac {a^2 \log (a+b x)}{2 b^3}-\frac {a \cos (a+b x) \sin (a+b x)}{2 b^3}+\frac {x \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}+\frac {a \text {Si}(2 a+2 b x)}{b^3} \]
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Rubi [A]
time = 0.48, antiderivative size = 218, normalized size of antiderivative = 1.00, number of
steps used = 21, number of rules used = 14, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.875, Rules used
= {6654, 6874, 2715, 8, 3391, 30, 3393, 3383, 6648, 4669, 6873, 2718, 3380, 6652}
\begin {gather*} \frac {a^2 \text {CosIntegral}(2 a+2 b x)}{2 b^3}-\frac {a^2 \log (a+b x)}{2 b^3}-\frac {\text {CosIntegral}(2 a+2 b x)}{b^3}+\frac {a \text {Si}(2 a+2 b x)}{b^3}-\frac {2 \text {Si}(a+b x) \sin (a+b x)}{b^3}+\frac {\log (a+b x)}{b^3}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {\cos (2 a+2 b x)}{2 b^3}-\frac {a \sin (a+b x) \cos (a+b x)}{2 b^3}+\frac {2 x \text {Si}(a+b x) \cos (a+b x)}{b^2}+\frac {a x}{2 b^2}+\frac {x \sin (a+b x) \cos (a+b x)}{2 b^2}+\frac {x^2 \text {Si}(a+b x) \sin (a+b x)}{b}-\frac {x^2}{4 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 30
Rule 2715
Rule 2718
Rule 3380
Rule 3383
Rule 3391
Rule 3393
Rule 4669
Rule 6648
Rule 6652
Rule 6654
Rule 6873
Rule 6874
Rubi steps
\begin {align*} \int x^2 \cos (a+b x) \text {Si}(a+b x) \, dx &=\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}-\frac {2 \int x \sin (a+b x) \text {Si}(a+b x) \, dx}{b}-\int \frac {x^2 \sin ^2(a+b x)}{a+b x} \, dx\\ &=\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}-\frac {2 \int \cos (a+b x) \text {Si}(a+b x) \, dx}{b^2}-\frac {2 \int \frac {x \cos (a+b x) \sin (a+b x)}{a+b x} \, dx}{b}-\int \left (-\frac {a \sin ^2(a+b x)}{b^2}+\frac {x \sin ^2(a+b x)}{b}+\frac {a^2 \sin ^2(a+b x)}{b^2 (a+b x)}\right ) \, dx\\ &=\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}+\frac {2 \int \frac {\sin ^2(a+b x)}{a+b x} \, dx}{b^2}+\frac {a \int \sin ^2(a+b x) \, dx}{b^2}-\frac {a^2 \int \frac {\sin ^2(a+b x)}{a+b x} \, dx}{b^2}-\frac {\int x \sin ^2(a+b x) \, dx}{b}-\frac {\int \frac {x \sin (2 (a+b x))}{a+b x} \, dx}{b}\\ &=-\frac {a \cos (a+b x) \sin (a+b x)}{2 b^3}+\frac {x \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}+\frac {2 \int \left (\frac {1}{2 (a+b x)}-\frac {\cos (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b^2}+\frac {a \int 1 \, dx}{2 b^2}-\frac {a^2 \int \left (\frac {1}{2 (a+b x)}-\frac {\cos (2 a+2 b x)}{2 (a+b x)}\right ) \, dx}{b^2}-\frac {\int x \, dx}{2 b}-\frac {\int \frac {x \sin (2 a+2 b x)}{a+b x} \, dx}{b}\\ &=\frac {a x}{2 b^2}-\frac {x^2}{4 b}+\frac {\log (a+b x)}{b^3}-\frac {a^2 \log (a+b x)}{2 b^3}-\frac {a \cos (a+b x) \sin (a+b x)}{2 b^3}+\frac {x \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}-\frac {\int \frac {\cos (2 a+2 b x)}{a+b x} \, dx}{b^2}+\frac {a^2 \int \frac {\cos (2 a+2 b x)}{a+b x} \, dx}{2 b^2}-\frac {\int \left (\frac {\sin (2 a+2 b x)}{b}+\frac {a \sin (2 a+2 b x)}{b (-a-b x)}\right ) \, dx}{b}\\ &=\frac {a x}{2 b^2}-\frac {x^2}{4 b}-\frac {\text {Ci}(2 a+2 b x)}{b^3}+\frac {a^2 \text {Ci}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}-\frac {a^2 \log (a+b x)}{2 b^3}-\frac {a \cos (a+b x) \sin (a+b x)}{2 b^3}+\frac {x \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}-\frac {\int \sin (2 a+2 b x) \, dx}{b^2}-\frac {a \int \frac {\sin (2 a+2 b x)}{-a-b x} \, dx}{b^2}\\ &=\frac {a x}{2 b^2}-\frac {x^2}{4 b}+\frac {\cos (2 a+2 b x)}{2 b^3}-\frac {\text {Ci}(2 a+2 b x)}{b^3}+\frac {a^2 \text {Ci}(2 a+2 b x)}{2 b^3}+\frac {\log (a+b x)}{b^3}-\frac {a^2 \log (a+b x)}{2 b^3}-\frac {a \cos (a+b x) \sin (a+b x)}{2 b^3}+\frac {x \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {\sin ^2(a+b x)}{4 b^3}+\frac {2 x \cos (a+b x) \text {Si}(a+b x)}{b^2}-\frac {2 \sin (a+b x) \text {Si}(a+b x)}{b^3}+\frac {x^2 \sin (a+b x) \text {Si}(a+b x)}{b}+\frac {a \text {Si}(2 a+2 b x)}{b^3}\\ \end {align*}
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Mathematica [A]
time = 0.24, size = 134, normalized size = 0.61 \begin {gather*} \frac {4 a b x-2 b^2 x^2+5 \cos (2 (a+b x))+4 \left (-2+a^2\right ) \text {CosIntegral}(2 (a+b x))+8 \log (a+b x)-4 a^2 \log (a+b x)-2 a \sin (2 (a+b x))+2 b x \sin (2 (a+b x))+8 \left (2 b x \cos (a+b x)+\left (-2+b^2 x^2\right ) \sin (a+b x)\right ) \text {Si}(a+b x)+8 a \text {Si}(2 (a+b x))}{8 b^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.66, size = 212, normalized size = 0.97
method | result | size |
derivativedivides | \(\frac {\sinIntegral \left (b x +a \right ) \left (a^{2} \sin \left (b x +a \right )-2 a \left (\cos \left (b x +a \right )+\left (b x +a \right ) \sin \left (b x +a \right )\right )+\left (b x +a \right )^{2} \sin \left (b x +a \right )-2 \sin \left (b x +a \right )+2 \left (b x +a \right ) \cos \left (b x +a \right )\right )-\frac {a^{2} \ln \left (b x +a \right )}{2}+\frac {a^{2} \cosineIntegral \left (2 b x +2 a \right )}{2}-\sin \left (b x +a \right ) \cos \left (b x +a \right ) a +a \left (b x +a \right )-\left (b x +a \right ) \left (-\frac {\sin \left (b x +a \right ) \cos \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )+\frac {\left (b x +a \right )^{2}}{4}-\frac {\left (\sin ^{2}\left (b x +a \right )\right )}{4}+a \sinIntegral \left (2 b x +2 a \right )+\cos ^{2}\left (b x +a \right )+\ln \left (b x +a \right )-\cosineIntegral \left (2 b x +2 a \right )}{b^{3}}\) | \(212\) |
default | \(\frac {\sinIntegral \left (b x +a \right ) \left (a^{2} \sin \left (b x +a \right )-2 a \left (\cos \left (b x +a \right )+\left (b x +a \right ) \sin \left (b x +a \right )\right )+\left (b x +a \right )^{2} \sin \left (b x +a \right )-2 \sin \left (b x +a \right )+2 \left (b x +a \right ) \cos \left (b x +a \right )\right )-\frac {a^{2} \ln \left (b x +a \right )}{2}+\frac {a^{2} \cosineIntegral \left (2 b x +2 a \right )}{2}-\sin \left (b x +a \right ) \cos \left (b x +a \right ) a +a \left (b x +a \right )-\left (b x +a \right ) \left (-\frac {\sin \left (b x +a \right ) \cos \left (b x +a \right )}{2}+\frac {b x}{2}+\frac {a}{2}\right )+\frac {\left (b x +a \right )^{2}}{4}-\frac {\left (\sin ^{2}\left (b x +a \right )\right )}{4}+a \sinIntegral \left (2 b x +2 a \right )+\cos ^{2}\left (b x +a \right )+\ln \left (b