Optimal. Leaf size=63 \[ \frac {3 \cosh (b x)}{2 b^4}+\frac {3 x^2 \cosh (b x)}{4 b^2}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {3 x \sinh (b x)}{2 b^3}-\frac {x^3 \sinh (b x)}{4 b} \]
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Rubi [A]
time = 0.06, antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6668, 12, 3377,
2718} \begin {gather*} \frac {3 \cosh (b x)}{2 b^4}-\frac {3 x \sinh (b x)}{2 b^3}+\frac {3 x^2 \cosh (b x)}{4 b^2}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {x^3 \sinh (b x)}{4 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2718
Rule 3377
Rule 6668
Rubi steps
\begin {align*} \int x^3 \text {Chi}(b x) \, dx &=\frac {1}{4} x^4 \text {Chi}(b x)-\frac {1}{4} b \int \frac {x^3 \cosh (b x)}{b} \, dx\\ &=\frac {1}{4} x^4 \text {Chi}(b x)-\frac {1}{4} \int x^3 \cosh (b x) \, dx\\ &=\frac {1}{4} x^4 \text {Chi}(b x)-\frac {x^3 \sinh (b x)}{4 b}+\frac {3 \int x^2 \sinh (b x) \, dx}{4 b}\\ &=\frac {3 x^2 \cosh (b x)}{4 b^2}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {x^3 \sinh (b x)}{4 b}-\frac {3 \int x \cosh (b x) \, dx}{2 b^2}\\ &=\frac {3 x^2 \cosh (b x)}{4 b^2}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {3 x \sinh (b x)}{2 b^3}-\frac {x^3 \sinh (b x)}{4 b}+\frac {3 \int \sinh (b x) \, dx}{2 b^3}\\ &=\frac {3 \cosh (b x)}{2 b^4}+\frac {3 x^2 \cosh (b x)}{4 b^2}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {3 x \sinh (b x)}{2 b^3}-\frac {x^3 \sinh (b x)}{4 b}\\ \end {align*}
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Mathematica [A]
time = 0.03, size = 53, normalized size = 0.84 \begin {gather*} \frac {3 \left (2+b^2 x^2\right ) \cosh (b x)}{4 b^4}+\frac {1}{4} x^4 \text {Chi}(b x)-\frac {x \left (6+b^2 x^2\right ) \sinh (b x)}{4 b^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.25, size = 56, normalized size = 0.89
method | result | size |
derivativedivides | \(\frac {\frac {b^{4} x^{4} \hyperbolicCosineIntegral \left (b x \right )}{4}-\frac {b^{3} x^{3} \sinh \left (b x \right )}{4}+\frac {3 b^{2} x^{2} \cosh \left (b x \right )}{4}-\frac {3 b x \sinh \left (b x \right )}{2}+\frac {3 \cosh \left (b x \right )}{2}}{b^{4}}\) | \(56\) |
default | \(\frac {\frac {b^{4} x^{4} \hyperbolicCosineIntegral \left (b x \right )}{4}-\frac {b^{3} x^{3} \sinh \left (b x \right )}{4}+\frac {3 b^{2} x^{2} \cosh \left (b x \right )}{4}-\frac {3 b x \sinh \left (b x \right )}{2}+\frac {3 \cosh \left (b x \right )}{2}}{b^{4}}\) | \(56\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 1.50, size = 85, normalized size = 1.35 \begin {gather*} - \frac {x^{4} \log {\left (b x \right )}}{4} + \frac {x^{4} \log {\left (b^{2} x^{2} \right )}}{8} + \frac {x^{4} \operatorname {Chi}\left (b x\right )}{4} - \frac {x^{3} \sinh {\left (b x \right )}}{4 b} + \frac {3 x^{2} \cosh {\left (b x \right )}}{4 b^{2}} - \frac {3 x \sinh {\left (b x \right )}}{2 b^{3}} + \frac {3 \cosh {\left (b x \right )}}{2 b^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x^3\,\mathrm {coshint}\left (b\,x\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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