x +a \right )-\cosineIntegral \left (2 b x +2 a \right )}{b^{3}}\) | \(212\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.37, size = 141, normalized size = 0.65 \begin {gather*} -\frac {b^{2} x^{2} - 8 \, b x \cos \left (b x + a\right ) \operatorname {Si}\left (b x + a\right ) - 2 \, a b x - 5 \, \cos \left (b x + a\right )^{2} - {\left (a^{2} - 2\right )} \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) - {\left (a^{2} - 2\right )} \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) + 2 \, {\left (a^{2} - 2\right )} \log \left (b x + a\right ) - 2 \, {\left ({\left (b x - a\right )} \cos \left (b x + a\right ) + 2 \, {\left (b^{2} x^{2} - 2\right )} \operatorname {Si}\left (b x + a\right )\right )} \sin \left (b x + a\right ) - 4 \, a \operatorname {Si}\left (2 \, b x + 2 \, a\right )}{4 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{2} \cos {\left (a + b x \right )} \operatorname {Si}{\left (a + b x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.43, size = 431, normalized size = 1.98 \begin {gather*} {\left (\frac {2 \, x \cos \left (b x + a\right )}{b^{2}} + \frac {{\left (b^{2} x^{2} - 2\right )} \sin \left (b x + a\right )}{b^{3}}\right )} \operatorname {Si}\left (b x + a\right ) - \frac {2 \, b^{2} x^{2} \tan \left (b x + a\right )^{2} - 4 \, a b x \tan \left (b x + a\right )^{2} + 4 \, a^{2} \log \left ({\left | b x + a \right |}\right ) \tan \left (b x + a\right )^{2} - 2 \, a^{2} \Re \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} - 2 \, a^{2} \Re \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} + 2 \, b^{2} x^{2} - 4 \, a \Im \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} + 4 \, a \Im \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} - 8 \, a \operatorname {Si}\left (2 \, b x + 2 \, a\right ) \tan \left (b x + a\right )^{2} - 4 \, a b x + 4 \, a^{2} \log \left ({\left | b x + a \right |}\right ) - 2 \, a^{2} \Re \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) - 2 \, a^{2} \Re \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) - 4 \, b x \tan \left (b x + a\right ) - 8 \, \log \left ({\left | b x + a \right |}\right ) \tan \left (b x + a\right )^{2} + 4 \, \Re \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} + 4 \, \Re \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) \tan \left (b x + a\right )^{2} - 4 \, a \Im \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) + 4 \, a \Im \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) - 8 \, a \operatorname {Si}\left (2 \, b x + 2 \, a\right ) + 4 \, a \tan \left (b x + a\right ) + 5 \, \tan \left (b x + a\right )^{2} - 8 \, \log \left ({\left | b x + a \right |}\right ) + 4 \, \Re \left ( \operatorname {Ci}\left (2 \, b x + 2 \, a\right ) \right ) + 4 \, \Re \left ( \operatorname {Ci}\left (-2 \, b x - 2 \, a\right ) \right ) - 5}{8 \, {\left (b^{3} \tan \left (b x + a\right )^{2} + b^{3}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^2\,\mathrm {sinint}\left (a+b\,x\right )\,\cos \left (a+b\,x\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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